Iterate over the array searching for multiple elements in Bash [duplicate] - linux

Question

This question already has answers here:
Compare/Difference of two arrays in Bash
(9 answers)
Closed 2 years ago.
firstvar="PRIMARY"
secondvar="SECONDARY"
thirdvar="TERTIARY"
array=($firstvar $secondvar $thirdvar)
echo ${array[*]} //prints PRIMARY SECONDARY TERTIARY
I want to iterate over this array in my bash script, and check if the 3 elements (PRIMARY SECONDARY TERTIARY) are present in the array with no specific order.
If yes, echo "Success. If not, echo Failed. What would be a good way to approach this?
EDIT:
I forgot to mention that if an element(e.g. PRIMARY) is missing from the array, it should also print out Primary is missing.
For a similar array:
array_health=($firsthealth $secondhealth $thirdhealth)
These 3 variables can have either 1 or something else
I want to check whether these 3 variables in the array have value=1, how would I check that? They're not initialized as firsthealth=0 or firsthealth=1.

Answer 1

Try bash rematch
[[ ${array[#]} =~ $firstvar ]] && [[ ${array[#]} =~ $secondvar ]] && [[ ${array[#]} =~ $thirdvar ]] && echo ok || echo ko
Then like this
for item in $firstvar $secondvar $thirdvar; {
[[ ${array[#]} =~ $item ]] && echo "$item" || echo "$item is missing"
}

Answer 2

beginner friendly simple loop with simple case counting all vars
followed by test concatenation and simple if statement
array=("$firstvar" "$secondvar" "$thirdvar")
for i in "${array[#]}"
do
echo "$i"
case "$i" in
"$firstvar")
first=$((first+1))
;;
"$secondvar")
second=$((second+1))
;;
"$thirdvar")
third=$((third+1))
;;
esac
done
if [ "$first" ] && [ "$second" ] && [ "$third" ]
then
echo "Success."
else
[ -z "$first" ] && echo "'$firstvar' missing"
[ -z "$second" ] && echo "'$secondvar' missing"
[ -z "$third" ] && echo "'$thirdvar' missing"
fi
regarding your second array basically same, quote your vars
(although it's unclear to me how you want preserve labels as you only have values in array)
array_health=("$firsthealth" "$secondhealth" "$thirdhealth")
uninitialized vars can be test'ed with -z (as above) or have default value with string manipulation
[ -z "$i" ] && echo "${i:-0}"

Answer 3

You can loop over the elements one by one:
flag=0
for ele in "$firstvar" "$secondvar" "$thirdvar"; do
if [[ ! " ${array[#]} " =~ " ${ele} " ]]; then
echo "$ele" is missing
flag=1
fi
done
if [[ flag -eq 0 ]]; then
echo "all there"
fi
If there is a possibility that your elements may have spaces, that will make the test above unreliable. You can use a different delimiter by using printf to add left and right delimiters to characters unlikely to be in your strings:
firstvar="PRIMARY SECONDARY"
secondvar="SECONDARY"
thirdvar="TERTIARY"
array=("$firstvar" "$thirdvar")
flag=0
printf -v tgt "|%s|" "${array[#]}" # |ele1||ele2||eleN|
for ele in "$firstvar" "$secondvar" "$thirdvar"; do
if [[ ! "$tgt" =~ "|${ele}|" ]]; then
echo "$ele" is missing
flag=1
fi
done
if [[ flag -eq 0 ]]; then
echo "all there"
fi
Prints SECONDARY is missing