I have the following code snippet in pyspark:
import pandas as pd
from pyspark import SparkContext, SparkConf
from pyspark.context import SparkContext
from pyspark.sql import Row, SQLContext, SparkSession
import pyspark.sql.dataframe
def validate_data():
conf = SparkConf().setAppName("app")
spark = SparkContext(conf=conf)
config = {
"val_path" : "s3://forecasting/data/validation.csv"
}
data1_df = spark.read.table("db1.data_dest”)
data2_df = spark.read.table("db2.data_source”)
print(data1_df.count())
print(data2_df.count())
if __name__ == "__main__":
validate_data()
Now this code works fine when run on jupyter notebook on sagemaker ( connecting to EMR )
but when we are running as a python script on terminal, its throwing this error
Error message
AttributeError: 'SparkContext' object has no attribute 'read'
We have to automate these notebooks, so we are trying to convert them to python scripts
You can only call read on a Spark Session, not on a Spark Context.
from pyspark import SparkContext, SparkConf
from pyspark.sql import SparkSession
conf = SparkConf().setAppName("app")
spark = SparkSession.builder.config(conf=conf)
Or you can convert the Spark context to a Spark session
conf = SparkConf().setAppName("app")
sc = SparkContext(conf=conf)
spark = SparkSession(sc)
Related
Trying to create SparkConf using PySpark but getting an error
Code
from pyspark.python.pyspark.shell import spark
from pyspark import SparkConf, SparkContext
from pyspark.shell import sqlContext
from pyspark.sql import SparkSession
conf = SparkConf().setAppName("Test-1 ETL").setMaster("local[*]").set("spark.driver.host", "localhost").set("spark.sql.execution.arrow.pyspark.enabled", "true")
sc = SparkContext(conf=conf)
Error
org.apache.spark.SparkException: Invalid Spark URL: spark://HeartbeatReceiver#xxxx_LPT-324:51380
I have also set set SPARK_LOCAL_HOSTNAME=localhost
Can anyone please help me?
I am trying to read data from BigQuery using pandas and pyspark. I am able to get the data but somehow getting below error while converting it into Spark DataFrame.
py4j.protocol.Py4JJavaError: An error occurred while calling o28.showString.
: java.lang.IllegalStateException: Could not find TLS ALPN provider; no working netty-tcnative, Conscrypt, or Jetty NPN/ALPN available
at com.google.cloud.spark.bigquery.repackaged.io.grpc.netty.shaded.io.grpc.netty.GrpcSslContexts.defaultSslProvider(GrpcSslContexts.java:258)
at com.google.cloud.spark.bigquery.repackaged.io.grpc.netty.shaded.io.grpc.netty.GrpcSslContexts.configure(GrpcSslContexts.java:171)
at com.google.cloud.spark.bigquery.repackaged.io.grpc.netty.shaded.io.grpc.netty.GrpcSslContexts.forClient(GrpcSslContexts.java:120)
at com.google.cloud.spark.bigquery.repackaged.io.grpc.netty.shaded.io.grpc.netty.NettyChannelBuilder.buildTransportFactory(NettyChannelBuilder.java:401)
at com.google.cloud.spark.bigquery.repackaged.io.grpc.internal.AbstractManagedChannelImplBuilder.build(AbstractManagedChannelImplBuilder.java:444)
at com.google.cloud.spark.bigquery.repackaged.com.google.api.gax.grpc.InstantiatingGrpcChannelProvider.createSingleChannel(InstantiatingGrpcChannelProvider.java:223)
at com.google.cloud.spark.bigquery.repackaged.com.google.api.gax.grpc.InstantiatingGrpcChannelProvider.createChannel(InstantiatingGrpcChannelProvider.java:169)
at com.google.cloud.spark.bigquery.repackaged.com.google.api.gax.grpc.InstantiatingGrpcChannelProvider.getTransportChannel(InstantiatingGrpcChannelProvider.java:156)
at com.google.cloud.spark.bigquery.repackaged.com.google.api.gax.rpc.ClientContext.create(ClientContext.java:157)
Following is the environment detail
Python version : 3.7
Spark version : 2.4.3
Java version : 1.8
The code is as follow
import google.auth
import pyspark
from pyspark import SparkConf, SparkContext
from pyspark.sql import SparkSession , SQLContext
from google.cloud import bigquery
# Currently this only supports queries which have at least 10 MB of results
QUERY = """ SELECT * FROM test limit 1 """
#spark = SparkSession.builder.appName('Query Results').getOrCreate()
sc = pyspark.SparkContext()
bq = bigquery.Client()
print('Querying BigQuery')
project_id = ''
query_job = bq.query(QUERY,project=project_id)
# Wait for query execution
query_job.result()
df = SQLContext(sc).read.format('bigquery') \
.option('dataset', query_job.destination.dataset_id) \
.option('table', query_job.destination.table_id)\
.option("type", "direct")\
.load()
df.show()
I am looking some help to solve this issue.
I managed to find the better solution referencing this link , below is my working code :
Install pandas_gbq package in python library before writing below code .
import pandas_gbq
from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
project_id = "<your-project-id>"
query = """ SELECT * from testSchema.testTable"""
athletes = pandas_gbq.read_gbq(query=query, project_id=project_id,dialect = 'standard')
# Get a reference to the Spark Session
sc = SparkContext()
spark = SparkSession(sc)
# convert from Pandas to Spark
sparkDF = spark.createDataFrame(athletes)
# perform an operation on the DataFrame
print(sparkDF.count())
sparkDF.show()
Hope it helps to someone ! Keep pysparking :)
I have written the below code to read the data from HIVE table and when I am trying to run no compilation errors and no data displaying.
from pyspark import SparkConf, SparkContext
from pyspark.sql import SQLContext, HiveContext, SparkSession
import os
os.environ['PYSPARK_SUBMIT_ARGS'] = '--jars hive-jdbc-2.1.0.jar
pyspark-shell'
sparkConf = SparkConf().setAppName("App")
sc = SparkContext(conf=sparkConf)
sqlContext = SQLContext(sc)
hiveContext = HiveContext(sc);
source_df = hiveContext.read.format('jdbc').options(
url='jdbc:hive2://localhost:10000/sample',
driver='org.apache.hive.jdbc.HiveDriver',
dbtable='abc',
user='root',
password='root').load()
print source_df.show()
When i run this, I am getting below output and not able to fetch the
data from table.
+--------+------+
|abc.name|abc.id|
+--------+------+
+--------+------+
Just try
df = hiveContext.read.table("your_hive_table") //reads from default db
df = hiveContext.read.table("your_db.your_hive_table") //reads from your db
you could also do
df = hiveContext.sql("select * from your_table")
My Spark package is spark-2.2.0-bin-hadoop2.7.
I exported spark variables as
export SPARK_HOME=/home/harry/spark-2.2.0-bin-hadoop2.7
export PATH=$SPARK_HOME/bin:$PATH
I opened spark notebook by
pyspark
I am able to load packages from spark
from pyspark import SparkContext, SQLContext
from pyspark.ml.regression import LinearRegression
print(SQLContext)
output is
<class 'pyspark.sql.context.SQLContext'>
But my error is
print(sc)
"sc is undefined"
plz can anyone help me out ...!
In pysparkShell, SparkContext is already initialized as SparkContext(app=PySparkShell, master=local[*]) so you just need to use getOrCreate() to set the SparkContext to a variable as
sc = SparkContext.getOrCreate()
sqlContext = SQLContext(sc)
For coding purpose in simple local mode, you can do the following
from pyspark import SparkConf, SparkContext, SQLContext
conf = SparkConf().setAppName("test").setMaster("local")
sc = SparkContext(conf=conf)
sqlContext = SQLContext(sc)
print(sc)
print(sqlContext)
I have the following test code:
from pyspark import SparkContext, SQLContext
sc = SparkContext('local')
sqlContext = SQLContext(sc)
print('Created spark context!')
if __name__ == '__main__':
df = sqlContext.read.format("jdbc").options(
url="jdbc:mysql://localhost/mysql",
driver="com.mysql.jdbc.Driver",
dbtable="users",
user="user",
password="****",
properties={"driver": 'com.mysql.jdbc.Driver'}
).load()
print(df)
When I run it, I get the following error:
java.lang.ClassNotFoundException: com.mysql.jdbc.Driver
In Scala, this is solved by importing the .jar mysql-connector-java into the project.
However, in python I have no idea how to tell the pyspark module to link the mysql-connector file.
I have seen this solved with examples like
spark --package=mysql-connector-java testfile.py
But I don't want this since it forces me to run my script in a weird way. I would like an all python solution or copy a file somewhere or, add something to the Path.
You can pass arguments to spark-submit when creating your sparkContext before SparkConf is initialized:
import os
from pyspark import SparkConf, SparkContext
SUBMIT_ARGS = "--packages mysql:mysql-connector-java:5.1.39 pyspark-shell"
os.environ["PYSPARK_SUBMIT_ARGS"] = SUBMIT_ARGS
conf = SparkConf()
sc = SparkContext(conf=conf)
or you can add them to your $SPARK_HOME/conf/spark-defaults.conf
from pyspark.sql import SparkSession
spark = SparkSession\
.builder\
.appName("Word Count")\
.config("spark.driver.extraClassPath", "/home/tuhin/mysql.jar")\
.getOrCreate()
dataframe_mysql = spark.read\
.format("jdbc")\
.option("url", "jdbc:mysql://localhost/database_name")\
.option("driver", "com.mysql.jdbc.Driver")\
.option("dbtable", "employees").option("user", "root")\
.option("password", "12345678").load()
print(dataframe_mysql.columns)
"/home/tuhin/mysql.jar" is the location of mysql jar file
If you are using pycharm and want to run line by line instead of submitting your .py through spark-submit, you can copy your .jar to c:\spark\jars\ and your code could be like:
from pyspark import SparkConf, SparkContext, sql
from pyspark.sql import SparkSession
sc = SparkSession.builder.getOrCreate()
sqlContext = sql.SQLContext(sc)
source_df = sqlContext.read.format('jdbc').options(
url='jdbc:mysql://localhost:3306/database1',
driver='com.mysql.cj.jdbc.Driver', #com.mysql.jdbc.Driver
dbtable='table1',
user='root',
password='****').load()
print (source_df)
source_df.show()