Minimizing the code using the enumerate function in Python - python-3.x

Question

Down below I have a function that checks and outputs any common number within the list_1, list_2, list_3 is there a way that I could use the enumerate or any other function function that would minimize the middle part of the code.
Bit that need minimization:
for elem in l1:#loop to access l1elements
if elem in l2:#checking for element in l2
if elem in l3:#checking for element in l3
Full Code:
def intersect(l1, l2, l3) :#function
for elem in l1:#loop to access l1elements
if elem in l2:#checking for element in l2
if elem in l3:#checking for element in l3
print (element) #display element
list_1 =[27, 20, 22, 21, 17, 12, 24, 23, 19, 14, 11, 26, 25, 13, 15, 21, 18, 28, 29, 10]
list_2 = [14, 25, 26, 21, 22, 17, 11, 23, 27, 18, 24, 28, 12, 29, 16, 19, 13, 10, 20, 15]
list_3 = [19, 21, 11, 24, 16, 17, 18, 22, 26, 10, 23, 29, 27, 13, 25, 14, 15, 20, 28, 12]
intersect(list_1, list_2, list_3) #calling function

Answer 1

You can use numpy intersect1d method to find the common values in the lists or array
def intersect(l1, l2, l3):
print(reduce(np.intersect1d, (l1, l2, l3)))
Result:
[10 11 12 13 14 15 17 18 19 20 21 22 23 24 25 26 27 28 29]
Code:
import numpy as np
from functools import reduce
def intersect(l1, l2, l3):
print(reduce(np.intersect1d, (l1, l2, l3)))
list_1 = [27, 20, 22, 21, 17, 12, 24, 23, 19, 14, 11, 26, 25, 13, 15, 21, 18, 28, 29, 10]
list_2 = [14, 25, 26, 21, 22, 17, 11, 23, 27, 18, 24, 28, 12, 29, 16, 19, 13, 10, 20, 15]
list_3 = [19, 21, 11, 24, 16, 17, 18, 22, 26, 10, 23, 29, 27, 13, 25, 14, 15, 20, 28, 12]
intersect(list_1, list_2, list_3) #calling functio

Answer 2

You should use set object instead.
set_1 = set([27, 20, 22, 21, 17, 12, 24, 23, 19, 14, 11, 26, 25, 13, 15, 21, 18, 28, 29, 10])
set_2 = set([14, 25, 26, 21, 22, 17, 11, 23, 27, 18, 24, 28, 12, 29, 16, 19, 13, 10, 20, 15])
set_3 = set([19, 21, 11, 24, 16, 17, 18, 22, 26, 10, 23, 29, 27, 13, 25, 14, 15, 20, 28, 12])
set_1.intersection(set_2, set_3)

Answer 3

#tony selcuk - It seems that you've tried to loop 3 lists to find corresponding matching numbers? In that case, You could try this code snippet to see if it works as you want. It used the enumerate() to loop all 3 lists together and get their (index, num) as tuple to compare if there is a match. Just run it. Once it proves to work as expected, you can turn it into a function easily. This approach will find all matching numbers that appear in all three list and at the SAME position (index).
for i, j, k in zip(enumerate(list_1), enumerate(list_2), enumerate(list_3)):
#print(i, j, k)
if i == j == k:
print("number:{} order:{}".format(i[1], j[0]))