Bash exercise giving multiple input to a script by another - linux

Question

i've come across to another exercise in preparation to the exam that i always find tricky for the redirection of input/output.
it asks:
Write a first script named "contaseparatamente.sh" that takes a variable number of arguments, each is a name of a file.
The script need to write on the Standard output the tot number of rows of the even's arguments and on the Standard error the tot number of rows of the odd's arguments.
(And i have done like this, and it works):
GNU nano 4.8 contaseparatamente.sh
#!/bin/bash
NUMEVEN=0
NUMODD=0
for((i=1; i<=$#; i++)); do
if((i%2==0))
then
NUMEVEN=$((${NUMEVEN} + `wc -l ${!i} | cut -d ' ' -f 1` ))
else
NUMODD=$((${NUMODD} + `wc -l ${!i} | cut -d ' ' -f 1` ))
fi;
done
echo rows of even ${NUMEVEN}
echo rows of odd ${NUMODD} 1<&2
then it asks: write a second script to launch and execute the first giving him as arguments the first 7 line of the output of ls -S1 /usr/include/*.h in the end this second script must show on the standard error also the output of the first script.
This is my try:
GNU nano 4.8
#!/bin/bash
./contaseparatamente.sh <( ls -S1 /usr/include/*.h | head -n 7 ) 2<&1
but in this way the result is
0 rows from the even
and 7 from the odd, which is not possible

Answer 1

I don't like the assignment, but...
To pass the args in the simplest way, use an unquoted subshell. (ugh)
#!/bin/bash
./contaseparatamente.sh $( ls -S1 /usr/include/*.h | head -n 7 )
The stderr of the first script will bleed through and show when you run the second script if you do nothing at all. If you need it on stdout, just redirect.
#!/bin/bash
./contaseparatamente.sh $( ls -S1 /usr/include/*.h | head -n 7 ) 2>&1