I am trying to fill a dataframe which originally has NaN values with the same number of values taken from an array. All the values in the dictionary leagueList (NFL,NBA, etc.) are individual dataframes.
Sorry, I can't place them here as the post will become too long.
The idea behind the loop below is to get the series of paired t-tests (p_value) between all leagues in the dataframe and compare them based on columns called 'win_loss_ratio'.
The resulting array with the same number of values as in the empty dataframe should be used to replace the NaN values in the dataframe but I am stuck on this part. How this could be accomplished?
leagueList={'NFL':NFL,'NBA':NBA,'NHL':NHL,'MLB':MLB}
df = pd.DataFrame(columns = leagueList, index = leagueList)
print(df)
NFL NBA NHL MLB
NFL NaN NaN NaN NaN
NBA NaN NaN NaN NaN
NHL NaN NaN NaN NaN
MLB NaN NaN NaN NaN
#Double loop for making all possible league combinations
for a in leagueList.values():
for b in leagueList.values():
df_comb=pd.merge(a,b,left_index=True,right_index=True,how='inner')
teststat,p_value=stats.ttest_rel(df_comb[['win_loss_ratio_x']],df_comb[['win_loss_ratio_y']])
print(p_value)
[nan]
[0.94179205]
[0.03088317]
[0.80206949]
[0.94179205]
[nan]
[0.02229705]
[0.95053998]
[0.03088317]
[0.02229705]
[nan]
[0.00070784]
[0.80206949]
[0.95053998]
[0.00070784]
[nan]
Put the p-values into a list to either use .fillna, or just construct it straight a way:
import pandas as pd
from scipy import stats
#some sample data
NFL = pd.DataFrame([.5,.6,.7], columns=['win_loss_ratio'])
NBA = pd.DataFrame([.7,.5,.3], columns=['win_loss_ratio'])
NHL = pd.DataFrame([.4,.3,.2], columns=['win_loss_ratio'])
MLB = pd.DataFrame([.9,.8,.9], columns=['win_loss_ratio'])
leagueList={'NFL':NFL,'NBA':NBA,'NHL':NHL,'MLB':MLB}
#Double loop for making all possible league combinations
rows = []
for a in leagueList.values():
for b in leagueList.values():
df_comb=pd.merge(a,b,left_index=True,right_index=True,how='inner')
teststat,p_value=stats.ttest_rel(df_comb[['win_loss_ratio_x']],df_comb[['win_loss_ratio_y']])
rows.append(p_value[0])
n=len(leagueList)
data = [rows[i * n:(i + 1) * n] for i in range((len(rows) + n - 1) // n )]
df = pd.DataFrame(data, columns = leagueList, index = leagueList)
Output:
print (df.to_string())
NFL NBA NHL MLB
NFL NaN 0.622036 0.12169 0.057191
NBA 0.622036 NaN 0.07418 0.092735
NHL 0.121690 0.074180 NaN 0.013560
MLB 0.057191 0.092735 0.01356 NaN
Related
I am trying to add a row of data to a pandas DataFrame, but it keeps adding a separate row for each piece of data. I feel I am missing something very simple and obvious, but what it is I do not know.
import pandas
colNames = ["ID", "Name", "Gender", "Height", "Weight"]
df1 = pandas.DataFrame(columns = colNames)
df1.set_index("ID", inplace=True, drop=False)
i = df1.shape[0]
person = [{"ID":i},{"Name":"Jack"},{"Gender":"Male"},{"Height":177},{"Weight":75}]
df1 = df1.append(pandas.DataFrame(person, columns=colNames))
print(df1)
Output:
ID Name Gender Height Weight
0 0.0 NaN NaN NaN NaN
1 NaN Jack NaN NaN NaN
2 NaN NaN Male NaN NaN
3 NaN NaN NaN 177.0 NaN
4 NaN NaN NaN NaN 75.0
You are using too many squiggly brackets. All of your data should be inside one pair of squiggly brackets. This creates a single python dictionary. Change that line to:
person = [{"ID":i,"Name":"Jack","Gender":"Male","Height":177,"Weight":75}]
I am working with a pandas dataframe, in which some of the columns have no entries. I want to put all columns at the end and I manage to do it (see code below), but I also notice that after sorting the remaining columns were also sorted alphabetically by column names in descending order. Can I prevent this from happening?
Input dataframe:
,colA,colB,colC,colD,colF
rowA,X,nan,nan,X,nan
rowB,nan,X,nan,nan,X
rowC,X,nan,nan,X,X
rowD,X,nan,nan,nan,nan
rowE,nan,X,nan,nan,X
Code:
import pandas as pd
df = pd.read_csv (r'q1.csv', dtype= 'str', index_col=0, na_values = 'nan')
ind = df.notnull().astype('int').any().sort_values(ascending= False).index
out = df.loc[:,ind]
out.to_csv(r'out.csv', na_rep= 'nan')
Output dataframe:
,colF,colD,colB,colA,colC
rowA,nan,X,nan,X,nan
rowB,X,nan,X,nan,nan
rowC,X,X,nan,X,nan
rowD,nan,nan,nan,X,nan
rowE,X,nan,X,nan,nan
Essentially, I want to keep order as it is for all other columns.
Thanks.
If I understand correctly, you may try this.
m = df.isna().all().sort_values(kind='mergesort')
df_new = df[m.index]
Out[243]:
colA colB colD colF colC
rowA X NaN X NaN NaN
rowB NaN X NaN X NaN
rowC X NaN X X NaN
rowD X NaN NaN NaN NaN
rowE NaN X NaN X NaN
I'm appending data from a list to pandas df. I keep getting NaN in my entries.
Based on what I've read I think I might have to mention the data type for each column in my code.
dumps = [];features_df = pd.DataFrame()
for i in range (int(len(ids)/50)):
dumps = sp.audio_features(ids[i*50:50*(i+1)])
for i in range (len(dumps)):
print(list(dumps[0].values()))
features_df = features_df.append(list(dumps[0].values()), ignore_index = True)
Expected results, something like-
[0.833, 0.539, 11, -7.399, 0, 0.178, 0.163, 2.1e-06, 0.101, 0.385, 99.947, 'audio_features', '6MWtB6iiXyIwun0YzU6DFP', 'spotify:track:6MWtB6iiXyIwun0YzU6DFP', 'https://api.spotify.com/v1/tracks/6MWtB6iiXyIwun0YzU6DFP', 'https://api.spotify.com/v1/audio-analysis/6MWtB6iiXyIwun0YzU6DFP', 149520, 4]
for one row.
Actual-
danceability energy ... duration_ms time_signature
0 NaN NaN ... NaN NaN
1 NaN NaN ... NaN NaN
2 NaN NaN ... NaN NaN
3 NaN NaN ... NaN NaN
4 NaN NaN ... NaN NaN
5 NaN NaN ... NaN NaN
For all rows
append() strategy in a tight loop isn't a great way to do this. Rather, you can construct an empty DataFrame and then use loc to specify an insertion point. The DataFrame index should be used.
For example:
import pandas as pd
df = pd.DataFrame(data=[], columns=['n'])
for i in range(100):
df.loc[i] = i
print(df)
time python3 append_df.py
n
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
real 0m13.178s
user 0m12.287s
sys 0m0.617s
https://pandas.pydata.org/docs/reference/api/pandas.DataFrame.append.html
Iteratively appending rows to a DataFrame can be more computationally intensive than a single concatenate. A better solution is to append those rows to a list and then concatenate the list with the original DataFrame all at once.
Given is a Pandas DataFrame with a numerical index representing the relative number of months:
df = pd.DataFrame(columns=['A', 'B'], index=np.arange(1,100))
df
A B
1 NaN NaN
2 NaN NaN
3 NaN NaN
...
How can the index be converted to a DateTimeIndex by specifying a start date (e.g., 2018-11-01)?
magic_function(df, start='2018-11-01', delta='month')
A B
2018-11-01 NaN NaN
2018-12-01 NaN NaN
2019-01-01 NaN NaN
...
I would favor a general solution that also works with arbitrary deltas, e.g. daily or yearly series.
Using date_range
idx=pd.date_range(start='2018-11-01',periods =len(df),freq='MS')
df.index=idx
I'm not sure with Pandas, but with plain datetime can't you just do this?
import datetime
start=datetime.date(2018,1,1)
months = 15
adjusted = start.replace(year=start.year + int(months/12), month=months%12)
Suppose a dataframe contains
attacker_1 attacker_2 attacker_3 attacker_4
Lannister nan nan nan
nan Stark greyjoy nan
I want to create another column called AttackerCombo that aggregates the 4 columns into 1 column.
How would I go about defining such code in python?
I have been practicing python and I reckon a list comprehension of this sort makes sense, but [list(x) for x in attackers]
where attackers is a numpy array of the 4 columns displays all 4 columns aggregated into 1 column, however I would like to remove all the nans as well.
So the result for each row instead of looking like
starknannanlannister would look like stark/lannister
I think you need apply with join and remove NaN by dropna:
df['attackers'] = df[['attacker_1','attacker_2','attacker_3','attacker_4']] \
.apply(lambda x: '/'.join(x.dropna()), axis=1)
print (df)
attacker_1 attacker_2 attacker_3 attacker_4 attackers
0 Lannister NaN NaN NaN Lannister
1 NaN Stark greyjoy NaN Stark/greyjoy
If need separator empty string use DataFrame.fillna:
df['attackers'] = df[['attacker_1','attacker_2','attacker_3','attacker_4']].fillna('') \
.apply(''.join, axis=1)
print (df)
attacker_1 attacker_2 attacker_3 attacker_4 attackers
0 Lannister NaN NaN NaN Lannister
1 NaN Stark greyjoy NaN Starkgreyjoy
Another 2 solutions with list comprehension - first compare by notnull and second check if string:
df['attackers'] = df[['attacker_1','attacker_2','attacker_3','attacker_4']] \
.apply(lambda x: '/'.join([e for e in x if pd.notnull(e)]), axis=1)
print (df)
attacker_1 attacker_2 attacker_3 attacker_4 attackers
0 Lannister NaN NaN NaN Lannister
1 NaN Stark greyjoy NaN Stark/greyjoy
#python 3 - isinstance(e, str), python 2 - isinstance(e, basestring)
df['attackers'] = df[['attacker_1','attacker_2','attacker_3','attacker_4']] \
.apply(lambda x: '/'.join([e for e in x if isinstance(e, str)]), axis=1)
print (df)
attacker_1 attacker_2 attacker_3 attacker_4 attackers
0 Lannister NaN NaN NaN Lannister
1 NaN Stark greyjoy NaN Stark/greyjoy
You can set a new column in the dataframe that you will fill thanks to a lambda function:
df['attackers'] = df[['attacker_1','attacker_2','attacker_3','attacker_4']].apply(lambda x : '{}{}{}{}'.format(x[0],x[1],x[2],x[3]), axis=1)
You don't specify how you want to aggregate them, so for instance, if you want separated by a dash:
df['attackers'] = df[['attacker_1','attacker_2','attacker_3','attacker_4']].apply(lambda x : '{}-{}-{}-{}'.format(x[0],x[1],x[2],x[3]), axis=1)