How to monkeypatch (mock) calls to ncurses crate? - rust

I come from Python where you have monkeypatch in pytest, so I refer to the operation I want to do as monkeypatching, however, I've been told that the actual operation is called mocking more generally.
Anyway, my application uses the ncurses crate, and I need to test some code that calls it. How would I monkeypatch (mock) the calls to crate's functions, methods, and other attributes properly?
For example,
fn get_page(&self, commands: &[String]) -> Vec<String> {
match commands
.chunks(ncurses::LINES() as usize - 3)
.nth(self.page as usize - 1)
{
Some(cmds) => cmds.to_vec(),
None => Vec::new(),
}
}
How would I patch the ncurses::LINES() call?

In python everything is dynamic and patchable, but rust is compiled and concrete. So in your source code you have to explicitly decouple your working code and the library code.
trait NcursesImpl {
// all functions in ncurses that you want to use need to have implementations here.
/// Here is a default implementation that just delegates to ncurses
fn LINES(&self) -> c_int {
ncurses::LINES()
}
}
struct DefaultNCruses;
impl NCursesImpl for DefaultNCurses {
// no functions overridden, everything uses default implementations
}
struct LinesLiarNCurses {
lines: c_int,
}
impl NCursesImpl for LinesLiarNCurses {
/// overrides default implementation for debug purposes
fn LINES(&self) -> c_int {
self.lines
}
}
get_page() has to change slightly to use a NCursesImpl instead of the bare ncurses.
fn get_page(&self, nc: &NCursesImpl, commands: &[String]) -> Vec<String> {
match commands
.chunks(nc.LINES() as usize - 3)
.nth(self.page as usize - 1)
{
Some(cmds) => cmds.to_vec(),
None => Vec::new(),
}
}
I'm not exactly sure where the NCursesImpl object should live. Here I've made it an explicit parameter of the get_page call, but it might actually belong as a member of Self in the struct that has the get_page impl. You might want to store it in a Box<dyn NCursesImpl> so that you don't have type parameters littering your data structures.

Related

Overriding or dynamic dispatch equivalent in rust

I've been learning rust for a while and loving it. I've hit a wall though trying to do something which ought to be simple and elegant so I'm sure I'm missing the obvious.
So I'm parsing JavaScript using the excellent RESSA crate and end up with an AST which is a graph of structs defined by the crate. Now I need to traverse this many times and 'visit' certain nodes with my logic. So I've written a traverser that does that but when it hits a certain nodes it needs to call a callback. In my niavity, I thought I'd define a struct with an attribute for every type with an Option<Fn()> value. In my traverser, I check for the Some value and call it. This works fine but it's ugly because I have to populate this enormous struct with dozens of attributes most of which are None because I'm not interested in those types. Then I thought traits, I'd define a trait 'Visit' which defines the function with a default implementation that does nothing. Then I can just redefine the trait implementation with my desired implementation but this is no good because all the types must have an implementation and then the implementation cannot be redefined. Is there as nice way I can just provide a specific implementation for a few types and leave the rest as default or check for the existence of a function before calling it ? I must be missing an idiomatic way to do this.
You can look at something like syn::Visit, which is a visitor in a popular Rust AST library, for inspiration.
The Visit trait is implemented by the visitor only, and has one method for each node type, with the default implementation only visiting the children:
// this snippet has been slightly altered from the source
pub trait Visit<'ast> {
fn visit_expr(&mut self, i: &'ast Expr) {
visit_expr(self, i);
}
fn visit_expr_array(&mut self, i: &'ast ExprArray) {
visit_expr_array(self, i);
}
fn visit_expr_assign(&mut self, i: &'ast ExprAssign) {
visit_expr_assign(self, i);
}
// ...
}
pub fn visit_expr<'ast, V>(v: &mut V, node: &'ast Expr)
where
V: Visit<'ast> + ?Sized,
{
match node {
Expr::Array(_binding_0) => v.visit_expr_array(_binding_0),
Expr::Assign(_binding_0) => v.visit_expr_assign(_binding_0),
// ...
}
}
pub fn visit_expr_array<'ast, V>(v: &mut V, node: &'ast ExprArray)
where
V: Visit<'ast> + ?Sized,
{
for el in &node.elems {
v.visit_expr(el);
}
}
// ...
With this pattern, you can create a visitor where you only implement the methods you need, and whatever you don't implement will just get the default behavior.
Additionally, because the default methods call separate functions that do the default behavior, you can call those within your custom visitor methods if you need to invoke the default behavior of visiting the children. (Rust doesn't let you invoke default implementations of an overriden trait method directly.)
So for example, a visitor to print all array expressions in a Rust program using syn::Visit could look like:
struct MyVisitor;
impl Visit<'ast> for MyVisitor {
fn visit_expr_array(&mut self, i: &'ast ExprArray) {
println("{:?}", i);
// call default visitor method to visit this node's children as well
visit_expr_array(i);
}
}
fn main() {
let root = get_ast_root_node();
MyVisitor.visit_expr(&root);
}

Storing a module as a variable in rust

I have 2 different modules with precisely the same implementation, same functions, types, etc. They just do different things. I would like to be able to choose one of these modules at runtime and use it exclusively. Furthermore, there are several of these modules that may or may not exist at compile-time based on platform, features, etc. this is a link to a super stripped-down version of what I want. I am trying to choose between the various gfx-hal backends. The best I have been able to come up with is a macro that creates an if statement for each possible module then fires that if statement whenever a function in a module is run. However, this doesn't really seem elegant or at all good. So is there a way to store the modules in a variable and access it, or some way to do this that mimics that?
Thanks in advance
You could do this by turning each of your modules into its own trait implementation, similar to how gfx-rs does things.
Your "trait" would in actuality never be implemented with state, and instead be a collection of associated items like functions, other types, etc.
You could package it up like so:
#![allow(dead_code)]
mod foo {
pub fn print() { println!("hello from foo") }
}
mod bar {
pub fn print() { println!("hello from bar"); }
}
mod zam { // this may not exist depending on the platform, one will always exist
pub fn print() { println!("hello from zam"); }
}
struct FOO;
struct BAR;
struct ZAM;
trait RuntimeModule {
fn print();
}
impl RuntimeModule for FOO {
fn print() { foo::print(); }
}
impl RuntimeModule for BAR {
fn print() { bar::print(); }
}
impl RuntimeModule for ZAM {
fn print() { zam::print(); }
}
fn main() {
// Here we decide which to use
print_module::<FOO>();
}
// This is our "entrypoint"
fn print_module<T: RuntimeModule>() {
T::print();
}
If we decide which to use at runtime (in this case in main), we can then call a generic function which will use the associated types/functions to make decisions.
Note that you would not be able to use Box<dyn RuntimeModule> if RuntimeModule contained associated types that were different for each implementation.

How do I get a function pointer from a trait in Rust?

How do I get over something like this:
struct Test {
foo: Option<fn()>
}
impl Test {
fn new(&mut self) {
self.foo = Option::Some(self.a);
}
fn a(&self) { /* can use Test */ }
}
I get this error:
error: attempted to take value of method `a` on type `&mut Test`
--> src/main.rs:7:36
|
7 | self.foo = Option::Some(self.a);
| ^
|
= help: maybe a `()` to call it is missing? If not, try an anonymous function
How do I pass a function pointer from a trait? Similar to what would happen in this case:
impl Test {
fn new(&mut self) {
self.foo = Option::Some(a);
}
}
fn a() { /* can't use Test */ }
What you're trying to do here is get a function pointer from a (to use Python terminology here, since Rust doesn't have a word for this) bound method. You can't.
Firstly, because Rust doesn't have a concept of "bound" methods; that is, you can't refer to a method with the invocant (the thing on the left of the .) already bound in place. If you want to construct a callable which approximates this, you'd use a closure; i.e. || self.a().
However, this still wouldn't work because closures aren't function pointers. There is no "base type" for callable things like in some other languages. Function pointers are a single, specific kind of callable; closures are completely different. Instead, there are traits which (when implemented) make a type callable. They are Fn, FnMut, and FnOnce. Because they are traits, you can't use them as types, and must instead use them from behind some layer of indirection, such as Box<FnOnce()> or &mut FnMut(i32) -> String.
Now, you could change Test to store an Option<Box<Fn()>> instead, but that still wouldn't help. That's because of the other, other problem: you're trying to store a reference to the struct inside of itself. This is not going to work well. If you manage to do this, you effectively render the Test value permanently unusable. More likely is that the compiler just won't let you get that far.
Aside: you can do it, but not without resorting to reference counting and dynamic borrow checking, which is out of scope here.
So the answer to your question as-asked is: you don't.
Let's change the question: instead of trying to crowbar a self-referential closure in, we can instead store a callable that doesn't attempt to capture the invocant at all.
struct Test {
foo: Option<Box<Fn(&Test)>>,
}
impl Test {
fn new() -> Test {
Test {
foo: Option::Some(Box::new(Self::a)),
}
}
fn a(&self) { /* can use Test */ }
fn invoke(&self) {
if let Some(f) = self.foo.as_ref() {
f(self);
}
}
}
fn main() {
let t = Test::new();
t.invoke();
}
The callable being stored is now a function that takes the invocant explicitly, side-stepping the issues with cyclic references. We can use this to store Test::a directly, by referring to it as a free function. Also note that because Test is the implementation type, I can also refer to it as Self.
Aside: I've also corrected your Test::new function. Rust doesn't have constructors, just functions that return values like any other.
If you're confident you will never want to store a closure in foo, you can replace Box<Fn(&Test)> with fn(&Test) instead. This limits you to function pointers, but avoids the extra allocation.
If you haven't already, I strongly urge you to read the Rust Book.
There are few mistakes with your code. new function (by the convention) should not take self reference, since it is expected to create Self type.
But the real issue is, Test::foo expecting a function type fn(), but Test::a's type is fn(&Test) == fn a(&self) if you change the type of foo to fn(&Test) it will work. Also you need to use function name with the trait name instead of self. Instead of assigning to self.a you should assign Test::a.
Here is the working version:
extern crate chrono;
struct Test {
foo: Option<fn(&Test)>
}
impl Test {
fn new() -> Test {
Test {
foo: Some(Test::a)
}
}
fn a(&self) {
println!("a run!");
}
}
fn main() {
let test = Test::new();
test.foo.unwrap()(&test);
}
Also if you gonna assign a field in new() function, and the value must always set, then there is no need to use Option instead it can be like that:
extern crate chrono;
struct Test {
foo: fn(&Test)
}
impl Test {
fn new() -> Test {
Test {
foo: Test::a
}
}
fn a(&self) {
println!("a run!");
}
}
fn main() {
let test = Test::new();
(test.foo)(&test); // Make sure the paranthesis are there
}

Convenient 'Option<Box<Any>>' access when success is assured?

When writing callbacks for generic interfaces, it can be useful for them to define their own local data which they are responsible for creating and accessing.
In C I would just use a void pointer, C-like example:
struct SomeTool {
int type;
void *custom_data;
};
void invoke(SomeTool *tool) {
StructOnlyForThisTool *data = malloc(sizeof(*data));
/* ... fill in the data ... */
tool.custom_data = custom_data;
}
void execute(SomeTool *tool) {
StructOnlyForThisTool *data = tool.custom_data;
if (data.foo_bar) { /* do something */ }
}
When writing something similar in Rust, replacing void * with Option<Box<Any>>, however I'm finding that accessing the data is unreasonably verbose, eg:
struct SomeTool {
type: i32,
custom_data: Option<Box<Any>>,
};
fn invoke(tool: &mut SomeTool) {
let data = StructOnlyForThisTool { /* my custom data */ }
/* ... fill in the data ... */
tool.custom_data = Some(Box::new(custom_data));
}
fn execute(tool: &mut SomeTool) {
let data = tool.custom_data.as_ref().unwrap().downcast_ref::<StructOnlyForThisTool>().unwrap();
if data.foo_bar { /* do something */ }
}
There is one line here which I'd like to be able to write in a more compact way:
tool.custom_data.as_ref().unwrap().downcast_ref::<StructOnlyForThisTool>().unwrap()
tool.custom_data.as_ref().unwrap().downcast_mut::<StructOnlyForThisTool>().unwrap()
While each method makes sense on its own, in practice it's not something I'd want to write throughout a code-base, and not something I'm going to want to type out often or remember easily.
By convention, the uses of unwrap here aren't dangerous because:
While only some tools define custom data, the ones that do always define it.
When the data is set, by convention the tool only ever sets its own data. So there is no chance of having the wrong data.
Any time these conventions aren't followed, its a bug and should panic.
Given these conventions, and assuming accessing custom-data from a tool is something that's done often - what would be a good way to simplify this expression?
Some possible options:
Remove the Option, just use Box<Any> with Box::new(()) representing None so access can be simplified a little.
Use a macro or function to hide verbosity - passing in the Option<Box<Any>>: will work of course, but prefer not - would use as a last resort.
Add a trait to Option<Box<Any>> which exposes a method such as tool.custom_data.unwrap_box::<StructOnlyForThisTool>() with matching unwrap_box_mut.
Update 1): since asking this question a point I didn't include seems relevant.
There may be multiple callback functions like execute which must all be able to access the custom_data. At the time I didn't think this was important to point out.
Update 2): Wrapping this in a function which takes tool isn't practical, since the borrow checker then prevents further access to members of tool until the cast variable goes out of scope, I found the only reliable way to do this was to write a macro.
If the implementation really only has a single method with a name like execute, that is a strong indication to consider using a closure to capture the implementation data. SomeTool can incorporate an arbitrary callable in a type-erased manner using a boxed FnMut, as shown in this answer. execute() then boils down to invoking the closure stored in the struct field implementation closure using (self.impl_)(). For a more general approach, that will also work when you have more methods on the implementation, read on.
An idiomatic and type-safe equivalent of the type+dataptr C pattern is to store the implementation type and pointer to data together as a trait object. The SomeTool struct can contain a single field, a boxed SomeToolImpl trait object, where the trait specifies tool-specific methods such as execute. This has the following characteristics:
You no longer need an explicit type field because the run-time type information is incorporated in the trait object.
Each tool's implementation of the trait methods can access its own data in a type-safe manner without casts or unwraps. This is because the trait object's vtable automatically invokes the correct function for the correct trait implementation, and it is a compile-time error to try to invoke a different one.
The "fat pointer" representation of the trait object has the same performance characteristics as the type+dataptr pair - for example, the size of SomeTool will be two pointers, and accessing the implementation data will still involve a single pointer dereference.
Here is an example implementation:
struct SomeTool {
impl_: Box<SomeToolImpl>,
}
impl SomeTool {
fn execute(&mut self) {
self.impl_.execute();
}
}
trait SomeToolImpl {
fn execute(&mut self);
}
struct SpecificTool1 {
foo_bar: bool
}
impl SpecificTool1 {
pub fn new(foo_bar: bool) -> SomeTool {
let my_data = SpecificTool1 { foo_bar: foo_bar };
SomeTool { impl_: Box::new(my_data) }
}
}
impl SomeToolImpl for SpecificTool1 {
fn execute(&mut self) {
println!("I am {}", self.foo_bar);
}
}
struct SpecificTool2 {
num: u64
}
impl SpecificTool2 {
pub fn new(num: u64) -> SomeTool {
let my_data = SpecificTool2 { num: num };
SomeTool { impl_: Box::new(my_data) }
}
}
impl SomeToolImpl for SpecificTool2 {
fn execute(&mut self) {
println!("I am {}", self.num);
}
}
pub fn main() {
let mut tool1: SomeTool = SpecificTool1::new(true);
let mut tool2: SomeTool = SpecificTool2::new(42);
tool1.execute();
tool2.execute();
}
Note that, in this design, it doesn't make sense to make implementation an Option because we always associate the tool type with the implementation. While it is perfectly valid to have an implementation without data, it must always have a type associated with it.

Recommended way to wrap C lib initialization/destruction routine

I am writing a wrapper/FFI for a C library that requires a global initialization call in the main thread as well as one for destruction.
Here is how I am currently handling it:
struct App;
impl App {
fn init() -> Self {
unsafe { ffi::InitializeMyCLib(); }
App
}
}
impl Drop for App {
fn drop(&mut self) {
unsafe { ffi::DestroyMyCLib(); }
}
}
which can be used like:
fn main() {
let _init_ = App::init();
// ...
}
This works fine, but it feels like a hack, tying these calls to the lifetime of an unnecessary struct. Having the destructor in a finally (Java) or at_exit (Ruby) block seems theoretically more appropriate.
Is there some more graceful way to do this in Rust?
EDIT
Would it be possible/safe to use this setup like so (using the lazy_static crate), instead of my second block above:
lazy_static! {
static ref APP: App = App::new();
}
Would this reference be guaranteed to be initialized before any other code and destroyed on exit? Is it bad practice to use lazy_static in a library?
This would also make it easier to facilitate access to the FFI through this one struct, since I wouldn't have to bother passing around the reference to the instantiated struct (called _init_ in my original example).
This would also make it safer in some ways, since I could make the App struct default constructor private.
I know of no way of enforcing that a method be called in the main thread beyond strongly-worded documentation. So, ignoring that requirement... :-)
Generally, I'd use std::sync::Once, which seems basically designed for this case:
A synchronization primitive which can be used to run a one-time global
initialization. Useful for one-time initialization for FFI or related
functionality. This type can only be constructed with the ONCE_INIT
value.
Note that there's no provision for any cleanup; many times you just have to leak whatever the library has done. Usually if a library has a dedicated cleanup path, it has also been structured to store all that initialized data in a type that is then passed into subsequent functions as some kind of context or environment. This would map nicely to Rust types.
Warning
Your current code is not as protective as you hope it is. Since your App is an empty struct, an end-user can construct it without calling your method:
let _init_ = App;
We will use a zero-sized argument to prevent this. See also What's the Rust idiom to define a field pointing to a C opaque pointer? for the proper way to construct opaque types for FFI.
Altogether, I'd use something like this:
use std::sync::Once;
mod ffi {
extern "C" {
pub fn InitializeMyCLib();
pub fn CoolMethod(arg: u8);
}
}
static C_LIB_INITIALIZED: Once = Once::new();
#[derive(Copy, Clone)]
struct TheLibrary(());
impl TheLibrary {
fn new() -> Self {
C_LIB_INITIALIZED.call_once(|| unsafe {
ffi::InitializeMyCLib();
});
TheLibrary(())
}
fn cool_method(&self, arg: u8) {
unsafe { ffi::CoolMethod(arg) }
}
}
fn main() {
let lib = TheLibrary::new();
lib.cool_method(42);
}
I did some digging around to see how other FFI libs handle this situation. Here is what I am currently using (similar to #Shepmaster's answer and based loosely on the initialization routine of curl-rust):
fn initialize() {
static INIT: Once = ONCE_INIT;
INIT.call_once(|| unsafe {
ffi::InitializeMyCLib();
assert_eq!(libc::atexit(cleanup), 0);
});
extern fn cleanup() {
unsafe { ffi::DestroyMyCLib(); }
}
}
I then call this function inside the public constructors for my public structs.

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