Match multiple instances of pattern in parenthesis - python-3.x

Question

For the following string, is it possible for regex to return the comma delimited matches within the square brackets?
"root.path.definition[id=1234,test=blah,scope=A,B,C,D]"
Expected output would be:
["id=1234", "test=blah", "scope=A,B,C,D"]
The closest I have gotten so far is the following:
(?<=\[)(.*?)(?=\])
But this will only return one match for everything within the square brackets.

Answer 1

One option is to use the re module and first get the part between the square brackets using a capturing group and a negated character class.
\[([^][]*)]
That part will match:
\[ Match [ char
([^][]*) Capture group 1, match 0+ times any char other than [ and ]
] A [ char
Then get the separate parts by matching the key value pairs separated by a comma.
\w+=.*?(?=,\w+=|$)
That part will match:
\w+ Match 1+ word characters
= Match literally
.*?(?=,\w+=|$) Match as least as possible chars until you either encounter a comma, 1+ word characters and = or the end of the string
For example
import re
s = "root.path.definition[id=1234,test=blah,scope=A,B,C,D]"
m = re.search(r"\[([^][]*)]", s)
if m:
print(re.findall(r"\w+=.*?(?=,\w+=|$)", m.group(1)))
Python demo
Output
['id=1234', 'test=blah', 'scope=A,B,C,D']
If you can make use of the regex module, this might also be an option matching the keys and values using lookarounds to assert the [ and ]
(?<=\[[^][]*)\w+=.*?(?=,\w+=|])(?=[^][]*])
For example
import regex
s = "root.path.definition[id=1234,test=blah,scope=A,B,C,D]"
print(regex.findall(r"(?<=\[[^][]*)\w+=.*?(?=,\w+=|])(?=[^][]*])", s))
Output
['id=1234', 'test=blah', 'scope=A,B,C,D']
Regex demo | Python demo