Execute Multiple .js Files From Terminal In Sequence - node.js

Question

I have about 100 JS files with each having different script.
file1.js , file2.js , file3.js , ... , file100.js
Right now, to execute each file I have to go to my terminal and do this:
node file1
node file2
node file3
.
.
node file100
That means I have to do this 100 times in the terminal. Is there a script to write in a JS file so I can execute ONLY ONE JS file that would execute all the 100 JS files in sequence?
I also want to give 3 seconds waiting between each execution which I believe I can achieve with the following code:
var interval = 3000;
var promise = Promise.resolve();
promise = promise.then(function () {
return new Promise(function (resolve) {
setTimeout(resolve, interval);
});
});
Any suggestion how to execute all the 100 JS files without typing node file# 100 times in the terminal?

Answer 1

here is a script that does that, you can also choose a different file format rather than
node file1
..
node filex
you can do this file1,file2,file3...filex,also look into child_process before using this code.
const { readFileSync } = require('fs');
const {exec} = require("child_process");
function executeEachFile(command){
exec(command, (error, stdout, stderr) => {
if(error){
console.log(error);
}
console.log("stdout: " + stdout)
});
}
function readFile(path){
const output = readFileSync(path,"utf8").split("\n").map(file=>{
return file.replace("\r","");
});
console.log(output)
return output
};
function IntervalLoop(ArrayofFiles){
let counter = 0;
const interval = setInterval(()=>{
const commandName = "node "+ ArrayofFiles[counter];
console.log(commandName);
executeEachFile(commandName);
counter++;
console.log(counter);
if (ArrayofFiles.length == counter){
clearInterval(interval);
}
},300)
}
const fileNames = readFile("exec.txt");
IntervalLoop(fileNames);