A formula that takes logical inputs and outputs either true or a statement if all logical inputs are true.
Hey there I am trying to have a cell in excel display a text of either Valid or Invalid under a column marked Status
=AND(IF(D2<TODAY(),"Invalid","Valid"),(IF(F2<TODAY(),"Invalid","Valid"),(IF(H2<TODAY(),"Invalid","Valid"))))
However the above formula I entered is giving me a 'value within is a wrong data type'
With the famous #Value!.
Is there anyway anyone can point out where I went wrong?
Each element inside of AND() needs to be an expression that evaluates to either TRUE or FALSE. Your formula has a single IF() statement inside of AND() that returns a text.
Guessing at what you would like to achieve, try
=IF(AND(D2<TODAY(),F2<TODAY(),H2<TODAY()),"Invalid","Valid")
in words: If D2 is before today AND F2 is before today AND H2 is before today, then return the text "Invalid", otherwise return the text "Valid"
Related
When I running formula =ISNUMBER(SEARCH($B$2,$A3)), the output is true. Cell B2= "Red" and "Red" appears in cell A3. The condition is TRUE.
This formula fails when cell E2 is blank. There are no spaces or hidden characters.
Why is =ISNUMBER(SEARCH(E$2,$A3)) returning True?
You need to first check if E2 is blank and then proceed with ISNUMBER if true
=IF(ISBLANK(E$2), FALSE, ISNUMBER(SEARCH(E$2,$A3)))
SEARCH will interpret blanks as empty strings.
Another approach to what it looks like you're trying to do is to replace the substring with an empty string and see if the length changes:
=LEN($A2)>LEN(SUBSTITUTE($A2,E$1,""))
So, two variations, one as per the other answer but the other using find().
For the first, it returns a blank.
For the second with find() then iferror will deal with the value error.
I am testing this if condition to whether O2 cell is matching with an element in A2:J2.
But the formula is displaying in the other 10 cells.
How can I get rid of this issue and execute the formula in only one cell?
Your criteria for the IF function: A2:J2=O2 is an array, which is the reason why it's spilling the values to the other cells. It's basically doing this: A2=O2 B2=O2 C2=O2 D2=O2 and so on..
And it returns all of the result of these. Therefore, you will have an array of results.
Maybe you want to consider this formula: =IF(ISNUMBER(MATCH(O2,A2:J2,0)),"Yes","No")
The match searches for O2 in A2:J2. If it finds the first match, it will return its position within the range. Otherwise, it will return an error. Therefore, we use ISNUMBER to check if the result of the match is a number. If it's a number, the ISNUMBER will return true. Otherwise, false. Then we'll use IF to capture the result of the ISNUMBER to return Yes if TRUE and No if FALSE.
Another way to solve this issue:
=IF(COUNTIF(A2:J2,O2)>0,"Yes","No")
this formula will count the content of cell O2 within A2:J2 and if available, it will return a number greater than 0.
I am very newbie in excel, I wanted to make my formula to return matched value instead of TRUE/FALSE
=NOT(NOT(SUM(--NOT(ISERR(SEARCH($D$2:$D$21;$B2))))))
is there anyway this formula can be revised to return like for example: found word "wow" and return the word into the cell instead of TRUE/FALSE?
thank you
Use the =IF function.
=IF(condition; value if true; value if false)
condition is your condition to test. For example $A$1 < 5
value if true is a value returned if condition is true
value if false opposite to previous part, this is a value returned if condition is false.
Following formula will return a $A$1 cell value if less than 5 and too big literally if $A$1's value is bigger or equal to 5:
=IF($A$1<5; $A$1; "too big")
Just combine it with your condition.
You can use IF function:
=IF(logical_test, CONCAT("Found word", $YourWord), "Not found")
This will help You Remember the "Text" must be in " "
=IF(ISNUMBER(SEARCH(substring;"WOW")); "Yes"; "No")
The Value will be only Yes or No , You may change that
There are two cases and I'm not sure which one you need
(1) You have a word like WOW, and you want to find matches in a list of strings like BOWWOW
(2) You have a word like WOW, and you want to find matches for part of it in a list of substrings like OW
The easiest way to do the first one is to use MATCH with a wildcard
=INDEX($D$2:$D$21,MATCH("*"&B2&"*",$D$2:$D$21,0))
For the second one you would need to modify your formula a bit
=INDEX($D$2:$D$21,MATCH(0,(ISERROR(SEARCH($D$2:$D$21,$B$2))+($D$2:$D$21="")),0))
or
=INDEX($D$2:$D$21,MATCH(1,ISNUMBER(SEARCH($D$2:$D$21,$B$2))*($D$2:$D$21<>""),0))
the last two entered as array formulae using CtrlShiftEnter
I use formula =SEARCH({"N.","No.","#"},D5) and it fails if doesn't fit first option "N." how can I fix it?
Using =SEARCH({"N.","No.","#"},D5) formula when you will see how the formula calculates the result using Evaluate Formula, you'll notice
evaluates to
That means formula is searching only for "N."
Therefore to search for the existence of "N.","No.","#" in a cell, number of approaches are available like:
1. =IF(COUNT(SEARCH({"N.","No.","#"},D5)),1,"")
This formula will give 1 if any of the string in the cell exists.
2. =SUMPRODUCT(--ISNUMBER(SEARCH(find_text,D5)))>0
This formula will give TRUE if any of the three string exists else FASLE.
=IF(D6=D$62;VLOOKUP(C6;D$63:E$68;2;FALSE);IF(D6=G$62;VLOOKUP(C6;G$63:H$67;2;FALSE)))
Can some one help? I have done this formula, but when I press enter then the answer in the cell is false instead of the value which is supposed to look up.
This is returning False because the second IF formula doesn't have the third parameter specified. IF takes three parameters, and if you neglect the third, it will just return False.
What this means is that D6 is not equal to D$62 and D6 is not equal to G$62, so it says False. In other words, it doesn't even attempt either Vlookup since neither condition is true.