Can I specify a default mapping source for unmapped members with AutoMapper? - automapper

Question

I have a type that encapsulates a bunch of related data
class CollectionNoteDetails
{
CollectionNote Note {get;set;}
Customer SourceCustomer {get;set;}
Customer DestinationCustomer {get;set;}
Haulier Haulier{ get;set;}
}
and I want to flatten it
class CollectionNoteDto
{
// using fields for brevity
int Id;
DateTime CollectionDate;
// ... plus about 30 more props
string SourceCustomerName;
string DestinationCustomerName;
string HaulierName;
}
there's about 30 properties on the DTO that come off the CollectionNote, and a few that come off the other entities. The other entities are easy to handle in the CreateMap() call:
CreateMap<CollectionNoteDetails, CollectionNoteDoc>(MemberList.Destination)
.ForMember(d => d.SourceCustomerName, o => o.MapFrom(s => s.SourceCustomer.Name))
.ForMember(d => d.DestinationCustomerName, o => o.MapFrom(s => s.DestinationCustomer.Name))
.ForMember(d => d.HaulierName, o => o.MapFrom(s => s.Haulier.Name));
... but is there an easy way to map the rest of the properties to the Note source property? Something like this made up method.
CreateMap<CollectionNoteDetails, CollectionNoteDoc>(MemberList.Destination)
.MapAllByDefault(o => o.MapFrom(s => s.Note))
// other explicit mappings here
.ForMember(d => d.HaulierName, o => o.MapFrom(s => s.Haulier.Name));

Answer 1

You might need to recognize a prefix. The example from the documentation:
public class Source {
public int frmValue { get; set; }
public int frmValue2 { get; set; }
}
public class Dest {
public int Value { get; set; }
public int Value2 { get; set; }
}
var configuration = new MapperConfiguration(cfg => {
cfg.RecognizePrefixes("frm");
cfg.CreateMap<Source, Dest>();
});
On different matters, note that flattening is automatically supported by automapper, which means that this code:
CreateMap<CollectionNoteDetails, CollectionNoteDoc>(MemberList.Destination)
.ForMember(d => d.SourceCustomerName, o => o.MapFrom(s => s.SourceCustomer.Name))
.ForMember(d => d.DestinationCustomerName, o => o.MapFrom(s => s.DestinationCustomer.Name))
.ForMember(d => d.HaulierName, o => o.MapFrom(s => s.Haulier.Name));
is equivalent to:
CreateMap<CollectionNoteDetails, CollectionNoteDoc>(MemberList.Destination);