Request help:
=IF(AND(OR(
S:S="Sales Hub",
S:S="Office Integration",
S:S="Opportunities",
S:S="Export to Excel",
S:S="Gamification",
S:S="LinkedIn",
S:S="Leads")),
"Project One",
IF(AND(OR(
S:S="Invoices",
S:S="Products and Pricelists",
S:S="Quotes and Orders")),
"Project Two",
IF(AND(OR(
S:S="Quick Campaigns",
S:S="Marketing Lists")),
"Project Three",
""
)
)
)
The above formula returns only Project One for all even though i have matching values to meet Project Two and Three as specified in the nested OR conditions.
Looks like you want to check if any of the specified values is present on column S and if true, then return Project #.
You can do it combining COUNTIF with array criteria and SUM. If it's greater than 0, it means the condition has been met.
=IF(SUM(COUNTIF(S:S;{"Sales Hub";"Office Integration";"Opportunities";"Export to Excel";"Gamification";"LinkedIn";"Leads"}))>0;"Project One";IF(SUM(COUNTIF(S:S;{"Invoices";"Products and Pricelists";"Quotes and Orders"}))>0;"Project Two";IF(SUM(COUNTIF(S:S;{"Quick Campaigns";"Marketing Lists"}))>0;"Project Three";"Error")))
Related
Given this JSON hash:
{
"id": 55555,
"name": "111111",
"custom_data_field": [
{
"id": 1,
"label": "Vehicle Type",
"value": "Coach"
},
{
"id": 2,
"label": "Vendor",
"value": 1
}
]
}
I need the value associated with each label.
I'm able to get the value using the array's index:
#item()?['custom_data_field'][0]['value'] # Coach
#item()?['custom_data_field'][1]['value'] # 1
But this is a bit fragile.
This syntax doesn't work:
#item()?['custom_data_field'][#label=='Vehicle Type']['value'] # Coach
#item()?['custom_data_field'][#label=='Vendor']['value'] # 1
Is there a way to do this reliably?
According to the description of your question, it seems the data {"id": 55555, "name": "111111"....} you provided is an item of a array list because your expression begins with item() (I guess you use this expression in a "For each" or something else loop action). And custom_data_field is array under the item, you want to do filter/select operation to get the value which its label equals Vehicle Type just by the expression. I don't think we can do it just in one expression (because the label and value are not key-value map, we can not do the filter/select in expression easily).
To meet the requirement, we need to use a more sophisticated approach such as "Filter array" action mentioned by Scott in comments. We need to set the array custom_data_field to the input box("From" box) of the "Filter array" action.
And then add the filter condition.
After running the logic app, it will filter the items by the filter condition.
As the filter action don't know how many items match the condition, so the output will always be a array but not an item or a record even if there is only one item matches the condition(label equals "Vehicle Type") in your custom_data_field list.
So if you want to get the value, you need to get it by writing an expression as below screenshot.
Hope it helps~
I have a sharepoint list. One of the fields in it(called DocNumber) is the document number including version. It will look like this ESI-1234-1.0
Basically the rule is, it should start with the text ESI-, then a number, followed by another hipen(-), followed by version number, then a dot(.), and a subversion number
How do i write the 'Column validation' for this. I'm using Sharepoint Online(365 I guess), so there's a placeholder in field level settings to write this formula. I searched online but the syntax is so difficult that I'm finding it hard to customize the formula -
I need something like this, but i don't want to indicate position because the numbers there could be of any length(its a serial number, currently we are at 1600, so we should support 1 to 5 digits atleast and version could be any number from 1 to 99)
=AND(
IF(ISERROR(FIND("ESI-",DocNumber,1)),FALSE,(FIND("ESI-",DocNumber)=1)),
IF(ISERROR(FIND("-",DocNumber,4)),FALSE,(FIND("-",DocNumber,4)=4)))
Thankyou for your help!
In the formula property of column You may use JSON structure like this:
{
"elmType": "div",
"txtContent": {
"operator": "+",
"operands": [
"ESI-",
"[$ID]",
"-",
"[$_UIVersionString]"
]
}
}
here we make a custom view in a div HTML element with text inside. The Text is static string "ESI-" then we add ID column then we add "-" then we add version number column as string
the result should be something like this
... I hope this will be of any help
I have a drop down with three different choices. I'm trying to make the below cell have a question depending which drop down selection you choose. so far it works with one statement
=IF($B$2="A","First","").
That works, but when i add an or statement it does not work
=IF($B$2="A","First","") OR IF$B$2="B","Second","")
This does not work how can i change this so i cave this statement work for three choices with the formula in one cell.
=IF($B$2="A","First", IF($B$2="B", "Second", IF($B$2="C", "Third","???")))
or
=IFERROR(VLOOKUP(B3,{"A","First";"B","Second";"C","Third"},2,FALSE),"???")
You cannot use OR function in Excel that way. Have a look at this: https://exceljet.net/excel-functions/excel-or-function
You could trying using nested IF statements OR you could use some other method (like a VLOOKUP)
Nested If would be something like this:
=IF($B$2='A', 'First', IF($B$2='B', "Second", ""))
The "nested ifs" is your best option.
=IF($B$2="A","First","")
=if($B$2=A,"condition 1","condition 2")
Condition 1 is true, i.e. $B$2=A
Condition 2 is false, i.e. $B$2 does not equal <> A
The way to nest the ifs is to include it instead of "condition 1" or "condition 2".
So =if($B$2=A,if($B$2=B,"condition 2", "condition 3"),"condition 1")
$B$2=A and $B$2=B are both true then condition 2
$B$2=A is true but $B$2=B is not true then condition 3
$B$2=A is not true then condition 1
This is the logic behind nested ifs. You can expand this.
Using a nested If Statement in Excel I have been trying to obtain results using the following criteria:
within 100 and 75000 Volts but should accept 11; 22; 25; 26; 30; 33; 66
as they will be in kV
Source data is in a table Transformers and the formula is also returning data on two other tables MASTER and META.
I have tried in vain all kinds of IF/AND/OR variants of the following, however I have rarely used nested if statements before so am not at home with the logic. Any help gratefully received !
Thank you
=IF(MASTER!N2="Failed Check 1","Failed Check 1",IF(META!N2="Failed Check 2","Failed Check 2"), IF(OR(Transformers!T2>=110, Transformers!T2<=75000) OR(Transformers!T2=11, Transformers!T2=22, Transformers!T2=25, Transformers!T2=26, Transformers!T2=30, Transformers!T2=33, Transformers!T2=66),"Failed Check 3","Passed Check 3"))
Thank you
It looks like you need an AND as the first term in your OR. The parenthesis also looked incorrect. Once the complexity reaches a certain stage it sometimes helps to compose the formulas in something like Notepad with white-space to display the logic:
=IF(MASTER!N2="Failed Check 1",
"Failed Check 1",
IF(META!N2="Failed Check 2",
"Failed Check 2",
IF(OR(
AND(Transformers!T2>=110, Transformers!T2<=75000),
Transformers!T2=11,
Transformers!T2=22,
Transformers!T2=25,
Transformers!T2=26,
Transformers!T2=30,
Transformers!T2=33,
Transformers!T2=66
),
"Failed Check 3",
"Passed Check 3"
)
)
)
Without linebreaks this is:
=IF(MASTER!N2="Failed Check 1","Failed Check 1",IF(META!N2="Failed Check 2","Failed Check 2", IF(OR(AND(Transformers!T2>=110, Transformers!T2<=75000),Transformers!T2=11, Transformers!T2=22, Transformers!T2=25, Transformers!T2=26, Transformers!T2=30, Transformers!T2=33, Transformers!T2=66),"Failed Check 3","Passed Check 3")))
=IF(MASTER!N2="Failed Check 1","Failed Check 1",IF(META!N2="Failed Check 2","Failed Check 2", IF(OR(Transformers!T2>=110, Transformers!T2<=75000, Transformers!T2=11, Transformers!T2=22, Transformers!T2=25, Transformers!T2=26, Transformers!T2=30, Transformers!T2=33, Transformers!T2=66),"Failed Check 3","Passed Check 3")))
Some problems in your formula:
before the second OR a comma is missing, it should be ),OR(
closing parenthesis of first OR is missing, it should be ...=66)),...
closing parenthesis of IF is missing, your formula should end to )))
+1 you are looking for values between 100 and 75000, this could be done with AND instead of OR
Another approach
To simplify your formula you can place your valid kV values in a range and refer to it; let's call it kVolts (one value per cell, either in one row or in one column)
The simplified formula:
=IF(MASTER!N2="Failed Check 1","Failed Check 1",IF(META!N2="Failed Check 2","Failed Check 2"), IF(OR(AND(Transformers!T2>=110, Transformers!T2<=75000),IFERROR(MATCH(Transformers!T2,kVolts,0)>0,FALSE)) ,"Failed Check 3","Passed Check 3")))
Based on your conditions, I would recommend you implement this one liner which assumes your data is in cell A1.
=IF(OR(AND(A1>=100,A1<=75000),A1=11,A1=22,A1=25,A1=26,A1=30,A1=33,A1=66),TRUE,FALSE)
Although this only returns TRUE or FALSE, which doesn't tell you which check it has passed.
I have a nested if statement is returning "False" rather than the expected outcome.
Scenario
Table "High VoltageCables" has data in it that default to numeric but may contain characters: kVa
Table "Master" checks "High VoltageCables" data as blank or not blank, and returns "Failed Check 1","Passed Check 1". This works fine.
Table "Meta" then checks the results of "Master" and then tests "High VoltageCables" data for length between 1 and 6, regardless of whether record is numeric or string.
Formula
=IF(MASTER!H2="Passed Check 1",IF(LEN('High VoltageCables'!O2)>=1,IF(LEN('High VoltageCables'!O2<6),"Passed Check 2","Failed Check 2")))
This is partially succesful, as it returns "Passed Check 2" for the following sample data in the source table "High VoltageCables".
1 numeric, or
1kVa str, or
50000 numeric
However if a field in "High VoltageCables"is blank, the formula returns "FALSE" rather than "Failed Check 1"
I inherited this task, (and would have preferred to do the whole thing in Access using relatively simple queries) - and unfortunately I am new to nested If statements, so I am probably missing something basic...
NB the data in High VoltageCables must default to numeric for a further check to work.
The first and second IF's seem to be missing the else part. They should be added at the end between the ))) like ), else ), else )
Every IF statement consists of IF( condition, truepart, falsepart) if you have two nested ifs it will be something like IF( condition, IF( condition2, truepart2, falsepart2), falsepart)
Hope that makes it a little clearer
You do have an unaccounted for FALSE in the middle IF. Try bring the latter two conditions together.
=IF(Master!H2="Passed Check 1",IF(OR(LEN('High VoltageCables'!O2)={1,2,3,4,5}),"Passed Check 2","Failed Check 2"))
It's still a bit unclear on what to show or not show if Master!H2 does not equal "Passed Check 1".
I failed to construct the formula with a concluding "else" - "Failed Check 1"
Using jeeped's and Tom's suggestion and adding the final "else" part I have solved the problem:
=IF(MASTER!H2="Passed Check 1",IF(OR(LEN('High VoltageCables'!O2)={1,2,3,4,5}),"Passed Check 2","Failed Check 2"),"Failed Check 1")