This question already has answers here:
Compare two files line by line and generate the difference in another file
(14 answers)
Closed 2 years ago.
FILE1:
cat
dog
house
tree
FILE2:
dog
cat
tree
I need to be printed only:
house
$ cat file1
cat
dog
house
tree
$ cat file2
dog
cat
tree
$ grep -vF -f file2 file1
house
The -v flag only shows non-matches, -f is for a filename to use as a filter, and -F is for exact matches (doesn't slow it down with any pattern matching).
Using awk
awk 'FNR==NR{arr[$0]=1; next} !($0 in arr)' FILE2 FILE1
First build an associative array with words from FILE2 and than loop over FILE1 and only print those.
Using comm
comm -2 -3 <(sort FILE1) <(sort FILE2)
-2 suppresses lines unique to FILE2 and -3 suppresses lines found in both.
If you want just the words, you can sort the files, diff them, then use sed to filter out diff's symbols:
diff <(sort file1) <(sort file2) | sed -n '/^</s/^< //p'
Awk is an option here:
awk 'NR==FNR { arr[$1]="1" } NR != FNR { if (arr[$1] == "") { print $0 } } ' file2 file1
Create an array called arr, using the contents of file2 as indexes. Then with file1, look at each entry and check to see if an entry in the array arr exists. If it doesn't, print.
Related
I basically am working with two files (file1 and file2). The goal is to write a script that pulls rows from file1, if columns 1,2,3 match between files1 and files2. Here's the code I have been playing with:
awk -F'|' 'NR==FNR{c[$1$2$3]++;next};c[$1$2$3] > 0' file1 file2 > filtered.txt
ile1 and file2 both look like this (but has many more columns):
name1 0 c
name1 1 c
name1 2 x
name2 3 x
name2 4 c
name2 5 c
The awk code I provided isn't producing any output. Any help would be appreciated!
your delimiter isn't pipe, try this
$ awk 'NR==FNR {c[$1,$2,$3]++; next} c[$1,$2,$3]' file1 file2 > filtered.txt
or
$ awk 'NR==FNR {c[$0]++; next} c[$0]' file1 file2 > filtered.txt
however, if you're matching the whole line perhaps easier with grep
$ grep -xFf file1 file2 > filtered.txt
awk '{key=$1 FS $2 FS $3} NR==FNR{file2[key];next} key in file2' file2 file1
This question already has answers here:
Fast way of finding lines in one file that are not in another?
(11 answers)
Closed 7 years ago.
Working in linux/shell env, how can I accomplish the following:
text file 1 contains:
1
2
3
4
5
text file 2 contains:
6
7
1
2
3
4
I need to extract the entries in file 2 which are not in file 1. So '6' and '7' in this example and now where it found them.
For example, 6, 7 in file 1
I already work with this awk command
awk 'FNR==NR{a[$0]++;next}!a[$0]' file1 file2
But this command can only show the difference, So, 6 and 7 but not where it fouind it.
How can I do this from the command line?
many thanks!
Using awk you can do this:
awk 'FNR==NR { seen[$0]=FILENAME; next }
{if ($1 in seen) delete seen[$1]; else print $1, FILENAME}
END { for (i in seen) print i, seen[i] }' file{1,2}
6 file2
7 file2
5 file1
While traversing file1 we are storing column1 of each row in an array seen with value as FILENAME. Next while iterating file2 we print each missing entry and delete if entry is found (common entries). Finally in END block we print all remaining entries from array seen.
The comm program will tell you what lines files have in common (or are unique to one file). comm works best when the files are sorted lexically.
$ echo "only in file1"; comm -2 -3 <(sort file1) <(sort file2)
only in file1
5
$ echo "only in file2"; comm -1 -3 <(sort file1) <(sort file2)
only in file2
6
7
$ echo "common to file1 and file2"; comm -1 -2 <(sort file1) <(sort file2)
common to file1 and file2
1
2
3
4
I have two diferrent files which some rows are missing in one of the files. I want to make a new file including those non-common rows between two files. as and example, I have following files:
file1:
id1
id22
id3
id4
id43
id100
id433
file2:
id1
id2
id22
id3
id4
id8
id43
id100
id433
id21
I want to extract those rows which exist in file2 but do not in file1:
new file:
id2
id8
id21
any suggestion please?
Use the comm utility (assumes bash as the shell):
comm -13 <(sort file1) <(sort file2)
Note how the input must be sorted for this to work, so your delta will be sorted, too.
comm uses an (interleaved) 3-column layout:
column 1: lines only in file1
column 2: lines only in file2
column 3: lines in both files
-13 suppresses columns 1 and 2, which prints only the values exclusive to file2.
Caveat: For lines to be recognized as common to both files they must match exactly - seemingly identical lines that differ in terms of whitespace (as is the case in the sample data in the question as of this writing, where file1 lines have a trailing space) will not match.
cat -et is a command that visualizes line endings and control characters, which is helpful in diagnosing such problems.
For instance, cat -et file1 would output lines such as id1 $, making it obvious that there's a trailing space at the end of the line (represented as $).
If instead of cleaning up file1 you want to compare the files as-is, try:
comm -13 <(sed -E 's/ +$//' file1 | sort) <(sort file2)
A generalized solution that trims leading and trailing whitespace from the lines of both files:
comm -13 <(sed -E 's/^[[:blank:]]+|[[:blank:]]+$//g' file1 | sort) \
<(sed -E 's/^[[:blank:]]+|[[:blank:]]+$//g' file2 | sort)
Note: The above sed commands require either GNU or BSD sed.
Edit: I only wanted to change 1 character but 6 is the minimum... Delete this...
You can try to sort both files then count the duplicate rows and select only those row where the count is 1
sort file1 file2 | uniq -c | awk '$1 == 1 {print $2}'
I want to find the last appearance of a string in a text file with linux commands. For example
1 a 1
2 a 2
3 a 3
1 b 1
2 b 2
3 b 3
1 c 1
2 c 2
3 c 3
In such a text file, i want to find the line number of the last appearance of b which is 6.
I can find the first appearance with
awk '/ b / {print NR;exit}' textFile.txt
but I have no idea how to do it for the last occurrence.
cat -n textfile.txt | grep " b " | tail -1 | cut -f 1
cat -n prints the file to STDOUT prepending line numbers.
grep greps out all lines containing "b" (you can use egrep for more advanced patterns or fgrep for faster grep of fixed strings)
tail -1 prints last line of those lines containing "b"
cut -f 1 prints first column, which is line # from cat -n
Or you can use Perl if you wish (It's very similar to what you'd do in awk, but frankly, I personally don't ever use awk if I have Perl handy - Perl supports 100% of what awk can do, by design, as 1-liners - YMMV):
perl -ne '{$n=$. if / b /} END {print "$n\n"}' textfile.txt
This can work:
$ awk '{if ($2~"b") a=NR} END{print a}' your_file
We check every second file being "b" and we record the number of line. It is appended, so by the time we finish reading the file, it will be the last one.
Test:
$ awk '{if ($2~"b") a=NR} END{print a}' your_file
6
Update based on sudo_O advise:
$ awk '{if ($2=="b") a=NR} END{print a}' your_file
to avoid having some abc in 2nd field.
It is also valid this one (shorter, I keep the one above because it is the one I thought :D):
$ awk '$2=="b" {a=NR} END{print a}' your_file
Another approach if $2 is always grouped (may be more efficient then waiting until the end):
awk 'NR==1||$2=="b",$2=="b"{next} {print NR-1; exit}' file
or
awk '$2=="b"{f=1} f==1 && $2!="b" {print NR-1; exit}' file
I have already tried all options that I found online to solve my issue but without good result.
Basically I have two csv files (pipe separated):
file1.csv:
123|21|0452|IE|IE|1|MAYOBAN|BRIN|OFFICE|STREET|MAIN STREET|MAYOBAN|
123|21|0453|IE|IE|1|CORKKIN|ROBERT|SURNAME|CORK|APTS|CORKKIN|
123|21|0452|IE|IE|1|CORKCOR|NAME|HARRINGTON|DUBLIN|STREET|CORKCOR|
file2.csv:
MAYOBAN|BANGOR|2400
MAYOBEL|BELLAVARY|2400
CORKKIN|KINSALE|2200
CORKCOR|CORK|2200
DUBLD11|DUBLIN 11|2100
I need a linux bash script to find the value of pos.3 from file2 based on the content of pos7 in file1.
Example:
file1, line1, pos 7: MAYOBAN
find MAYOBAN in file2, return pos 3 (2400)
the output should be something like this:
**2400**
**2200**
**2200**
**etc...**
Please help
Jacek
A little approach, far away to be perfect:
DELIMITER="|"
for i in $(cut -f 7 -d "${DELIMITER}" file1.csv );
do
grep "${i}" file2.csv | cut -f 3 -d "${DELIMITER}";
done
This will work, but since the input files must be sorted, the output order will be affected:
join -t '|' -1 7 -2 1 -o 2.3 <(sort -t '|' -k7,7 file1.csv) <(sort -t '|' -k1,1 file2.csv)
The output would look like:
2200
2200
2400
which is useless. In order to have a useful output, include the key value:
join -t '|' -1 7 -2 1 -o 0,2.3 <(sort -t '|' -k7,7 file1.csv) <(sort -t '|' -k1,1 file2.csv)
The output then looks like this:
CORKCOR|2200
CORKKIN|2200
MAYOBAN|2400
Edit:
Here's an AWK version:
awk -F '|' 'FNR == NR {keys[$7]; next} {if ($1 in keys) print $3}' file1.csv file2.csv
This loops through file1.csv and creates array entries for each value of field 7. Simply referring to an array element creates it (with a null value). FNR is the record number in the current file and NR is the record number across all files. When they're equal, the first file is being processed. The next instruction reads the next record, creating a loop. When FNR == NR is no longer true, the subsequent file(s) are processed.
So file2.csv is now processed and if it has a field 1 that exists in the array, then its field 3 is printed.
You can use Miller (https://github.com/johnkerl/miller).
Starting from input01.txt
123|21|0452|IE|IE|1|MAYOBAN|BRIN|OFFICE|STREET|MAIN STREET|MAYOBAN|
123|21|0453|IE|IE|1|CORKKIN|ROBERT|SURNAME|CORK|APTS|CORKKIN|
123|21|0452|IE|IE|1|CORKCOR|NAME|HARRINGTON|DUBLIN|STREET|CORKCOR|
and input02.txt
MAYOBAN|BANGOR|2400
MAYOBEL|BELLAVARY|2400
CORKKIN|KINSALE|2200
CORKCOR|CORK|2200
DUBLD11|DUBLIN 11|2100
and running
mlr --csv -N --ifs "|" join -j 7 -l 7 -r 1 -f input01.txt then cut -f 3 input02.txt
you will have
2400
2200
2200
Some notes:
-N to set input and output without header;
--ifs "|" to set the input fields separator;
-l 7 -r 1 to set the join fields of the input files;
cut -f 3 to extract the field named 3 from the join output
cut -d\| -f7 file1.csv|while read line
do
grep $line file1.csv|cut -d\| -f3
done