Simple question: How to escape the "#" character in Blazor so you don't get reference error in this example?
<script src="https://unpkg.com/#here/harp.gl/dist/harp.js"></script>
I already tried "\#" and "\\#"
You need to use double ##.
Docs are here
Related
how I could use eval(rlang::parse_expr(string))’ or alternative with such expresssion string <-"print('A\s*B')"`? I am getting unrecognized escape character. The expression is evaluated inside function, print is an example, I am using grepl in similar manier.
Simply using second escape slash helped "print('A\s*B')"
For instance, if I wanted to a find and replace with strings containing backward or forward slashes, how would this be accomplished in vim?
Examples
Find & Replace is: :%s/foo/bar/g
what if I wanted to find all occurrences of <dog/> and replace it with <cat\>
Same way you escape characters most anywhere else in linuxy programs, with a backslash:
:%s/<dog\/>/<cat\\>
But note that you can select a different delimiter instead:
:%s#<doc/>#<cat\\>#
This saves you all typing all those time-consuming, confusing backslashes in patterns with a ton of slashes.
From the documentation:
Instead of the / which surrounds the pattern and replacement string, you
can use any other single-byte character, but not an alphanumeric character,
\, " or |. This is useful if you want to include a / in the search
pattern or replacement string.
%s:<dog/>:<cat>
You can replace the / delimiters if they become annoying for certain patterns.
Quote them with a backslash. Also, it often helps to use another delimiter besides slash.
:%s#<dog/>#<cat\\>#
or if you have to use slash as the substitute command delimiter
:%s/<dog\/>/<cat\\>/
I was looking for something similar, to search for register values containing the / character (to record a macro). The solution was to search using the ? token instead of the /.
The syntax is:
:%s/<dog\/>/<cat\\>/g
backslash slash backslash star
/(<- the prompt)\/\*
so after you type it looks like
/\/\*
i need to search a string containing + like 'abc+xyz' or 'test+1234',
currently I am using 'abc.*' but not able to search 'abc+xyz'
Basic regex docs will explain that you can reference a special character by escaping it. The following pattern matches on abc+xyz.
abc\+xyz
A tutorial explaining the above.
for finding regex which contains special character like above situation, just add "\" (back slash)
I want to modify a string with replace in Smarty.
{$var|replace:'aaa':'bbb'}
Simple. But I need to replace this:
{$var|replace:'value="AA"':'value="$string_b"'}
I've also tried with the following syntax with no success:
{$var|replace:'value="AA"':'value="'$string_b'"'}
{$var|replace:'value="AA"':'value="`$string_b`"'}
{$var|replace:'value="AA"':'value=""$string_b""'}
you have to enclose the string in double quotes if you want smarty to recognize variables inside, so in your case you also have to escape the double quotes inside the string:
{$var|replace:'value="AA"':"value=\"{$string_b}\""}
Using brackets around the variable is not necessary but recommended
In the end I managed to find the right syntax to use.
{$var|replace:"value=\"AA\"":"value=\"$string\"}
I want to replace a as using C#. I could not able to achive this using Regex.Replace functions as follos
Regex.Replace(html, "\\"", "\"");
execution this command again produces the original output
Anyone have already faced issue like this,Any help would be of greatly appreciated.
Regards,
Ganesan
first of all "\\""produces a compiler error, since you are just escaping one backslash but not the quote.
you are working with 2 escape mechanisms here, one is from the c# compiler, and another is from the regex interpreter.
Which means:
when you give this C# string as a regex: "\\\"" then after compilation there is a string looking like that \", which is then interpreted by the regex engine, which also uses \ as the escape character. therefor regex will escape ", so your code will replace " with "
so if you now use "\\\\\"", first the c# compiler will make \\" out of that, then the regex engine will make \" out of that (both are using \ as escape character)
now c# has a nice little feature to make such strings easier to write.
if you add an # before your string, \ will no long be the escape character, but now you have to escape " with ""
that means "\\\"" == #"\""" and "\\\\\"" == #"\\"""
so you could write Regex.Replace(html,#"\\""","\"")
which is easier to read then Regex.Replace(html,"\\\\\","\"")
i think i got it right this time :D