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I have these files in my source folder
source_path/date=20191230/somefile.txt
source_path/date=20191231/somefile.txt
source_path/date=20200101/somefile.txt
source_path/date=20200102/somefile.txt
If I do the bellow command all files will be copied to my dest_path folder
cp --recursive source_path/ dest_path/
I just want to copy all folders where dates are in 2020 or something
I just need these to files of 2020
source_path/date=20200101/somefile.txt
source_path/date=20200102/somefile.txt
How can I add filters with cp command
This question is not suitable for Stack Overflow, but this is the answer:
cp --recursive source_path/date=20200* dest_path/
Or does dest_path not exist? Then you would write
mkdir -p dest_path && cp --recursive source_path/date=20200* dest_path/
You can use find with the -name, -type and -exec flags and so if the source directory was /home/foo and the destination directory /tmp:
find /home/foo -type d -name "*date-2020*" -exec cp '{}' /tmp \;
-type signifies that we only searching directories, -name is the name we are searching for and exec for command we are executing with the results
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Need to create a single script that would Gzip or tars logs that are older than 7 days in multiple (3) paths /home/temp, home/logs, then confirm this one is over 50% capacity home/var/lib/mongo. This is what I got so far but I can't think of how to combine these:
find . -mtime +7 -print -exec gzip {} \; for all 3 but them
find /tmp/log/ -mtime +7 -type f -exec sh -c \
'tar -czvPf /tmp/older_log_$(basename $0)_$(date +%F).tar.gz $0' {} ;
# create a single tar file for each archive +7 days old on one mount
If I understand you correclty, you would like to archive multiple old logs in one tar files:
find /tmp/log /home/temp /home/logs -mtime +7 -type f \
| xargs tar -czf /tmp/older_log_$(date +%F).tar.gz --remove-files
For easy reading I put it on two lines.
It searches for all files you want to archive
Pass the found files as arguments to the tar archive (using xargs)
tar will make the new archive and add all the files
additionally tar will remove the original files with the last oiption (from GNU tar)
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I am trying to find all empty directory using find command and also using alpinelinux , but unfortunately we don't have any option of action as empty in alpine. Anyone have any suggestion on how can achieve this.
I am trying to use below
find . -depth -type d -empty -mmin +120 -print;
Anyone can suggest if any package/library can solve this issue .
You may google how to check empty dir in shell and execute a subshell for each directory and make the subshell exit with zero exit status if the directory is empty:
find . -depth -type d -exec sh -c '[ -z "$(ls -A "$1")" ]' _ {} \; -print
Other then that, install GNU find.
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Closed 6 years ago.
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I've created script which delete old backup file from directory but this command was worked fine before 1 week and Nothing change on script or packages but still getting below error:
root#:# find /var/backups/abc/* -type d -mtime +6
/var/backups/abc/2016-03-09_0321
root#:~# find /var/backups/abc/* -type d -mtime +6 -exec rm -rf {} \;
find: `/var/backups/abc/2016-03-08_0321': No such file or directory
Problem is that, this script run every day on cron, I getting a mail like " find: `/var/backups/abc/2016-03-08_0321': No such file or directory". files are deleted but such a mails are getting from root.
find /var/backups/abc/* -type d -mtime +6 -prune -exec rm -rf {} \;
Here, we use -prune on the directories that we're about to delete, so find will then not try to read their contents.
This is because of after having returned your directory, find will try to look in it (to continue his recursive search), and will fail because of you just removed it.
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Closed 7 years ago.
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Can someone with more Linux knowledge answer this correctly for me.
On our web server, we host and run ALOT of web scripts.
we control these via Datestamp files, So the script is not over ran, or ran more than once.
A lot of files are all 0 KB. I wanted to know if there is a quick way in Linux to locate the files and update them.
I have located the files using:
find /var/www/vhosts/DOMAINNAME.co.uk/httpdocs -name "datestamp.*" -type f -empty
I have a long list of files, Can i update these with a simple datestamp format:
i.e.
20150923114046
You can use the -exec option of find:
find /var/www/vhosts/DOMAINNAME.co.uk/httpdocs -name "datestamp.*" -type f -empty \
-exec bash -c 'echo 20150923114046 > {}' \;
To get the timestamp dynamically, use date:
bash -c 'echo $(date +%Y%m%d%H%M%S) > {}'
To use the last modified timestamp, use the -r option:
bash -c 'echo $(date +%Y%m%d%H%M%S -r {}) > {}'
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Closed 9 years ago.
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Remember I need the command to change permissions of all files in current folder?
It depends on what you mean by "current" folder; if you mean the current folder (and all subfolders) then you could use find and chmod like so -
find . -type 'f' -exec chmod +x {} \;
If you mean the current folder (and no sub-folders) then you would use it like so -
find . -maxdepth 1 -type 'f' -exec chmod +x {} \;
OR you could use find (possibly with maxdepth) and xargs likes so
find . -print0 | xargs -0 chmod +x
Note that these commands will correctly handle files with spaces in the name and most other edge cases.
Use chmod with a glob:
chmod +x *
(Technically that will give permission to list directories, too, but that shouldn't be a problem.)