What is the quickest way to move curly braces to be on the same line?
from this:
const value = {
input: 123
}
to this:
const value = { input: 123 }
The way I do it is by using Visual with a combination of hjkl.
Bonus: How can I achieve the edits but the other way around?
Place cursor at or before the first {.
Press v, then shift+%.
Press shift+j.
Note: the behavior may break if unpaired { or } exists in comment/string/etc.
Put cursor at first line (const...) and then press J repeatedly until all the code is on one line.
If you haven't bound Caps lock to anything else, you can press it before to avoid holding Shift
For a more automated way of transforming code in both directions, consider my "splitjoin" plugin: https://github.com/andrewradev/splitjoin.vim
Being a single mapping, it would, technically, be the quickest way :)
Related
Assuming I have the following code:
bool myCopiedFunc() {
Some code that I've written;
The cursor is on this line; <<<<<<<<<<<<<<
if (something) {
bool aValue;
some of this is inside braces;
return aValue;
}
if (somethingElse) {
this is also inside braces;
bool anotherValue;
{
more braces;
}
return anotherValue;
}
return false;
}
I decide I want to rewrite the remainder of the function, from the line with the cursor on it.
To replace up to a char on the same line, I can use ct<char> e.g. ct;
To replace up to and including a char on the same line I can use cf<char> e.g. cf;
To replace up to a string across multiple lines, I can use c/<string> e.g. c/return false
To replace up to and including a string across multiple lines, I can use... ?? e.g. ??
I can't just search for a semicolon, as there are an unknown number of them between the cursor and the end of the function, and counting them would be slow.
I can't just search for a closing brace, as there are several blocks between the cursor and the end of the function, and counting all closing braces would be slow.
With the help of code highlighting, I can easily see that the unique string I can search for is return false.
Is there an elegant solution to delete or change up to and including a string pattern?
I've already looked at a couple of related questions.
Make Vim treat forward search as "up to and including" has an accepted answer which doesn't answer my question.
In my case, I settled for deleting up to the search string, then separately deleting up to the semicolon, but it felt inefficient, and like it would have been quicker to just reach for the mouse. #firstworldproblems
To replace up to and including a string across multiple lines, I can
use... ?? e.g. ??
The / supports offsets.
In your case, you are gonna need the e offset, that is, c/foo/e.
You may want to know more details about "search offset":
:h offset
If you'll replace up to the closing brace associated to your current scope, you have c]}.
If you're looking for the end of the function, even if it means crossing to the upper scope, you'll need a plugin if the function may not be 0-indented as it's the case in C++, Java... See the related Q/A on vi.SE
Supose I have a function such as
myfunc(arg1 = whatever, arg2 = different)
I would like to transform it to
myfunc(arg2 = different, arg1 = whatever)
What is the quickest command sequence to achieve this? suppose the cursor is on the first "m". My best attempt is fadt,lpldt)%p.
There is a vim plugin: vim-exchange
visual select arg1 = whatever
press Shiftx
visual select arg2 = different
press Shiftx
I would recommend you change it a bit so it will work from wherever the cursor is and so that it will work on any arguments:
0f(ldt,lpldt)%p
All I changed from your method was I added 0 to move the cursor to the beginning and I changed fa to f(l so that it will work regardless of argument name.
Now you can either put this into a macro, or, if you use it a lot, you can make it a mapping:
nnoremap <C-k> 0f(ldt,lpldt)%p
I arbitrarily chose Ctrl-k here put you can use whatever you like.
I wrote a plugin for manipulating function arguments called Argumentative. With it you just execute >, and the argument your cursor is on will shift to the right. It also provides argument text object in the form of i, and a,.
With pure vim, with your cursor at the start of the line:
%3dB%pldt,lp
This is the quickest I could think of on the spot (12 strokes).
This should work for all names as long as there is always a space around the equal signs.
% " Jump to closing brace
3dB " Delete to the beginning of 3 WORDS, backwards
% " Jump to the beginning brace
p " Paste the deleted text from the default register
l " Move right one character
dt, " Delete until the next comma
l " Move right one character
p " paste the deleted text from the default register
You could also turn this into a Macro to use at any time.
This is probably a basic vim questions to all those vim gurus out there.
If I want to delete a particular if statement and its closing bracket, but without deleting the code inside the expression, how can I achieve this through some keyboard shortcuts?
eg:
if (a == 2) {
// do not delete this part.
for (int i = 1; i < 10; i++) {
// code
}
}
The result will be:
// do not delete this part.
for (int i = 1; i < 10; i++) {
// code
}
Thanks for any help.
Alternatively to Zachs solution, you could use this:
di{Vk]p
Explanation:
You start inside the { } block, and with di{ you delete inside the { } block.
Then, you select the the if statement, which you want to remove, which now is two lines. Vk selects both, and you paste the block you just deleted over it with p. The ] makes the pasted block be correctly indented (thanks, Kache)
There could be a more elegant solution to the pasting part, buth this was the first one that came to mind.
The anvantage over Zachs answer is that you don't have to move the cursor to the line with the if, you just need to be inside it (although you may run into trouble with nested {} blocks, which there usually are). In addition, you don't need to fix indentation.
Move your cursor anywhere on the line with the if statement. Here is the sequence of commands (will be explained after)
$%dd''.
Explanation:
$ goes to the end of the line (cursor is now on {).
% goes to the matching curly brace (or parentheses etc...). Cursor is now on } of the if statement
dd deletes the line the cursor is on (} is now deleted)
'' goes to the line of the last jump. The last jump was when we used %. (cursor is back on if statement line)
. Repeats the last command (dd). This deletes the line (if statement line is now deleted)
Result:
// do not delete this part.
for (int i = 1; i < 10; i++) {
// code
}
The indentation will be off so you can use gg=G (which correctly indents the file) to fix it.
If you do this alot you can make map it to a key in your .vimrc or you can make it into a macro
Making it into a mapping:
Example of a mapping in your .vimrc:
nnoremap <C-d> $%dd''.gg=G
Whenever you press control-d (you can choose any key, just replace <C-d>) Vim will run those commands, doing what I explained before followed by an entire file indentation this time. Make sure your cursor is on the if statement line when using this command otherwise there could be unintended results.
I have this code:
def foo(c: Char) = c match {
case 'a': 'B'
}
My cursor is on the space after =. I want to delete everything until, including, the }. How can I do that?
Can I do the same where the cursor is anywhere on the first line? Anywhere in the block (and place the cursor after the =)?
d/}/e
does the job.
d/} deletes until the } but adding the /e flag moves the cursor on the last char of the match, effectively deleting everything between the cursor and the }, inclusive.
Using visual selection works too, in a slightly more intuitive way:
v/}<CR>d
Try with this: d%.
The d is for delete and the % moves between braces.
This should work:
d}
This deletes one paragraph forward.
You can achieve something like this with the EasyMotion plugin.
In PHP, if I have a function such as:
function test($b) {
var $a = 0;
while ($a < b) {
$a += 3;
}
return $a;
}
and the cursor is on the $a += 3 line, is it possible to quickly select the entire function?
"v2aB" would select everything including the function braces but not the declaration function test($b)
Press V after the selection command you post, to convert the selection to line selection, and it will select the function declaration:
v2aBV
It's been a long time since this question was asked and answered, but I will add my own answer because it's the one I was looking for and none of the others work exactly like this one:
nnoremap vaf ?func.*\n*\s*{<cr>ma/{<cr>%mb`av`b
vmap af o<esc>kvaf
The first mapping, "Visual around function" or vaf, will jump back to the start of the function definition, regardless that the { is in the same line or the next one, and even if it's a lambda function, and visually select it characterwise to it's ending bracket. This works in PHP, Javascript and Go.
The user can then press V to turn to linewise select mode if she wants to.
The only problem that I found is that when I am in the body of a big function, but below a line that uses a lambda (let's say "small") function, this will stop searching at the beginning of the small function and select it's body instead of reaching the start of the big function and select all of its body.
function show_video_server(v_server) {
// this whole function should get selected
var something = function(){ /* this function gets selected */ };
// | the cursor is here when I type "vaf"
}
As a workaround I use the second mapping: vmap af o<esc>kvaf. It feels like a repetition or expansion of the selection. What it really does is abandon the selection and go to the line before it, and then try it agan. If the "big" function uses several lambda functions the user has to repeat the af several times to reach the big one.
Usually, vaf es enough. Sometimes vaf af or vaf af af is needed. Anyway, it's the closest I could get to what I wanted, so this is the version I'm using.
Here's a mapping that seems to work very well, no matter the nesting level.
:map t ? function <CR>f{vaBV
Here's another method that will work if you have function-level folding turned on: z c v
That closes the current fold and selects it, but it leaves it closed. If you want it to remain open: z c v $
If you have block-level folding turned on, you would have to close twice, since you're inside the while loop, so: 2 z c v
To enable PHP class/function folding: let php_folding = 1
simple way
nmap vaf va}V
I like this
nmap vaf [{?function<CR>:nohl<CR>vf{]}
if ‘{’ is in new line
nmap vaF [{?function<CR>:nohl<CR>v/{<CR>]}
Yet another way. This should select the entire function definition regardless of your cursor position within the definition, not just when you're at the $a += 3 line.
Use this in normal mode (<CR> means press enter)
?func<CR>V/{%
Explanation of each part:
?func search backward for the word "func" (the idea is to get to the first line of the function definition)
V go to visual line mode
/{ search forward for the opening brace (I didn't use f{ because the opening brace might be on a separate line)
% go to the matching brace
If you are using OOP programming this works (it looks for extra words before function[public, private, protected])
nmap vaf [{?\S* function<CR>:nohl<CR>v/{<CR>]}
As a bonus here is a wrapper around if
nmap vai [{?if<CR>:nohl<CR>v/{<CR>]}