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I am having a text file containing a list of date and time just like the sample below -
posted_at"
2012-06-09 11:48:31"
2012-08-09 12:40:02"
2012-04-09 13:10:00"
2012-03-09 13:40:00"
2012-10-09 14:30:01"
2012-12-09 15:30:00"
2012-11-09 16:20:00"
I want to extract the month from each line.
P.S - grep should not be used at any point of the code
Thanks in advance!
First select date pattern :
egrep '[0-9]{4}-[0-9]{2}-[0-9]{2} ' content_file
Second, extract the month :
awk -F '-' '{print $2}'
Third redirect to desired file :
>> desired_file
So mix of all this with | to final solution :
egrep '[0-9]{4}-[0-9]{2}-[0-9]{2} ' content_file| awk -F '-' '{print $2}'>> desired_file
Voilà
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I have a text file which contains a series of same line except at the end.
eg
lesi-1-1500-1
lesi-1-1500-2
lesi-1-1500-3
how can I remove the last number? it goes upto 250
to change in the file itself
sed -i 's/[0-9]\+$//' /path/to/file
or
sed 's/[0-9]\+$//' /path/to/file > /path/to/output
see example
You can do it with Awk by breaking it into fields.
echo "lesi-1-1500-2" > foo.txt
echo "lesi-1-1500-3" >> foo.txt
cat foo.txt | awk -F '-' '{print $1 "-" $2 "-" $3 }'
The -F switch allows us to set the delimiter which is -. Then we just print the first three fields with - for formatting.
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I'm trying to find the smallest file by character length inside of a directory and, once it is found, I want to rename it and copy it to another directory.
For example, I have two files in one directory ~/Files and these are cars.txt and rabbits.txt
Text in cars.txt:
I like red cars that are big.
Text in rabbits.txt:
I like rabbits.
So far I know how to get the character length of a single file with the command wc -m 'filename' but I don't know how to do it in all the files and sort them in order. I know rabbits.txt is smaller in character length, but how do I compare both of them?
You could sort the files by size, then select the name of the first one:
file=$(wc -m ~/Files/* 2>/dev/null | sort -n | head -n 1 | awk '{print $2}')
echo $file
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I have two text file like below:
File1.txt
A|234-211
B|234-244
C|234-351
D|999-876
E|456-411
F|567-211
File2.txt
234-244
999-876
567-211
And I want to compare both files and get containing values like below:
Dequired output
B|234-244
D|999-876
F|567-211
$ grep -F -f file2.txt file1.txt
B|234-244
D|999-876
F|567-211
The -F makes grep search for fixed strings (not patterns). Both -F and -f are POSIX options to grep.
Note that this assumes your file2.txt does not contain short strings like 11 which could lead to false positives.
Try:
grep -f File2.txt File1.txt
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I work with Bash script and I want to get line from big text by special text
for example i have these lines
first fffffffffffffffffffffffffff
.................................
second ssssssssssssssssssssssssss
.................................
third ttttttttttttttttttttttttttt
and I want to get ssssssssssssssssssssssssss string .
Can anybody help me?
Is this what you want?
echo "$longstring" | awk '$1 == "second" { print $2 }'
since you seem to not have any criterion as to which line you want to output, i suggest something like:
echo "ssssssssssssssssssssssssss"
this is pretty robust regarding the content of your input, doesn't depend on a "file", and is a fast solution.
cat filename | grep "^second" | cut -d " " -f 2
Or, if you are ALF:
<filename grep "^second" | cut -d " " -f 2
Or
grep "^second" filename | cut -d " " -f 2
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I have comma deliminated file that basically has the structure of:
1, 2, 3, 4, 5 ,,,, 6, etc
I have to count the number of unique 6th columns. Pleasseee help
(btw this is an intro to unix/linux class so this should be able to be done with basic commands)
cut -d "," -f 6 myFile |sort |uniq -c |wc -l
Looking into my crystal ball, I see that your class is discussing awk. Try
awk -F, '!a[$6]++{c++} END{ print c }' input-file