I need the following view types on CRM hide calendar,pivot,graph,cohort,dashboard using a custom module
I tried with this without success
<record id="crm_action" model="ir.actions.act_window">
<field name="name">CRM views</field>
<field name="type">ir.actions.act_window</field>
<field name="res_model">crm.lead</field>
<field name="view_type">crm.lead.kanban</field>
<field name="view_mode">tree,form,calendar,graph</field>
</record>
thanks
UPDATE
Your module should depend on crm. Then, the code must be this:
<record model="ir.actions.act_window" id="crm.crm_lead_action_pipeline">
<field name="view_mode">kanban,tree,form</field>
</record>
Related
I am porting a localization accountability model from Odoo 8 to Odoo 12, I ported a function that worked flawlessly but then right after that I tried porting some other code that does not interfere with the first on, even though, whenever it is initialized by the init.py Odoo brings up an error telling me that the model cannot be found, even though it is correctly set up.
All I've tried is to ignore the new modules I added right after setting up the one that should be perfectly working right now. Without them (or without any new module at all, because I've tried porting different ones) it works, but this shouldn't be the case at all.
wizard_nro_ctrl.py
class WizNroctrl(models.TransientModel):
_name = 'nroctrl'
_description = "Wizard that changes the invoice control number"
new_nroctrl = fields.Char('Control Number', required=True)
sure = fields.Boolean('Are you sure?')
# Change control number of the invoice
def set_noctrl(self):
if not self.sure:
raise except_orm('Error!', 'Please confirm that you want to do this by checking the option')
current_id = self._context['current_id']
inv_object = self.env['account.invoice'].browse(current_id)
inv_object.nro_ctrl = self.new_nroctrl
return True
wizard_nro_ctrl_view.xml
<?xml version='1.0' encoding='UTF-8'?>
<odoo>
<data>
<record model="ir.ui.view" id="wizard_nro_ctrl_form">
<field name="name">wizard.nro.ctrl.form</field>
<field name="model">nroctrl</field>
<field name="arch" type="xml">
<form string="Changing the Control Number">
<field name="new_nroctrl" placeholder="New control number"/>
<separator string="Are you sure you want to do this?" colspan="4"/>
<field name="sure"/>
<footer>
<button name="set_noctrl" string="Confirm" type="object"/>
<button special="cancel" string="Cancel"/>
</footer>
</form>
</field>
</record>
<record id="action_wiz_nroctrl" model="ir.actions.act_window">
<field name="name">Change control number</field>
<field name="type">ir.actions.act_window</field>
<field name="model">wiz.nroctrl</field>
<field name="view_type">form</field>
<field name="view_mode">form</field>
<field name="target">new</field>
</record>
</data>
</odoo>
The init.py has the model initialized and the folder as well.
The model should work just fine, without this error. There's no reason to my knowledge for this issue.
odoo.tools.convert.ParseError: "Error while validating constraint
Model not found: nroctrl
Please make sure that in the model action you have wrote include model name 'nroctrl'. give the below xml code (nroctrl):
<record id="action_wiz_nroctrl" model="ir.actions.act_window">
<field name="name">Change control number</field>
<field name="type">ir.actions.act_window</field>
<field name="model">nroctrl</field>
<field name="view_type">form</field>
<field name="view_mode">form</field>
<field name="target">new</field>
</record>
Also please ensure that you have given file name in init.py of wizard folder. also the folder name in ini.py of module.
i'm using odoo 11 and i want to set a default filter which group by employee. i made a modification on the module but it doesn't shows the right result(i want to remove the administrator filter) .I don't know what's the problem .Any idea for help please ?
.
<record id="action_bt_overtime_management" model="ir.actions.act_window">
<field name="name">Overtime</field>
<field name="type">ir.actions.act_window</field>
<field name="res_model">bt.hr.overtime</field>
<field name="view_type">form</field>
<field name="view_mode">tree,form</field>
<field name="context">{'search_default_employee_id':1}</field>
<field name="search_view_id" ref="bt_overtime_management_search"/>
<field name="help" type="html">
<p class="oe_view_nocontent_create">
Create Overtime Request
</p>
</field>
</record>
Try to give like this
<record id="action_bt_overtime_management" model="ir.actions.act_window">
<field name="name">Overtime</field>
<field name="type">ir.actions.act_window</field>
<field name="res_model">bt.hr.overtime</field>
<field name="view_type">form</field>
<field name="view_mode">tree,form</field>
<field name="context">{'group_by':'employee_id'}</field>
<field name="search_view_id" ref="bt_overtime_management_search"/>
<field name="help" type="html">
<p class="oe_view_nocontent_create">
Create Overtime Request
</p>
</field>
</record>
I'm working on a private sale website. If the user is a manager, the menu2 will look, else user is a salesman, the menu3 will look. How can I do that?
What is the best solution?
Here is my code:
<record id="menu_shop_sales" model="website.menu">
<field name="name">menu2</field>
<field name="url">/shop_sales</field>
<field name="parent_id" ref="website.main_menu"/>
<field name="sequence" type="int">21</field>
</record>
<record id="menu_shop_dealer" model="website.menu">
<field name="name">menu3</field>
<field name="url">/shop_dealer</field>
<field name="parent_id" ref="website.main_menu"/>
<field name="sequence" type="int">22</field>
</record>
Add groups like this.
<field name="groups" eval="[(6, 0, [ref('base.group_user')])]"/>
Or write access rule in csv.
Add groups attribute.
groups="base.group_user"
example:
<record id="menu_shop_dealer" model="website.menu">
<field name="name">menu3</field>
<field name="url">/shop_dealer</field>
<field name="parent_id" ref="website.main_menu"/>
<field name="sequence" type="int">22</field>
<field name="groups">base.group_user</field>
</record>
I have code that shows I have multiple stations each station have a different worker.. I use rule to show each station to it's worker only .. I have supervisor who must see all stations .. how can I do rule for the supervisor to see all stations
This is rule for worker
<record model="ir.rule" id="station_worker_rule">
<field name="name">station worker Rule</field>
<field name="model_id" ref="model_mrp_production_workcenter_line"/>
<field name="domain_force">[('user_id','=',user.id)]</field>
<field name="groups" eval="[(4, ref('group_worker'))]"/>
<field name="perm_read" eval="True"/>
<field name="perm_write" eval="True"/>
<field name="perm_unlink" eval="True"/>
<field name="perm_create" eval="True"/>
</record>
For the supervisor you have to change a domain and groups.
You have to put a domain
<field name="domain_force">[(1 ,'=', 1)] </field>
<field name="groups" eval="[(4, ref('group_supervisor'))]"/>
If there are four records created by four users. The Manager can be able to see all the records of all users. But a user should not be able view another user's record.
user – Can create/view/edit only his/her own record.
This is my need.
Thank You in advance.
you need to create ir.rules. For example in your case it would be something like this:
For administrators:
<record id="manager_rule" model="ir.rule">
<field name="name">My first rule</field>
<field name="model_id" ref="model_your_model"/>
<field name="domain_force">[(1,'=',1)]</field>
<field name="groups" eval="[(4,ref('your_manager_group'))]"/>
</record>
For other users:
<record id="others_rule" model="ir.rule">
<field name="name">My second rule</field>
<field name="model_id" ref="model_your_model"/>
<field name="domain_force">[('user_id','=',user.id)]</field>
<field name="groups" eval="[(4,ref('base.group_user'))]"/>
</record>
For more information about access rules you could visit odoo_security, access_rules.
I hope this help you!
Your problem solved using domain like
Eg.
domain = [('user_id','=',user.id)]
i hope it helps you