Extract Numeric data from the Column in Spark Dataframe - apache-spark

Question

I have a Dataframe with 20 columns and I want to update one particular column (whose data is null) with the data extracted from another column and do some formatting. Below is a sample input
+------------------------+----+
|col1 |col2|
+------------------------+----+
|This_is_111_222_333_test|NULL|
|This_is_111_222_444_test|3296|
|This_is_555_and_666_test|NULL|
|This_is_999_test |NULL|
+------------------------+----+
and my output should be like below
+------------------------+-----------+
|col1 |col2 |
+------------------------+-----------+
|This_is_111_222_333_test|111,222,333|
|This_is_111_222_444_test|3296 |
|This_is_555_and_666_test|555,666 |
|This_is_999_test |999 |
+------------------------+-----------+
Here is the code I have tried and it is working only when the the numeric is continuous, could you please help me with a solution.
df.withColumn("col2",when($"col2".isNull,regexp_replace(regexp_replace(regexp_extract($"col1","([0-9]+_)+",0),"_",","),".$","")).otherwise($"col2")).show(false)
I can do this by creating a UDF, but I am thinking is it possible with the spark in-built functions. My Spark version is 2.2.0
Thank you in advance.

Answer 1

A UDF is a good choice here. Performance is similar to that of the withColumn approach given in the OP (see benchmark below), and it works even if the numbers are not contiguous, which is one of the issues mentioned in the OP.
import org.apache.spark.sql.functions.udf
import scala.util.Try
def getNums = (c: String) => {
c.split("_").map(n => Try(n.toInt).getOrElse(0)).filter(_ > 0)
}
I recreated your data as follows
val data = Seq(("This_is_111_222_333_test", null.asInstanceOf[Array[Int]]),
("This_is_111_222_444_test",Array(3296)),
("This_is_555_666_test",null.asInstanceOf[Array[Int]]),
("This_is_999_test",null.asInstanceOf[Array[Int]]))
.toDF("col1","col2")
data.createOrReplaceTempView("data")
Register the UDF and run it in a query
spark.udf.register("getNums",getNums)
spark.sql("""select col1,
case when size(col2) > 0 then col2 else getNums(col1) end new_col
from data""").show
Which returns
+--------------------+---------------+
| col1| new_col|
+--------------------+---------------+
|This_is_111_222_3...|[111, 222, 333]|
|This_is_111_222_4...| [3296]|
|This_is_555_666_test| [555, 666]|
| This_is_999_test| [999]|
+--------------------+---------------+
Performance was tested with a larger data set created as follows:
val bigData = (0 to 1000).map(_ => data union data).reduce( _ union _)
bigData.createOrReplaceTempView("big_data")
With that, the solution given in the OP was compared to the UDF solution and found to be about the same.
// With UDF
spark.sql("""select col1,
case when length(col2) > 0 then col2 else getNums(col1) end new_col
from big_data""").count
/// OP solution:
bigData.withColumn("col2",when($"col2".isNull,regexp_replace(regexp_replace(regexp_extract($"col1","([0-9]+_)+",0),"_",","),".$","")).otherwise($"col2")).count

Answer 2

Here is another way, please check the performance.
df.withColumn("col2", expr("coalesce(col2, array_join(filter(split(col1, '_'), x -> CAST(x as INT) IS NOT NULL), ','))"))
.show(false)
+------------------------+-----------+
|col1 |col2 |
+------------------------+-----------+
|This_is_111_222_333_test|111,222,333|
|This_is_111_222_444_test|3296 |
|This_is_555_666_test |555,666 |
|This_is_999_test |999 |
+------------------------+-----------+