I need to do a complicated vlookup/maxif type of selection. The data I have is as below
Row Col G Col H Col I colJ col K
1 Bench Strip Block BenchAbove BenchBelow
2 1 1 4
3 1 1 5
4 1 1 6
5 1 1 7
6 1 1 8
7 8 1 4 ?? ??
8 8 1 5
9 8 1 6
10 8 1 7
11 8 1 8
12 9 1 4
13 9 1 5
14 9 1 6
15 9 1 7
.....this list is long ( this is a sample only)
For every combination of (Strip, block) like say (1,4) There are benches like 1, 8 and 9. So bench above for 8 is 1 and bench below for 8 is 9. I need to determine the bench above and bench below for each row. There are no bench above 1 and no bench below 9.
I dont think vlookup is the solution here. Not sure if MAX(IF..) can help either. What would be the best formulae to obtain say on row 7, block combination is 1,4. The bench in question is 8. The bench above is 1 and bench below is 9. So 2 formulae will be required on Col J and Col I above.
The expected answer for the above sample data is :
Row Col G Col H Col I colJ col K
1 Bench Strip Block BenchAbove BenchBelow
2 1 1 4 - 8
3 1 1 5 - 8
4 1 1 6 - 8
5 1 1 7 - 8
6 1 1 8 - 8
7 8 1 4 1 9
8 8 1 5 1 9
9 8 1 6 1 9
10 8 1 7 1 9
11 8 1 8 1 9
12 9 1 4 8 -
13 9 1 5 8 -
14 9 1 6 8 -
15 9 1 7 8 -
Maybe in J2:
=IFERROR(LOOKUP(2,1/((H$1:H1=H2)*(I$1:I1=I2)),G$1:G1),"-")
In K2:
=IFERROR(INDEX(G3:G$16,MATCH(1,INDEX((H3:H$16=H2)*(I3:I$16=I2),),0)),"-")
However, I find your question a bit confusing so this answer might be a bit off.
If you have Office365 then you can use MAXIFS(), MINIFS() easily to get BenchAbove and BenchBelow. Try-
=MAXIFS(A2:A15,B2:B15,B7,C2:C15,C7)
=MINIFS(A2:A15,B2:B15,B7,C2:C15,C7)
EDIT: Solution for Excel-2016
Try below formula-
=INDEX($A$2:$A$15,AGGREGATE(14,6,ROW($A$2:$A$15)-ROW($A$1)/(($B$2:$B$15=B7)*($C$2:$C$15=C7)),ROW(1:1)))
=INDEX($A$2:$A$15,AGGREGATE(15,6,ROW($A$2:$A$15)-ROW($A$1)/(($B$2:$B$15=B7)*($C$2:$C$15=C7)),ROW(1:1)))
Related
If I type !i.10 it gives the factorial of first 10 numbers.
However if I try to add a column of ordinal numbers >/.!i.10, 1+i.10, then J freezes or I get an "Out of memory" error. How do I create custom tables?
I think that what is happening is that you are creating something much bigger than you expect. Taking it in steps:
1+ i. 10 NB. list of 1 to 10
1 2 3 4 5 6 7 8 9 10
10 , 1+ i. 10 NB. 10 prepended
10 1 2 3 4 5 6 7 8 9 10
i. 10 , 1+ i. 10 NB. creates an 11 dimension array with shape 10 1 2 3 4 5 6 7 8 9 10 and largest value of 36287999
When you apply ! to that i. 10 , 1+ i. 10 you get some very large numbers. I am not sure what you are trying to do with the leading >/.
Is this what you had in mind?
(!1 + i.10),. (1+i.10) NB. using parenthesis to isolate operations
1 1
2 2
6 3
24 4
120 5
720 6
5040 7
40320 8
362880 9
3.6288e6 10
To give extended type and get rid of the 3.6288e6 we can use x:
(x:!1 + i.10),. (1+i.10)
1 1
2 2
6 3
24 4
120 5
720 6
5040 7
40320 8
362880 9
3628800 10
or tacit
(x:#! ,. ]) # (1+i.) 10
1 1
2 2
6 3
24 4
120 5
720 6
5040 7
40320 8
362880 9
3628800 10
Or a version I find a little better
([: (,.~ !) 1x + i.) 10
1 1
2 2
6 3
24 4
120 5
720 6
5040 7
40320 8
362880 9
3628800 10
I have the following values in a sheet (in A1:G10) range:
1 1 1 1 1 1 1
2 2 2 2 2 2 2
3 3 3 3 3 3 3
4 4 4 4 4 4 4
5 5 5 5 5 5 5
6 6 6 6 6 6 6
7 7 7 7 7 7 7
8 8 8 8 8 8 8
9 9 9 9 9 9 9
10 10 10 10 10 10 10
I need to calculate the sum of differences of values between two rows in the array above when both rows are defined by row numbers, for example: sum of differences of values between 10-th and 1-st rows, between 9-th and 2-nd rows and so on. Row numbers I defined in J1:K10 range:
1 10
2 9
3 8
4 7
5 6
6 5
7 4
8 3
9 2
10 1
Then I selected L1:L10 range, and in the first cell of it I entered the following formula:
=SUM((OFFSET(A1,INDEX(K1:K10,ROW(K1:K10)-ROW(K1)+1)-1,0,1,7)-OFFSET(A1,INDEX(J1:J10,ROW(J1:J10)-ROW(J1)+1)-1,0,1,7)))
and then pressed CTRL+SHIFT+ENTER so the formula is enterd as an array formula. And the formula returned a #VALUE! error for each cell in the range.
I tried to evaluate the formula, and it evaluates correctly except the last step: SUM({9,9,9,9,9,9,9}) becomes a #VALUE!
Here is a screenshot of the sheet for clarity:
What I'm doing wrong? Please suggest.
use SUMPRODUCT in L1:
=SUMPRODUCT(INDEX($A$1:$G$10,J1,0)-INDEX($A$1:$G$10,K1,0))
and copy down.
I have 15 datafiles with unequal row sizes, but number of columns in each file is same. e.g.
ifile1.dat ifile2.dat ifile3.dat and so on ............
0 0 0 0 1 6
1 2 5 3 2 7
2 5 6 10 4 6
5 2 8 9 5 9
10 2 10 3 8 2
In each file 1st column represents the index number.
I would like to compute average of all these files for each index number in column 1. i.e.
ofile.txt
0 0 [This is computed as (0+0)/2]
1 4 [This is computed as (2+6)/2]
2 6 [This is computed as (5+7)/2]
3 [no value]
4 6 [This is computed as (6)/1]
5 4.66 [This is computed as (2+3+9)/3]
6 10
7
8 5.5
9
10 2.5
I can't think of any simple method to do it. I was thinking of a method, but seems very lengthy. Taking the average after converting all the files with same row size, .e.g.
ifile1.dat ifile2.dat ifile3.dat and so on ............
0 0 0 0 0 0
1 2 1 1 6
2 5 2 2 7
3 3 3
4 4 4 6
5 2 5 3 5 9
6 6 10 6
7 7 7
8 8 9 8 2
9 9 9
10 2 10 3 10
$ awk '{s[$1]+=$2; c[$1]++;} END{for (i in s) print i,s[i]/c[i];}' ifile*.dat
0 0
1 4
2 6
4 6
5 4.66667
6 10
8 5.5
10 2.5
In the above code, there are two arrays, s and c. s[i] is the sum of all entries with index i and c[i] is the number of entries with index i. After we have read all the files, we print the average, s[i]/c[i], for each index i.
I have an input file that contains following data:
1 2 3 4
4 6
8 9
10
2 1 5 7
3
3 4 2 9
2 7
11
I'm trying to sort the group of data based on the third column and get such an output:
2 1 5 7
3
1 2 3 4
4 6
8 9
10
3 4 2 9
2 7
11
Could you tell me how to do so?
sort -nk3r
will sort in reverse order based on 3rd column. Note however, that this outputs
2 1 5 7
1 2 3 4
3 4 2 9
10
11
2 7
3
4 6
8 9
because of the way bash sort functions, and this produces a different result than the output you posted, but correct according to the question.
I am going to convert an array as [1 2 6 12 13 15 20 8 30 31] to range [1 2 3 4 5 6 7 8 9 10] in EXCEL or in MATLAB. Is there any function to do it? Is there any suggestion to convert this type of arbitrary range to definite range?
Solution for MATLAB
In MATLAB, unique can do the trick. For example:
A = [1 1 1 1 4 4 5 3 3 6 6 6 6 8]
[C, ia, ic] = unique(A);
Now ic holds the values that you're looking for:
ic =
1 1 1 1 3 3 4 2 2 5 5 5 5 6
Also, you can remap ic to a new order if you wish to do so. For instance, here's a new order similar to the one you suggested:
new_order = [1 3 2 4 6 5];
ic_new = new_order(ic);
which yields:
ic_new =
1 1 1 1 2 2 4 3 3 6 6 6 6 5
Hope that helps!
In Matlab:
v = [1 2 6 12 13 15 20 8 30 31];
v_index = 1:length(v);