Clamp segment inside rectangle - geometry

I have a rectangle, and there lines that outgoing from center of it into arbitrary position outside of rectangle. I need to clamp them to rectangle edges, so endpoint will lie on rectangle. I tried using intersection algorithms and it works, but it pretty slow because it handles any kind of collisions, while I have specific conditions: start of segment is always in center of rectangle, and end of line is always outside of rectangle, maybe there some fast algorithm for this?

I assume that rectangle dimensions are width, height and rectangle center is at (0,0)
(otherwise subtract center coordinates from endx, endy variables and add them to final results)
if abs(endx) * height <= abs(endy) * width //top or bottom side
return height/2 * endx / abs(endy), sign(endy) * height/2
else //left or right side
return sign(endx) * width/2, width/2 * endy / abs(endx)
Python quick check:
from math import copysign
def rectclamp(rectcenterx, rectcentery, width, height, lineendx, lineendy):
endx = lineendx - rectcenterx
endy = lineendy - rectcentery
if abs(endx) * height <= abs(endy) * width: #at top or bottom
return (rectcenterx + height / 2 * endx / abs(endy),
rectcentery + copysign(1, endy) * height / 2)
else:
return (rectcenterx + copysign(1, endx) * width/2,
rectcentery+ width/2 * endy / abs(endx))
print(rectclamp(6, 4, 12, 8, 9, 9))
print(rectclamp(6, 4, 12, 8, 27, 10))
print(rectclamp(6, 4, 12, 8, -12, -8))
>>>
(8.4, 8.0) #top edge
(12.0, 5.714285714285714) # right edge
(0.0, 0.0) #corner

Related

How to scale a list of 2D coordinates to a desired size

I have a list of 2D coordinates that draw a shape, e.g. [{12, 14}, {22, 44}, {59, 33}, ...]
I'd like to be able to take this shape, and center it in a canvas of arbitrary size (let's say 400x400) and have it take as much space as possible.
I've figured out how to normalize the list so it's in the 0-1 range, but ended up being stuck there when trying to then scale it up to the desired size.
Any help would be appreciated!
Find minimal and maximal values for X and Y coordinates xmin, xmax, ymin, ymax
Calculate point cloud width and height, and middle coordinates
cw = xmax - xmin
ch = ymax - ymin
mx = (xmax + xmin) / 2
my = (ymax + ymin) / 2
Now find coefficient
if cw * canvas.height >= ch * canvas.width
coeff = canvas.width / cw
else
coeff = canvas.height / ch
Now get canvas center
centerx = canvas.width / 2
centery = canvas.height / 2
and apply the next transformation to every point (x,y):
screenx = centerx + coeff * (x - mx)
screeny = centery + coeff * (y - my)

How to translate points on image after cropping it and resizing it?

I am creating a program which allows a user to annotate images with points.
This program allows user to zoom in an image so user can annotate more precisely.
Program zooms in an image doing the following:
Find the center of image
Find minimum and maximum coordinates of new cropped image relative to center
Crop image
Resize the image to original size
For this I have written the following Python code:
import cv2
def zoom_image(original_image, cut_off_percentage, list_of_points):
height, width = original_image.shape[:2]
center_x, center_y = int(width/2), int(height/2)
half_new_width = center_x - int(center_x * cut_off_percentage)
half_new_height = center_y - int(center_y * cut_off_percentage)
min_x, max_x = center_x - half_new_width, center_x + half_new_width
min_y, max_y = center_y - half_new_height, center_y + half_new_height
#I want to include max coordinates in new image, hence +1
cropped = original_image[min_y:max_y+1, min_x:max_x+1]
new_height, new_width = cropped.shape[:2]
resized = cv2.resize(cropped, (width, height))
translate_points(list_of_points, height, width, new_height, new_width, min_x, min_y)
I want to resize the image to original width and height so user always works on same "surface"
regardless of how zoomed image is.
The problem I encounter is how to correctly scale points (annotations) when doing this. My algorithm to do so was following:
Translate points on original image by subtracting min_x from x coordinate and min_y from y coordinate
Calculate constants for scaling x and y coordinates of points
Multiply coordinates by constants
For this I use the following Python code:
import cv2
def translate_points(list_of_points, height, width, new_height, new_width, min_x, min_y):
#Calculate constants for scaling points
scale_x, scale_y = width / new_width, height / new_height
#Translate and scale points
for point in list_of_points:
point.x = (point.x - min_x) * scale_x
point.y = (point.y - min_y) * scale_y
This code doesn't work. If I zoom in once, it is hard to detect the offset of pixels but it happens. If I keep zooming in, it will be much easier to detect the "drift" of points. Here are images to provide examples. On original image (1440x850) I places a point in the middle of blue crosshair. The more I zoom in the image it is easier to see that algorithm doesn't work with bigger cut-ofs.
Original image. Blue crosshair is middle point of an image. Red angles indicate what will be borders after image is zoomed once
Image after zooming in once.
Image after zooming in 5 times. Clearly, green point is no longer in the middle of image
The cut_off_percentage I used is 15% (meaning that I keep 85% of width and height of original image, calculated from the center).
I have also tried the following library: Augmentit python library
Library has functions for cropping images and resizing them together with points. Library also causes the points to drift. This is expected since the code I implemented and library's functions use the same algorithm.
Additionally, I have checked whether this is a rounding problem. It is not. Library rounds the points after multiplying coordinates with scales. Regardless on how they are rounded, points are still off by 4-5 px. This increases the more I zoom in the picture.
EDIT: A more detailed explanation is given here since I didn't understand a given answer.
The following is an image of right human hand.
Image of a hand in my program
Original dimension of this image is 1440 pixels in width and 850 pixels in height. As you can see in this image, I have annotated right wrist at location (756.0, 685.0). To check whether my program works correctly, I have opened this exact image in GIMP and placed a white point at location (756.0, 685.0). The result is following:
Image of a hand in GIMP
Coordinates in program work correctly. Now, if I were to calculate parameters given in first answer according to code given in first answer I get following:
vec = [756, 685]
hh = 425
hw = 720
cov = [720, 425]
These parameters make sense to me. Now I want to zoom the image to scale of 1.15. I crop the image by choosing center point and calculating low and high values which indicate what rectangle of image to keep and what to cut. On the following image you can see what is kept after cutting (everything inside red rectangle).
What is kept when cutting
Lows and highs when cutting are:
xb = [95,1349]
yb = [56,794]
Size of cropped image: 1254 x 738
This cropped image will be resized back to original image. However, when I do that my annotation gets completely wrong coordinates when using parameters described above.
After zoom
This is the code I used to crop, resize and rescale points, based on the first answer:
width, height = image.shape[:2]
center_x, center_y = int(width / 2), int(height / 2)
scale = 1.15
scaled_width = int(center_x / scale)
scaled_height = int(center_y / scale)
xlow = center_x - scaled_width
xhigh = center_x + scaled_width
ylow = center_y - scaled_height
yhigh = center_y + scaled_height
xb = [xlow, xhigh]
yb = [ylow, yhigh]
cropped = image[yb[0]:yb[1], xb[0]:xb[1]]
resized = cv2.resize(cropped, (width, height), cv2.INTER_CUBIC)
#Rescaling poitns
cov = (width / 2, height / 2)
width, height = resized.shape[:2]
hw = width / 2
hh = height / 2
for point in points:
x, y = point.scx, point.scy
x -= xlow
y -= ylow
x -= cov[0] - (hw / scale)
y -= cov[1] - (hh / scale)
x *= scale
y *= scale
x = int(x)
y = int(y)
point.set_coordinates(x, y)
So this really is an integer rounding issue. It's magnified at high zoom levels because being off by 1 pixel at 20x zoom throws you off much further. I tried out two versions of my crop-n-zoom gui. One with int rounding, another without.
You can see that the one with int rounding keeps approaching the correct position as the zoom grows, but as soon as the zoom takes another step, it rebounds back to being wrong. The non-rounded version sticks right up against the mid-lines (denoting the proper position) the whole time.
Note that the resized rectangle (the one drawn on the non-zoomed image) blurs past the midlines. This is because of the resize interpolation from OpenCV. The yellow rectangle that I'm using to check that my points are correctly scaling is redrawn on the zoomed frame so it stays crisp.
With Int Rounding
Without Int Rounding
I have the center-of-view locked to the bottom right corner of the rectangle for this demo.
import cv2
import numpy as np
# clamp value
def clamp(val, low, high):
if val < low:
return low;
if val > high:
return high;
return val;
# bound the center-of-view
def boundCenter(cov, scale, hh, hw):
# scale half res
scaled_hw = int(hw / scale);
scaled_hh = int(hh / scale);
# bound
xlow = scaled_hw;
xhigh = (2*hw) - scaled_hw;
ylow = scaled_hh;
yhigh = (2*hh) - scaled_hh;
cov[0] = clamp(cov[0], xlow, xhigh);
cov[1] = clamp(cov[1], ylow, yhigh);
# do a zoomed view
def zoomView(orig, cov, scale, hh, hw):
# calculate crop
scaled_hh = int(hh / scale);
scaled_hw = int(hw / scale);
xlow = cov[0] - scaled_hw;
xhigh = cov[0] + scaled_hw;
ylow = cov[1] - scaled_hh;
yhigh = cov[1] + scaled_hh;
xb = [xlow, xhigh];
yb = [ylow, yhigh];
# crop and resize
copy = np.copy(orig);
crop = copy[yb[0]:yb[1], xb[0]:xb[1]];
display = cv2.resize(crop, (width, height), cv2.INTER_CUBIC);
return display;
# draw vector shape
def drawVec(img, vec, pos, cov, hh, hw, scale):
con = [];
for point in vec:
# unpack point
x,y = point;
x += pos[0];
y += pos[1];
# here's the int version
# Note: this is the same as xlow and ylow from the above function
# x -= cov[0] - int(hw / scale);
# y -= cov[1] - int(hh / scale);
# rescale point
x -= cov[0] - (hw / scale);
y -= cov[1] - (hh / scale);
x *= scale;
y *= scale;
x = int(x);
y = int(y);
# add
con.append([x,y]);
con = np.array(con);
cv2.drawContours(img, [con], -1, (0,200,200), -1);
# font stuff
font = cv2.FONT_HERSHEY_SIMPLEX;
fontScale = 1;
fontColor = (255, 100, 0);
thickness = 2;
# draw blank
res = (800,1200,3);
blank = np.zeros(res, np.uint8);
print(blank.shape);
# draw a rectangle on the original
cv2.rectangle(blank, (100,100), (400,200), (200,150,0), -1);
# vectored shape
# comparison shape
bshape = [[100,100], [400,100], [400,200], [100,200]];
bpos = [0,0]; # offset
# random shape
vshape = [[148, 89], [245, 179], [299, 67], [326, 171], [385, 222], [291, 235], [291, 340], [229, 267], [89, 358], [151, 251], [57, 167], [167, 164]];
vpos = [100,100]; # offset
# get original image res
height, width = blank.shape[:2];
hh = int(height / 2);
hw = int(width / 2);
# center of view
cov = [600, 400];
camera_spd = 5;
# scale
scale = 1;
scale_step = 0.2;
# loop
done = False;
while not done:
# crop and show image
display = zoomView(blank, cov, scale, hh, hw);
# drawVec(display, vshape, vpos, cov, hh, hw, scale);
drawVec(display, bshape, bpos, cov, hh, hw, scale);
# draw a dot in the middle
cv2.circle(display, (hw, hh), 4, (0,0,255), -1);
# draw center lines
cv2.line(display, (hw,0), (hw,height), (0,0,255), 1);
cv2.line(display, (0,hh), (width,hh), (0,0,255), 1);
# draw zoom text
cv2.putText(display, "Zoom: " + str(scale), (15,40), font,
fontScale, fontColor, thickness, cv2.LINE_AA);
# show
cv2.imshow("Display", display);
key = cv2.waitKey(1);
# check keys
done = key == ord('q');
# Note: if you're actually gonna make a GUI
# use the keyboard module or something else for this
# wasd to move center-of-view
if key == ord('d'):
cov[0] += camera_spd;
if key == ord('a'):
cov[0] -= camera_spd;
if key == ord('w'):
cov[1] -= camera_spd;
if key == ord('s'):
cov[1] += camera_spd;
# z,x to decrease/increase zoom (lower bound is 1.0)
if key == ord('x'):
scale += scale_step;
if key == ord('z'):
scale -= scale_step;
scale = round(scale, 2);
# bound cov
boundCenter(cov, scale, hh, hw);
Edit: Explanation of the drawVec parameters
img: The OpenCV image to be drawn on
vec: A list of [x,y] points
pos: The offset to draw those points at
cov: Center-Of-View, where the middle of our zoomed display is pointed at
hh: Half-Height, the height of "img" divided by 2
hw: Half-Width, the width of "img" divided by 2
I have looked through my code and realized where I was making a mistake which caused points to be offset.
In my program, I have a canvas of specific size. The size of canvas is a constant and is always larger than images being drawn on canvas. When program draws an image on canvas it first resizes that image so it could fit on canvas. The size of resized image is somewhat smaller than size of canvas. Image is usually drawn starting from top left corner of canvas. Since I wanted to always draw image in the center of canvas, I shifted the location from top left corner of canvas to another point. This is what I didn't account when doing image zooming.
def zoom(image, ratio, points, canvas_off_x, canvas_off_y):
width, height = image.shape[:2]
new_width, new_height = int(ratio * width), int(ratio * height)
center_x, center_y = int(new_width / 2), int(new_height / 2)
radius_x, radius_y = int(width / 2), int(height / 2)
min_x, max_x = center_x - radius_x, center_x + radius_x
min_y, max_y = center_y - radius_y, center_y + radius_y
img_resized = cv2.resize(image, (new_width,new_height), interpolation=cv2.INTER_LINEAR)
img_cropped = img_resized[min_y:max_y+1, min_x:max_x+1]
for point in points:
x, y = point.get_original_coordinates()
x -= canvas_off_x
y -= canvas_off_y
x = int((x * ratio) - min_x + canvas_off_x)
y = int((y * ratio) - min_y + canvas_off_y)
point.set_scaled_coordinates(x, y)
In the code below canvas_off_x and canvas_off_y is the location of offset from top left corner of canvas

Finding the characteristics of a hand written Arrows with opencv

I'm trying to retrieve the orientation of a hand written arrows:
after removing shadows and applying binarization and dilating the lines, here are the images:
Now I'd like to get the orientation of the arrow so I have tried using HoughLines,
lines = cv2.HoughLines(edges, rho=1, theta=np.pi / 180, threshold=20)
But is seems it generates too many lines (around 54 lines), I'd like it to generate only 3 lines so I would be able to find the intersection of those lines. I can group the lines into groups of similar angle (+/-20 degrees) and then average the angle. but I'm not sure what should be rho of an average line, can somebody please give a simple example?
Is there any other approach which may be more accurate?
I'll be glad to hear, thank you all
I suggest a different approach. In summary, the approach goes as follows (made it in a hurry, might need some tuning):
Find the center of the minimum area rectangle (rotated rectangle) that encloses the whole arrow. (The circle drawn in the third image)
Find the center of gravity for all white points. It will be shifted a bit towards the actual head of the arrow. (Drawn in 4th pic as the origin of the eigenvector)
Find eigenvectors for all white points.
Find the displacement vector (the center of gravity - the center of the rotated rectangle)
Now:
Arrow angle(unoriented): is the angle of the first eigenvector
Arrow direction: is the sign of the dot product of (the first eigenvector and the centers' displacement vector)
Code:
Parts related to PCA are inspired by and mostly copied from this. I only made a minor change to the "getOrientation" method, added the following lines before it returns
angle = (angle - math.pi) * 180 / math.pi
return angle, (mean[0,0]), (mean[0,1]), p1
Code implementing the logic above:
#threshold
_, img = cv2.threshold(img, 128, 255, cv2.THRESH_OTSU)
imshow(img)
#close the image to make sure the contour is connected)
st_el = cv2.getStructuringElement(cv2.MORPH_RECT, (5, 5))
img = cv2.morphologyEx(img, cv2.MORPH_CLOSE, st_el)
imshow(img)
#get white points
pnts = cv2.findNonZero(img)
#min area rect
rect_center = cv2.minAreaRect(pnts)[0]
#draw rect center
cv2.circle(img, (int(rect_center[0]), int(rect_center[1])), 3, 128, -1)
imshow(img)
angle, pca_center, eigen_vec = getOrientation(pnts, img)
cc_vec = (rect_center[0] - pca_center[0], rect_center[1] - pca_center[1])
dot_product = cc_vec[0] * eigen_vec[0] + cc_vec[1] * eigen_vec[1]
if dot_product > 0:
angle *= -1
print ("Angle = ", angle)
imshow(img)
Edit
I suggest a simpler method. This new method does not depend on PCA for finding the unoriented angle [0 - 180]. Instead, uses the min area rectangle angle immediately. And uses the contour momentum for finding the center of gravity.
Simpler Method Code:
#get white points
pnts = cv2.findNonZero(img)
#min area rect
rect_center, size, angle = cv2.minAreaRect(pnts)
#simple fix for angle to make it in [0, 180]
angle = abs(angle)
if size[0] < size[1]:
angle += 90
#find center of gravity
M = cv2.moments(img)
gravity_center = (M["m10"] / M["m00"], M["m01"] / M["m00"])
#rot rect vec based on angle
angle_unit_vec = (math.cos(angle * 180 / math.pi), math.sin(angle * 180 / math.pi))
#cc_vec = gravity center - rect center
cc_vec = (gravity_center[0] - rect_center[0], gravity_center[1] - rect_center[1])
#if dot product is negative add 180 -> angle between [0, 360]
dot_product = cc_vec[0] * angle_unit_vec[0] + cc_vec[1] * angle_unit_vec[1]
angle += (dot_product < 0) * 180
#draw rect center
cv2.circle(img, (int(rect_center[0]), int(rect_center[1])), 3, 128, -1)
cv2.circle(img, (int(gravity_center[0]), int(gravity_center[1])), 3, 20, -1)
imshow(img)
print ("Angle = ", angle)
Edit2:
This edit includes these changes:
Use cv2.fitLine() and use the fitted line angle for orientation.
Replace angle_unit_vec with a vector that has the gravity center as the origin and goes parallel to the fitted line.
Code
#get white points
pnts = cv2.findNonZero(img)
#min area rect
rect_center, size, angle = cv2.minAreaRect(pnts)
#fit line to get angle
[vx, vy, x, y] =cv2.fitLine(pnts, cv2.DIST_L12, 0, 0.01, 0.01)
angle = (math.atan2(vy, -vx)) * 180 / math.pi
M = cv2.moments(img)
gravity_center = (M["m10"] / M["m00"], M["m01"] / M["m00"])
angle_vec = (int(gravity_center[0] + 100 * vx), int(gravity_center[1] + 100 * vy))
#cc_vec = gravity center - rect center
cc_vec = (gravity_center[0] - rect_center[0], gravity_center[1] - rect_center[1])
#if dot product is positive add 180 -> angle between [0, 360]
dot_product = cc_vec[0] * angle_vec[0] + cc_vec[1] * angle_vec[1]
angle += (dot_product > 0) * 180
angle += (angle < 0) * 360
#draw rect center
cv2.circle(img, (int(rect_center[0]), int(rect_center[1])), 3, 128, -1)
cv2.circle(img, (int(gravity_center[0]), int(gravity_center[1])), 3, 20, -1)
imshow(img)
print ("Angle = ", angle)
Output:
Using code from edit2:
First image:
Second image:
Third image:

Turtle inner circle boundary in python

Okay, I've been at this all day and haven't a clue. I need to get my turtle object to draw random lines outside of a circle.
I've made code that restricts the random lines within the boundaries before, so I thought all I had to do was change the sign, but that didn't work. I'm not allowed to use coordinate geometry - it has to be something more basic...
Here's my code in it's current format:
import turtle, random
mRoshi = turtle.Turtle()
def draw_any_shape(myTurtle, sideLength, numSides):
turnAng = 360/numSides
for i in range(numSides):
myTurtle.forward(sideLength)
myTurtle.right(turnAng)
def drawCircle(myTurtle, radius, startX, startY):
circumference = 2*3.1415*radius
sideLength = circumference/360
myTurtle.penup()
myTurtle.goto(startX, startY)
#myTurtle.dot()
myTurtle.goto(startX, startY+radius)
myTurtle.pendown()
draw_any_shape(myTurtle, sideLength, 360)
def stumblingTurtle(myTurtle, radius, startX, startY, paramN5):
circumference = 2*3.1415*radius
myTurtle.speed(6)
drawCircle(myTurtle, radius, startX, startY)
myTurtle.penup()
for i in range(paramN5):
drx = random.randint(-800, 800)
drw = random.randint(-800, 800)
if (drx**2 + drw**2) > radius**2:
myTurtle.goto(drx,drw)
crx = random.randint(-800, 800)
crw = random.randint(-800, 800)
xdif = crx-drx
ydif = crw-drw
for j in range(drx, crx):
for k in range(drw, crw):
if (xdif**2 + ydif**2) > radius**2:
myTurtle.goto(crx,crw)
Does this do what you want? It's also based on code that originally kept the turtle within a circle. It uses Python3 turtle's undo capability to allow the turtle to accidentally wander into the circle and then undo that accident as if it never happened:
import turtle
import random
RADIUS = 50
MAXIMUM_TURN = 45
STEP_SIZE = 10
BORDER = 20
def bounded_random_move():
yertle.forward(STEP_SIZE)
x, y = yertle.position()
if (x * x + y * y) < RADIUS * RADIUS or x < -window_width/2 or x > window_width/2 or y < -window_height/2 or y > window_height/2:
yertle.undo() # undo misstep
turn = random.randint(180 - MAXIMUM_TURN, 180 + MAXIMUM_TURN)
yertle.left(turn)
turtle.ontimer(bounded_random_move, 100)
turtle.setup(RADIUS * 10, RADIUS * 10)
window_width = turtle.window_width() - BORDER
window_height = turtle.window_height() - BORDER
magic_marker = turtle.Turtle(visible=False)
magic_marker.penup()
magic_marker.color("red")
magic_marker.sety(-RADIUS)
magic_marker.pendown()
magic_marker.circle(RADIUS)
yertle = turtle.Turtle(shape="turtle", visible=False)
yertle.speed("fastest")
yertle.penup()
yertle.goto(RADIUS * 2, RADIUS * 2) # start outside circle
yertle.pendown()
yertle.showturtle()
turtle.ontimer(bounded_random_move, 100)
turtle.exitonclick()
My undo trick might not be rigorous enough for everyone, however.

SVG marker on Highcharts path

I want to draw arrows on my Highcharts chart and came up with this so far. Looks nice but has problems:
higher stroke-width gives a longer arrow.
rotating the arrow will require complicated calculation like here.
If I could use a SVG marker on a Highcharts path like in this SVG tutorial drawing arrows would become much easier
My code:
renderer.path(['M', 200, 0, 'L', 200, 200,'L', 225, 200,'L',200,250,'L', 175, 200,'L', 200, 200])
.attr({
'stroke-width': 5,
stroke: 'red',fill:'red'
})
.add();
renderer.path(['M', 400, 0, 'L', 400, 200,'L', 425, 200,'L',400,250,'L', 375, 200,'L', 400, 200])
.attr({
'stroke-width': 50,
stroke: 'red',fill:'red'
})
.add();
I managed to draw arrows without using SVG marker. The arrow points exactly to the right spot, regardless of the rotation. It can even take into account the radius of the start and end point.
See fiddle
function drawArrow(startX, startY, startRadius, endX, endY, endRadius, width) {
var angle = Math.PI + Math.atan((endX - startX) / (endY - startY)),
arrowLength = 3 * width,
arrowWidth = 1.5 * width,
path = [],
startArrowX,
startArrowY,
margin = 5;
if (endY >= startY) {
//correct for circle radius
startX -= ((startRadius + margin) * Math.sin(angle));
startY -= ((startRadius + margin) * Math.cos(angle));
endX += ((endRadius + margin) * Math.sin(angle));
endY += ((endRadius + margin) * Math.cos(angle));
//correct for arrow head length
endX += (arrowLength * Math.sin(angle));
endY += (arrowLength * Math.cos(angle));
//draw arrow head
path.push('M', endX, endY);
path.push(
'L',
endX - arrowWidth * Math.cos(angle),
endY + arrowWidth * Math.sin(angle));
path.push(
endX - arrowLength * Math.sin(angle),
endY - arrowLength * Math.cos(angle));
path.push(
endX + arrowWidth * Math.cos(angle),
endY - arrowWidth * Math.sin(angle), 'Z');
} else {
//correct for circle radius
startX += ((startRadius + margin) * Math.sin(angle));
startY += ((startRadius + margin) * Math.cos(angle));
endX -= ((endRadius + margin) * Math.sin(angle));
endY -= ((endRadius + margin) * Math.cos(angle));
//correct for arrow head length
endX -= (arrowLength * Math.sin(angle));
endY -= (arrowLength * Math.cos(angle));
//draw arrow head
path.push('M', endX, endY);
path.push(
'L',
endX + arrowWidth * Math.cos(angle),
endY - arrowWidth * Math.sin(angle));
path.push(
endX + arrowLength * Math.sin(angle),
endY + arrowLength * Math.cos(angle));
path.push(
endX - arrowWidth * Math.cos(angle),
endY + arrowWidth * Math.sin(angle), 'Z');
}
renderer.path(path)
.attr({
'stroke-width': 1,
stroke: '#989898',
fill: '#989898'
}).add();
renderer.path(['M', startX, startY, 'L', endX, endY])
.attr({
'stroke-width': width,
stroke: '#989898'
}).add();

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