Splitting string involving parenthesis, whilst retaining the parenthesis - python-3.x

Question

I have a column named Roles in a df, that has values like the below :
ABCD (Actor), XYZ (Actor, Director), PQR (Producer, Writer)
I want to split this string, such that i get a value containing lists of each individual
So the output should be:
[[ABCD (Actor)], [XYZ (Actor, Director)], [PQR (Producer, Writer)]]
I am trying to use the below, however what happens is the ) gets cut and i end up with the string without the ) in the output
df['Role_Split'] = df['Roles'].str.split("\), ")
results in
['ABCD (Actor, XYZ (Actor, Director, PQR (Producer, Writer)']
Further, my plan was to create new columns, each for Actor, Director, Producer, etc
And populate those columns if the list element contains the string "Actor" or "Director" or "Producer" etc
Can you advise if there is a easier way to do this?
So the final output
Some more columns Roles Role_Split Actor Other Roles
ABCD (Actor), XYZ (Actor, Director), PQR (Producer, Writer) [[ABCD (Actor)], [XYZ (Actor, Director)], [PQR (Producer, Writer)]] ABCD, XYZ XYZ, PQR

Answer 1

Looks like you can use str.findall
Ex:
df = pd.DataFrame({"Roles":['ABCD (Actor), XYZ (Actor, Director), PQR (Producer, Writer)']})
df['Role_Split'] = df['Roles'].str.findall(r"(\w+ \(.*?\))")
print(df['Role_Split']) # print(df['Role_Split'][0]
Output:
['ABCD (Actor)', 'XYZ (Actor, Director)', 'PQR (Producer, Writer)']
Edit as per comment
df = pd.DataFrame({"Roles":['ABCD Walters Sr (Actor), XYZ PQR AB (Lead Role, Producer, Director)']})
df['Role_Split'] = df['Roles'].str.findall(r"([\w\s]+ \(.*?\))")
print(df['Role_Split'][0])
# ->['ABCD Walters Sr (Actor)', ' XYZ PQR AB (Lead Role, Producer, Director)']
Use str.extractall with named regex groups
Ex:
df2 = df['Roles'].str.extractall(r"(?P<Actor>[\w\s]+) (?P<roles>\(.*?\))")
print(df2)
Output:
Actor roles
match
0 0 ABCD Walters Sr (Actor)
1 XYZ PQR AB (Lead Role, Producer, Director)

Answer 2

Using a regular expression with a look-behind for a bracket:
(?<=\)),\s+
It splits on the comma and any following space (requiring at least one forward space) where that comma is after a closing bracket.
s = 'ABCD (Actor), XYZ (Actor, Director), PQR (Producer, Writer)'
pd.Series([s]).str.split(r'(?<=\)),\s+', expand=True)
Yields output like so:
Out[5]:
0 1 2
0 ABCD (Actor) XYZ (Actor, Director) PQR (Producer, Writer)
Note that pd.Series.str.split takes a regular expression input directly. If you want to place it into different columns, pass expand=True to your s.str.split(pattern) call; otherwise, if desiring a lists in each series cell, don't pass that parameter.