I am making a word guesser for discord, and I have stumbled upon a problem I can not figure out. Full code here.
I have a keyword, a counter, and a wordhelp list. I am calling a function every x seconds, which will add a letter to the wordhelp list, from the keyword, based on the counter.
My question is: How can I start with the wordhelp list being dots for len(keyword), and then replace each dot with it's corresponding letter in the function.
I have tried something like this: wordhelp[counter] = keyword[counter] but that gives me this list assignment index out of range, because there is no dots in the wordhelp list to be replaced.
def __init__(self, bot):
self.bot.counter = 0
self.bot.keyword = ""
self.bot.wordhelp = []
# Called every 60 seconds
#tasks.loop(seconds=60)
async def loop_update(self):
# Add the new letter to the wordhelp list
self.bot.wordhelp[self.bot.counter] = self.bot.keyword[self.bot.counter]
# Edit the ini variable embed to show new keyword letter
await self.bot.ini.edit(embed=discord.Embed(title="Guessing game started!", description=f"Find the keyword starting with:\n`{''.join(self.bot.wordhelp)}`"))
self.bot.counter += 1
Instead of keeping an explicit list of dots, you can just keep a count of how many letters you want to 'reveal', and then create the display dynamically based on that. Something like this:
def hidden_word(word, reveal=0):
hidden = len(word) - reveal
dots = '.' * hidden
return word[:reveal] + dots
Now you can just feed it the count of how many letters to reveal:
word = 'giraffe'
for i in range(len(word)+1):
print(hidden_word(word, reveal=i))
# Produces:
.......
g......
gi.....
gir....
gira...
giraf..
giraff.
giraffe
Related
Just quick side question. Is there a way and if, how to remove/delete a specific word from a bigram in a list (must be the same list!) that also contains just words. E.g.
In:
x = ['Peter Parker', 'Hugo', 'Fischerman']
Task, delete Parker from that same list:
Expected output:
x as ['Peter', 'Hugo', 'Fischerman']
I tried to use xx = [x.replace('Parker, '') for x in xx]but it seems to give me a new list in the sack.
Any ideas?
list = ['Peter Parker', 'Hugo', 'Fischerman'] # initialize list
for item in range(len(list)): # loop
list[item] = list[item].replace("Parker", "").strip() # replace item nu=umber "item" with its fixed result, replacing "Parker" with nothing and stripping - this just does nothing if "Parker" is not in item number "item".
That should work, just omit the list initialization to add it wherever (and don't forget to fix the variable names!)
I have just started learning python and i have been given an assignment to create a list of players and stats using different loops.
I cant work out how to create a function that searches the player list and gives an output of the players name and the players stat.
Here is the assignment:
Create an empty list called players
Use two input() statements inside a for loop to collect the name
and performance of each player (the name will be in the form of a
string and the performance as an integer from 0 – 100.) Add both
pieces of information to the list (so in the first iteration of the
loop players[0] will contain the name of the first player and
players[1] will contain their performance.) You are not required to
validate this data.
Use a while loop to display all the player information in the
following form:
Player : Performance
Use a loop type of your choice to copy the performance values from
the players list and store these items in a new list called results
Write a function that accepts the values “max” or “min” and
returns the maximum or minimum values from the results list
Write a function called find_player() that accepts a player name
and displays their name and performance from the players list, or an
error message if the player is not found.
Here is what I have so far:
print ("Enter 11 Player names and stats")
# Create player list
playerlist = []
# Create results list
results = []
# for loop setting amount of players and collecting input/appending list
for i in range(11):
player = (input("Player name: "))
playerlist.append(player)
stats = int(input("Player stats: "))
playerlist.append(stats)
# While loop printing player list
whileLoop = True
while whileLoop == True:
print (playerlist)
break
# for loop append results list, [start:stop:step]
for i in range(11):
results.append(playerlist[1::2])
break
# max in a custom function
def getMax(results):
results = (playerlist[1::2])
return max(results)
print ("Max Stat",getMax(results))
# custom function to find player
def find_player(playerlist):
list = playerlist
name = str(input("Search keyword: "))
return (name)
for s in list:
if name in str(s):
return (s)
print (find_player(playerlist))
I have tried many different ways to create the find player function without success.
I think I am having problems because my list consists of strings and integers eg. ['john', 6, 'bill', 8]
I would like it to display the player that was searched for and the stats ['John', 6]
Any help would be greatly appreciated.
PS:
I know there is no need for all these loops but that is what the assignment seems to be asking for.
Thank you
I cut down on the fat and made a "dummy list", but your find_player function seems to work well, once you remove the first return statement! Once you return something, the function just ends.
All it needs is to also display the performance like so:
# Create player list
playerlist = ["a", 1, "b", 2, "c", 3]
# custom function to find player
def find_player(playerlist):
name = str(input("Search keyword: "))
searchIndex = 0
for s in playerlist:
try:
if name == str(s):
return ("Player: '%s' with performance %d" % (name, playerlist[searchIndex+1]))
except Exception as e:
print(e)
searchIndex += 1
print (find_player(playerlist))
>>Search keyword: a
>>Player: 'a' with performance 1
I also added a try/except in case something goes wrong.
Also: NEVER USE "LIST" AS A VARIABLE NAME!
Besides, you already have an internal name for it, so why assign it another name. You can just use playerlist inside the function.
Your code didn't work because you typed a key and immediately returned it. In order for the code to work, you must use the key to find the value. In this task, it is in the format of '' key1 ', value1,' key2 ', value2, ...]. In the function, index is a variable that stores the position of the key. And it finds the position of key through loop. It then returns list [index + 1] to return the value corresponding to the key.
playerlist = []
def find_player(playerlist):
list = playerlist
name = str(input("Search keyword: "))
index = 0
for s in list:
if name == str(s):
return ("This keyword's value: %d" % (list[index+1]))
index+=1
print (find_player(playerlist))
Starting out by saying this is for school and I'm still learning so I'm not looking for a direct solution.
What I want to do is take an input from a user (one word or more).
I then make it in to a list.
I have my dictionary and the code that I'm posting is printing out the values correctly.
My question is how do I compare the characters in my list to the keys in the dictionary and then print only those values that correspond to the keys?
I have also read a ton of different questions regarding dictionaries but it was no help at all.
Example on output;
Word: wow
Output: 96669
user_word = input("Please enter a word: ")
user_listed = list(user_word)
def keypresses():
my_dict = {'.':1, ',':11, '?':111, '!':1111, ':':11111, 'a':2, 'b':22, 'c':222, 'd':3, 'e':33, 'f':333, 'g':4, 'h':44,
'i':444, 'j':5, 'k':55, 'l':555, 'm':6, 'n':66, 'o':666, 'p':7, 'q':77, 'r':777, 's':7777, 't':8, 'u':88,
'v':888, 'w':9, 'x':99, 'y':999, 'z':9999, ' ':0}
for key, value in my_dict.items():
print(value)
I am not going to hand you code for the project, but I will definitely send you in a right direction;
so, 2 parts to this in my view; match each character to a key/get a value, and combine the numbers for an output.
For the first part, you can iterate character-by-character by simply making a for loop;
for letter in 'string':
print(letter)
would output s t r i n g. So you can use this to find the value of the key(each letter)
Then, you can get the definition as a string(so as not to add each number mathematically) so something like;
letter = 'w'
value = my_dict[letter]
value_as_string = str(value)
then, combine this all into a for loop and add each string to each other to create the desired output.
I have a homework question which asks:
Write a function print_word_counts(filename) that takes the name of a
file as a parameter and prints an alphabetically ordered list of all
words in the document converted to lower case plus their occurrence
counts (this is how many times each word appears in the file).
I am able to get an out of order set of each word with it's occurrence; however when I sort it and make it so each word is on a new line the count disappears.
import re
def print_word_counts(filename):
input_file = open(filename, 'r')
source_string = input_file.read().lower()
input_file.close()
words = re.findall('[a-zA-Z]+', source_string)
counts = {}
for word in words:
counts[word] = counts.get(word, 0) + 1
sorted_count = sorted(counts)
print("\n".join(sorted_count))
When I run this code I get:
a
aborigines
absence
absolutely
accept
after
and so on.
What I need is:
a: 4
aborigines: 1
absence: 1
absolutely: 1
accept: 1
after: 1
I'm not sure how to sort it and keep the values.
It's a homework question, so I can't give you the full answer, but here's enough to get you started. Your mistake is in this line
sorted_count = sorted(counts)
Firstly, you cant sort a dictionary by nature. Secondly, what this does is take the keys of the dictionary, sorts them, and returns a list.
You can just print the value of counts, or, if you really need them in sorted order, consider changing the dictionary items into a list, then sorting them.
lst = list(count.items())
#sort and return lst
Hi so I am trying to write a function, classify(csv_file) that creates a default dictionary of dictionaries from a csv file. The first "column" (first item in each row) is the key for each entry in the dictionary and then second "column" (second item in each row) will contain the values.
However, I want to alter the values by calling on two functions (in this order):
trigram_c(string): that creates a default dictionary of trigram counts within the string (which are the values)
normal(tri_counts): that takes the output of trigram_c and normalises the counts (i.e converts the counts for each trigram into a number).
Thus, my final output will be a dictionary of dictionaries:
{value: {trigram1 : normalised_count, trigram2: normalised_count}, value2: {trigram1: normalised_count...}...} and so on
My current code looks like this:
def classify(csv_file):
l_rows = list(csv.reader(open(csv_file)))
classified = dict((l_rows[0], l_rows[1]) for rows in l_rows)
For example, if the csv file was:
Snippet1, "It was a dark stormy day"
Snippet2, "Hello world!"
Snippet3, "How are you?"
The final output would resemble:
{Snippet1: {'It ': 0.5352, 't w': 0.43232}, Snippet2: {'Hel' : 0.438724,...}...} and so on.
(Of course there would be more than just two trigram counts, and the numbers are just random for the purpose of the example).
Any help would be much appreciated!
First of all, please check classify function, because I can't run it. Here corrected version:
import csv
def classify(csv_file):
l_rows = list(csv.reader(open(csv_file)))
classified = dict((row[0], row[1]) for row in l_rows)
return classified
It returns dictionary with key from first column and value is string from second column.
So you should iterate every dictionary entry and pass its value to trigram_c function. I didn't understand how you calculated trigram counts, but for example if you just count the number of trigram appearence in string you could use the function below. If you want make other counting you just need to update code in the for loop.
def trigram_c(string):
trigram_dict = {}
start = 0
end = 3
for i in range(len(string)-2):
# you could implement your logic in this loop
trigram = string[start:end]
if trigram in trigram_dict.keys():
trigram_dict[trigram] += 1
else:
trigram_dict[trigram] = 1
start += 1
end += 1
return trigram_dict