i'm pretty new to Sequelize. I have a scenario in which I want to retrieve records from the DB with filters on the desired model records and his related records. I need to find records that answer the query with properties on the "main" model OR records that answer the query on the related field.
let customers = await db.customers.findAll({
where: {
location: locationId,
some_kind_of_string_identifier: someKindOfStringIdentifier
},
include: [
{
model: db.users,
where: db.sequelize.where(
db.sequelize.fn(
'concat',
db.sequelize.col('first_name'),
' ',
db.sequelize.col('last_name'),
),
db.sequelize.Op.like,
`%${query}%`,
),
},
],
});
So in the example above I have a free text search query (query variable), and I want to get all customers with name like query OR that has "someKindOfStringIdentifier" which matches query.
Is there a way to do so?
I'd try the following:
customers.findAll({
where: {
$and: [{ location: locationId },
{ $or: [{ some_kind_of_string_identifier: someKindOfStringIdentifier },
Sequelize.where(
Sequelize.fn('concat',
Sequelize.col('$db.users.first_name$'), ' ', Sequelize.col('$db.users.last_name$')),
{ like: '%' + query + '%' }
)]
}]
},
include: [{
model: db.users,
required: false
}]
});
Ref: https://stackoverflow.com/a/36287978/5430833, Sequelize: Concat fields in WHERE LIKE clause
Right now, you are effectively doing the WHERE when doing a join. This is not what you want. You want to JOIN both tables (customers and users) and then apply WHERE with your or condition, right?
Above code is untested, but I believe you've got to apply condition in findAll, not the include.
Related
I have a table of book users and a table of movie users. I'm trying to return a list of the top 100 movie viewers, along with their book profile information. I want to join on ids, but I can't seem to find the right syntax.
This is what I've tried:
const mostActiveMovieWatchers = await MovieWatchers.findAll({
order: [
['moviesWatched', 'DESC'],
],
limit: '100',
include: [{
model: BookReaders,
where: {
userId: '$MovieWatchers.id$'
},
required: true
}]
});
I've also seen examples where the where clause looks something like this where: ['userId = id']
Before join tables you need create association:
BookReaders.hasMany(MovieWatchers, { foreignKey: 'bookId' });
MovieWatchers.belongsTo(BookReaders, { foreignKey: 'bookId' });
Then, you can use the include option in a find or findAll method call on the MovieWatchers model to specify that you want to include the associated BookReaders data:
MovieWatchers.findAll({
include: [
{
model: BookReaders,
},
],
}).then((movies) => {
// array of movies including books
});
I have an array=[1,2,3]
Only 1 & 2 are in the database under the column ID.
When I perform a query using WHERE IN it gives me result of 1 & 2.
What I want to do is if all data matches then show me the result otherwise null
I am using Sequelize. How can this be done?
Query:
Models.Question.findOne({
where: {
id:1
},
include: [{
model: Models.QuestionOptions,
as: 'options',
required: true,
where: {
id:[1,2,3]
}
}]
});
expect result Null because only 1 & 2 are in DB
require:true means INNER JOIN. In other words it will only return lines with existing associations(If the condition is also true of course). You should remove it if you want to get all lines(Left Join) even if there is no corresponding association
You can achieve this using group and having clause.
Models.Question.findOne({
attributes: ["id"],
where: {
id:1
},
group: ['id'],
having: sequelize.where(sequelize.fn('count', sequelize.col('options.id')), {
[sequelize.Op.gte]: 3,
}),
include: [{
model: Models.QuestionOptions,
as: 'options',
attributes: [],
required: true,
where: {
id:[1,2,3]
}
}]
});
I have two models with a one to many relation. Given that below query returns a record of ModelA (lets say it has id 1) with 3 associated ModelB (1, 2 and 3).
If I were to replace [1,2,3] in the query to just [1] it would still return the same ModelA record (with id 1) but only with the one associated ModelB (of id 1). How can I modify this query so it returns all three associated ModelB records?
ModelA.findAll({
include: [{
model: JoinTableModel,
where: {
modelB_ID: {
[Op.in]: [1,2,3]
}
},
include: [ModelB]
}]
})
Model definitions like so.
db.ModelA.hasMany(db.JoinTableModel, { foreignKey: 'modelA_ID' })
db.JoinTableModel.belongsTo(db.ModelA, { foreignKey: 'modelA_ID' })
db.ModelB.hasMany(db.JoinTableModel, { foreignKey: 'modelB_ID' })
db.JoinTableModel.belongsTo(db.ModelB, { foreignKey: 'modelB_ID' })
You can try something like this:
JoinTableModel.findAll({
where: {
modelB_ID: {
[Op.in]: [1]
}
},
include: [{
model: ModelA,
include: [{
model: JoinTableModel,
include: [ModelB]
}]
}]
})
If you add an association like this:
ModelA.belongsToMany(ModelB, { through: JoinTableModel })
then you can simplify the above query to this one:
JoinTableModel.findAll({
where: {
modelB_ID: {
[Op.in]: [1]
}
},
include: [{
model: ModelA,
include: [ModelB]
}]
})
For anyone with a similar issue as me, what I ended up doing that works for my case is modifying my initial query like this.
ModelA.findAll({
where: {
id: sequelize.literal(`
ModelA.id
IN (
SELECT modelA_ID FROM JoinTableModel
WHERE modelB_ID IN (1,2,3)
GROUP BY modelA_ID
HAVING COUNT(*) = 3
)`)
},
include: [{
model: JoinTableModel,
include: [ModelB]
}]
})
This way I could easily replace IN (1,2,3) and COUNT(*) 3 with IN (1) and COUNT(*) 1 and it would still work as intended and it doesn't break any other part of the query.
I'm still curious if anyone could solve this without using sequelize.literal in any way or if there is a more efficient way of doing it.
With Sequelize, I have two models with many to many association : User and Category.
I want to get all categories that belongs to the current user, and also categories with a certain property, but I don't understand how, with only one query...
I'm using the Op.or operator, according to the documentation, and the $Model.attribute$ syntax for associated model (seen here).
let categories = await models.category.findAll({
where: {
[Op.or]: [
{ someCategoryProperty: true },
{ '$User.id$': req.currentUser.id },
],
},
include: [{
model: models.user,
as: 'User',
}],
});
The operator works if I add 2 conditions about the Category model, but how to add a condition on the association ?
I finally found the tips :
Actually, $Model.attribute$ wasn't the good pattern, $database_table_name.attribute$ is the good one.
With the '$..$' syntax, we must use the database table name, and not the model.
If my model is called user, Sequelize set the database name users !
So this code works :
let categories = await models.category.findAll({
where: {
[Op.or]: [
{ someCategoryProperty: true },
{ '$users.id$': req.currentUser.id },
],
},
include: [{
model: models.user,
}],
});
Thanks
In Rails I can perform a simple ORM query for the number of Likes a model has:
#records = Model
.select( 'model.*' )
.select( 'count(likes.*) as likes_count' )
.joins( 'LEFT JOIN likes ON model.id = likes.model_id' )
.group( 'model.id' )
This generates the query:
SELECT models.*, count(likes.*) as likes_count
FROM "models" JOIN likes ON models.id = likes.model_id
GROUP BY models.id
In Node Sequelize, any attempt at doing something similar fails:
return Model.findAll({
group: [ '"Model".id' ],
attributes: ['id', [Sequelize.fn('count', Sequelize.col('"Likes".id')), 'likes_count']],
include: [{ attributes: [], model: Like }],
});
This generates the query:
SELECT
Model.id,
count(Likes.id) AS likes_count,
Likes.id AS Likes.id # Bad!
FROM Models AS Model
LEFT OUTER JOIN Likes
AS Likes
ON Model.id = Likes.model_id
GROUP BY Model.id;
Which generates the error:
column "Likes.id" must appear in the GROUP BY clause or be used in an aggregate function
It's erroneously selecting likes.id, and I have no idea why, nor how to get rid of it.
This sequelize github issue looks totally like your case:
User.findAll({
attributes: ['User.*', 'Post.*', [sequelize.fn('COUNT', 'Post.id'), 'PostCount']],
include: [Post]
});
To resolve this problem we Need to upgrade to latest version of sequelize and include raw = true,
Here is How I had done after lot of iteration and off-course googling.
getUserProjectCount: function (req, res) {
Project.findAll(
{
attributes: ['User.username', [sequelize.fn('COUNT', sequelize.col('Project.id')), 'ProjectCount']],
include: [
{
model: User,
attributes: [],
include: []
}
],
group: ['User.username'],
raw:true
}
).then(function (projects) {
res.send(projects);
});
}
where my reference models are
//user
var User = sequelize.define("User", {
username: Sequelize.STRING,
password: Sequelize.STRING
});
//project
var Project = sequelize.define("Project", {
name: Sequelize.STRING,
UserId:{
type:Sequelize.INTEGER,
references: {
model: User,
key: "id"
}
}
});
Project.belongsTo(User);
User.hasMany(Project);
after migration ORM create 'Users' & 'Projects' table into my postgres server.
Here is SQL Query by ORM
SELECT
"User"."username", COUNT("Project"."id") AS "ProjectCount"
FROM
"Projects" AS "Project"
LEFT OUTER JOIN "Users" AS "User" ON "Project"."UserId" = "User"."id"
GROUP BY
"User"."username";
What worked for me counting column A and grouping by column B
const noListingsPerRetailer = Listing.findAll({
attributes: [
'columnA',
[sequelize.fn('COUNT', sequelize.col('columnB')), 'labelForCountColumn'],
],
group:["columnA"]
});