How to use vtkCylinderSource to make cylinder be vertical aligned - vtk

I use python to create cylinder in vtk format
cylinder = vtk.vtkCylinderSource()
cylinder.SetRadius(4)
cylinder.SetHeight(8)
cylinder.SetCenter(0,0,0)
cylinder.SetResolution(12)
cylinder.Update()
writer = vtk.vtkPolyDataWriter()
writer.SetInputData(cylinder.GetOutput())
writer.SetFileName('cylinder.vtk')
writer.Update()
sphereMesh = pv.read('cylinder.vtk')
plotter.add_mesh(sphereMesh, color='#9C7FF1', show_edges=show_ed)
plotter.add_axes()
This a result of visualization:
How can I change it to be symetric around z not y

import vtk
cylinder = vtk.vtkCylinderSource()
cylinder.SetRadius(4)
cylinder.SetHeight(8)
cylinder.SetCenter(0,0,0)
cylinder.SetResolution(12)
cylinder.Update()
writer = vtk.vtkPolyDataWriter()
writer.SetInputData(cylinder.GetOutput())
writer.SetFileName('cylinder.vtk')
writer.Update()
# with pyvista:
import pyvista as pv
plotter = pv.Plotter()
sphereMesh = pv.read('cylinder.vtk')
sphereMesh.rotate_x(90)
plotter.add_mesh(sphereMesh, color='#9C7FF1', show_edges=1)
plotter.add_axes()
plotter.show()
# with vedo:
import vedo
# vedo.Cylinder().write('cylinder.vtk')
vedo.load('cylinder.vtk').rotateX(90).c('#9C7FF1').lw(1).show(axes=1)

Related

How could I edit my code to plot 4D contour something similar to this example in python?

Similar to many other researchers on stackoverflow who are trying to plot a contour graph out of 4D data (i.e., X,Y,Z and their corresponding value C), I am attempting to plot a 4D contour map out of my data. I have tried many of the suggested solutions in stackover flow. From all of the plots suggested this, and this were the closest to what I want but sill not quite what I need in terms of data interpretation. Here is the ideal plot example: (source)
Here is a subset of the data. I put it on the dropbox. Once this data is downloaded to the directory of the python file, the following code will work. I have modified this script from this post.
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import matplotlib.tri as mtri
#####Importing the data
df = pd.read_csv('Data_4D_plot.csv')
do_random_pt_example = False;
index_x = 0; index_y = 1; index_z = 2; index_c = 3;
list_name_variables = ['x', 'y', 'z', 'c'];
name_color_map = 'seismic';
if do_random_pt_example:
number_of_points = 200;
x = np.random.rand(number_of_points);
y = np.random.rand(number_of_points);
z = np.random.rand(number_of_points);
c = np.random.rand(number_of_points);
else:
x = df['X'].to_numpy();
y = df['Y'].to_numpy();
z = df['Z'].to_numpy();
c = df['C'].to_numpy();
#end
#-----
# We create triangles that join 3 pt at a time and where their colors will be
# determined by the values of their 4th dimension. Each triangle contains 3
# indexes corresponding to the line number of the points to be grouped.
# Therefore, different methods can be used to define the value that
# will represent the 3 grouped points and I put some examples.
triangles = mtri.Triangulation(x, y).triangles;
choice_calcuation_colors = 2;
if choice_calcuation_colors == 1: # Mean of the "c" values of the 3 pt of the triangle
colors = np.mean( [c[triangles[:,0]], c[triangles[:,1]], c[triangles[:,2]]], axis = 0);
elif choice_calcuation_colors == 2: # Mediane of the "c" values of the 3 pt of the triangle
colors = np.median( [c[triangles[:,0]], c[triangles[:,1]], c[triangles[:,2]]], axis = 0);
elif choice_calcuation_colors == 3: # Max of the "c" values of the 3 pt of the triangle
colors = np.max( [c[triangles[:,0]], c[triangles[:,1]], c[triangles[:,2]]], axis = 0);
#end
#----------
###=====adjust this part for the labeling of the graph
list_name_variables[index_x] = 'X (m)'
list_name_variables[index_y] = 'Y (m)'
list_name_variables[index_z] = 'Z (m)'
list_name_variables[index_c] = 'C values'
# Displays the 4D graphic.
fig = plt.figure(figsize = (15,15));
ax = fig.gca(projection='3d');
triang = mtri.Triangulation(x, y, triangles);
surf = ax.plot_trisurf(triang, z, cmap = name_color_map, shade=False, linewidth=0.2);
surf.set_array(colors); surf.autoscale();
#Add a color bar with a title to explain which variable is represented by the color.
cbar = fig.colorbar(surf, shrink=0.5, aspect=5);
cbar.ax.get_yaxis().labelpad = 15; cbar.ax.set_ylabel(list_name_variables[index_c], rotation = 270);
# Add titles to the axes and a title in the figure.
ax.set_xlabel(list_name_variables[index_x]); ax.set_ylabel(list_name_variables[index_y]);
ax.set_zlabel(list_name_variables[index_z]);
ax.view_init(elev=15., azim=45)
plt.show()
Here would be the output:
Although it looks brilliant, it is not quite what I am looking for (the above contour map example). I have modified the following script from this post in the hope to reach the required graph, however, the chart looks nothing similar to what I was expecting (something similar to the previous output graph). Warning: the following code may take some time to run.
import matplotlib
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
df = pd.read_csv('Data_4D_plot.csv')
x = df['X'].to_numpy();
y = df['Y'].to_numpy();
z = df['Z'].to_numpy();
cc = df['C'].to_numpy();
# convert to 2d matrices
Z = np.outer(z.T, z)
X, Y = np.meshgrid(x, y)
C = np.outer(cc.T,cc)
# fourth dimention - colormap
# create colormap according to cc-value
color_dimension = C # change to desired fourth dimension
minn, maxx = color_dimension.min(), color_dimension.max()
norm = matplotlib.colors.Normalize(minn, maxx)
m = plt.cm.ScalarMappable(norm=norm, cmap='jet')
m.set_array([])
fcolors = m.to_rgba(color_dimension)
# plot
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.plot_surface(X,Y,Z, rstride=1, cstride=1, facecolors=fcolors, vmin=minn, vmax=maxx, shade=False)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_zlabel('z')
plt.show()
Now I was wondering from our kind community and experts if you can help me to plot a contour figure similar to the example graph (image one in this post), where the contours are based on the values within the range of C?

How to translate hexagon matplotlib plot to an interactive bokeh plot?

I have been working with the excellent minisom package and want to plot interactively the hexagonal map that reflects the results of the self-organising maps training process. There's already a code example that does this statically using matplotlib but to do so interactively, I would like to use bokeh. This is where I am struggling.
This is the code to generate a simplified matplotlib example of what's already on the package page:
from minisom import MiniSom
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.patches import RegularPolygon
from matplotlib import cm
from bokeh.plotting import figure
from bokeh.io import save, show, output_file, output_notebook
output_notebook()
data = pd.read_csv('https://archive.ics.uci.edu/ml/machine-learning-databases/00236/seeds_dataset.txt',
names=['area', 'perimeter', 'compactness', 'length_kernel', 'width_kernel',
'asymmetry_coefficient', 'length_kernel_groove', 'target'], sep='\t+')
t = data['target'].values
data = data[data.columns[:-1]]
# data normalisation
data = (data - np.mean(data, axis=0)) / np.std(data, axis=0)
data = data.values
# initialisation and training
som = MiniSom(15, 15, data.shape[1], sigma=1.5, learning_rate=.7, activation_distance='euclidean',
topology='hexagonal', neighborhood_function='gaussian', random_seed=10)
som.train(data, 1000, verbose=True)
# plot hexagonal topology
f = plt.figure(figsize=(10,10))
ax = f.add_subplot(111)
ax.set_aspect('equal')
xx, yy = som.get_euclidean_coordinates()
umatrix = som.distance_map()
weights = som.get_weights()
for i in range(weights.shape[0]):
for j in range(weights.shape[1]):
wy = yy[(i, j)]*2/np.sqrt(3)*3/4
hex = RegularPolygon((xx[(i, j)], wy), numVertices=6, radius=.95/np.sqrt(3),
facecolor=cm.Blues(umatrix[i, j]), alpha=.4, edgecolor='gray')
ax.add_patch(hex)
for x in data:
w = som.winner(x)
# place a marker on the winning position for the sample xx
wx, wy = som.convert_map_to_euclidean(w)
wy = wy * 2 / np.sqrt(3) * 3 / 4
plt.plot(wx, wy, markerfacecolor='None',
markeredgecolor='black', markersize=12, markeredgewidth=2)
plt.show()
matplotlib hexagonal topology plot
I've tried to translate the code into bokeh but the resulting hex plot (to me, primitively) looks like it needs to be flipped vertically onto the points and for the skew to be straightened out.
tile_centres_column = []
tile_centres_row = []
colours = []
for i in range(weights.shape[0]):
for j in range(weights.shape[1]):
wy = yy[(i, j)] * 2 / np.sqrt(3) * 3 / 4
tile_centres_column.append(xx[(i, j)])
tile_centres_row.append(wy)
colours.append(cm.Blues(umatrix[i, j]))
weight_x = []
weight_y = []
for x in data:
w = som.winner(x)
wx, wy = som.convert_map_to_euclidean(xy=w)
wy = wy * 2 / np.sqrt(3) * 3/4
weight_x.append(wx)
weight_y.append(wy)
# plot hexagonal topology
plot = figure(plot_width=800, plot_height=800,
match_aspect=True)
plot.hex_tile(q=tile_centres_column, r=tile_centres_row,
size=.95 / np.sqrt(3),
color=colours,
fill_alpha=.4,
line_color='black')
plot.dot(x=weight_x, y=weight_y,
fill_color='black',
size=12)
show(plot)
bokeh hexagonal topology plot
How can I translate this into a bokeh plot?
Found out how to do it after reaching out to the minisom package author for help. Complete code available here.
from bokeh.colors import RGB
from bokeh.io import curdoc, show, output_notebook
from bokeh.transform import factor_mark, factor_cmap
from bokeh.models import ColumnDataSource, HoverTool
from bokeh.plotting import figure, output_file
hex_centre_col, hex_centre_row = [], []
hex_colour = []
label = []
# define labels
SPECIES = ['Kama', 'Rosa', 'Canadian']
for i in range(weights.shape[0]):
for j in range(weights.shape[1]):
wy = yy[(i, j)] * 2 / np.sqrt(3) * 3 / 4
hex_centre_col.append(xx[(i, j)])
hex_centre_row.append(wy)
hex_colour.append(cm.Blues(umatrix[i, j]))
weight_x, weight_y = [], []
for cnt, i in enumerate(data):
w = som.winner(i)
wx, wy = som.convert_map_to_euclidean(xy=w)
wy = wy * 2 / np.sqrt(3) * 3 / 4
weight_x.append(wx)
weight_y.append(wy)
label.append(SPECIES[t[cnt]-1])
# convert matplotlib colour palette to bokeh colour palette
hex_plt = [(255 * np.array(i)).astype(int) for i in hex_colour]
hex_bokeh = [RGB(*tuple(rgb)).to_hex() for rgb in hex_plt]
output_file("resulting_images/som_seed_hex.html")
# initialise figure/plot
fig = figure(title="SOM: Hexagonal Topology",
plot_height=800, plot_width=800,
match_aspect=True,
tools="wheel_zoom,save,reset")
# create data stream for plotting
source_hex = ColumnDataSource(
data = dict(
x=hex_centre_col,
y=hex_centre_row,
c=hex_bokeh
)
)
source_pages = ColumnDataSource(
data=dict(
wx=weight_x,
wy=weight_y,
species=label
)
)
# define markers
MARKERS = ['diamond', 'cross', 'x']
# add shapes to plot
fig.hex(x='y', y='x', source=source_hex,
size=100 * (.95 / np.sqrt(3)),
alpha=.4,
line_color='gray',
fill_color='c')
fig.scatter(x='wy', y='wx', source=source_pages,
legend_field='species',
size=20,
marker=factor_mark(field_name='species', markers=MARKERS, factors=SPECIES),
color=factor_cmap(field_name='species', palette='Category10_3', factors=SPECIES))
# add hover-over tooltip
fig.add_tools(HoverTool(
tooltips=[
("label", '#species'),
("(x,y)", '($x, $y)')],
mode="mouse",
point_policy="follow_mouse"
))
show(fig)

Set centre of geopandas map

I can plot a world map with geopandas with:
world = geopandas.read_file(geopandas.datasets.get_path('naturalearth_lowres'))
fig, ax = plt.subplots()
world.plot(ax=ax, color=(0.8,0.5,0.5))
and it works fine, but I would like to center the map on a different longitude than the Prime Meridian. How do I do this?
This is how you can do it:
from shapely.geometry import LineString
from shapely.ops import split
from shapely.affinity import translate
import geopandas
world = geopandas.read_file(geopandas.datasets.get_path('naturalearth_lowres'))
def shift_map(shift):
shift -= 180
moved_map = []
splitted_map = []
border = LineString([(shift,90),(shift,-90)])
for row in world["geometry"]:
splitted_map.append(split(row, border))
for element in splitted_map:
items = list(element)
for item in items:
minx, miny, maxx, maxy = item.bounds
if minx >= shift:
moved_map.append(translate(item, xoff=-180-shift))
else:
moved_map.append(translate(item, xoff=180-shift))
gdf = geopandas.GeoDataFrame({"geometry":moved_map})
fig, ax = plt.subplots()
gdf.plot(ax=ax)
plt.show()
In the first step, you create your world and split it on a pre defined border of yours.
Then you get the bounds of all elements and check if the bounds match your desired shift. Afterwards you translate every element bigger than your border to the left side of the map and move all other elements to the right side, so that they aling with +180°.
This gives you for example:
A map shifted by 120°
Like in this question I needed to reset the centre of the map, but I also needed to move scatter plot network node positions that where bound to (long,lat) coordinates too.
I am hoping to save someone some time, as it's probably not obvious initially that to solve this problem you will have to wrangle some unfamiliar types.
Here is a method for shifting both the underlying map and some additional points:
import geopandas
world =
geopandas.read_file(geopandas.datasets.get_path('naturalearth_lowres'))
import matplotlib.pyplot as plt
import geopandas as gpd
from shapely.geometry import LineString
from shapely.ops import split
from shapely.affinity import translate
def shift_geom(shift, gdataframe,pos_all, plotQ=True):
# this code is adapted from answer found in SO
# will be credited here: ???
shift -= 180
moved_geom = []
splitted_geom = []
border = LineString([(shift,90),(shift,-90)])
for row in gdataframe["geometry"]:
splitted_geom.append(split(row, border))
for element in splitted_geom:
items = list(element)
for item in items:
minx, miny, maxx, maxy = item.bounds
if minx >= shift:
moved_geom.append(translate(item, xoff=-180-shift))
else:
moved_geom.append(translate(item, xoff=180-shift))
# got `moved_geom` as the moved geometry
moved_geom_gdf = gpd.GeoDataFrame({"geometry": moved_geom})
# can change crs here
if plotQ:
fig1, ax1 = plt.subplots(figsize=[8,6])
moved_geom_gdf.plot(ax=ax1)
plt.show()
df = pd.DataFrame({'Latitude': [xy[1] for xy in pos_all.values()],
'Longitude': [xy[0] for xy in pos_all.values()]})
gdf = geopandas.GeoDataFrame(df, geometry=geopandas.points_from_xy(df.Longitude, df.Latitude))
border2 = LineString([(shift,90),(shift,-90)])
geom = gdf.geometry.values
moved_map_points = []
moved_map_dict = {}
for element,key in zip(geom,list(pos_all.keys())):
if float(element.x) >= shift:
moved_map_points.append(translate(element, xoff=-180-shift))
else:
moved_map_points.append(translate(element, xoff=180-shift))
moved_map_dict[key] = (moved_map_points[-1].x,moved_map_points[-1].y)
return moved_geom_gdf,moved_map_dict
In this context pos_all are networkx node positions made of [(lat,long)]
shifted_world,moved_map_points = shift_geom(300, world,pos_all,plotQ= False)

Ploting building surfaces from CityGML data

I've been struggling with 3D ploting some coordinates since a long ago and now I'm really frustrated, so your help will be really appreciated.
I'd like to plot the facade of a building from a CityGML file (which is originally simply an XML file). I have no problem with parsing the CityGML file using XML.etree and extracting the coordinates. But after extracting the coordinates, I cann't find a way to 3D plot them.
from xml.etree import ElementTree as ET
tree = ET.parse('3860_5819__.gml')
root = tree.getroot()
namespaces = {
'ns0': "http://www.opengis.net/citygml/1.0",
'ns1': "http://www.opengis.net/gml",
'ns2': "http://www.opengis.net/citygml/building/1.0"
}
c = 0
wallString = []
for wallSurface in root.findall('.//ns2:WallSurface', namespaces):
for posList in wallSurface.findall('.//ns1:posList', namespaces):
c += 1
wallCoordinates = posList.text
wallCoordinates = wallCoordinates.split()
wallString.append(wallCoordinates)
verts = []
for string in wallString:
X, Y, Z = [], [], []
c = 0
for value in string:
value = float(value)
if c % 3 == 0:
X.append(value)
elif c % 3 == 1:
Y.append(value)
else:
Z.append(value)
c += 1
if c > len(string) - 3:
break
vert = [list(zip(X, Y, Z))]
verts.append(vert)
from mpl_toolkits.mplot3d import Axes3D
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
import matplotlib.pyplot as plt
fig = plt.figure()
ax = Axes3D(fig)
for vert in verts:
ax.add_collection3d(Poly3DCollection(vert))
ax.autoscale_view(tight=True, scalex=True, scaley=True, scalez=True)
plt.show()
plt.close()
Could the problem be that I can't make my plot "tight"? And if not, is there something I'm doing fundamentally wrong?
If relevant, the CityGML file in this case is related to TU Berlin center of entrepreneurship which can be taken from here.
Just realized that nothing was wrong with the main part of the code. The only issue was that the axis were not set. I change the plot part like this:
import matplotlib.pyplot as plt
import mpl_toolkits.mplot3d as mpl3
fig = plt.figure()
ax = mpl3.Axes3D(fig)
for vert in verts:
poly = mpl3.art3d.Poly3DCollection(vert)
ax.add_collection3d(poly)
ax.set_xlim3d(left=386284-50,right=386284+50)
ax.set_ylim3d(bottom=5819224-50, top=5819224+50)
ax.set_zlim3d(bottom=32-10,top=32+20)
plt.show()
plt.close()
Now it works perfectly fine.

Visualization of satellite track retrieved with pyephem is off

using the code below, and using pyephem and fastkml, I'd like to extract a ground track of a satellite from a TLE. The code looks as follows:
import numpy as np
import ephem
import datetime as dt
from fastkml import kml
from shapely.geometry import Point, LineString, Polygon
name = "ISS (ZARYA)"
line1 = "1 25544U 98067A 16018.27038796 .00010095 00000-0 15715-3 0 9995"
line2 = "2 25544 51.6427 90.6544 0006335 30.9473 76.2262 15.54535921981506"
tle_rec = ephem.readtle(name, line1, line2)
start_dt = dt.datetime.today()
intervall = dt.timedelta(minutes=1)
timelist = []
for i in range(100):
timelist.append(start_dt + i*intervall)
positions = []
for t in timelist:
tle_rec.compute(t)
positions.append((tle_rec.sublong,tle_rec.sublat,tle_rec.elevation))
k = kml.KML()
ns = '{http://www.opengis.net/kml/2.2}'
p = kml.Placemark(ns, 'Sattrack', 'Test', '100 Minute Track')
p.geometry = LineString(positions)#, tesselate=1,altitudemode="absolute")
k.append(p)
with open("test.kml", 'w') as kmlfile:
kmlfile.write(k.to_string())
Sadly, when I load the kml into Google Earth, the track looks as follows:
Any ideas where this goes wrong?
Your ground track is a loop around the position 0°N (on the Equator) and 0°E (directly south of Greenwich, near the Gulf of Guinea). This suggests that you are using angles expressed in radians, which can reach at most a value of about 6.2, and passing them to mapping software which reads them as degrees.
You should try converting them to degrees first:
positions.append((tle_rec.sublong / ephem.degree,
tle_rec.sublat / ephem.degree,
tle_rec.elevation))

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