This question already has answers here:
Difference between sh and Bash
(11 answers)
Closed 2 years ago.
i'm coding a simple bash script and i found this error syntax error at line XX `(' unexpected
my code:
function myfun(){
echo XXXX
echo YYYY
read choice
}
choice=$(myfun)
where is the error. i used the ShellCheck and no errors were detected.
Make sure you are running the script with bash. That error is a commonly seen dash shell error.
I suspect the first line of your script is not #!/bin/bash, i.e. you may have left out the shebang line entirely resulting in the default shell being used (which will often be dash especially on Debian derived Linuxes where /bin/sh -> dash).
Try running this:
#!/bin/bash
myfun()
{
echo XXXX
echo YYYY
read choice
}
choice=$(myfun)
Related
This question already has answers here:
Command not found error in Bash variable assignment
(5 answers)
why subtraction return - symbol
(2 answers)
Closed 2 years ago.
I have a Linux shell script with the below code
#! /bin/bash
echo $BASH
name = Mark
echo $name
When I run the script, I'm getting an error:
./my_script.sh: line 3: =: command not found
What am I doing wrong?
Note: I'm using Kali Linux.
In shell, you need to write:
echo $BASH
name=Mark
echo $name
Note there are no spaces around = when setting a variable. The shell usually interprets name = Mark as calling the command name with arguments =and Mark, hardly what you intend. It also seems that name somehow expands to nothing (an alias?), thus the confusing message about command =.
This question already has answers here:
Difference between sh and Bash
(11 answers)
Closed 2 years ago.
"paste -d'|' <(echo 22)
the code is righ in command line , but I wrote it to a shell file , it's error.
this result :
How to resolve this!
Thinks!
#!/bin/bash informs the shell to use bash, and when you run it with sh it does not use bash as sh is forced.
sh is way more limited than bash, so if your script uses bash logic, but is run via sh, it is not fully compatible, and errors out where sh does not understand the commands.
This question already has answers here:
What is the difference between $(command) and `command` in shell programming?
(6 answers)
Closed 4 years ago.
Hi I am trying to print the public ip of the machine in a file using shell script. I am using the command
ip=${curl ipinfo.io/ip}
in my script file and it gives an error saying bad substitution. whereas this command works when i run it in command line.
Is this the right way to get the ip through the script?
Thanks in advance!!
You are capturing the result of program so you should use $(). The following should work for you (with the -s parameter to curl stopping unnecessary output)
ip=$(curl -s ipinfo.io/ip)
This question already has answers here:
Difference between sh and Bash
(11 answers)
Closed 2 years ago.
The community is reviewing whether to reopen this question as of yesterday.
I'm working with a bash script that is currently working on a server (RHEL4). I'm developing on my laptop with Ubuntu 10.04, but I don't think the platform is causing the problem.
Here's what's happening:
I have a skeleton script that calls another script that does most of the work. However, it makes calls to getConfig.sh a lot. getConfig.sh basically just parses some command line argument (using getopts) and calls a Java program to parse some XML files. Anyways, getConfig.sh is throwing up lots of errors (but still seems to work).
Here's the message that I'm getting
getconfig.sh: 89: [[: not found
getconfig.sh: 89: [[: not found
getconfig.sh: 94: [[: not found
I get those three errors every time it runs; however, the script completes and the Java code runs.
Here's the relavent code section
parseOptions $*
if [[ "${debugMode}" == "true" ]] ; then
DEBUG="-DDEBUG=true"
echo "${JAVA_HOME}/bin/java ${DEBUG} -Djava.endorsed.dirs=${JAXP_HOME} -jar $(dirname $0)/GetXPath.jar ${XML_File} ${XPath_Query}"
fi
Line 89 is "parseOptions $* and line 94 is "fi"
Thanks for the answers.
If your script is executable and you are executing it like ./getconfig.sh, the first line of your script needs to be:
#!/bin/bash
Without that shebang line, your script will be interpreted by sh which doesn't understand [[ in if statements.
Otherwise, you should run your script like bash getconfig.sh, not sh getconfig.sh. Even if your default shell is bash, scripts run with sh will use a reduced set of bash's features, in order to be more compliant with the POSIX standard. [[ is one of the features that is disabled.
Use:
bash scriptname.sh
instead of:
sh scriptname.sh
If you are checking for equality, shouldn't the if be ?
if [[ "${debugMode}" = "true" ]]; then
....
fi
This question already has an answer here:
Why would a correct shell script give a wrapped/truncated/corrupted error message? [duplicate]
(1 answer)
Closed 6 years ago.
I am writing a bash script which is a follows
#!/bin/bash
#getting the environment variable from commandline
environment=$1
echo $environment
Now when I run the script with bash ./bashScript.sh Hello , I get the following errors on line
: command not found line 2
: command not found line 5
I see that both of these lines are space and bash script is thus giving me an error
To solve it I write my script as
#!/bin/bash
#
#getting the environment variable from commandline
environment=$1
#
echo $environment
But it looks kind of messy
Is there any other way to achieve this. Thanks for help in advance.
Your comment add the precision that your lines use DOS end of lines (\r\n) when you dump it with od -xc file. To avoid it, you should make sure that your editor uses Unix end of lines (\n).
To fix it on an existing text file, you can use tr:
tr -d '\r' < dos_file > unix_file