I am having a challenge getting just the username in a response below. How do I access the username. i can access the other data but this
[
{
"_id": "5f44d450aaa72313549d519f",
"imageTitle": "uuuuu",
"imageDesc": "uuuuu",
"imageControl": "public",
"imageUrl": "http://localhost:3000/uploads/image-1598346320523.jpg",
"userId": {
"local": {
"username": "uuuuu"
},
"_id": "5f44d3e9aaa72313549d519e"
},
"uploadedOn": "2020-08-25T09:05:20.840Z",
"__v": 0
},
{ ....}
]
You can do it like so
var arr = JSON.parse(`
[ { "_id": "5f44d450aaa72313549d519f", "imageTitle": "uuuuu", "imageDesc": "uuuuu", "imageControl": "public", "imageUrl": "http://localhost:3000/uploads/image-1598346320523.jpg", "userId": { "local": { "username": "uuuuu" }, "_id": "5f44d3e9aaa72313549d519e" }, "uploadedOn": "2020-08-25T09:05:20.840Z", "__v": 0 },
{}
]`);
console.log(arr[0].userId.local.username);
If you are on a newer version of node (14.0.0, and up), then I recommend using the optional chaining operator
arr[0].userId?.local?.username
Related
`I have two collections in MongoDB. One is users and the other is companies. I need to be able to populate the users.endpoints with the endpoints from companies that match ObjectID's which are in the user.endPoints property. It is a bit hard for me to wrap my head around considering there are two steps.
This is the companies collection.
{
"_id": {
"$oid": "63ed39162bfc2cf8065b76cf"
{
"_id": {
"$oid": "63ed39162bfc2cf8065b76cf"
},
"companyName": "Sowegatel",
"amount": 0,
"signalwireSid": "id",
"numbers": [
{
"number": "+12068133580",
"_id": {
"$oid": "63ed39c72bfc2cf8065b76f0"
},
"createdAt": {
"$date": {
"$numberLong": "1676491207931"
}
},
"updatedAt": {
"$date": {
"$numberLong": "1676491207931"
}
}
}
],
"endPoints": [
{
"userName": "4009",
"_id": "fb1d0ef9-c713-400e-a3c9-cbc6823aaf57"
},
{
"userName": "4019",
"_id": "506e710d-14a6-4345-bc89-8488af4cabe4"
},
{
"userName": "4020",
"_id": "c80bd1ab-ca8d-4649-9d35-56d64ef8fab5",
"type": "sip_endpoint"
}
],
"__v": 6
} },
"companyName": "Sowegatel",
"amount": 0,
"signalwireSid": "id",
"numbers": [
{
"number": "+12068133580",
"_id": {
"$oid": "63ed39c72bfc2cf8065b76f0"
},
"createdAt": {
"$date": {
"$numberLong": "1676491207931"
}
},
"updatedAt": {
"$date": {
"$numberLong": "1676491207931"
}
}
}
],
"endPoints": [
{
"userName": "4009",
"_id": "fb1d0ef9-c713-400e-a3c9-cbc6823aaf57"
},
{
"userName": "4019",
"_id": "506e710d-14a6-4345-bc89-8488af4cabe4"
},
{
"userName": "4020",
"_id": "c80bd1ab-ca8d-4649-9d35-56d64ef8fab5",
"type": "sip_endpoint"
}
],
"__v": 6
}
This is the users collection.
{
"_id": {
"$oid": "63ed39162bfc2cf8065b76d2"
},
"firstName": "mark",
"lastName": "thomas",
"email": "mt#st.com",
"password": "",
"companyId": {
"$oid": "63ed39162bfc2cf8065b76cf"
},
"active": true,
"role": "companyAdmin",
"tokens": [],
"__v": 2,
"endpoints": [
// I need to populate to endpoints here!!!! //
"c80bd1ab-ca8d-4649-9d35-56d64ef8fab5"
]
}
I can do a single step aggregation, but this is a little complicated for me.`
I want to join more than two collections in MongoDB . Is it possible to join?
I have 2 collections and I want to join them based by their ids
news collection
{
"lang": "ru",
"news": [{
"title": "title",
"content": "desc",
"image": "path",
"categoryId": {
"$oid": "6171499e0ba3d75082823c9a"
},
"createdAt": {
"$date": "2021-10-21T12:30:33.215Z"
},
"_id": {
"$oid": "61715d7990905adefcf314d1"
}
}]
}
and I have got newscategory collection like that
[
{
"lang": "ru",
"categories": [{
"name": "sdfsdsdcsdf",
"_id": {
"$oid": "6171499e0ba3d75082823c9a"
}
}]
},
{
"lang": "en",
"categories": [{
"name": "ooo",
"_id": {
"$oid": "61712980f8ee795c6a569dcb"
}
}, {
"name": "yuy",
"_id": {
"$oid": "61712980f8ee795c6a569dcc"
}
}, {
"name": "rtyrty",
"_id": {
"$oid": "61712980f8ee795c6a569dcd"
}
}]
}
]
Expected Output:
[
{
"_id": "61715d7990905adefcf314d0",
"lang": "ru",
"news": [
{
"title": "sdf",
"content": "sdf",
"image": "asdas",
"categoryId": "6171499e0ba3d75082823c9a",
"caregory": [
{
"name": "sdfsdsdcsdf",
"_id": "6171499e0ba3d75082823c9a"
},
]
"createdAt": "2021-10-21T12:30:33.215Z",
"_id": "61715d7990905adefcf314d1"
}
],
Match is based on both "category_id" and "categories._id".
How can I achieve result like that ?
I'm new to mongodb and I've been trying to query this doc for awhile now.
Im trying to query all the rooms that have a room name of 100.
json
{
"count": 3,
"reviews": [
{
"_id": "5f9d42a0a8e71e004643f584",
"user": {
"_id": "5f7308cde0a4a7a66bc3d184",
"name": "Guest"
},
"room": {
"_id": "5f98f9321fd5bb0045b3d886",
"name": "100",
},
"rating": 4,
},
{
"_id": "5f9d431ea8e71e004643f585",
"user": {
"_id": "5f7308cde0a4a7a66bc3d184",
"name": "Guest",
},
"room": {
"_id": "5f98f9321fd5bb0045b3d886",
"name": "100",
},
"rating": 5,
},
{
"_id": "5f9e74fea6c06a0046d3cae2",
"user": {
"_id": "5f7308cde0a4a7a66bc3d184",
"name": "Guest",
},
"room": {
"_id": "5f98fa8b1fd5bb0045b3d88a",
"name": "300",
},
"rating": 5,
}
]}
what I've tried
1. find({},{"reviews.room.name": {$eq: "100"}}) // getting a projection error
2. find({"reviews.room.name": "100"}) // getting null
Any help to the right direction would be greatly appreciated.
Check out the docs about how to use find:
https://docs.mongodb.com/manual/reference/method/db.collection.find/
and try this
db.reviews.find({
"room.name": "100"
})
Here is the playground with your example: https://mongoplayground.net/p/dPfH5fSOePq
did u try this ? const response = await Room.find({name: "100"})
I'm getting below response from loopback when I filter with below api:
http://localhost:8001/myloopback/productDetails?q=product.productId==apple
I want to exclude the data which doesn't have property "productModel" - how can we achieve this in Loopback rest API. Is there any option to exclude property from the rest API query param? I'm new to Loopback - it would be really grateful if someone can help me to fix this
{
"myData": [{
"data": {
"product": {
"productId": "apple",
"productName": "iPhone",
"productModel": "6s"
},
"statusCode": "active",
"date": "2018-08-07T00:00:00.000Z"
},
"links": [{
"productUrl": "test"
},
{
"productImage": "test"
}
],
"info": {}
},
{
"data": {
"product": {
"productId": "apple",
"productName": "iPhone",
"productModel": "7"
},
"statusCode": "active",
"date": "2018-08-07T00:00:00.000Z"
},
"links": [{
"productUrl": "test"
},
{
"productImage": "test"
}
],
"info": {}
},
{
"data": {
"product": {
"productId": "apple",
"productName": "Macbook"
},
"statusCode": "active",
"date": "2018-08-07T00:00:00.000Z"
},
"links": [{
"productUrl": "test"
},
{
"productImage": "test"
}
],
"info": {}
}
],
"metadata": {
"count": 3,
"offset": 0
}
}
There is no such inbuilt function to do that but you can use multiple Fields filter to achieve that.
Here i like to explain my problem.
How can i write a mongoose query to retrieve every subdocument from JSON without passing parent_id.
[
{
"_id": "56a320003fe17cc7363dd0d7",
"name": "Leanna Jacobson",
"gender": "female",
"friends": [
{
"id": 0,
"name": "Riley Case"
},
{
"id": 1,
"name": "Herman Carter"
},
{
"id": 2,
"name": "Pacheco Woodard"
}
]
},
{
"_id": "56a3200001501cfa1ea2641d",
"name": "Juliana Bonner",
"gender": "female",
"friends": [
{
"id": 0,
"name": "Keller Woodward"
},
{
"id": 1,
"name": "Fern Knight"
},
{
"id": 2,
"name": "Cain Richards"
}
]
},
{
"_id": "56a3200006864c78ecb1aeed",
"name": "Gena Stark",
"gender": "female",
"friends": [
{
"id": 0,
"name": "Kate Franco"
},
{
"id": 1,
"name": "Araceli Mcclure"
},
{
"id": 2,
"name": "Molly Nelson"
}
]
},
{
"_id": "56a320006d868155161038b6",
"name": "Eve Gonzalez",
"gender": "female",
"friends": [
{
"id": 0,
"name": "Pam Lang"
},
{
"id": 1,
"name": "Christy Marks"
},
{
"id": 2,
"name": "Donovan Warren"
}
]
},
{
"_id": "56a3200066b94852f5680568",
"name": "Coleman Wooten",
"gender": "male",
"friends": [
{
"id": 0,
"name": "Roberta Olson"
},
{
"id": 1,
"name": "Roseann Reid"
},
{
"id": 2,
"name": "Kerri Russell"
}
]
}
]
Here i need to retrieve every friends details from the subdocument array friends for every parent.
so how can i write query for this?????
Suppose the name of your schema is Person, try this one.
//find all document, only select `friends` field from every document
Person.find({}, 'friends', function (err, friends) {
// the return friends is the [[friends], [friends], ...]
});