On my website I have this message "Internal Server Error". How can I kill a process in linux. so that I can run the proccess manually /usr/bin/gunicorn --workers 3 flaskodesiapp:create_app
root#localhost:/flask_app_project# ps -A | grep gunicorn
13210 ? 00:00:00 gunicorn3
13212 ? 00:00:00 gunicorn3
13215 ? 00:00:00 gunicorn3
13216 ? 00:00:00 gunicorn3
root#localhost:/flask_app_project# sudo killall gunicorn3
root#localhost:/flask_app_project# ps -A | grep gunicorn
13232 ? 00:00:00 gunicorn3
13234 ? 00:00:00 gunicorn3
13235 ? 00:00:00 gunicorn3
13236 ? 00:00:00 gunicorn3
/etc/systemd/system/gunicorn.service
[Service]
User=root
Group=root
WorkingDirectory=/flask_app_project
Restart=on-failure
ExecStart= /usr/bin/gunicorn --workers 3 flaskodesiapp:create_app
[Install]
WantedBy=multi-user.target
supervisord /etc/supervisor/conf.d/flask_app.conf
[program:flask_app]
directory=/flask_app_project
command=gunicorn3 --workers=3 flaskodesiapp:create_app
autostart=true
autorestart=true
stopasgroup=true
killasgroup=true
stderr_logfile=/var/log/flask_app/flask_app.err.log
stdout_logfile=/var/log/flask_app/flask_app.out.log
I had to stop supversisord first
ps -ef | grep supervisord
root 12836 1 0 01:38 ? 00:00:00 /usr/bin/python3 /usr/bin/supervisord -n -c /etc/supervisor/supervisord.conf
root 13310 13127 0 02:13 pts/0 00:00:00 grep --color=auto supervisord
kill -s SIGTERM 12836
ps -ef | grep supervisord
root 13325 13127 0 02:14 pts/0 00:00:00 grep --color=auto supervisord
sudo killall gunicorn3
Related
Following this solution from another post I've made an alias in my .zshrc (I use ohmyzsh) to stop my celery workers:
alias stopcelery="ps auxww | grep 'celery' | awk '{print $2}' | xargs kill -9"
However when I have running celery workers, using this command fails:
➜ stopcelery
kill: invalid argument
Usage:
kill [options] <pid> [...]
Options:
<pid> [...] send signal to every <pid> listed
-<signal>, -s, --signal <signal>
specify the <signal> to be sent
-l, --list=[<signal>] list all signal names, or convert one to a name
-L, --table list all signal names in a nice table
-h, --help display this help and exit
-V, --version output version information and exit
For more details see kill(1).
The workers are still running:
➜ ps auxww | grep 'celery'
myuser 49126 67.0 0.5 189132 92280 ? S 15:59 0:02 /home/myuser/.local/share/virtualenvs/myproject-JLNbaOhA/bin/python -m celery worker -A wsgi.celery --loglevel=INFO --logfile=/tmp/celery.log --pidfile=celeryd.pid
myuser 49304 0.0 0.5 188160 85060 ? S 15:59 0:00 /home/myuser/.local/share/virtualenvs/myproject-JLNbaOhA/bin/python -m celery worker -A wsgi.celery --loglevel=INFO --logfile=/tmp/celery.log --pidfile=celeryd.pid
myuser 49305 0.0 0.5 188164 84844 ? S 15:59 0:00 /home/myuser/.local/share/virtualenvs/myproject-JLNbaOhA/bin/python -m celery worker -A wsgi.celery --loglevel=INFO --logfile=/tmp/celery.log --pidfile=celeryd.pid
myuser 49306 0.0 0.5 188168 84848 ? S 15:59 0:00 /home/myuser/.local/share/virtualenvs/myproject-JLNbaOhA/bin/python -m celery worker -A wsgi.celery --loglevel=INFO --logfile=/tmp/celery.log --pidfile=celeryd.pid
myuser 49307 0.0 0.5 188172 84844 ? S 15:59 0:00 /home/myuser/.local/share/virtualenvs/myproject-JLNbaOhA/bin/python -m celery worker -A wsgi.celery --loglevel=INFO --logfile=/tmp/celery.log --pidfile=celeryd.pid
myuser 49312 0.0 0.0 20556 2924 pts/8 S+ 15:59 0:00 grep --color=auto --exclude-dir=.bzr --exclude-dir=CVS --exclude-dir=.git --exclude-dir=.hg --exclude-dir=.svn --exclude-dir=.idea --exclude-dir=.tox celery
But using the actual command it works:
➜ ps auxww | grep 'celery' | awk '{print $2}' | xargs kill -9
kill: (48078): No such process
Indeed, checking again:
➜ ps auxww | grep 'celery'
myuser 49782 0.0 0.0 20556 664 pts/8 S+ 16:03 0:00 grep --color=auto --exclude-dir=.bzr --exclude-dir=CVS --exclude-dir=.git --exclude-dir=.hg --exclude-dir=.svn --exclude-dir=.idea --exclude-dir=.tox celery
So what is the difference, why using the alias does not having the same effect?
As #Philippe has pointed out, I forgot to escape the $ sign as I was using double quotes.
This question already has answers here:
How to get process ID of background process?
(9 answers)
Closed 1 year ago.
Below is the output of executing two commands ads2 svcd& and ps -aux|grep ads2
nvidia#nvidia-desktop:~$ ads2 svcd&
[1] 4593
nvidia#nvidia-desktop:~$ ps -aux|grep ads2
nvidia 4593 0.5 0.0 39796 23864 pts/0 Sl 08:20 0:00 /opt/ads2/arm-
linux64/bin/ads2svcd
nvidia 4603 0.0 0.0 6092 672 pts/0 S+ 08:20 0:00 grep --color=auto ads2
nvidia#nvidia-desktop:~$
nvidia#nvidia-desktop:~$
the command ads2 svcd& runs a process related to ads2 software. with ps -aux|grep ads2 i displayed the whole processes that contains the name "ads2".
Now What i'm trying to do is to get the process number of the ads2 which in this example is 4593. So i wrote the follwing bash script:
#!/usr/bin/env bash
process="$(ps -aux|grep ads | grep 'nvidia' | cut -d' ' -f 3)"
echo "The current ads2 process is " $process
The bash script outputs the following:
nvidia#nvidia-desktop:~$ ./test.sh
The current ads2 process is
As you see the process number is not filtered. So what i'm i doing wrong?
thanks in advance
List all the processes in the current shell with $$ built-in variable
ps --forest -gp $$
PID TTY STAT TIME COMMAND
3809 pts/1 Ss 0:01 bash
4896 pts/1 T 0:00 \_ vim file.json
22965 pts/1 S+ 0:00 \_ ssh dw
3607 pts/0 Ss 0:01 bash
2500 pts/0 R+ 0:00 \_ ps --forest -gp 3607
3327 tty2 Ssl+ 0:00 /usr/lib/gdm3/gdm-x-session --run-script i3
3329 tty2 Sl+ 8:12 \_ /usr/lib/xorg/Xorg vt2 -displayfd 3 -auth /run/user/1000/gdm/Xauthority -background none -noreset -keeptty -verbose 3
3346 tty2 S+ 0:03 \_ i3
Just see the pid of them:
ps -opid --forest -gp $$
PID
3809
4896
22965
3607
2688
3327
3329
3346
If you need to use grep for any reason, use -opid,cmd with current shell:
ps -opid,cmd -gp $$ | grep vim
3851 grep --color=auto vim
4896 vim file.json
For all, just use -e
ps -e -opid,cmd | grep vim
4141 grep --color=auto vim
4896 vim file.json
The complete one, we have to ignore the grep itself:
ps -e -opid,cmd | grep vim | grep -v grep | cut -d' ' -f 2
4896
Without double grep using comm option for ps
ps -opid,comm -gp $$ | grep vim
4896 vim
of course the simplest one is pgrep
pgrep vim
4896
NOTE for variable assignment there should NOT be any space:
# wrong
ads2ProcessId = $(pgrep ads2)
# right
ads2ProcessId=$(pgrep ads2)
I am trying to find the PID of a process (motion_sensor.py), but pgrep returns nothing. Why does it not return the process id?
pgrep -u www-data motion_sensor.py
ps -ef | grep "motion_sensor" returns
root 7149 1 93 Apr25 ? 15:59:08 python motion_sensor.py
www-data 31872 23531 0 14:09 ? 00:00:00 sh -c sudo python /home/pi/Desktop/PiControl/motion_sensor.py
root 31873 31872 0 14:09 ? 00:00:00 sudo python /home/pi/Desktop/PiControl/motion_sensor.py
root 31874 31873 47 14:09 ? 00:14:30 python /home/pi/Desktop/PiControl/motion_sensor.py
pi 32645 32202 0 14:39 pts/0 00:00:00 grep --color=auto motion_sensor.py
Normally pgrep applies the search pattern to process names. The process name in this case is python and not motion_sensor.py. If you want to grep for the full path rather than just the process name you need to pass -f:
pgrep -u www-data -f motion_sensor.py
Check man pgrep
the requirement is to find out PID of a process,
So you can try :
ps aux | grep www-data motion_sensor.py
My Command Interpreter is bash shell.After opening terminal on my OS(cent OS), I have executed following commands:
scenario 1
$sh -c "ps -l"
UID PID PPID TIME CMD
3038 2577 2504 00:00:00 bash
3038 2992 2577 00:00:00 ps
scenario 2
$sh
$ps -l
UID PID PPID TIME CMD
3038 2577 2504 00:00:00 bash
3038 3005 2577 00:00:00 sh
3038 3006 3005 00:00:00 ps
Observe PID and PPID of ps.
In scenario 1, I am executing ps -l command on sh shell. So it's parent should be sh i.e., it's PPID should be PID of sh. But ps -l command listing that it's parent is bash. I am not understanding what is happening exactly. I am understanding the difference between scenario 1 and scenario 2. But when I am executing the same commands on another OS(ubuntu), I am getting same listing under ps -l in scenario 3 and scenario 4, as below:
scenario 3
$sh
$ps -l
UID PID PPID TIME CMD
3038 2577 2504 00:00:00 bash
3038 2991 2577 00:00:00 sh
3038 2992 2991 00:00:00 ps
scenario 4
$sh
$ps -l
UID PID PPID TIME CMD
3038 2577 2504 00:00:00 bash
3038 3005 2577 00:00:00 sh
3038 3006 3005 00:00:00 ps
Here in both scenarios, I am getting PPID of ps CMD as PID of sh. What is happening exactly. Is my interpretation wrong?
When you type a command, bash just fork then execve the command. scenario 3 and scenario 4 are the case.
While sh -c 'ps -l' depends on shells.
On my linux distribution, the result of ls -l `which sh` islrwxrwxrwx 1 root root 4 Oct 6 14:06 /usr/bin/sh -> bash.
When -c is present, bash execve the following command directly. While another shell like fish does not.
fish -c 'ps -l'
F S UID PID PPID C PRI NI ADDR SZ WCHAN TTY TIME CMD
0 S 1000 711 710 0 80 0 - 5707 wait pts/5 00:00:00 bash
0 S 1000 1519 711 0 80 0 - 7054 wait pts/5 00:00:00 fish
0 R 1000 1526 1519 0 80 0 - 9266 - pts/5 00:00:00 ps
What execve does is replacing the current process image with a new process image.fork creates a new process.
The real thing I want to do is like ps -ef|head -n1 && ps -ef|grep httpd. The output should be something like this.
UID PID PPID C STIME TTY TIME CMD
xxxxx 6888 6886 0 16:49 pts/1 00:00:00 grep --color=auto httpd
root 10992 1 0 13:56 ? 00:00:00 sudo ./myhttpd
root 10993 10992 0 13:56 ? 00:00:00 ./myhttpd
root 11107 10993 0 13:56 ? 00:00:00 ./myhttpd
root 12142 10993 0 14:00 ? 00:00:00 ./myhttpd
root 31871 10993 0 15:03 ? 00:00:00 ./myhttpd
But I hate duplicates. So, I want ps -ef to appear only once.
Considering bash process substitution, I tried ps -ef | tee > >(head -n1) >(grep httpd), but the only output is
UID PID PPID C STIME TTY TIME CMD
However, ps -ef | tee > >(head -n1) >(head -n2) can work fine in the following way
UID PID PPID C STIME TTY TIME CMD
root 1 0 0 13:36 ? 00:00:00 /sbin/init
UID PID PPID C STIME TTY TIME CMD
Can anyone help me ?
You can do head and grep on the same stream.
ps -ef | (head -n 1; grep '[h]ttpd')
It might be marginally more efficient to refactor to use sed:
ps -ef | sed -n -e '1p' -e '/[h]ttpd/p'
... but not all sed dialects deal amicably with multiple -e options. Perhaps this is more portable:
ps -ef | sed '1b;/[h]ttpd/b;d'
Also note the old trick to refactor the regex so as not to match itself by using a character class.
This can be achieved simply with pgrep and ps.
ps -fp $(pgrep -d, -o -f httpd)
use AWK
ps -ef | awk 'NR==1 || /httpd/'
print out 1st line or any line contains "httpd"
or use sed
ps -ef | sed -n '1p;/httpd/p'
ps -f -C httpd --noheaders | head -n1