if else statement python using plot parameters in function - python-3.x

Question

I have an if else statement in my function that is not wokring the way i want it to. Mind you I am still learning python and all things programming.
I have a function to define a plot. Idea is to create a large python repo for data analysis. EDIT: i added a working make shift dataframe for you to try
import matplotlib
import matplotlib.pyplot as plt
import pandas as pd
#import numpy as np
#import os
#import dir_config as dcfg
#import data_config as datacfg
import matplotlib.dates as md
#import cartopy.crs as ccrs
data = {'dates': [20200901,20200902,20200903,20200904,20200905,20200906,20200907,20200908,20200909,20200910],
'depth': [1,2,3,4,5,6,7,8,9,10],
'cond': [30.1,30.2,30.3,30.6,31,31.1,31.0,31.4,31.1,30.9]
}
df = pd.DataFrame(data, columns = ['dates', 'depth', 'cond'])
df['pd_datetime'] = pd.to_datetime(df['dates'])
def ctd_plots_timeseries(time=[],cond=[], sal =[], temp=[], depth=[], density=[]):
#-----------
# CONDUCTIVITY PLOT
#-----------
if cond == []:
print("there is no data for cond")
pass
else:
plt.scatter(time,depth,s=15,c=cond,marker='o', edgecolor='none')
plt.show()
#-----------
# SALINITY (PSU) PLOT: I do not want this to plot at all due to its parameter being 'empty' in the function when called
#-----------
if sal == []:
print('there is no salinity data')
pass
else:
plt.scatter(time,depth,s=15,c=sal,marker='o', edgecolor='none')
plt.show()
ctd_plots_timeseries(depth = df['depth'], time = df['pd_datetime'], cond = df['cond'])
The idea here is that if there is no data in the cond value, do pass to not show the plot.
However ever time I run this, the plot shows, even thought there is no data for it.
When i call the function i put in plot_timeseries(time=time_data, depth=depth_data temp=temp_data)
my aim is for only the temp data in this example to show, not a cond graph with no variables.
what i have tried is
if cond != []:
plotting code
plt.show()
else:
print('there is no cond data')
pass
and
plotting code
if cond == []:
print('no cond data')
pass
else:
plt.show()
to no avail.
note that there are 4 other plots in this function i would like to do the same thing. thanks for any insight this community can give me.
UPDATE:
I changed the conditions in the function to def ctd_plots_timeseries(time=0,cond=0, sal =0, temp=0, depth=0, density=0):
and then changed conditional statement to
if cond != 0:
graphing code
else:
print('no data here')
i get the following error:
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

Answer 1

I've simplified it. Try that:
def plots_timeseries(cond = []): # Single argument for clarity
if not cond:
print('there is no cond value')
else:
print('There is cond')
plots_timeseries()
# there is no cond value

Answer 2

So I figured out a working solution.
if len(cond) == 0:
print('there is no cond data')
else:
plt.scatter(time,depth,s=15,c=cond)
plt.show()
Lots of time and effort was put in to trying to solve this, and this solution was a test, after a good night sleep. Thanks for all the help. hope this helps someone else if that have a similar issue