I am working in a project of VBA, and I need to open some Workbooks, but the name is kind of dynamic, but only the last name. Sometimes the name comes like "OnHand 066 May" and sometimes with "OnHand 006 Jun"
Dim Dir As String
Dir = ActiveWorkbook.Path
Do not use Dir as a variable name. It is a reserved function name.
Use a wildcard with the Dir function to find a file that matches.
The Dir function will not return a full path, so you have to append it again if you want to actually open the file.
Let's assume there is only one file in that folder that matches, as you did not specify that in your question.
Dim sFile As String
sFile = Dir(ActiveWorkbook.Path & "\OnHand*.xls*")
If sFile <> "" Then
' if you get an error on the next line, someone else may have it open already
Debug.Print "About to open: " & ActiveWorkBook.Path & "\" & sFile
WorkBooks.Open ActiveWorkBook.Path & "\" & sFile
Else
MsgBox "Cannot find a file like that"
End If
Related
I am trying to open a file which will be updated periodically. The current name is "GDE Portfolio Characteristics 12.31.2021" and the idea is to instruct the code to open it, no matter the date (i.e. the last 10 characters). I should only have one file in the folder with such a partial name.
The code I use is the following:
Workbooks.Open Filename:=ThisWorkbook.Path & "\Parametric GDE Portfolio Characteristics*.xlsx"
When running it, it seems it does not find the file. It works if I instead use the entire name of the file.
Newbie problem, but scratching my head in frustration!
Many thanks
There is no way to use a wildcard in the Open-statement. However, you can use the
Dir-command to get the real file name as it allows wildcards:
Dim fileName As String
fileName = Dir(ThisWorkbook.Path & "\Parametric GDE Portfolio Characteristics*.xlsx")
If fileName <> "" Then
Workbooks.Open Filename:=ThisWorkbook.Path & "\" & fileName
End If
Here is a more generic approach:
Sub OpenFiles()
Dim Files As Collection
Set Files = ListFiles(ThisWorkbook.Path, "Parametric GDE Portfolio Characteristics*.xlsx")
Dim Filename As Variant
For Each Filename In Files
Workbooks.Open Filename:=Filename
Next
End Sub
Function ListFiles(FolderName As String, SearchString As String) As Collection
Set ListFiles = New Collection
Dim Filename As String
Filename = Dir(FolderName & "\" & SearchString)
If Len(Filename) = 0 Then Exit Function
Do While Filename <> ""
ListFiles.Add Filename
Filename = Dir()
Loop
End Function
I have a file that is placed in a folder, but the date is unknown to me, is there anyway I can pick it up regardless of the date?
FilePath = "\\0_Received\Business_Level_Report_yyyymmdd.xlsx"
The file name will be for example Business_Level_Report_20200729
The date will be unknown but it is the only file with Business Level Report as its prefix.
Can anyone help with this?
Maybe try this solution here: VBA partial file name
You can likely modify this just a bit to get what you're looking for.
For example, in your case you might try this:
myPath = "\\0_Received\"
fname = Dir(myPath & "Business_Level_Report*")
For example, this code opens the workbook named Business_Level_Report_blah_blah_blah without having to specify blah_blah_blah:
Here's the code if you want to run it, too:
Private Sub whatever()
Dim fname As Variant
Dim myPath As String
myPath = "C:\Users\beckj\"
fname = Dir(myPath & "Business_Level_Report*")
If fname <> "" Then
Workbooks.Open (myPath & fname)
MsgBox "File is open."
Else
MsgBox "ERROR."
End If
End Sub
For taday:
FilePath = "\\0_Received\Business_Level_Report_" & Format(Date, "yyyymmdd") & ".xlsx"
for "07/29/2020"
Dim D as Date
D = cDate("07/29/2020")
FilePath = "\\0_Received\Business_Level_Report_" & Format(D, "yyyymmdd") & ".xlsx"
Or if you do not care about a specific date, you must iterate between the folder workbooks and choose the appropriate one in this way:
If fileName like "*Business_Level_Report########.xlsx" then
FilePath = fileName
End If
Since I am very new to the excel macro I am trying to develop a code which is able to open the PDF file.But There are some PDF files in my system which are generated by another system therefore those files names change day by day and some figures are included too.
As an example,"Process Report 151120183569844" like this.These figures change everyday.I tried it with adding WILDCARD option but it doesn't work.How do I open this PDF with only a part of the file name?
Sub Open_PDF()
Dim pdfPath As String
pdfPath ="D:\Reports\Process Report*" & ".pdf" 'I used wildcard instead "Process Report 151120183569844"'
Call OpenAnyFile(pdfPath)
End Sub
Function openAnyFile(strPath As String)
Set objShell = CreateObject("Shell.Application")
objShell.Open(strPath)
End Function
As pointed out in another answer, the Dir function with a wildcard should do the trick.
Here's an example using the original openAnyFile function.
Sub Open_PDF()
Dim filePath As String, fileName As String
filePath = "D:\Reports\"
fileName = Dir(filePath & "Process Report*.pdf")
If fileName <> "" Then
openAnyFile filePath & fileName
End If
End Sub
Function openAnyFile(strPath As String)
Dim objShell As Object
Set objShell = CreateObject("Shell.Application")
objShell.Open (strPath)
End Function
You cannot open a file using a wildcard - it's just common sense, what if more than one file was matching your criteria - which one would you want to program to open? You have to specify the exact file name to open it.
if there is just one file in the target directory, you can use something like the following code to open it, regardless of its name:
sFound = Dir(ActiveWorkbook.Path & "\Process Report*.xlsm")
If sFound <> "" Then
Workbooks.Open filename:= ActiveWorkbook.Path & "\" & sFound
End If
I randomly create a new folder on my desktop, in this folder I have one template file with .xlsm extension, which contains my VBA code. Meanwhile I have several csv files saved in the same folder with my raw data.
The purpose is looping through all those csv files one by one, open it, and copy some data and paste to my template file(I know how to do this part) from it and close it after all operations are done.
Currently I meet a problem about how to loop through my folder and open those csv one by one. I didn't set a specific folder name, since I want to share it with other people to use,therefore I use Application.ActiveWorkbook.Path to get the path for my current folder.
Here is my code:
Option Explicit
Sub Range_End_Method()
Dim Dir As String
Dim i As String
Application.ScreenUpdating = False
Dir = Application.ActiveWorkbook.Path & "\"
For Each i In Dir.Files
Debug.Print i.Name
If (i.Name Like "*.csv") Then
Workbooks.Open (i.Path)
End If
Next
End Sub
I'm guessing you want to use the Dir function. To use that, make a call to it, specifying folder and file type in the first call, then call it empty until it returns an empty string. Like this:
Folder = Dir(Application.ActiveWorkbook.Path & "\*.csv")
Do While Folder <> ""
Debug.Print Folder
Workbooks.Open Folder
Folder = Dir()
Loop
You can use this function and macro.
Juste replace MsgBox (myFile + "OK") by the action you want to execute.
FUNCTION
Function ClasseurOuvert(NomFich)
On Error Resume Next
Workbooks(NomFich).Activate
If Err <> 0 Then Workbooks.Open FileName:=NomFich
On Error GoTo 0
End Function
MACRO
Sub LoopFiles()
Dim myPath As String, myFile As String
myPath = Application.ActiveWorkbook.Path & "\"
myFile = Dir(myPath & "\*.*")
Do While myFile <> "" And myFile Like "*.csv"
Call ClasseurOuvert(myPath & "\" & myFile)
With Workbooks(myFile)
MsgBox (myFile + "OK")
End With
Workbooks(myFile).Save
Workbooks(myFile).Close
myFile = Dir()
Loop
End Sub
I want to use a wildcard to open a workbook stored in the same folder as my macro workbook. In the folder is a file named 302113-401yr-r01.xlsm. Here is my code:
Workbooks.Open filename:=ActiveWorkbook.Path & "\302113*.xlsm"
However, it tells me that there is no such file. Any advice?
We cannot open a file using a wildcard - imagine the chaos if we could!
You'll need to use Dir(ActiveWorkbook.Path & "\302113*.xlsm") to loop through the files that this returns. If there will only be one then just use this function once:
Dim sFound As String
sFound = Dir(ActiveWorkbook.Path & "\302113*.xlsm") 'the first one found
If sFound <> "" Then
Workbooks.Open filename:= ActiveWorkbook.Path & "\" & sFound
End If
Dir Function :tech on the net
From my experience this works if you have the wildcard/asterix as the last symbol in the string and if there is only one file. Try doing:
Workbooks.Open filename:=ActiveWorkbook.Path & "\302113*"
For example I am using:
Workbooks.Open Filename:="X:\business\2014\Easy*"
and it works.
You can open files using the wildcard, but only with UNC paths for some reason.
For example :
Set xlFile = xlObj.WorkBooks.Open("\\yourServerHere\dataAutomation\*.xlsx")
I'm not that experienced yet with Excel but the following works well for me for using wildcards in filenames to open files. This example requires all files to be in the same directory/folder. Yes, it is pretty simplistic.
Sub using_wildcards_to_open_files_in_excel_vba()
Dim mypath As String
Dim sFilename As String
'Suppose you have three files in a folder
' Named blank.xlsx,, ex1_939_account.xlsx, and ex1_opt 5.xlsx
'Manually open the blank.xlsx file
'The following code lines will open the second two files before closing the previously opened file.
ActiveWorkbook.Activate
mypath = ActiveWorkbook.Path
'opening xlsx file with name containing "939" and closing current file
mypath = mypath & "\*939*.xlsx"
'MsgBox mypath 'Checking
sFilename = Dir(mypath)
'MsgBox sFilename 'Checking
ActiveWorkbook.Close savechanges:=False
Workbooks.Open Filename:=sFilename
ActiveWorkbook.Activate
mypath = ActiveWorkbook.Path
'opening xlsx file with name ending in "opt 5" and closing current file
mypath = mypath & "\*opt 5.xlsx"
'MsgBox mypath 'Checking
sFilename = Dir(mypath)
'MsgBox sFilename 'Checking
ActiveWorkbook.Close savechanges:=False
Workbooks.Open Filename:=sFilename
End Sub