I have a Dockerfile that I am putting together to install a vanilla python environment (into which I will be installing an app, but at a later date).
FROM ubuntu:12.04
# required to build certain python libraries
RUN apt-get install python-dev -y
# install pip - canonical installation instructions from pip-installer.org
# http://www.pip-installer.org/en/latest/installing.html
ADD https://bitbucket.org/pypa/setuptools/raw/bootstrap/ez_setup.py /tmp/ez_setup.py
ADD https://raw.github.com/pypa/pip/master/contrib/get-pip.py /tmp/get-pip.py
RUN python /tmp/ez_setup.py
RUN python /tmp/get-pip.py
RUN pip install --upgrade pip
# install and configure virtualenv
RUN pip install virtualenv
RUN pip install virtualenvwrapper
ENV WORKON_HOME ~/.virtualenvs
RUN mkdir -p $WORKON_HOME
RUN source /usr/local/bin/virtualenvwrapper.sh
The build runs ok until the last line, where I get the following exception:
[previous steps 1-9 removed for clarity]
...
Successfully installed virtualenvwrapper virtualenv-clone stevedore
Cleaning up...
---> 1fc253a8f860
Step 10 : ENV WORKON_HOME ~/.virtualenvs
---> Running in 8b0145d2c80d
---> 0f91a5d96013
Step 11 : RUN mkdir -p $WORKON_HOME
---> Running in 9d2552712ddf
---> 3a87364c7b45
Step 12 : RUN source /usr/local/bin/virtualenvwrapper.sh
---> Running in c13a187261ec
/bin/sh: 1: source: not found
If I ls into that directory (just to test that the previous steps were committed) I can see that the files exist as expected:
$ docker run 3a87 ls /usr/local/bin
easy_install
easy_install-2.7
pip
pip-2.7
virtualenv
virtualenv-2.7
virtualenv-clone
virtualenvwrapper.sh
virtualenvwrapper_lazy.sh
If I try just running the source command I get the same 'not found' error as above. If I RUN an interactive shell session however, source does work:
$ docker run 3a87 bash
source
bash: line 1: source: filename argument required
source: usage: source filename [arguments]
I can run the script from here, and then happily access workon, mkvirtualenv etc.
I've done some digging, and initially it looked as if the problem might lie in the difference between bash as the Ubuntu login shell, and dash as the Ubuntu system shell, dash not supporting the source command.
However, the answer to this appears to be to use '.' instead of source, but this just causes the Docker runtime to blow up with a go panic exception.
What is the best way to run a shell script from a Dockerfile RUN instruction to get around this (am running off the default base image for Ubuntu 12.04 LTS).
Original Answer
FROM ubuntu:14.04
RUN rm /bin/sh && ln -s /bin/bash /bin/sh
This should work for every Ubuntu docker base image. I generally add this line for every Dockerfile I write.
Edit by a concerned bystander
If you want to get the effect of "use bash instead of sh throughout this entire Dockerfile", without altering and possibly damaging* the OS inside the container, you can just tell Docker your intention. That is done like so:
SHELL ["/bin/bash", "-c"]
* The possible damage is that many scripts in Linux (on a fresh Ubuntu install grep -rHInE '/bin/sh' / returns over 2700 results) expect a fully POSIX shell at /bin/sh. The bash shell isn't just POSIX plus extra builtins. There are builtins (and more) that behave entirely different than those in POSIX. I FULLY support avoiding POSIX (and the fallacy that any script that you didn't test on another shell is going to work because you think you avoided basmisms) and just using bashism. But you do that with a proper shebang in your script. Not by pulling the POSIX shell out from under the entire OS. (Unless you have time to verify all 2700 plus scripts that come with Linux plus all those in any packages you install.)
More detail in this answer below. https://stackoverflow.com/a/45087082/117471
The default shell for the RUN instruction is ["/bin/sh", "-c"].
RUN "source file" # translates to: RUN /bin/sh -c "source file"
Using SHELL instruction, you can change default shell for subsequent RUN instructions in Dockerfile:
SHELL ["/bin/bash", "-c"]
Now, default shell has changed and you don't need to explicitly define it in every RUN instruction
RUN "source file" # now translates to: RUN /bin/bash -c "source file"
Additional Note: You could also add --login option which would start a login shell. This means ~/.bashrc for example would be read and you don't need to source it explicitly before your command
Simplest way is to use the dot operator in place of source, which is the sh equivalent of the bash source command:
Instead of:
RUN source /usr/local/bin/virtualenvwrapper.sh
Use:
RUN . /usr/local/bin/virtualenvwrapper.sh
If you are using Docker 1.12 or newer, just use SHELL !
Short Answer:
general:
SHELL ["/bin/bash", "-c"]
for python vituralenv:
SHELL ["/bin/bash", "-c", "source /usr/local/bin/virtualenvwrapper.sh"]
Long Answer:
from https://docs.docker.com/engine/reference/builder/#shell
SHELL ["executable", "parameters"]
The SHELL instruction allows the default shell used for the shell form
of commands to be overridden. The default shell on Linux is
["/bin/sh", "-c"], and on Windows is ["cmd", "/S", "/C"]. The SHELL
instruction must be written in JSON form in a Dockerfile.
The SHELL instruction is particularly useful on Windows where there
are two commonly used and quite different native shells: cmd and
powershell, as well as alternate shells available including sh.
The SHELL instruction can appear multiple times. Each SHELL
instruction overrides all previous SHELL instructions, and affects all
subsequent instructions. For example:
FROM microsoft/windowsservercore
# Executed as cmd /S /C echo default
RUN echo default
# Executed as cmd /S /C powershell -command Write-Host default
RUN powershell -command Write-Host default
# Executed as powershell -command Write-Host hello
SHELL ["powershell", "-command"]
RUN Write-Host hello
# Executed as cmd /S /C echo hello
SHELL ["cmd", "/S"", "/C"]
RUN echo hello
The following instructions can be affected by the SHELL instruction
when the shell form of them is used in a Dockerfile: RUN, CMD and
ENTRYPOINT.
The following example is a common pattern found on Windows which can
be streamlined by using the SHELL instruction:
...
RUN powershell -command Execute-MyCmdlet -param1 "c:\foo.txt"
...
The command invoked by docker will be:
cmd /S /C powershell -command Execute-MyCmdlet -param1 "c:\foo.txt"
This is inefficient for two reasons. First, there is an un-necessary
cmd.exe command processor (aka shell) being invoked. Second, each RUN
instruction in the shell form requires an extra powershell -command
prefixing the command.
To make this more efficient, one of two mechanisms can be employed.
One is to use the JSON form of the RUN command such as:
...
RUN ["powershell", "-command", "Execute-MyCmdlet", "-param1 \"c:\\foo.txt\""]
...
While the JSON form is unambiguous and does not use the un-necessary
cmd.exe, it does require more verbosity through double-quoting and
escaping. The alternate mechanism is to use the SHELL instruction and
the shell form, making a more natural syntax for Windows users,
especially when combined with the escape parser directive:
# escape=`
FROM microsoft/nanoserver
SHELL ["powershell","-command"]
RUN New-Item -ItemType Directory C:\Example
ADD Execute-MyCmdlet.ps1 c:\example\
RUN c:\example\Execute-MyCmdlet -sample 'hello world'
Resulting in:
PS E:\docker\build\shell> docker build -t shell .
Sending build context to Docker daemon 4.096 kB
Step 1/5 : FROM microsoft/nanoserver
---> 22738ff49c6d
Step 2/5 : SHELL powershell -command
---> Running in 6fcdb6855ae2
---> 6331462d4300
Removing intermediate container 6fcdb6855ae2
Step 3/5 : RUN New-Item -ItemType Directory C:\Example
---> Running in d0eef8386e97
Directory: C:\
Mode LastWriteTime Length Name
---- ------------- ------ ----
d----- 10/28/2016 11:26 AM Example
---> 3f2fbf1395d9
Removing intermediate container d0eef8386e97
Step 4/5 : ADD Execute-MyCmdlet.ps1 c:\example\
---> a955b2621c31
Removing intermediate container b825593d39fc
Step 5/5 : RUN c:\example\Execute-MyCmdlet 'hello world'
---> Running in be6d8e63fe75
hello world
---> 8e559e9bf424
Removing intermediate container be6d8e63fe75
Successfully built 8e559e9bf424
PS E:\docker\build\shell>
The SHELL instruction could also be used to modify the way in which a
shell operates. For example, using SHELL cmd /S /C /V:ON|OFF on
Windows, delayed environment variable expansion semantics could be
modified.
The SHELL instruction can also be used on Linux should an alternate
shell be required such as zsh, csh, tcsh and others.
The SHELL feature was added in Docker 1.12.
I had the same problem and in order to execute pip install inside virtualenv I had to use this command:
RUN pip install virtualenv virtualenvwrapper
RUN mkdir -p /opt/virtualenvs
ENV WORKON_HOME /opt/virtualenvs
RUN /bin/bash -c "source /usr/local/bin/virtualenvwrapper.sh \
&& mkvirtualenv myapp \
&& workon myapp \
&& pip install -r /mycode/myapp/requirements.txt"
I hope it helps.
Building on the answers on this page I would add that you have to be aware that each RUN statement runs independently of the others with /bin/sh -c and therefore won't get any environment vars that would normally be sourced in login shells.
The best way I have found so far is to add the script to /etc/bash.bashrc and then invoke each command as bash login.
RUN echo "source /usr/local/bin/virtualenvwrapper.sh" >> /etc/bash.bashrc
RUN /bin/bash --login -c "your command"
You could for instance install and setup virtualenvwrapper, create the virtual env, have it activate when you use a bash login, and then install your python modules into this env:
RUN pip install virtualenv virtualenvwrapper
RUN mkdir -p /opt/virtualenvs
ENV WORKON_HOME /opt/virtualenvs
RUN echo "source /usr/local/bin/virtualenvwrapper.sh" >> /etc/bash.bashrc
RUN /bin/bash --login -c "mkvirtualenv myapp"
RUN echo "workon mpyapp" >> /etc/bash.bashrc
RUN /bin/bash --login -c "pip install ..."
Reading the manual on bash startup files helps understand what is sourced when.
According to https://docs.docker.com/engine/reference/builder/#run the default [Linux] shell for RUN is /bin/sh -c. You appear to be expecting bashisms, so you should use the "exec form" of RUN to specify your shell.
RUN ["/bin/bash", "-c", "source /usr/local/bin/virtualenvwrapper.sh"]
Otherwise, using the "shell form" of RUN and specifying a different shell results in nested shells.
# don't do this...
RUN /bin/bash -c "source /usr/local/bin/virtualenvwrapper.sh"
# because it is the same as this...
RUN ["/bin/sh", "-c", "/bin/bash" "-c" "source /usr/local/bin/virtualenvwrapper.sh"]
If you have more than 1 command that needs a different shell, you should read https://docs.docker.com/engine/reference/builder/#shell and change your default shell by placing this before your RUN commands:
SHELL ["/bin/bash", "-c"]
Finally, if you have placed anything in the root user's .bashrc file that you need, you can add the -l flag to the SHELL or RUN command to make it a login shell and ensure that it gets sourced.
Note: I have intentionally ignored the fact that it is pointless to source a script as the only command in a RUN.
According to Docker documentation
To use a different shell, other than ‘/bin/sh’, use the exec form passing in the desired shell. For example,
RUN ["/bin/bash", "-c", "echo hello"]
See https://docs.docker.com/engine/reference/builder/#run
I also had issues in running source in a Dockerfile
This runs perfectly fine for building CentOS 6.6 Docker container, but gave issues in Debian containers
RUN cd ansible && source ./hacking/env-setup
This is how I tackled it, may not be an elegant way but this is what worked for me
RUN echo "source /ansible/hacking/env-setup" >> /tmp/setup
RUN /bin/bash -C "/tmp/setup"
RUN rm -f /tmp/setup
If you have SHELL available you should go with this answer -- don't use the accepted one, which forces you to put the rest of the dockerfile in one command per this comment.
If you are using an old Docker version and don't have access to SHELL, this will work so long as you don't need anything from .bashrc (which is a rare case in Dockerfiles):
ENTRYPOINT ["bash", "--rcfile", "/usr/local/bin/virtualenvwrapper.sh", "-ci"]
Note the -i is needed to make bash read the rcfile at all.
You might want to run bash -v to see what's being sourced.
I would do the following instead of playing with symlinks:
RUN echo "source /usr/local/bin/virtualenvwrapper.sh" >> /etc/bash.bashrc
This is my solution on "Ubuntu 20.04"
RUN apt -y update
RUN apt -y install curl
SHELL ["/bin/bash", "-c"]
RUN curl -o- https://raw.githubusercontent.com/nvm-sh/nvm/v0.38.0/install.sh | bash
RUN source /root/.bashrc
RUN bash -c ". /root/.nvm/nvm.sh && nvm install v16 && nvm alias default v16 && nvm use default"
This might be happening because source is a built-in to bash rather than a binary somewhere on the filesystem. Is your intention for the script you're sourcing to alter the container afterward?
I ended up putting my env stuff in .profile and mutated SHELL something like
SHELL ["/bin/bash", "-c", "-l"]
# Install ruby version specified in .ruby-version
RUN rvm install $(<.ruby-version)
# Install deps
RUN rvm use $(<.ruby-version) && gem install bundler && bundle install
CMD rvm use $(<.ruby-version) && ./myscript.rb
If you're just trying to use pip to install something into the virtualenv, you can modify the PATH env to look in the virtualenv's bin folder first
ENV PATH="/path/to/venv/bin:${PATH}"
Then any pip install commands that follow in the Dockerfile will find /path/to/venv/bin/pip first and use that, which will install into that virtualenv and not the system python.
Here is an example Dockerfile leveraging several clever techniques to all you to run a full conda environment for every RUN stanza. You can use a similar approach to execute any arbitrary prep in a script file.
Note: there is a lot of nuance when it comes to login/interactive vs nonlogin/noninteractive shells, signals, exec, the way multiple args are handled, quoting, how CMD and ENTRYPOINT interact, and a million other things, so don't be discouraged if when hacking around with these things, stuff goes sideways. I've spent many frustrating hours digging through all manner of literature and I still don't quite get how it all clicks.
## Conda with custom entrypoint from base ubuntu image
## Build with e.g. `docker build -t monoconda .`
## Run with `docker run --rm -it monoconda bash` to drop right into
## the environment `foo` !
FROM ubuntu:18.04
## Install things we need to install more things
RUN apt-get update -qq &&\
apt-get install -qq curl wget git &&\
apt-get install -qq --no-install-recommends \
libssl-dev \
software-properties-common \
&& rm -rf /var/lib/apt/lists/*
## Install miniconda
RUN wget -nv https://repo.anaconda.com/miniconda/Miniconda3-4.7.12-Linux-x86_64.sh -O ~/miniconda.sh && \
/bin/bash ~/miniconda.sh -b -p /opt/conda && \
rm ~/miniconda.sh && \
/opt/conda/bin/conda clean -tipsy && \
ln -s /opt/conda/etc/profile.d/conda.sh /etc/profile.d/conda.sh
## add conda to the path so we can execute it by name
ENV PATH=/opt/conda/bin:$PATH
## Create /entry.sh which will be our new shell entry point. This performs actions to configure the environment
## before starting a new shell (which inherits the env).
## The exec is important! This allows signals to pass
RUN (echo '#!/bin/bash' \
&& echo '__conda_setup="$(/opt/conda/bin/conda shell.bash hook 2> /dev/null)"' \
&& echo 'eval "$__conda_setup"' \
&& echo 'conda activate "${CONDA_TARGET_ENV:-base}"' \
&& echo '>&2 echo "ENTRYPOINT: CONDA_DEFAULT_ENV=${CONDA_DEFAULT_ENV}"' \
&& echo 'exec "$#"'\
) >> /entry.sh && chmod +x /entry.sh
## Tell the docker build process to use this for RUN.
## The default shell on Linux is ["/bin/sh", "-c"], and on Windows is ["cmd", "/S", "/C"]
SHELL ["/entry.sh", "/bin/bash", "-c"]
## Now, every following invocation of RUN will start with the entry script
RUN conda update conda -y
## Create a dummy env
RUN conda create --name foo
## I added this variable such that I have the entry script activate a specific env
ENV CONDA_TARGET_ENV=foo
## This will get installed in the env foo since it gets activated at the start of the RUN stanza
RUN conda install pip
## Configure .bashrc to drop into a conda env and immediately activate our TARGET env
RUN conda init && echo 'conda activate "${CONDA_TARGET_ENV:-base}"' >> ~/.bashrc
ENTRYPOINT ["/entry.sh"]
I've dealing with a similar scenario for an application developed with Django web web framework and these are the steps that worked perfectly for me:
content of my Dockerfile
[mlazo#srvjenkins project_textile]$ cat docker/Dockerfile.debug
FROM malazo/project_textile_ubuntu:latest
ENV PROJECT_DIR=/proyectos/project_textile PROJECT_NAME=project_textile WRAPPER_PATH=/usr/share/virtualenvwrapper/virtualenvwrapper.sh
COPY . ${PROJECT_DIR}/
WORKDIR ${PROJECT_DIR}
RUN echo "source ${WRAPPER_PATH}" > ~/.bashrc
SHELL ["/bin/bash","-c","-l"]
RUN mkvirtualenv -p $(which python3) ${PROJECT_NAME} && \
workon ${PROJECT_NAME} && \
pip3 install -r requirements.txt
EXPOSE 8000
ENTRYPOINT ["tests/container_entrypoint.sh"]
CMD ["public/manage.py","runserver","0:8000"]
content of the ENTRYPOINT file "tests/container_entrypoint.sh":
[mlazo#srvjenkins project_textile]$ cat tests/container_entrypoint.sh
#!/bin/bash
# *-* encoding : UTF-8 *-*
sh tests/deliver_env.sh
source ~/.virtualenvs/project_textile/bin/activate
exec python "$#"
finally, the way I deploy the container was :
[mlazo#srvjenkins project_textile]$ cat ./tests/container_deployment.sh
#!/bin/bash
CONT_NAME="cont_app_server"
IMG_NAME="malazo/project_textile_app"
[ $(docker ps -a |grep -i ${CONT_NAME} |wc -l) -gt 0 ] && docker rm -f ${CONT_NAME}
docker run --name ${CONT_NAME} -p 8000:8000 -e DEBUG=${DEBUG} -e MYSQL_USER=${MYSQL_USER} -e MYSQL_PASSWORD=${MYSQL_PASSWORD} -e MYSQL_HOST=${MYSQL_HOST} -e MYSQL_DATABASE=${MYSQL_DATABASE} -e MYSQL_PORT=${MYSQL_PORT} -d ${IMG_NAME}
I really hope this would be helpful for somebody else.
Greetings,
I had the same issue. If you also use a python base image you can change the shebang line in your shell script to #!/bin/bash.
See for example the container_entrypoint.sh from Manuel Lazo.
Folks,
I'm following the Docker tutorial here: https://docs.docker.com/get-started/part4/#configure-a-docker-machine-shell-to-the-swarm-manager and coming up against resistance when running this particular command:
eval $(docker-machine env myvm1)
I'm actually running (as above but with addition of sudo).
eval $(sudo docker-machine env myvm1)
I get no output from the command line to tell me anything has been done and when I run:
sudo docker-machine ls
I see that myvm1 does not have an active state as expected. I do know that this step isn't necessary but I'd like to understand why the command is not working and try to fix it.
I am running docker 17.09.0-ce
On Ubuntu 16.04 LTS
zsh shell (have tried switching to bash)
This is just on my local machine by the way, not a server.
Any help would be much appreciated.
There's less to go wrong if you run the eval on the far side of sudo:
sudo sh -c 'eval "$(docker-machine env myvm1)"; docker-machine ls'
Otherwise, the environment variables set by evaling the output of docker-machine env aren't necessarily (barring some very specific /etc/sudoers configuration) propagated through to the future docker-machine invocation.
If you wanted to automate this with a shell function, that can be done:
# docker-env sudo; usage: desudo vm-name command-to-run
desudo() {
local cmd1 cmd2
printf -v cmd1 'eval "$(docker-machine env %q)"' "$1"; shift
printf -v cmd2 '%q ' "$#"
sudo bash -c "${cmd1} && exec ${cmd2}"
}
...used as:
desudo vm1 docker-machine ls
You should run eval $(docker-machine env myvm1).
In fact, you don't have to add sudo.
But you may doesn't have permission to run docker without sudo, here is how to solve this issue on Linux.
Following the steps in this article "Post-installation steps for Linux"
Create the docker group. sudo groupadd docker
Add your user to the docker group. sudo usermod -aG docker $USER
Log out and log back in so that your group membership is re-evaluated.
Verify that you can run docker commands without sudo.docker run hello-world.
If you see the following error:
WARNING: Error loading config file: /home/user/.docker/config.json -
stat /home/user/.docker/config.json: permission denied
Fix it with:
$ sudo chown "$USER":"$USER" /home/"$USER"/.docker -R
$ sudo chmod g+rwx "/home/$USER/.docker" -R
I too was having the exact same problem as posted and have spent the better part of the morning googling for an answer. I went back through the documentation and realised that I completely omitted the post-installation steps for Linux.
https://docs.docker.com/install/linux/linux-postinstall/
I followed the instructions laid out in the section labelled Manage Docker as a non-root user and eval $(sudo docker-machine env myvm1) and the subsequent docker-machine ls worked as expected. In addition... it eliminates the need to prefix all your docker commands withsudo.
I should have RTFM I guess?
I'm actually running (as above but with addition of sudo).
eval $(sudo docker-machine env myvm1)
I get no output from the command line to tell me anything has been done and when I run:
sudo docker-machine ls
I see that myvm1 does not have an active state as expected.
run this command it will work
sudo sh -c 'eval "$(docker-machine env myvm1)"; docker-machine ls'
I'm trying to npm install a package in Ubuntu 16.04. I get the following error message:
npm install
...
> padlock#2.0.0-beta.1 bower-install /home/kent/Documents/padlock
> pushd app && bower install && popd app
sh: 1: pushd: not found
My Research
According to /bin/sh: pushd: not found, my problem is clearly that npm install is trying to execute pushd with sh not bash.
However, my default shell is already bash
$ env | grep SHELL
SHELL=/bin/bash
$ echo $SHELL
/bin/bash
$ echo $0
bash
and I'm not sure what I need to change. I've also tried adding SHELL=/bin/bash before I execute pushd app but I have had no luck with that either.
npm-scripts run using sh
Scripts are run by passing the line as a script argument to sh
https://docs.npmjs.com/misc/scripts#exiting
If you want to use bash for your scripts make the script
bash -c 'pushd app && bower install && popd'
Update: As of November 2017 you can now set script-shell in .npmrc to use a custom shell
I was able to work around a similar situation by creating this file in my project directory:
$ cat .npmrc
script-shell=/bin/bash
FWIW, the issue I stumbled upon was relying on bash-specific "curly-brace expansion" commands in the postinstall section of the package.json file for the offending module. That malformed command works in MacOS, but not Linux.
I'm learning to work with linux but it isn't working out
Script 1, did work until I updated opensuse:
#!/bin/bash
useradd Test
passwd Test123
mkhomedir_helper Test
(It now says that all these commands don't exist)
Script 2, I can only get into my MySql console and he doesn't execute everything:
#!/bin/bash
mysql -u root -ppassword
sleep 3
CREATE USER 'Test'#'localhost' IDENTIFIED BY 'password'
I would really appreciate some help here since I'm new to linux
Run following cmd:
echo $PATH
Output should be list some paths as below
/Usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin
If not then run below command:
export PATH="/Usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin"
Now try running above script-1, if it still gives same error, then you are missing some packages, install 'pam' package which contains mkhomedir_helper binaries, so run following command to install pam.
zypper in pam
Script 2, to run mysql query from command line or as a shell script you need to use '-e' option, change the script 2 as below:
#!/bin/bash
mysql -u root -ppassword -e 'CREATE USER "Test"#"localhost" IDENTIFIED BY "password"'