How to access variable from other function in python - python-3.x

Question

I am working on one project and wanted to implement it in OOP. So for that I have craeted one class Person having 2 different methods funcA which returns fullname and funcB which takes varible from funcA and return age.
Now my question is how can i use var2 from function funcA into the funcB.
class Person:
def __init__(self, name):
self.name = name
def funcA(self):
var1 = self.name + "Satav"
var2 = 22
return(var1)
def funcB(self):
return("my age is " + var2)
dc = Person("Mayur")
#first wanted to run funcA
fullname = dc.funcA()
print(fullname)
#then wanted to run funcB
age = funcB()
print(age)
I tried many available solution but got confused. Please apologies for this silly question
I am working on one complex project and because of that it not possible to add entire code here. and that's why i use this dummy scenario

Answer 1

An answer to the edit is to change funcB to:
def funcB(self):
A_VAR = self.funcA
return "my age is " + A_VAR

Answer 2

It would make more sense to make var2 be age and be one of the attributes of the class, that way you could access it in any method that has self in it.
Example:
class Person:
def __init__(self, name, age):
self.name = name
self.age = age
def funcA(self):
var1 = self.name + "Satav"
#since you were only returning var1, var2 was doing nothing here
return(var1)
def funcB(self):
return("my age is " + self.age)
dc = Person("Mayur", 22)
#first wanted to run funcA
fullname = dc.funcA()
print(fullname)
#then wanted to run funcB
age = funcB()
print(age)

Answer 3

After return(var1) in funcA(), put global var2

Answer 4

class Person:
def __init__(self, name):
self.name = name
def funcA(self):
var1 = self.name + "Satav"
self.var2 = 22
return(var1)
def funcB(self):
return("my age is " + str(self.var2))
dc = Person("Mayur")
#first wanted to run funcA
fullname = dc.funcA()
print(fullname)
#then wanted to run funcB
age = dc.funcB()
print(age)
It would be best to set var2 as a local variable of the class instead of one function, as you are calling var2 in another function in another scope. But this here can work.

Answer 5

You can use as follows
def Person(name, age=None):
print('name: {}'.format(name))
if(age is not None):
print('age: {}'.format(age))
else:
print('age: not informed')
And call the function this way
Person('Mayur', 22)
The result
name: Mayur
age: 22
If you call the aged function, this way
Person('Joe')
As defined in the function if you do not enter the age, the function returns
name: Joe
age: not informed

Answer 6

Here try this code-
class Person:
def __init__(self, name):
self.name = name
self.var1 = ''
self.var2 = 0
def funcA(self):
self.var1 = self.name + " Satav"
self.var2 = 22
return(self.var1)
def funcB(self):
return(f"my age is {self.var2}")
dc = Person("Mayur")
#first wanted to run funcA
fullname = dc.funcA()
print(fullname)
#then wanted to run funcB
age = dc.funcB()
print(age)
First of all i have defined the variables in the init menthod so they can be accessed.
And second of all i used f-string to format 'funtB'.
Last of all i fixed some errors in your code.
Cheers!
I Hope the following code helps you further
I have defined the funcB outside of the class. Two values cannot be returned to functA so i have printed them out
def funcB(value):
print(f"my age is {value}")
class Person:
def __init__(self, name):
self.name = name
self.var1 = ''
self.var2 = 0
def funcA(self):
fullname = self.name + " Satav"
print(fullname)
funcB(self.var2)
dc = Person("Mayur")
#first wanted to run funcA
fullname = dc.funcA()