I have a use case where I want to set a systemd-network configuration files in a user defined path.
By default the path is /etc/systemd/network/example.network. Is there any possibility to keep my example.network config file in a different folder for ex:/home/user/network/example.network and to make the systemd to look for .network files in this custom path.
Related
As far as I'm aware I'm using best practices to define paths (using raw strings) and how I go about joining them (using os.path.join()), e.g.
import os
fdir = r'C:\Code\...\samples'
fpath = os.path.join(fdir, 'fname.ext')
and doing so has not caused me any problems when running my code within a Python or command shell. If I print fpath to the console I get consistent use of \s in the path:
C:\Code...\samples\fname.ext
But when I run a Docker containerized version of the code and run the image I get the error:
FileNotFoundError: [Errno 2] No such file or directory:
'C:\Code\...\samples/fname.ext'
I don't understand why os.path.join() has used a / to join fdir and fname.ext when the rest of the path included \\. It doesn't do this when I run the code outside of the container.
I have tried using os.path.normpath():
fpath = os.path.join(fdir, 'fname.ext')
fpath = os.path.normpath(fpath)
as discussed here, and os.sep.join():
fpath = os.sep.join([fdir, 'fname.ext'])
as covered here, and Path().joinpath():
from pathlib import Path
fpath = Path(fdir).joinpath('fname.ext')
as well as Path() / 'path_to_add':
fpath = Path(fdir) / 'fname.ext'
as discussed here, but in every case I end up with the same result using os.path.join().
Can someone please help me to understand what is going on and how to create consistent paths that will work whether I run the code in Python in a Windows environment, or in a Docker container?
Update Nov. 16:
In trying to keep my question brief I think I've left out details that are crucial. Apologies to those who have kindly taken the time to offer suggestions based on my incomplete description of the problem.
My code needs to import/export files from/to directories that are defined within a user-specified configuration file.
So the configuration file has a section of code where the user defines variables and paths, e.g.
samplesDir = r"path-to-samples-directory"
The variables are stored in a dictionary of dictionaris and stored as a .json.
At the start of the code the user defines the key that selects the dictionary of interest so that at various parts in my code when a file needs to be imported/exported, the paths are at hand.
So back to my example, samplesDir is stored in the configuration dictionary, cfgDict, so all I need to do is append the file name:
sampleFpath = os.path.join(sampleDir, sampleFname)
and sampleFname is determined based on other variables.
Because of the dynamic nature of the variables (including directory paths and file paths), I think it rules out the use of static path defined in a .yml with Docker Compose.
Update Nov. 18:
It may help to include a few more details and some screenshots.
The above screenshot shows the file and folder structure of the src directory containing the source code, the main app.py script for command-line use, the Dockerfile, etc.
The configs folder contains JSON files that includes variables, paths to directories and files. The user can create configuration files either by copying an existing one and modifying the entries, or configuration files can be generated by calling config.py.
Within config.py I have pre-set variables and paths, so that the directory path to the configuration files (configs), sample files (sample_DROs) and others (e.g. fiducials) are all within src.
I don't anticipate any reason why the user would want to store the config files anywhere else, nor do I expect them to want to use different sample files (or move them elsewhere). However, they will undoubtedly create their own fiducials and may decide not to store them in the fiducials directory (i.e. somewhere not within the src directory).
Likewise I have pre-set the download directory (based on the parameters stored within the configuration files, files are fetched from a server and downloaded) to be the default Downloads directory:
rootDownloadDir = os.path.join(Path.home(), "Downloads", "xnat_downloads")
Those files are later imported, processed, and the outputs are (by default) exported into sub-directories within rootDownloadDir.
Within Dockerfile I set the working directory of the container to be that of the source code and copy all of the contents of src (with the exception of some directories defined in .dockerignore):
WORKDIR C:/Code/WP1.3_multiple_modalities/src
...
COPY . .
so that the structure of the container mimics that of WORKDIR:
Hence I have allowed for flexibility in import/export directories, and they are by default a combination of paths within and outside of the src directory. And so, the code executed within the container will need to access files both within and outside of src.
That said, I don't know what rootDownloadDir will look like when os.path.join(Path.home(), "Downloads", "xnat_downloads") is run within the container.
This has got me thinking - Is it bad practice to set the download directory outside of src?
Returning to the original error:
the sample file is in the container:
From the actual behavior I can suppose that the container is based on Unix-like image. Path separator is / in such systems.
To build an environment-independent path which works inside and outside of the container you need the following steps:
Mounting of host folder to container directory.
Environment variable inside and outside the container.
I can show an example of how this is achievable via docker-compose tool and its configuration file docker-compose.yml:
# docker-compose.yml file
version: '3'
services:
<service_name>: # your service name here
image: <image_name> # name of image your container is built on
environment:
- SAMPLES_PATH=/samples
volumes:
- C:\Code\somepath\samples:/samples
In your python code you can use the following structure:
import os
fdir = os.getenv('SAMPLES_PATH', r'C:\Code\...\samples')
fpath = os.path.join(fdir, 'fname.ext')
I already have the relative path: /home/Folder1/Folder2 which its original absolute path is /home/user1/Folder1/Folder2. And I have several scripts that are using /home/Folder1/Folder2. Now, I need to delete user1 so I created user2 with the same structure of user1 so now I have a new path which is /home/user2/Folder1/Folder2. If I delete user1, my scripts will then fail because they are using the relative path /home/Folder1/Folder2 which its original absolute path is /home/user1/Folder1/Folder2. So I want my new path /home/user2/Folder1/Folder2 to point to /home/Folder1/Folder2 so that my scripts won't fail and I don't want to go through the trouble of opening each script and change the relative path to my new created path. Any idea how I can do this?
I guess, you got confused between soft links and absolute/relative path.
I assume you have a soft link created from "/home/Folder1/Folder2" pointing to "/home/user1/Folder1/Folder2" and you want to delete user1 directory and create user2 directory with same structure. If my assumption is right, recreate the softlink "/home/Folder1/Folder2" to point to "/home/user2/Folder1/Folder2". Your existing scripts will work seamlessly.
I have a file that is required in many other files, that are on different folders, inside the main directory.
Is there a way to just require the filename without having to write the relative path, or the absolute path? Like require('the_file'). And without having to go to npm and install it?
Create a folder inside your main directory , put the_file.js inside and set the NODE_PATH variable to this folder.
Example :
Let's say you create a ./libs folder within your main directory, you can just use :
export NODE_PATH = /.../main/lib
after that, you can require any module inside this directory using just :
var thefile = require('the_file')
To not have to do that every time, you'd have to add the variable to your .bashrc (assuming you're running a Unix system).
Or you can set a global variable inside your app.js file and store the path of your 'the_file' in it like so :
global.rootPath = __dirname;
Then you can require from any of your files using :
var thefile = require(rootPath+'/the_file')
These are the most convenient methods for me, short of creating a private npm, but there are a few other alternatives that I discovered when looking up an answer to your question, have a look here : https://gist.github.com/branneman/8048520
I'm installing a package from a module (Nginx in this specific case) and would like to include a configuration file from outside of the module, i.e. from a top level files directory parallel to the top level manifests directory. I don't see any way to source the file though without including it in a module or in my current Vagrant environment referring to the absolute local path.
Does Puppet allow for sourcing files from outside of modules as described in the documentation?
if I understand your question correctly, you can.
In your module a simple code like this
file { '/path/to/file':
ensure => present,
source => [
"puppet:///files/${fqdn}/path/to/file",
"puppet:///files/${hostgroup}/path/to/file",
"puppet:///files/${domain}/path/to/file",
"puppet:///files/global/path/to/file",
],
}
will do the job. The /path/to/file will be sourced using a file located in the "files" Puppet share.
(in the example above, it search in 4 different locations).
update maybe you're talking about a directory to store files which is not shared by Puppet fileserver (look at http://docs.puppetlabs.com/guides/file_serving.html), and in this case you can't i think, Vagrant or not, but you can add it to your Puppet fileserver to do it. I thinks it's the best (and maybe only) way to do it.
If you have a number of Vagrant VMs you can simply store files within your Vagrant project directory (containing your VagrantFile).
This directory is usually available to all VMs as /vagrant within the VM on creation.
If you want other directories on your computer to be available to your VMs just add the following to your VagrantFile
# see http://docs.vagrantup.com/v1/docs/config/vm/share_folder.html
config.vm.share_folder "v-packages", "/vagrant_packages", "../../dpkg"
Then to use the files within puppet you can simply treat them as local files to the VM
# bad example, bub basically use 'source => 'file:///vagrant/foo/bar'
file { '/opt/cassandra':
ensure => directory,
replace => true,
purge => true,
recurse => true,
source => 'file:///vagrant/conf/dist/apache-cassandra-1.2.0',
}
This is probably only wise to do if you only using local puppet manifests/modules.
Probably too late to help bennylope, but for others who happen across this question, as I did before figuring it out for myself ...
Include stuff like this in your Vagrantfile ...
GUEST_PROVISIONER_CONFDIR = "/example/destination/path"
HOST_PROVISIONER_CONFDIR = "/example/source/path"
config.vm.synced_folder HOST_PROVISIONER_CONFIDIR, GUEST_PROVISIONER_CONFDIR
puppet.options = "--fileserverconfig='#{GUEST_PROVISIONER_CONFDIR}/fileserver.conf'"
Then make sure /example/source/path contains the referenced fileserver.conf file. It should look something like ...
[foo]
path /example/destination/path
allow *
Now, assuming example-file.txt exists in /example/source/path, the following will work in your manifests:
source => "puppet:///foo/example-file.txt",
See:
Puppet configuration reference entry for fileserverconfig
Serving Files From Custom Mount Points
I'm packaging up a rails app with warbler and I want app specific logging. I've added the log4j and commons-loggin jar to the WEB-INF/lib directory, and I want to add log4j.properties to the WEB-INF/classes directory. The problem is, I also want environment specific logging, so my staging/production use different properties (ie. INFO instead of DEBUG) than my devel. I can't just do a:
config.java_classes = FileList["lib/log4j-#{RAILS_ENV}.properties"]
because Tomcat seems to look for the specific file log4j.properties. Is there any way to get warbler to rename this file to just log4j.properties? Or is there a better mechanism for app specific, environment specific logging?
And for the final answer. RAILS_ENV doesn't seem to work in warbler, but looking through the docs on warble config, there's a webxml attribute that contains rails.env, modifying my code to pull the file like:
config.java_classes = FileList["lib/properties/log4j.properties.#{config.webxml.rails.env}"]
Worked like a charm!
Guess I should just read further down in the warble file itself. You can configure pathmaps for the java_classes. Here's what I used:
config.java_classes = FileList["lib/properties/log4j.properties.#{RAILS_ENV}"]
config.pathmaps.java_classes << "%n"
The only problem I've found is that this doesn't actually put the log4j.properties in the WEB-INF/classes directory anymore. It now puts it in the Root. Seems odd that it specifically says in the docs:
One or more pathmaps defining how the java classes should be copied into WEB-INF/classes
I wouldn't think I'd have to add in that WEB-INF/classes path manually but I did. So finally then, this worked:
config.java_classes = FileList["lib/properties/log4j.properties.#{RAILS_ENV}"]
config.pathmaps.java_classes << "WEB-INF/classes/%n"
using the files log4j.properties.#{RAILS_ENV} in the lib/properties directory