Excel IF Function with LEFT Function criteria - excel

I am using GOOGLE SHEETS and I am trying to manipulate received data in the following way:
In column A, I have a number. In column B I have a department. In column C I change the number to concatenate with the first letter of column B's value ONLY IF the number starts with 36. If it doesn't it simply returns the new number as the original number. I had to use the SEARCH function because IF LEFT
is not working here, so the issue is if changes the number wherever it finds a 36, instead of just those numbers starting with 36. Any assistance will be highly appreciated.
This formula is used in column C :
=IFERROR(IF(SEARCH("36",A2),CONCATENATE(A2,LEFT(B2,1)),A2),A2)
Here is the IF LEFT function that I've tried :
=IFERROR(IF(LEFT(A2,2) = "36",CONCATENATE(A2,LEFT(B2,1)),A2),A2)
(If errors occur or the old number doesn't start with 36 the new number should remain the original)
Thanks in advance
Edit: Changed LEFT function to correct ranges, forgot to edit this in initially when asking the question.

Give this a try:
=IF(LEFT(A2,2)="36",A2 & LEFT(B2,1),A2)
This approach does not use IFERROR() or CONCATENATE().It assumes your version of Excel uses the English version of the function names and uses , as the argument separator.

=IF(LEFT(A2,2)="36",CONCATENATE(A2,LEFT(B2,1)),A2)

=A2 & LEFT(B2, LEFT(A2, 2)="36")
This is a 'golfed' answer: made as short as possible (although, I have left the spaces in for readability)
If the first 2 characters of cell A2 are "36", then LEFT(A2, 2)="36" will be True. Otherwise, LEFT(A2, 2)="36" will be False.
Excel will treat True and False as 1 and 0 - so, the LEFT(B2, LEFT(A2, 2)="36") will take either the first character from cell B2, or no characters from cell B2, and add that to the end of the value from cell A2.

Related

Need to count contents of cells to produce a knitting pattern

So this needs a bit of detail:
n,X,X,X,n is in cells B5 to F5
I need to get the following output:
1n,3x,1n
for this particular row.
Now the n's and X's represent stitches in knitting with the "n" being the background color and the "x" being the front color.
There is an array of cells B5:F12 representing the rows and stitches, so each row will have a different arrangement of stitches or background color.
I need to avoid vba as this needs to be as stable as possible with the user being my Mum who is 90 years old :) and all she needs is a place to enter the name and the layout (which I have done) and a pattern list for each row (also sorted).
I have started to consider things like:
if(B5=C5,1&B5,"")
But given the n umber of combinations that becomes very long.
Any ideas? Cheers.
You could try:
Formula in H5:
=BYROW(B5:F12,LAMBDA(x,LET(z,REDUCE(VSTACK(TAKE(x,,1),1),DROP(x,,1),LAMBDA(a,b,IF(b=#TAKE(a,,-1),IF(COLUMNS(a)=1,VSTACK(b,TAKE(a,-1)+1),HSTACK(DROP(a,,-1),VSTACK(b,DROP(TAKE(a,,-1),1)+1))),HSTACK(a,VSTACK(b,1))))),TEXTJOIN(",",,DROP(z,1)&TAKE(z,1)))))
I'll see if I can golf the bytecount down a bit...
EDIT:
After a considerable amount of golfing (came down to 119), I came up with:
=BYROW(B5:F12,LAMBDA(x,MID(REDUCE("",x,LAMBDA(a,b,IF(RIGHT(a)=b,LEFT(a,LEN(a)-2)&1+LEFT(RIGHT(a,2)),a&",1")&b)),2,99)))
Though less dynamic than the 1st one, but possible due to the fact there are only <10 columns for each knitting pattern.
If your mother doesn't have the latest Excel (with LAMBDA etc), here is an alternative to #JvdV's answer which only uses LET,SEQUENCE and FILTER.
It only accepts a single row, so you'd need to fill the formula down.
=LET(p,LOWER(B5:F5),c,COLUMNS(p),s,SEQUENCE(,c),
a,IF(s=c,c,IF(INDEX(p,,s)<>INDEX(p,s+1),s,0)),
b,FILTER(a,a>0),t,SEQUENCE(,COLUMNS(b)),
n,IF(t=1,INDEX(b,,t),INDEX(b,,t)-INDEX(b,,t-1)),
TEXTJOIN(",",TRUE,n & INDEX(p,,b)))
I might add that it allows for adding more than one colour into the pattern ...
and with a bit of conditional formatting, the good lady can design her own multicolour patterns!
This is just a start of a solution, but in cell "B6" you can put the formula:
=(IF(B5=A5,A6+1,1))
This will generate following list:
B C D E F
5: n x x x n
6: 1 1 2 3 1
From there, you can try to get the Subtotals feature to work, based on the Max formula, ... (as I said, this is just a start).
If you are willing to spread the logic over multiple sheets, it's quite easy to come up with a way to do this. Consider a workbook with three sheets:
Pattern
EqualPrevCol, where each cell of Pattern is checked for equality against the previous column of the same row.
The formula for cell EqualPrevCol!D3 is:
=Pattern!D3=Pattern!C3
And finally PatternResult, where most of the logic resides:
Consider one row of EqualPrevCol:
At every FALSE column, we want to know how many columns until the next FALSE. To do this, we want to find the next exact MATCH for D3 in the rest of the row:
=MATCH(EqualPrevCol!D3, EqualPrevCol!E3:$H3, 0)
If no match is found, that means the rest of the row is all TRUE. In this situation, we want to return the length of the rest of the row plus this current cell.
=IFNA(MATCH(...), COLUMNS(D3:$H3))
And finally, we append this to the current character:
=IFNA(...) & Pattern!D3
Also, if the 7 row at this column is TRUE, we want to keep this blank:
=IF(EqualPrevCol!D3, "", IFNA(...) & ...)
The full formula of cell PatternResult!D3 is:
=IF(EqualPrevCol!D3, "", IFNA(MATCH(EqualPrevCol!D3, EqualPrevCol!E3:$H3, 0), COLUMNS(D3:$H3)) & Pattern!D3)
Finally, the pattern is condensed to the Pattern sheet. The Pattern!B3 cell contains:
=TEXTJOIN(", ", TRUE, PatternResult!D3:$H3)
To scale this up, you simply need to change all occurrences of $H in the formulas (this was a reference to the last column) and re-fill the cells on the latter two sheets.

How to extract text from excel cell

having this data in excel cell
kerass(xcvbn=2, abcdefg_iD='510863005')
having 100000 of records so, how to extract id number using excel formula from that excel sheet
Thanks in advance
Assuming your value is in cell A2. Here is a formula to be inserted
=SUBSTITUTE(RIGHT(A2,LEN(A2)-SEARCH("_iD='",A2)-4),"')","")
This means:
Search for "_iD='"
Once found, subtract the length of "_iD='" of that location (hence the 4)
Use the total length of the string, subtracted with location and 4, in order to find where the actual identifier begins
Take the right part of the string, only the part behind "_id='...'" remains
In that part, replace "')" by an empty string (otherwise you get "...005')"
Alternative answer:
=MID(A1,FIND("'",A1)+1,9)
The find formula finds the first "'" starting position
Assuming all the ID's are 9 digits, the MID formula uses the starting pos. from find and takes the following 9 digits.
So assuming your text is in cell A2, and that the id is the first 9 characters of the last 11 then this is the simplest I can think of:
=LEFT(RIGHT(A2,11),9)
But if extra characters get added or the ID changes length.
Does have the benefit of being minimalist on functions and low volativity.

SumProduct, doesn't return me text and number. (Only Number)

At first thanks to answer)) (It's important for me :p )
I have a number in A3.
When there is this number in column A (Sheet1), per exemple A7 then it will take the value of the cell B7.
=SOMMEPROD(('Sheet1'!A3:A34=Sheet1!A3)*('Sheet1'!B3:B34))
I use SOMMEPROD, it's working but only with number, and sometimes I have text and number in my cell (column B).
I already changed the format of the cell but doesn't work.
Thanks a lot)))
I think you are saying that some of the values in column B are expressed as text, not as a number, probably because they were imported from another source.
if that is the case: First, convert column B into numbers, Then, use sumproduct.
For example, FIRST convert text to values:
in C3 you would enter
=value(b3)
Then copy that down to from C3 to C34.
Then
=SOMMEPROD(('Sheet1'!A3:A34=Sheet1!A3)*('Sheet1'!C3:C34))
should have the desired effect.
Note that you sometime get #N/A errors with the "value" function, for example if there are unexpected spaces. To be safe, rather than using value alone, try this:
= iferror(value(B3),0)
or to be more creative you can try:
= iferror(value(substitute(B3," ","")),0) ' deletes all spaces
= iferror(value(substitute(substitute(b3,char(160),"")," ","")),0)
'deletes all spaces and "nonbreaking spaces" copied from a web page
It depends on what you're trying to use SumProduct for. There's two main reasons this function shows up. Those are:
To sum the product of two ranges.
To sum a range of numbers that meet multiple criteria. This relies on that True = 1 and False = 0 so when want to find the combined weight of blue dogs in some cells, your formula might look like =SUMPRODUCT(1*($A$1:$A$50 = "Blue"), 1*($B$1:$B$50 = "Dog"), $C$1:$C$50). Note the 1* which guarantees the formula will know how to multiply the results. After all, True and False don't multiply. Their binary representations (1 and 0) though, do.
NB though that people also sometimes remember it as a lookup formula because of the second use, and therefore expect to be able to get text back. Such approaches are an easy misunderstanding to end up with, but really there you want to use an INDEX(<Result Array>,MATCH(1,INDEX(1 * (FIRST CONDITION) * (SECOND CONDITION) * (AND SO ON),,),0). This approach basically gives you an array formula without CTRL-SHIFT-ENTER (it's not faster, but because the condition is in an index formula, it works), and your conditions can be arbitrary (the same way as for sumproduct). But it'll give you the FIRST result, not the sum of all of them.
Hope that helps.
Edit: Crossed my mind, you might be expecting A1 to contain Erp and B1 to contain 54, and in C1 you want Erp54. This doesn't even need a function - just the & operator, which joins two strings together - so in C1, you'd just put =A1 & B1. And you're done.

Looking up a value in a specified column

Something I've wanted to do quite a bit lately, and can't work out how to do, is MATCH in a column I pass as an argument. Essentially, I have a two dimensional array, and I want to be able to find the first occurrence of a given value in the nth column, for any given value of n, and return the row number it occurs at. Alternatively (and more-or-less equivalently), I want to be able to search in the column with a given column header. Is there any way to do this?
Effectively, I want to simulate the non-existent function =MATCH(lookup_value,lookup_array,lookup_column,[match_type])
I've kludged together a horrible bodge job using INDIRECT, which works, but offends me horribly.
=MATCH(lookup_value,INDIRECT("R"&<top of array>&"C"&<left of array>+<column reference>&":R"&<bottom of array>&"C"&<left of array>+<column reference>,FALSE),FALSE)
This formula should work for you and will avoid INDIRECT. Anytime you can avoid using Indirect, I recommend doing so.
=MATCH(lookup_value,INDEX(lookup_array,0,MATCH(lookup_header,array_headers,0)),0)
If you aren't looking up the column by column header and just have the column number, then it becomes easier:
=MATCH(lookup_value,INDEX(lookup_array,0,column_number),0)
You could do something like this:
Set findCell = ActiveSheet.Range("A:Z").Find(What:="term_to_search")
Will select a header based on your search term.
Set range = ActiveSheet.Range(findCell, findCell.Offset(DEF_MAX_ROWS, 0))
Set up a range which will search from that header down a whole column.
For column references beyond Z you might switch notation (Excel Options, Formulas, Working with formulas and check R1C1 reference style) and, assuming the value to be looked up is in 'A1' (R1C1) with the column number in 'A2' (R2C1) apply:
=MATCH(R1C1,INDIRECT("C"&R2C1,0),0)
to save some complexity in converting a string of two or three characters into the relevant column number.
Say we have a two dimensional array: B3:E17 and we wish to locate Happiness in the third column of that array.In G1 enter:
B3:E17
In G2 enter:
3
In G3 enter:
=ADDRESS(ROW(INDIRECT(G1)),COLUMN(INDIRECT(G1))+$G$2-1) & ":" & ADDRESS(ROW(INDIRECT(G1))+ROWS(INDIRECT(G1))-1,COLUMN(INDIRECT(G1))+$G$2-1)
This will display the address of that third column. Then in G4 enter:
=MATCH("Happiness",INDIRECT(G3),0)
For example:
You can specify a range in a formula using the INDIRECT function. So, for example, if you put the letter designation for the column you want to search in cell A75, you could use:
=MATCH("Value_To_Match", INDIRECT(A75 & ":" & A75), 0)
So, if the value in A75 is G, the string built up in the INDIRECT call is G:G, and the MATCH will look through column G for "Value_To_Match" and return the row number in which it's found.
Using this idea, you can put a formula into A75 that generates the column designation for the column you want to search. For example, if your column headers are all in row 1, and the header you want to search for is in A74, you can do:
=CHAR(MATCH(A74, 1:1, 0) + 64)
using the CHAR function to convert numbers into ASCII characters, so 65 becomes A, 66 becomes B, etc. Note that this will only work if you don't have columns past Z. You'd need a more fussy formula to do the right thing with AA, etc.
You can overcome the annoyances of dealing with column letters by using R1C1 notation instead, which you can activate by adding a second parameter of FALSE to the INDIRECT expression. Now, instead of specifying your column by a letter, you'll specify it using a number. This simplifies the column-finder in A75:
=MATCH(A74, 1:1, 0)
and also the INDIRECT expression in your overall MATCH:
=MATCH("Value_To_Match", INDIRECT("C" & A75, FALSE), 0)

Conditional Min and Max in Excel 2010

I would like to find Min and Max of Quantity (Column 2) based on Type (coloumn 1), is it possible to have this done?
I have tried this but the result was unexpected
Similar question
Assuming your data above is in A2:B13, this works:
=MAX(IF(A2:A13="A",1,0)*(B2:B13))
=MAX(IF(A2:A13="B",1,0)*(B2:B13))
=MAX(IF(A2:A13="C",1,0)*(B2:B13))
You have to press ctrl+shft+Enter when you enter the formula into a cell. This finds all rows with the A, B, or C, and multiplies 1 with the value next to it if the letter matches your formula, and 0 if it doesn't match. Then you take the MAX() of the values.
<<< Edit >>>
As #GSerg suggested, you can also do it with these formulas, if you press ctrl+shft+Enter when entering them into each cell:
=MAX(IF(A:A="A",B:B))
=MAX(IF(A:A="B",B:B))
=MAX(IF(A:A="C",B:B))
A much more elegant way of doing it!
Anything other than a PivotTable (as suggested by #andy holaday) seems sheer masochism (unless for a very good but presumably very peculiar reason):
Note that for illustration I doubled the OP's data quantities for B and these again for C.
This works without ctrl+shift+enter, but your table should be sorted by a TYPE column.
Let's assume that your table is placed in B3:C15, then in A4 put
=IF(B4=B3;A3;A3+1)
in E4 - "1", in E5 - "2" , in E6 - "3", in F4 put:
=MAX(INDIRECT("C" & MATCH(E4;$A$1:$A$17;0) & ":C" & MATCH(E4;$A$1:$A$17;1) ))
and copy it to F5 and F6
in G4 put:
=MIN(INDIRECT("C" & MATCH(E4;$A$1:$A$17;0) & ":C" & MATCH(E4;$A$1:$A$17;1) ))
and copy it to G5 and G6
MATCH function handles strings incorrectly, so I had to number TYPEs, you can use VLOOKUP to change numbers in column E to a strings
In my table I used this solution to find strings with maximum values this way:
A rather sneaky but simple way to do it is
1. create a new column that concatenates both Type and Qty and Call it "TypeQty" or whatever you'd like
2. Sort (Ascending) the new table ie Type,Qty and TypeQty all together but sort on the TypeQty column.
3. apply a formulat that checks if the type in the row above is the same as the current row. if not then mark that row because its the last of the current type.
you will end up with the "mark" only the max rows for each type.
See screenshots
#JamesL's solution always resulted in zero for me when attempting
=MIN(IF(A2:A13="A",1,0)*(B2:B13))
If I set it up with an arbitrarily large number for the false result, then it worked
=MIN(IF(A2:A13="A",1,99999)*(B2:B13))
However, #GSerg's elegant solution also works for the min:
=MIN(IF(A:A="A",B:B))
I would suggest to use =large(if(...=...;...);k) to solve that problem.

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