I'm trying to perform a Keys.ARROW_DOWN in selenium but it doesn't want to work, the code open the context menu, but the key arrow_down don't work, example of what I'm doing:
from selenium import webdriver
from selenium.webdriver import ActionChains
from selenium.webdriver.common.keys import Keys
import time
driver = webdriver.Chrome()
driver.get('http://www.google.com.br')
time.sleep(1)
actions = ActionChains(driver)
actions.context_click().send_keys(Keys.ARROW_DOWN).perform()
chromedriver version 83
Someone can give me a light please of what I'm doing wrong?
Thanks for the help!
You can achieve with the help of pyautogui as shown in the below code
import time
import pyautogui
from selenium import webdriver
from selenium.webdriver import ActionChains
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.keys import Keys
options = webdriver.ChromeOptions()
options.add_argument( "user-data-dir=C:\\Users\\Sangeeta-Laptop\\AppData\\Local\\Google\\Chrome\\User Data\\Guest Profile");
cdriver = "C:\\Users\\Sangeeta-Laptop\\Downloads\\chromedriver_win32 (4)\\chromedriver"
driver = webdriver.Chrome(executable_path=cdriver, chrome_options=options)
driver.get('http://www.google.com.br')
time.sleep(1)
actions = ActionChains(driver)
actions.context_click().perform()
time.sleep(1)
pyautogui.press("down");
But as 0buz said in the comment, there are multiple ways to achieve your requirement. So please tell us what are you trying to achieve in detail and maybe we all will help you to resolve your issue :)
Keys.ARROW_DOWN within Context Menu
Context Menu initiated through context_click() is generally invoked on a WebElement e.g. a link.
Invoking context_click() on a element opens a browser native context menu which is a browser native operation and can't be managed by Selenium by design.
Conclusion
Using Selenium you won't be able to interact with browser native context menu items using send_keys(Keys.ARROW_DOWN), send_keys(Keys.DOWN), etc.
Reference
You can find a relevant discussion in:
Could not do Arrow down using sendKeys(Keys.ARROW_DOWN) in chrome
When you perform keys.ARROW_DOWN you should enter values into field then you can perform action.
Related
ENV
Python 3.10
Selenium 4
Hi,
I use :
def findAllByXPath(p_driver, xpath, time=5):
try:
#return WebDriverWait(p_driver, time).until(EC.presence_of_all_elements_located((By.XPATH, (xpath))))
return WebDriverWait(p_driver, time).until(EC.presence_of_all_elements_located((By.XPATH, xpath)))
except Exception as ex:
print(f"ERROR findAllByXPath : {ex}")
posts = findAllByXPath(p_driver,"//article//a",2)
for index in range(0,len(posts)):
p_driver.execute_script("arguments[0].scrollIntoView()", posts[index])
time.sleep(random.uniform(0.5, 0.8))
action.move_to_element(posts[index]).perform()
To make a mouse over and try to get elements.
I am trying to get the number of comments on an Instagram post from a page profile.
If you pass manually the mouse over a post, the number of comments or likes is displayed.
But when I try to do it in python, it doesn't find the element.
I tried the XPath from console
$x(//article//li//span[string-length(text())>0]")
It gives results when I freeze the browser with F8.
action.move_to_element(post).perform() doesn't work? I suspect this version 4.3.0 removed many functions like ActionChains from the Selenium version 3, didn't it?
How can I extract this element?
Or Am I doing something wrong?
ActionChains works nicely in Selenium v4!
I don't have an Instagram account so I cannot try there but you can see by running this code that move_to_element() works and how it works.
The About button (top left corner of stackoverflow homepage) get highlighted.
Remember to don't move your mouse while running of course!
from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
driver = webdriver.Firefox()
actions = ActionChains(driver)
driver.get("https://stackoverflow.com/")
about_button = WebDriverWait(driver, 30).until(EC.visibility_of_element_located((By.XPATH, "//a[#href='https://stackoverflow.co/']")))
actions.move_to_element(about_button)
actions.perform()
EDIT: I am using Selenium 4.4.3 and Python 3.10 but it should work with Selenium 4.3.0 as well.
I am working on Ubuntu and writing a web automation script which can open a page and zoom in the page. I am using python selenium. Below is the code:
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait
from selenium import webdriver
from selenium.webdriver.common.by import By
import time
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("https://www.wikipedia.org/")
driver.maximize_window()
time.sleep(2)
This opens the browser and opens the wikipedia page. Now I have to do the zoom in functionality. For this I tried below line of code:
driver.execute_script("document.body.style.zoom='150%'")
It didn't work. So I tried below line of code:
driver.execute_script('document.body.style.MozTransform = "scale(1.50)";')
driver.execute_script('document.body.style.MozTransformOrigin = "0 0";')
It kind of worked but the webpage height and width were disturbed and it looks like below:
It should look like below:
Can anyone please suggest some good working solution to zoom in a webpage using python selenium in FireFox.
I didn't find any working solution so what I did is, I used pyautogui to simulate the keys.
pyautogui.keyDown('ctrl')
pyautogui.press('+')
pyautogui.keyUp('ctrl')
This made the webpage zoom to 110%. You can run it again to make it to 120% and so on.
Thanks
I'm trying to automate some tedious copy / paste I do monthly from my bank's online service via Selenium and Python 3. Unfortunately, I can't get Selenium to click the log-in link.
It's the blue continue button at https://www1.bmo.com/onlinebanking/cgi-bin/netbnx/NBmain?product=5.
Strangely, when I try to click that link manually in the browser launched by Selenium, it doesn't work either - whereas it does work in a browser I launch manually.
I suspect the issue is that the bank's website is smart enough to detect that I'm automating the browser activity. Is there any way to get around that?
If not, could it be something else?
I've tried using Chrome and Firefox - to no avail. I'm using a 64 bit Windows 10 machine with Chrome 73.0.3683.103 and Firefox 66.0.
Relevant code is below.
#websites and log in information
bmo_login_path = 'https://www1.bmo.com/onlinebanking/cgi-bin/netbnx/NBmain?product=5'
bmo_un = 'fake_user_name'
bmo_pw = 'fake_password'
#Selenium setup
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import time
chrome_driver_path = 'C:\\Path\\To\\Driver\\chromedriver.exe'
gecko_driver_path = 'C:\\Path\\To\\Driver\\geckodriver.exe'
browswer_bmo = webdriver.Firefox(executable_path = gecko_driver_path)
#browswer_bmo = webdriver.Chrome(executable_path = chrome_driver_path)
#log into BMO
browswer_bmo.get(bmo_login_path)
time.sleep(5)
browswer_bmo.find_element_by_id('siBankCard').send_keys(bmo_un)
browswer_bmo.find_element_by_id('regSignInPassword').send_keys(bmo_pw)
browswer_bmo.find_element_by_id('btnBankCardContinueNoCache1').click()
Sending the keys works perfectly. I may actually have the wrong element ID (I was trying to test that in Chrome when I realized I couldn't click the link manually) - but I think the bigger issue is that I can't manually click the link in the browser launched by Selenium. Thank you for any ideas.
EDIT
This is a screenshot that I get of all I get when I try to click the continue button.
Ultimately the error message I get in my IDE (Jupyter Notebook) is:
TimeoutException: Message: timeout
(Session info: chrome=74.0.3729.108)
(Driver info: chromedriver=74.0.3729.6 (255758eccf3d244491b8a1317aa76e1ce10d57e9-refs/branch-heads/3729#{#29}),platform=Windows NT 10.0.17134 x86_64)
To click on the button with text as Continue you can fill up the Card Number and Password field inducing WebDriverWait for the element_to_be_clickable() and you can use the following solution:
Code Block:
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
options = webdriver.ChromeOptions()
options.add_argument('start-maximized')
options.add_argument('disable-infobars')
options.add_argument('--disable-extensions')
driver = webdriver.Chrome(chrome_options=options, executable_path=r'C:\WebDrivers\chromedriver.exe')
driver.get('https://www1.bmo.com/onlinebanking/cgi-bin/netbnx/NBmain?product=5')
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input.dijitReset.dijitInputInner#siBankCard[name='FBC_Number']"))).send_keys("1234567890112233")
driver.find_element_by_css_selector("input.dijitReset.dijitInputInner#regSignInPassword[name='FBC_Password']").send_keys("fake_password")
driver.find_element_by_css_selector("span.dijitReset.dijitInline.dijitIcon.dijitNoIcon").click()
# driver.quit()
Browser Snapshot:
I was able to fix this issue and solve the problem by adding the following line below the options variables. This disables the chrome check for automation. I used the whole sale code and then added the following line in the correct location before starting the driver.
options.add_experimental_option("excludeSwitches", ['enable-automation'])
ref: https://help.applitools.com/hc/en-us/articles/360007189411--Chrome-is-being-controlled-by-automated-test-software-notification
I am trying to locate a search box with id as (search2) from a website. I have been able to successfully login to the website using the below code.
import requests
from tqdm import tqdm
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
options = webdriver.ChromeOptions()
driver = webdriver.Chrome(executable_path=r'C:\chromedriver_win32\chromedriver.exe', chrome_options=options)
driver.implicitly_wait(30)
tgt = "C:\\mypath"
profile = {"plugins.plugins_list": [{"enabled":False, "name":"Chrome PDF Viewer"}],
"download.default_directory" : tgt}
options.add_experimental_option("prefs",profile)
print(options)
driver.get("http://mylink.com/")
user=driver.find_element_by_id("username")
passw=driver.find_element_by_id("password")
user.send_keys("abc#xyz.com")
passw.send_keys("Pwd")
driver.find_element_by_xpath('/html/body/div[2]/div/div/div[2]/form/div[3]/button').click()
page=driver.find_element_by_id("search2")
print(page)
The code works perfectly till here but the moment I add the below to it I get an error
page.send_keys("abc")
The error that I get is as below.
selenium.common.exceptions.StaleElementReferenceException: Message: stale element reference: element is not attached to the page document
What I am trying to do here is login to the website and search for some items and download the results. I have already tried using the implicitly wait options as mentioned in the code. Any help would be highly appreciated.
Adding the below piece of code did the trick. Had to make the current thread sleep while the program continues to run the next steps.
time.sleep(5)
Thanks everyone.
I want to search a special keyword in Instagram. For example, I want to search this word:"fast food". I can send this key in search box. But, when I use submit method in Selenium by Python3, it doesn't work and give me error. This is my code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.alert import Alert
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support import expected_conditions as EC
import time
driver = webdriver.Firefox()
url="https://www.instagram.com/p/pTPI-kyX7g/?tagged=resurant"
driver.get(url)
#login_button=driver.find_element_by_xpath("""/html/body/span/section/main/article/div[2]/div[2]/p/a""")
#login_button.click()
import time
driver.implicitly_wait(5)
search_button=driver.find_element_by_xpath("""/html/body/span/section/nav/div[2]/div/div/div[2]/input""")
search_button.send_keys("fast food")
search_button.submit()
This is gave error:
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: ./ancestor-or-self::form
Could you help me?
Instead of. submit() try '.send_keys(u'\ue007')'
See: http://selenium-python.readthedocs.io/api.html#module-selenium.webdriver.common.keys
It need more clicks:
search_button=driver.find_element_by_xpath("""/html/body/span/section/nav/div[2]/div/div/div[2]/input""")
search_button.send_keys("fast")
while True:
search_button.send_keys(u'\ue007')
That is very interesting. Another solution is better. It is very important to know that, you must press 2 Enter press on Instagram search box. So, for eliminating while loop, you can use this code:
search_button.send_keys("#fast")
time.sleep(5)
search_button.send_keys(u'\ue007')
search_button.send_keys(u'\ue007')