When the user enters nothing, it is supposed to loop back and ask the question again. It performs correctly with every other type of input.
Here is the code:
string = ""
def str_analysis(string):
while True:
if string.isdigit():
if int(string) > 99:
print(str(string)+ " is a pretty big number!")
break
else:
print(str(string)+ " is a smaller number than expected")
break
elif string.isalpha():
print(string + " is an alphabetical character")
break
elif string == "":
print("")
else:
print(string + " is a surprise! It's neither all alpha nor all digit characters!")
break
print(str_analysis(input("Enter word or integer: ")))
There are a few things in your code that make no sense.
1:
print(str_analysis(input("Enter word or integer: ")))
You are trying to print the output of a function that has no return value
2:
It cant loop back and ask the question again, because the input is not taken inside of the function.
3:
If the string is empty you dont break the code but constantly print newlines.
Here is some code wich I think should do what you wanted:
def str_analasys():
while True:
string = input("Enter word or integer: ")
if string == '':
continue
elif string.isdigit():
if int(string) > 99:
print(str(string)+ " is a pretty big number!")
else:
print(str(string)+ " is a smaller number than expected")
elif string.isalpha():
print(string + " is an alphabetical character")
else:
print(string + " is a surprise! It's neither all alpha nor all digit characters!")
break
str_analasys()
This because when string is empty you are just printing an empty ""
elif string == "":
print("")
# break it here or take input again
# break or string = input()
Related
print("Give me two numbers, I'll sum them")
print("Enter 'q' to quit")
while True:
num1 = input("Please, enter a number here: ")
if num1 == 'q':
break
num2 = input("Please, enter a number here: ")
if num2 == 'q':
break
try:
sum = int(num1) + int(num2)
except ValueError:
print("'q' entered, program exit 0")
else:
print(sum)
Hi the above program in Python3 works fine when numbers are inputted.
But when I input q, it just exits with no exception.
May you please assist me with this issue?
Thank you very much indeed.
the break statement will exit your loop without printing anything, because your try-except test is after breaks.
Here is what you can do:
print("Give me two numbers, I'll sum them")
print("Enter 'q' to quit")
while True:
num1 = input("Please, enter a number here: ")
if num1 == 'q':
print("'q' entered, program exit 0")
break
num2 = input("Please, enter a number here: ")
if num2 == 'q':
print("'q' entered, program exit 0")
break
if not num1.isdecimal() or not num2.isdecimal():
print('Wrong input, please enter decimal numbers !')
continue
sum = int(num1) + int(num2)
print(sum)
Trying to exit the program by importing sys.exit(), break and ask == False, but nothing works. Full code here
#import sys
def body_cycle(*args):
if option == "/":
error_func_for_zero(first_number, second_number, option)
print(division_option(first_number, second_number))
print()
print(begin)
def error_func_for_zero(*args):
try:
first_number / 0 or second_number / 0
except ZeroDivisionError:
print("YOU CANNOT DIVIDE BY ZERO!")
print(begin)
def division_option(*args):
return first_number / second_number
begin = " "
while begin:
print("Hello, I am calculator. ")
print("Please, enter your numbers (just integers) ! ")
print()
first_number = int(input("First number: "))
print()
second_number = int(input("Second number: "))
print()
option = input("Remember: you can't divide by zero.\nChoose your option (+, -, *, /): ")
print(body_cycle(first_number, second_number, option))
ask = " "
while ask:
exit_or_continue = input("If you want continue press 'Y', 'y'. For break press 'N' or 'n'? \nChoice: ")
if exit_or_continue == "Y" or "y":
print("OK")
elif exit_or_continue == "N" or "n":
#break
ask == False
else:
print("Break program. ")
break
You just want to replace ask == False by ask = False.
In addition, you could really use a simpler code structure. The whole thing before begin can be compacted down to:
def operation(a, b, option):
if option == "+":
return a + b
elif option == "-":
return a - b
elif option == "*":
return a * b
elif option == "/":
try:
return a / b
except ZeroDivsionError
return "YOU CANNOT DIVIDE BY ZERO!"
The rest can be put in a single loop instead of two, like so:
print("Hello, I am calculator. ")
while True:
print("Please, enter your numbers (just integers) ! ")
print()
first_number = int(input("First number: "))
print()
second_number = int(input("Second number: "))
print()
option = input("Remember: you can't divide by zero.\n
Choose your option (+, -, *, /): ")
# Result.
print(operation(first_number, second_number, option))
exit_or_continue = input("If you want continue press 'Y', 'y'. For break press 'N' or 'n'.\n
Choice: ").lower()
if exit_or_continue == "y":
print("OK")
elif exit_or_continue == "n":
break
I'm trying to get a guessing game with the user input as an answer and if the user type exit the game will show the amount of time the player tried but the program won't run because it can only take either interger or string type.
import random
while True:
number = random.randint(1,9)
guess = int(input('guess the number: '))
time = 0
time += 1
if guess == number:
print('you guessed correct')
elif guess < number:
print('your guessed is lower than the actual number')
elif guess > number:
print('your guessed is higher than the actual number')
elif guess == 'exit':
print(time)
break
something like this
import random
time = 0
number = random.randint(1,9)
while True:
guess = input('guess the number: ')
time += 1
if guess == "exit":
print(time)
break
elif int(guess) < number:
print('your guessed is lower than the actual number')
elif int(guess) > number:
print('your guessed is higher than the actual number')
elif int(guess) == number:
print('you guessed correct')
print(time)
break
note that time and number have to be initializate outside the while loop, because if not, we would get different random numbers for each iteration, and also time would be initializate to 0 each time.
You can test the input as a string first before converting it to an integer:
while True:
response = input('guess the number: ')
if response == 'exit':
break
guess = int(response)
# the rest of your code testing guess as a number
So I tried to make a game where the computer chooses a random 4 digit number out of 10 given numbers. The computer then compares the guess of the user with the random chosen code, and will give feedback accordingly:
G = correct digit that is correctly placed
C = correct digit, but incorrectly placed
F = the digit isn't in the code chosen by the computer
However, the feedback doesn't always output correctly.
Fox example, when I guess 9090, the feedback I get is F C F, while the feedback should consist of 4 letters.... How can I fix this?
#chooses the random pincode that needs to be hacked
import random
pincode = [
'1231', '9997', '8829', '6765', '9114', '5673', '0103', '4370', '8301', '1022'
]
name = None
#Main code for the game
def main():
global code
global guess
#Chooses random pincode
code = random.choice(pincode)
#Sets guessestaken to 0
guessesTaken = 0
while guessesTaken < 10:
#Makes sure every turn, an extra guess is added
guessesTaken = guessesTaken + 1
#Asks for user input
print("This is turn " + str(guessesTaken) + ". Try a code!")
guess = input()
#Easteregg codes
e1 = "1955"
e2 = "1980"
#Checks if only numbers have been inputted
if guess.isdigit() == False:
print("You can only use numbers, remember?")
guessesTaken = guessesTaken - 1
continue
#Checks whether guess is 4 numbers long
if len(guess) != len(code):
print("The code is only 4 numbers long! Try again!")
guessesTaken = guessesTaken - 1
continue
#Checks the code
if guess == code:
#In case the user guesses the code in 1 turn
if (guessesTaken) == 1:
print("Well done, " + name + "! You've hacked the code in " +
str(guessesTaken) + " turn!")
#In cases the user guesses the code in more than 1 turn
else:
print("Well done, " + name + "! You've hacked the code in " +
str(guessesTaken) + " turns!")
return
#Sets empty list for the feedback on the user inputted code
feedback = []
nodouble = []
#Iterates from 0 to 4
for i in range(4):
#Compares the items in the list to eachother
if guess[i] == code[i]:
#A match means the letter G is added to feedback
feedback.append("G")
nodouble.append(guess[i])
#Checks if the guess number is contained in the code
elif guess[i] in code:
#Makes sure the position of the numbers isn't the same
if guess[i] != code[i]:
if guess[i] not in nodouble:
#The letter is added to feedback[] if there's a match
feedback.append("C")
nodouble.append(guess[i])
#If the statements above are false, this is executed
elif guess[i] not in code:
#No match at all means an F is added to feedback[]
feedback.append("F")
nodouble.append(guess[i])
#Easteregg
if guess != code and guess == e1 or guess == e2:
print("Yeah!")
guessesTaken = guessesTaken - 1
else:
print(*feedback, sep=' ')
main()
You can try the game here:
https://repl.it/#optimusrobertus/Hack-The-Pincode
EDIT 2:
Here, you can see an example of what I mean.
Here is what I came up with. Let me know if it works.
from random import randint
class PinCodeGame(object):
def __init__(self):
self._attempt = 10
self._code = ['1231', '9997', '8829', '6765', '9114', '5673', '0103', '4370', '8301',
'1022']
self._easterEggs = ['1955', '1980', '1807', '0609']
def introduction(self):
print("Hi there stranger! What do I call you? ")
player_name = input()
return player_name
def show_game_rules(self):
print("10 turns. 4 numbers. The goal? Hack the pincode.")
print(
"For every number in the pincode you've come up with, I'll tell you whether it is correct AND correctly placed (G), correct but placed incorrectly (C) or just plain wrong (F)."
)
def tutorial_needed(self):
# Asks for tutorial
print("Do you want a tutorial? (yes / no)")
tutorial = input().lower()
# While loop for giving the tutorial
while tutorial != "no" or tutorial != "yes":
# Gives tutorial
if tutorial == "yes":
return True
# Skips tutorial
elif tutorial == "no":
return False
# Checks if the correct input has been given
else:
print("Please answer with either yes or no.")
tutorial = input()
def generate_code(self):
return self._code[randint(0, len(self._code))]
def is_valid_guess(self, guess):
return len(guess) == 4 and guess.isdigit()
def play(self, name):
attempts = 0
code = self.generate_code()
digits = [code.count(str(i)) for i in range(10)]
while attempts < self._attempt:
attempts += 1
print("Attempt #", attempts)
guess = input()
hints = ['F'] * 4
count_digits = [i for i in digits]
if self.is_valid_guess(guess):
if guess == code or guess in self._easterEggs:
print("Well done, " + name + "! You've hacked the code in " +
str(attempts) + " turn!")
return True, code
else:
for i, digit in enumerate(guess):
index = int(digit)
if count_digits[index] > 0 and code[i] == digit:
count_digits[index] -= 1
hints[i] = 'G'
elif count_digits[index] > 0:
count_digits[index] -= 1
hints[i] = 'C'
print(*hints, sep=' ')
else:
print("Invalid input, guess should be 4 digits long.")
attempts -= 1
return False, code
def main():
# initialise game
game = PinCodeGame()
player_name = game.introduction()
print("Hi, " + player_name)
if game.tutorial_needed():
game.show_game_rules()
while True:
result, code = game.play(player_name)
if result:
print(
"Oof. You've beaten me.... Do you want to be play again (and be beaten this time)? (yes / no)")
else:
print("Hahahahaha! You've lost! The correct code was " + code +
". Do you want to try again, and win this time? (yes / no)")
play_again = input().lower()
if play_again == "no":
return
main()
getting this error meassage despite having exactly same output as expected output.
* ERROR: Expected to find a number in the line Available Letters: abcdefghijklmnopqrstuvwxyz.
Check to be sure your lines match up with the expected output!!! *
MY CODE:
def hangman(secretWord):
print ("Welcome to the game, Hangman!")
print ("I am thinking of a word that is " + str(len(secretWord)) + " letters long" )
lettersGuessed=[]
guesses = 8
p = " "
while guesses > 0:
print ("You have " + str(guesses) + " guesses left")
print ("Available Letters: " + str(getAvailableLetters(lettersGuessed))),
user_input = input("Please guess a letter: ")
user_input = str(user_input)
user_input = user_input.lower()
if user_input in lettersGuessed:
print ("Oops! You've already guessed that letter: " + str(getGuessedWord(secretWord, lettersGuessed)))
else:
lettersGuessed.append(user_input)
if user_input in secretWord:
print ("Good guess: " + str(getGuessedWord(secretWord,lettersGuessed)))
if isWordGuessed(secretWord, lettersGuessed):
break
else: continue
else:
print("Oops! That letter is not in my word: " + str(getGuessedWord(secretWord, lettersGuessed)))
guesses = guesses - 1
p = str(getGuessedWord(secretWord, lettersGuessed))
p = p.split(" ")
p = "".join(p)
p = str(p)
if p == secretWord:
print ("Congratulations, you won!")
return
else:
print ("Sorry, you ran out of guesses. The word was " + secretWord + ".")
return
Check each line and "be sure your lines match up with the expected output".
It's possible the automated system that is checking the output requires the lines of output must exactly match their "correct output" including the ----------- lines, and you're code doesn't print those lines.
Easy as:
print ("I am thinking of a word that is " + str(len(secretWord)) + " letters long" )
print ("-----------") ### <---- Add this one line
lettersGuessed=[]
and
print ("Good guess: " + str(getGuessedWord(secretWord,lettersGuessed)))
print ("-----------") ### <---- Add this one line
if isWordGuessed(secretWord, lettersGuessed):
It's possible that you'll need to add that one line in other conditions within the code, as in the else: conditions.
And as always to make debugging easier, less repetition and cleaner code, you could assign that output to a variable and print it when needed:
def hangman(secretWord):
line_break = "-----------"
...
print ("I am thinking of a word that is " + str(len(secretWord)) + " letters long" )
print (line_break)
, etc.
Hope this helps.