I have x number of columns that contain NaN value
With the following code i can check that
for index,value in df.iteritems():
if value.isnull().values.any() == True:
this will show me with Boolean values which volumns have NaN.
If true I need to create new column that will have prefix 'Interpolation' + name of that column in its name.
So to make it clear if Column with the name 'XXX' has NaN I need to create new column with the name 'Interpolation XXX'.
Any ides how to do this ?
Something like this:
In [80]: df = pd.DataFrame({'XXX':[1,2,np.nan,4], 'YYY':[1,2,3,4], 'ZZZ':[1,np.nan, np.nan, 4]})
In [81]: df
Out[81]:
XXX YYY ZZZ
0 1.0 1 1.0
1 2.0 2 NaN
2 NaN 3 NaN
3 4.0 4 4.0
In [92]: nan_cols = df.columns[df.isna().any()].tolist()
In [94]: for col in df.columns:
...: if col in nan_cols:
...: df['Interpolation ' + col ] = df[col]
...:
In [95]: df
Out[95]:
XXX YYY ZZZ Interpolation XXX Interpolation ZZZ
0 1.0 1 1.0 1.0 1.0
1 2.0 2 NaN 2.0 NaN
2 NaN 3 NaN NaN NaN
3 4.0 4 4.0 4.0 4.0
Related
I have a dataframe and I want to use columns to create new rows in a new dataframe.
>>> df_1
mix_id ngs phr d mp1 mp2 mp1_wt mp2_wt mp1_phr mp2_phr
2 M01 SBR2353 100.0 NaN MES/HPD SBR2353 0.253731 0.746269 25.373134 74.626866
3 M02 SBR2054 80.0 NaN TDAE SBR2054 0.264706 0.735294 21.176471 58.823529
I would like to have a dataframe like this.
>>> df_2
mix_id ngs phr d
1 M01 MES/HPD 25.373134 NaN
2 M01 SBR2353 74.626866 NaN
3 M02 TDAE 21.176471 NaN
4 M02 SBR2054 58.823529 NaN
IIUC
you can use pd.wide_to_long, it does however needs the repeating columns to have numbers as suffix. So, the first part of solution, just renames the columns to bring the number as suffix
df.columns=[col for col in df.columns[:6]] + [re.sub(r'\d','',col) + str(re.search(r'(\d)',col).group(0)) for col in df.columns[6:] ]
# this makes mp1_wt as mp_wt1, to support pd.wide_to_long
df2=pd.wide_to_long(df, stubnames=['mp','mp_wt','mp_phr'], i=['mix_id','ngs','d'], j='val').reset_index().drop(columns='val')
df2.drop(columns=['ngs','phr','mp_wt'], inplace=True)
df2.rename(columns={'mp':'ngs','mp_phr':'phr'}, inplace=True)
df2
mix_id d ngs phr
0 M01 NaN MES/HPD 25.373134
1 M01 NaN SBR2353 74.626866
2 M02 NaN TDAE 21.176471
3 M02 NaN SBR2054 58.823529
I have a dataframe of the following scheme in pyspark:
user_id datadate page_1.A page_1.B page_1.C page_2.A page_2.B \
0 111 20220203 NaN NaN NaN NaN NaN
1 222 20220203 5 5 5 5.0 5.0
2 333 20220203 3 3 3 3.0 3.0
page_2.C page_3.A page_3.B page_3.C
0 NaN 1.0 1.0 2.0
1 5.0 NaN NaN NaN
2 4.0 NaN NaN NaN
So it contains columns like user_id, datadate, and few columns for each page (got 3 pages), which are the result of 2 joins. In this example, i have page_1, page_2, page_3, and each has 3 columns: A,B,C. Additionally, for each page columns, for each row, they will either be all null or all full, like in my example.
I don't care about the values of each of the columns per page, I just want to get for each row, the [A,B,C] values that are not null.
example for a wanted result table:
user_id datadate A B C
0 111 20220203 1 1 2
1 222 20220203 5 5 5
2 333 20220203 3 3 3
so the logic will be something like:
df[A] = page_1.A or page_2.A or page_3.A, whichever is not null
df[B] = page_1.B or page_2.B or page_3.B, whichever is not null
df[C] = page_1.C or page_2.C or page_3.C, whichever is not null
for all of the rows..
and of course, I would like to do it in an efficient way.
Thanks a lot.
You can use the sql functions greatest to extract the greatest values in a list of columns.
You can find the documentation here: https://spark.apache.org/docs/3.1.1/api/python/reference/api/pyspark.sql.functions.greatest.html
from pyspark.sql import functions as F
(df.withColumn('A', F.greates(F.col('page_1.A'), F.col('page_2.A), F.col('page_3.A'))
.withColumn('B', F.greates(F.col('page_1.B'), F.col('page_2.B), F.col('page_3.B'))
.select('userid', 'datadate', 'A', 'B'))
I have a dataframe as
col 1 col 2
A 2020-07-13
A 2020-07-15
A 2020-07-18
A 2020-07-19
B 2020-07-13
B 2020-07-19
C 2020-07-13
C 2020-07-18
I want it to become the following in a new dataframe
col_3 diff_btw_1st_2nd_date diff_btw_2nd_3rd_date diff_btw_3rd_4th_date
A 2 3 1
B 6 NaN NaN
C 5 NaN NaN
I tried getting the groupby at Col 1 level , but not getting the intended result. Can anyone help?
Use GroupBy.cumcount for counter pre column col 1 and reshape by DataFrame.set_index with Series.unstack, then use DataFrame.diff, remove first only NaNs columns by DataFrame.iloc, convert timedeltas to days by Series.dt.days per all columns and change columns names by DataFrame.add_prefix:
df['col 2'] = pd.to_datetime(df['col 2'])
df = (df.set_index(['col 1',df.groupby('col 1').cumcount()])['col 2']
.unstack()
.diff(axis=1)
.iloc[:, 1:]
.apply(lambda x: x.dt.days)
.add_prefix('diff_')
.reset_index())
print (df)
col 1 diff_1 diff_2 diff_3
0 A 2 3.0 1.0
1 B 6 NaN NaN
2 C 5 NaN NaN
Or use DataFrameGroupBy.diff with counter for new columns by DataFrame.assign, reshape by DataFrame.pivot and remove NaNs by c2 with DataFrame.dropna:
df['col 2'] = pd.to_datetime(df['col 2'])
df = (df.assign(g = df.groupby('col 1').cumcount(),
c1 = df.groupby('col 1')['col 2'].diff().dt.days)
.dropna(subset=['c1'])
.pivot('col 1','g','c1')
.add_prefix('diff_')
.rename_axis(None, axis=1)
.reset_index())
print (df)
col 1 diff_1 diff_2 diff_3
0 A 2.0 3.0 1.0
1 B 6.0 NaN NaN
2 C 5.0 NaN NaN
You can assign a cumcount number grouped by col 1, and pivot the table using that cumcount number.
Solution
df["col 2"] = pd.to_datetime(df["col 2"])
# 1. compute date difference in days using diff() and dt accessor
df["diff"] = df.groupby(["col 1"])["col 2"].diff().dt.days
# 2. assign cumcount for pivoting
df["cumcount"] = df.groupby("col 1").cumcount()
# 3. partial transpose, discarding the first difference in nan
df2 = df[["col 1", "diff", "cumcount"]]\
.pivot(index="col 1", columns="cumcount")\
.drop(columns=[("diff", 0)])
Result
# replace column names for readability
df2.columns = [f"d{i+2}-d{i+1}" for i in range(len(df2.columns))]
print(df2)
d2-d1 d3-d2 d4-d3
col 1
A 2.0 3.0 1.0
B 6.0 NaN NaN
C 5.0 NaN NaN
df after assing cumcount is like this
print(df)
col 1 col 2 diff cumcount
0 A 2020-07-13 NaN 0
1 A 2020-07-15 2.0 1
2 A 2020-07-18 3.0 2
3 A 2020-07-19 1.0 3
4 B 2020-07-13 NaN 0
5 B 2020-07-19 6.0 1
6 C 2020-07-13 NaN 0
7 C 2020-07-18 5.0 1
I have a long form dataframe that contains multiple samples and time points for each subject. The number of samples and timepoint can vary, and the days between time points can also vary:
test_df = pd.DataFrame({"subject_id":[1,1,1,2,2,3],
"sample":["A", "B", "C", "D", "E", "F"],
"timepoint":[19,11,8,6,2,12],
"time_order":[3,2,1,2,1,1]
})
subject_id sample timepoint time_order
0 1 A 19 3
1 1 B 11 2
2 1 C 8 1
3 2 D 6 2
4 2 E 2 1
5 3 F 12 1
I need to figure out a way to generalize grouping this dataframe by subject_id and putting all samples and time points on the same row, in time order.
DESIRED OUTPUT:
subject_id sample1 timepoint1 sample2 timepoint2 sample3 timepoint3
0 1 C 8 B 11 A 19
1 2 E 2 D 6 null null
5 3 F 12 null null null null
Pivot gets me close, but I'm stuck on how to proceed from there:
test_df = test_df.pivot(index=['subject_id', 'sample'],
columns='time_order', values='timepoint')
Use DataFrame.set_index with DataFrame.unstack for pivoting, sorting MultiIndex in columns, flatten it and last convert subject_id to column:
df = (test_df.set_index(['subject_id', 'time_order'])
.unstack()
.sort_index(level=[1,0], axis=1))
df.columns = df.columns.map(lambda x: f'{x[0]}{x[1]}')
df = df.reset_index()
print (df)
subject_id sample1 timepoint1 sample2 timepoint2 sample3 timepoint3
0 1 C 8.0 B 11.0 A 19.0
1 2 E 2.0 D 6.0 NaN NaN
2 3 F 12.0 NaN NaN NaN NaN
a=test_df.iloc[:,:3].groupby('subject_id').last().add_suffix('1')
b=test_df.iloc[:,:3].groupby('subject_id').nth(-2).add_suffix('2')
c=test_df.iloc[:,:3].groupby('subject_id').nth(-3).add_suffix('3')
pd.concat([a, b,c], axis=1)
sample1 timepoint1 sample2 timepoint2 sample3 timepoint3
subject_id
1 C 8 B 11.0 A 19.0
2 E 2 D 6.0 NaN NaN
3 F 12 NaN NaN NaN NaN
I am trying to populate column 'C' with values from column 'A' based on conditions in column 'B'. Example: If column 'B' equals 'nan', then row under column 'C' equals the row in column 'A'. If column 'B' does NOT equal 'nan', then leave column 'C' as is (ie 'nan'). Next, the values in column 'A' to be removed (only the values that were copied from column A to C).
Original Dataset:
index A B C
0 6 nan nan
1 6 nan nan
2 9 3 nan
3 9 3 nan
4 2 8 nan
5 2 8 nan
6 3 4 nan
7 3 nan nan
8 4 nan nan
Output:
index A B C
0 nan nan 6
1 nan nan 6
2 9 3 nan
3 9 3 nan
4 2 8 nan
5 2 8 nan
6 3 4 nan
7 nan nan 3
8 nan nan 4
Below is what I have tried so far, but its not working.
def impute_unit(cols):
Legal_Block = cols[0]
Legal_Lot = cols[1]
Legal_Unit = cols[2]
if pd.isnull(Legal_Lot):
return 3
else:
return Legal_Unit
bk_Final_tax['Legal_Unit'] = bk_Final_tax[['Legal_Block', 'Legal_Lot',
'Legal_Unit']].apply(impute_unit, axis = 1)
Seems like you need
df['C'] = np.where(df.B.isna(), df.A, df.C)
df['A'] = np.where(df.B.isna(), np.nan, df.A)
A different, maybe fancy way to do it would be to swap A and C values only when B is np.nan
m = df.B.isna()
df.loc[m, ['A', 'C']] = df.loc[m, ['C', 'A']].values
In other words, change
bk_Final_tax['Legal_Unit'] = bk_Final_tax[['Legal_Block', 'Legal_Lot',
'Legal_Unit']].apply(impute_unit, axis = 1)
for
bk_Final_tax['Legal_Unit'] = np.where(df.Legal_Lot.isna(), df.Legal_Block, df.Legal_Unit)
bk_Final_tax['Legal_Block'] = np.where(df.Legal_Lot.isna(), np.nan, df.Legal_Block)