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I have several files in one folder and I would like to compress 1 by 1
Folder: /files
file1 to file1.gz
file2 to file2.gz
Etc
And that with all the files that are in the folder: /file
Is it possible to compress only the files (and not the folder) at once?
Looks like you are in search of looping mechanism to perform a GZIP. Below single-line execution can be a simple method to do it without any scripting.
for file_name in /files/* ; do gzip $file_name ;done
However, in case if the same directory holds directories as well as files, it better to have some beautified script for continuous use as below;
for file_name in /files/*
do
if [ -f $file_name ]; then
gzip $file_name
else
echo "$file_name is a directory."
fi
done
PS :-
else logic is purely optional and can be commented.
Try to keep this script outside of /files directory, else it would zip the shell script file as well.
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Closed 11 months ago.
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Be nice. I'm learning Linux and can't find this answer (I've searched)
I'm trying to move all the .txt files in Folder1 to my Documents directory.
~$ ls
Desktop Documents Downloads file1.txt Music Public Templates test user0files.txt user-files.txt Videos
~$ cd ~/Documents
~/Documents$ ls
Folder1 Folder2 test1.txt test2.txt
~/Documents$ cd ~/Documents/Folder1
~/Documents/Folder1$ ls
bale.txt, ball.txt, bowl.txt, foldernew
~/Documents/Folder1$ mv *.txt ~/Documents
mv: cannot stat '*.txt': No such file or directory
From here I tried moving foldernew by name to ~/Documents and it worked. Can someone explain what I am doing incorrectly?
Thanks so much!!
It looks like you have a bunch of files that end in .txt, (note the comma), so *.txt doesn't find them.
Rename the files to remove the comma and try again.
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I want to rename all files in selected directory using rename command or move command from :
_02_mp3_cbr_320.m4a?anghakamitoken=sc245ae5a454547.5
_02_mp3_fsgsfsdfsfdfdsfcbr_320.m4a?anghakamitoken=sc245.ae5a
to
1.m4a
2.m4a
If those files always have a sheme like this:
_02_mp3_ * _320.m4a?anghakamitoken= *
You can do it like that:
#!/bin/bash
COUNT=0
for f in ./"_02_mp3_"*"_320.m4a?anghakamitoken="*; do
mv $f "$((++COUNT)).m4a"
done
This will result in
1.m4a
2.m4a
Assuming the initial files are in the same directory as the bash script.
Try this with GNU Parallel. it basically uses GNU Parallel's job number ({#}) as the number for renaming:
parallel --dry-run -k mv {} {#}.m4a ::: *m4a*
Sample Output
mv _02_mp3_cbr_320.m4a\?anghakamitoken\=sc245ae5a454547.5 1.m4a
mv _02_mp3_fsgsfsdfsfdfdsfcbr_320.m4a\?anghakamitoken\=sc245.ae5a 2.m4a
If the commands look correct, remove the --dry-run part and run it again. The -k keeps the output in order. The {} refers to the current file.
Make a backup before using any commands you are unfamiliar with...
To rename any file in Linux using mv (move) command:
mv (cfr. "man mv")
In this case, you need to enter the following lines on the command line:
$mv _02_mp3_cbr_320.m4a?anghakamitoken=sc245ae5a454547.5 1.m4a
$mv _02_mp3_fsgsfsdfsfdfdsfcbr_320.m4a?anghakamitoken=sc245.ae5a 1.m4a
It is important that you refer to the manual when you know the command you must use, to understand how to use it.
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I have a folder that contains many folders and my wordpresses sites.
At the same folder i need to catch up the "uploads" subfolder and tar it named by its site.
Can anyone help me out?
Does this do the trick?
find /var/www -name uploads -a -type d | awk -F '/' '{ system("tar -czvf "$3".tar "$0) }'
The find command lists all the directories named upload under /var/www.
That's piped to awk, which splits it using the slash and runs tar. The third field is used as the file name and the whole string as the target for the tar.
This works for me: tar -cvf thisstuff.tar */uploads/*
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Closed 7 years ago.
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I have multiple tar's that I want to untar into a folder and then append a prefix to them. The problem is that I don't know the name of the folder that it would create on the target system since these are build tar's and they have a date-timestamp inside. Here is what I tried -
tar xfz <filename>-*.tar.gz -C $UNTAR_LOCATION
so this creates a folder like this 20140909-0900 on the target UNTAR_LOCATION. How can I append a prefix to the date-timestamp ?
Note - there will be multiple folders with different date-timestamps under UNTAR_LOCATION for which I want to add the same prefix.
With versions of tar that support the --transform flag you should be able to use something like this:
tar -xzf <filename>-*.tar.gz -C "$untar_location" --transform='s,^,prefix,'
Here's how to do it with pax, the portable archiver:
gzip -cd filename.tar.gz | ( cd "$untar_location" && pax -r -s,^,prefix-, )
Most implementations of pax also has a -z option to filter through gzip, in which case it becomes
( cd "$untar_location" && pax -zrf filename.tar.gz -s,^,prefix-, )
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I have many files named xxxx.min.js and want to rename the files to xxxx.js so basically want to remove .min only.
Is there a command I can use to do this job?
I thought using rename command would be easy for each single file, but that would take forever since I have many of them.
any idea?
Here's a bash-only command (not requiring Perl)
for i in *.min.js; do a=$(basename $i .min.js); echo mv $i $a.js; done
Explanation
for i in *.min.js; do
loop over all files matching *.min.js
a=$(basename $i .min.js)
extract the base name of the file (i.e. strip off .min.js) and save the result in $a
echo mv $i $a.js
for now, print to the console the command that WOULD be run if you removed the echo
When you are satisfied that it generates the correct commands, remove the echo to actually rename the files.
Ubuntu and Debian linux distribution both have a perl version of mv function called rename or prename, which supports regexp. The manual can be found here.
Go to the folder of the files and run the command as follows:
rename s/\.min\.js$/\.js/ *.min.js