I need to search for all files - in cur dir and all subdirs with a name ending by ~, or a name that start and end by #, delete all files found.
this not working, it does not display found files
find -type f -name "~" or "#*#" ls -a -delete
and this is not working with piping:
find -type f -name "~" or "#*#" | ls -a | -delete
how to specify both conditions?
EDIT: The command line will find files matching the condition, print and then delete them.
Use -o (=or; the implicit default is -a = and) to combine operators and \(/\) to specify operator precedence:
find -type f \( -name "~" -o -name "#*#" \) -delete
You can combine multiple actions, e.g. outputting and deleting at the same time by simply providing all required actions:
find -type f \( -name "~" -o -name "#*#" \) -print -delete
An other option would be to simply filter the results with grep
find -type f | grep -E '(~|#*#)' | xargs rm
That would also allow to build additional steps (like displaying the files) into it
Related
I would like to recursively find all files contained into a directory that has name “name1” or name “name2”
for instance:
structure/of/dir/name1/file1.a
structure/of/dir/name1/file2.b
structure/of/dir/name1/file3.c
structure/of/dir/name1/subfolder/file1s.a
structure/of/dir/name1/subfolder/file2s.b
structure/of/dir/name2/file1.a
structure/of/dir/name2/file2.b
structure/of/dir/name2/file3.c
structure/of/dir/name2/subfolder/file1s.a
structure/of/dir/name2/subfolder/file2s.b
structure/of/dir/name3/name1.a ←this should not show up in the result
structure/of/dir/name3/name2.a ←this should not show up in the result
so when I start my magic command the expected output should be this and only this:
structure/of/dir/name1/file1.a
structure/of/dir/name1/file2.b
structure/of/dir/name1/file3.c
structure/of/dir/name2/file1.a
structure/of/dir/name2/file2.b
structure/of/dir/name2/file3.c
I scripted something but it does not work because it search within the files and not only folder names:
for entry in $(find $SEARCH_DIR -type f | grep 'name1\|name2');
do
echo "FileName: $(basename $entry)"
done
If you can use the -regex option, avoiding subfolders with [^/]:
~$ find . -type f -regex ".*name1/[^/]*" -o -regex ".*name2/[^/]*"
./structure/of/dir/name2/file1.a
./structure/of/dir/name2/file3.c
./structure/of/dir/name2/subfolder
./structure/of/dir/name2/file2.b
./structure/of/dir/name1/file1.a
./structure/of/dir/name1/file3.c
./structure/of/dir/name1/file2.b
I'd use -path and -prune for this, since it's standard (unlike -regex which is GNU specific).
find . \( -path "*/name1/*" -o -path "*/name2/*" \) -prune -type f -print
But more importantly, never do for file in $(find...). Use finds -exec or a while read loop instead, depending on what you really need to with the matching files. See UsingFind and BashFAQ 20 for more on how to handle find safely.
I need to find all the iplanets on one server and I was thinking to use this command:
find / type d -name https-* | uniq
But at the same time I need to ignore some directories/file. I've been trying to use !, but it not always work. I have a command like this:
find / type d -name https-* ! -name https-admserv* ! -name conf_bk* ! -name alias* ! -name *db* ! -name ClassCache* | uniq
I need to ignore all that. The directories admserv, conf_bk, alias and tmp and the files *.db*
Basically I need find this:
/opt/mw/iplanet/https-daniel.com
/opt/https-daniel1.com
/apps/https-daniel2.com
I only need to find the directory name. How can I ignore all the other stuff?
Use -prune to keep from recursing into directories:
find / \( -type d \( -name 'https-admserv*' -o -name 'conf_bk*' -o -name 'alias*' -o -name 'tmp' \) -prune -o -type d -name 'https-*' -print
There's no need to ignore any files. You're only selecting https-* directories, so everything else is ignored.
And there's no need to pipe to uniq, since find never produces duplicates.
Someone created directories with names like source.c. I am doing a find over all the directories in a tree. I do want find to search in the source.c directory, but I do not want source.c to be passed to the grep I am doing on what is found.
How can I make find not pass directory names to grep? Here is what my command line looks like:
find sources* \( -name "*.h" -o -name "*.cpp" -o -name "*.c" \) -exec grep -Hi -e "ThingToFind" {} \;
Add -a -type f to your find command. This will force find to only output files, not directories. (It will still search directories):
find sources* \( -name "*.h" -o -name "*.cpp" -o -name "*.c" \) -a -type f -exec grep -Hi -e "ThingToFind" {} \;
I'm trying to find all files whose name matches certain C++ file extensions but exclude certain directories matching a pattern with this:
find /home/palchan/code -name "*.[CcHh]" -o -name "*.cpp" -o -name "*.hpp" -a ! -name "*pattern*"
and this still gives me as output certain files like:
/home/palchan/code/libFox/pattern/hdr/fox/RedFox.H
which has the pattern in it?
Here is an example:
> ls -R .
.:
libFox
./libFox:
RedFox.C RedFox.H pattern
./libFox/pattern:
RedFox.C RedFox.H
and then I run:
> find . \( -name "*.[HC]" -a ! -name "*pattern*" \)
./libFox/pattern/RedFox.C
./libFox/pattern/RedFox.H
./libFox/RedFox.C
./libFox/RedFox.H
The following should work:
find /home/palchan/code \( -name "*pattern*" \) -prune -o -type f \( -name "*.[CcHh]" -o -name "*.cpp" -o -name "*.hpp" \) -print
From man find:
-name pattern
Base of file name (the path with the leading directories removed) matches shell pattern pattern. The metacharacters (`*', `?', and `[]') match
a `.' at the start of the base name (this is a change in findutils-4.2.2; see section STANDARDS CONFORMANCE below). To ignore a directory and
the files under it, use -prune; see an example in the description of -path. Braces are not recognised as being special, despite the fact that
some shells including Bash imbue braces with a special meaning in shell patterns. The filename matching is performed with the use of the
fnmatch(3) library function. Don't forget to enclose the pattern in quotes in order to protect it from expansion by the shell.
So, basically, you should use -prune to exclude directories instead of ! -name something
Try doing this :
find /home/palchan/code \( -name "*.[CcHh]" -o -name "*.cpp" -o -name "*.hpp" -a ! -name "*pattern*" \)
I use Emacs and it sometimes makes backup for edited files. After a few days, I would have a lot of backup files whose name ends with a tilde.
Is there a way to find these files and delete them at once?
I tried this:
find "*" -type f -iname *~
But it doesn't work. I want the command to work recursively – something like ls -alR.
You need to escape from the shell. And you need to specify search path, not *
find . -type f -name '*~'
To delete the files:
find . -type f -name '*~' -exec rm -f '{}' \;
You can do something like that :
find . -type f -name '*~' -delete
If you want to delete also #*# file :
find . -type f -name '*~' -o -name '#*#' -delete
You can print all deleted files with "-print":
find . -type f -name '*~' -delete -print
Another way is by using grep.
lnydex99uhc:javastuff user$ ls
Permutation.java VigenereCipher.java VigenereCipher.java~
lnydex99uhc:javastuff user $ find . | grep .~$
./VigenereCipher.java~
You can also pass any command you want like this :
lnydex99uhc:javastuff zatef$ rm $(find . | grep .~$)