NodeJS + mongoDB query after another : Promises/callback - node.js

Question

I have three functions
A -> mongoDb query then call B then console.log("test")
B -> set some rules and call C
C --> mongoDb query go back to A -> console.log("test")
I am having a hard time with async/promises, after quite a long time I found a working solution that does not seem super elegant.
(Maybe because I'm not super familiar with async/await)
I was wondering if there's a better/more elegant/more readable solution?
Here's the code with only the "useful part". (The console.logs should write 1,2,3,4,5,6.)
app.get('/searchWingding', (req,res)=>{
users.findOneAndUpdate( mongoDBQuery
{returnOriginal : false})
.then(async () =>{
//remove unnecessary code for issue
console.log(1)
await wingdingsExhibitionRule(users,player, allWingdings)
console.log(6)
})})
async function wingdingsExhibitionRule(users,player, wingdingsList){
//remove unnecessary code for issue
console.log(2)
await changePlayerUnlock(users,player,"wingdingsExhibition")
console.log(5)
}
async function changePlayerUnlock(users,player,unlockRule){
//remove unnecessary code for issue
console.log(3)
const a = users.findOneAndUpdate(mongoDBQuery,
{returnOriginal : false})
.then(()=>{
console.log(4)
if(!checkStringInArray(player.unlock,unlockRule)){
player.unlock.push(unlockRule)
}
})
await a
}
```

Answer 1

You are using async-await syntax as well as promises. Your code can be written as shown below using only async-await syntax
app.get('/searchWingding', async (req,res)=> {
await users.findOneAndUpdate()
console.log(1)
await wingdingsExhibitionRule(users,player, allWingdings)
console.log(6)
async function wingdingsExhibitionRule(users,player, wingdingsList){
console.log(2)
await changePlayerUnlock(users,player,"wingdingsExhibition")
console.log(5)
}
async function changePlayerUnlock(users,player,unlockRule) {
console.log(3)
const a = await users.findOneAndUpdate()
console.log(4)
}