multiple column style with python openpyxl - python-3.x

I want to specify the style of the columns in the table. If I select only one column as the style, it works, but if I want to specify more than one of the columns. I get this error message: AttributeError: 'tuple' object has no attribute 'style'
import openpyxl
from openpyxl import Workbook
from openpyxl import load_workbook
from openpyxl.styles import Font, Color, Alignment, Border, Side, colors
from openpyxl.styles import NamedStyle
path = "my xlsx file path"
workbook = load_workbook(path)
sheet = workbook.active
sheet
shetnames_str = workbook.sheetnames
print(shetnames_str)
print(sheet)
dimensions = sheet.dimensions
print("DimenziĆ³: "+dimensions)
selected_sheetname = workbook["Munka1"]
#Style definition
highlight = NamedStyle(name="highlight")
bd = Side(style='thin', color="000000")
highlight.border = Border(left=bd, top=bd, right=bd, bottom=bd)
for cell in sheet["A:B"]:
print(cell)
cell.style = highlight
workbook.save(filename="moddedxlsx.xlsx")

I modified my code
import openpyxl
from openpyxl import Workbook
from openpyxl import load_workbook
from openpyxl.styles import Font, Color, Alignment, Border, Side, colors
from openpyxl.styles import NamedStyle
path = "C:\\Users\\Jutasig\\Documents\\python_jegyzetek\\Dev\\Style\\master_xls_style\\szamla.xlsx"
workbook = load_workbook(path)
sheet = workbook.active
sheet
shetnames_str = workbook.sheetnames
print(shetnames_str)
print(sheet)
dimensions = "\""+sheet.dimensions+"\""
print("DimenziĆ³: "+dimensions)
selected_sheetname = workbook["Munka1"]
#Style definition
def set_border(ws, cell_range):
border = Border(left=Side(border_style='thin', color='000000'),
right=Side(border_style='thin', color='000000'),
top=Side(border_style='thin', color='000000'),
bottom=Side(border_style='thin', color='000000'))
rows = ws[cell_range]
for row in rows:
for cell in row:
cell.border = border
set_border(sheet, sheet.dimensions)
workbook.save(filename="moddedxlsx.xlsx")

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The following code works great the first time I run it (when it creates a new spreadsheet).
When I try to run it again (update existing sheet) to add more data (additional rows) I get the following error
Traceback (most recent call last):
File "C:/PythonPrograms/Workout Program/test_excel_format.py", line 35, in
cell.style = wdata
File "C:\Users\Mark\AppData\Local\Programs\Python\Python37\lib\site-packages\openpyxl\styles\named_styles.py", line 193, in append
raise ValueError("""Style {0} exists already""".format(style.name))
ValueError: Style wdata exists already
from openpyxl import Workbook
from openpyxl.styles import PatternFill
from openpyxl import load_workbook
from openpyxl.styles import Font, Color, Alignment, Border, Side, colors
from openpyxl.styles import NamedStyle
from datetime import date
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I want to be able to add new rows of formatted data esch time I run this code.
I don't see any way to use a NamedStyle to update the format for rows added to an existing
workbook/sheet. If you define the NamedStyle you get the "Already Exists" error. If you don't then you get an error that the "NamedStyle is not defined". The doc states pretty much verbatim what Charlie Clark said in his comment above, "Styles registered automatically on their first use and can then be referenced by name." It does not elaborate or show examples of how to use an existing NamedStyle. Given this I gave up trying to use a NamedStyle and updated the code as follows to make it work. If there is a way to do this with NamedStyle I'd love to see it.
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from openpyxl.styles import PatternFill
from openpyxl import load_workbook
from openpyxl.styles import Font, Color, Alignment, Border, Side, colors
from openpyxl.styles import NamedStyle
from datetime import date
from os import path
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# wdata.font = Font(bold=True)
# wdata.alignment = Alignment(horizontal="center", vertical="center")
for x in range(1, 3):
sheet.append(data) # appends the data to the first empty row.
print("current row: ", sheet._current_row)
ucell = "A" + str(sheet._current_row)
wdata_row = sheet[sheet._current_row]
for cell in wdata_row:
#cell.style = wdata
sheet[str(cell.coordinate)].font = Font(bold=True)
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I have been trying to research this for the past 2 days and the most regular answer I see is to use data_only=True however that does not seem to fix the issue of printing the value of a formula. Here is my scrip. Does anyone have an answer for this?
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from openpyxl import Workbook
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from openpyxl import load_workbook
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if name.startswith("BEA"):
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print filename
wb = load_workbook(filename, data_only=True)
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Tricks like chart.plots[0].series[0].marker.fill.fore_color = pptx.dml.color.RGBColor(0,0,0) don't work
Below an sample of code:
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import sys
from pptx import Presentation
from pptx.chart.data import ChartData
from pptx.enum.chart import XL_CHART_TYPE
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import pptx
from pptx import Presentation
from pptx.util import Cm, Pt
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chart_data = ChartData()
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chart_data.add_series('West', (32.2, 28.4, 34.7))
chart_data.add_series('East', (24.3, 30.6, 20.2))
chart_data.add_series('Midwest', (20.4, 18.3, 26.2))
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traceback.print_exc()
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Traceback (most recent call last): File
"", line 38, in
fill.fore_color = RGBColor(0,0,0) AttributeError: can't set attribute
Try:
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(Note the .format between marker and fill.)
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