Here is my ini file parameters.ini:
[parameters]
Vendor = Cat
Here is my python code:
#!/usr/bin/python3
# -*- coding: utf-8 -*-
import codecs
import sys
import os
import configparser
### Script with INI file:
INI_fileName="parameters.ini"
if not os.path.exists(INI_fileName):
print("file does not exist")
quit()
print("Here is the INI_fileName: " + INI_fileName)
config = configparser.ConfigParser()
config.read('INI_fileName')
vendor = config['parameters']['Vendor']
print("Here is the vendor name: " + vendor)
Here is the error:
python3 configParser-test.py
Here is the INI_fileName: parameters.ini
Traceback (most recent call last):
File "configParser-test.py", line 18, in <module>
vendor = config['parameters']['Vendor']
File "/usr/local/Cellar/python/3.7.7/Frameworks/Python.framework/Versions/3.7/lib/python3.7/configparser.py", line 958, in __getitem__
raise KeyError(key)
KeyError: 'parameters'
If I run the same code interactively it works. However if it was related to the file path, the error would be different, I assume: "file does not exist". Interactively:
>>> print(INI_fileName)
parameters.ini
>>> config.read('INI_fileName')
[]
>>> config.read('parameters.ini')
['parameters.ini']
>>>
Why is it not picking up the file name?
While playing with the interactive command I think I found the reason. Since I use the filename as variable i do not need to use quotes! Omg...
config.read(INI_fileName)
This problem may be due to the UTF byte order mark (BOM) added by Windows text editor.
BOM should be deleted before reading the config parameters in Linux/Unix.
Try:
config = configparser.ConfigParser()
config_file_path = '/app/config.ini' # full absolute path here!
s = open(config_file_path, mode='r', encoding='utf-8-sig').read()
open(config_file_path, mode='w', encoding='utf-8').write(s)
config.read(config_file_path)
# now check if it is OK
Related
This is my original question
The following script copies the text in /home/my_files/document1.txt to my clipboard.
import pyperclip
path = '/home/my_files/document1.txt'
The_text_of_the_file_that_will_be_copied = open(path, 'r').read()
pyperclip.copy(The_text_of_the_file_that_will_be_copied)
Let's say /home/my_files/ contains the following five documents:
/home/my_files/document1.txt
/home/my_files/document2.txt
/home/my_files/document3.txt
/home/my_files/image1.jpg
/home/my_files/image2.png
I would like to create a script to randomly copy the contents of one of the three text documents in /home/my_files/ to my clipboard.
Of course the following script does not work but it shows some of the modules I've been experimenting with.
import glob,random,pyperclip
pattern = "*.txt"
path = random.choice((glob.glob(pattern))("/home/my_files/"))
The_text_of_the_file_that_will_be_copied = open(path, 'r').read()
pyperclip.copy(The_text_of_the_file_that_will_be_copied)
Do you have any relevant suggestions for me?
I added the subsequent content to my original question above
When I tried the following solution which #Jacob Lee created...
import glob
import random
import pyperclip
files = [os.path.abspath(f) for f in glob.glob("./home/my_files")]
path = random.choice(files)
with open(path) as f:
pyperclip.copy(f.read())
I received the following error message...
Traceback (most recent call last):
File "abc.py", line 3, in <module>
path = random.choice(glob.glob(pattern))
File "/usr/lib/python3.8/random.py", line 290, in choice
raise IndexError('Cannot choose from an empty sequence') from None
IndexError: Cannot choose from an empty sequence
Someone else suggested the following script to me...
import glob,random,pyperclip
pattern = "/home/my_files/*.txt"
path = random.choice(glob.glob(pattern))
print("copying contents of ", path)
The_text_of_the_file_that_will_be_copied = open(path, 'r').read()
pyperclip.copy(The_text_of_the_file_that_will_be_copied)
But that script doesn't work either. I received the following error when I ran that script...
Traceback (most recent call last):
File "abc.py", line 3, in <module>
path = random.choice(glob.glob(pattern))
File "/usr/lib/python3.8/random.py", line 290, in choice
raise IndexError('Cannot choose from an empty sequence') from None
IndexError: Cannot choose from an empty sequence
I am confused.
The following successfully copies the entire contents of a random text file in /home/my_files/ to my clipboard
import glob,random,pyperclip
pattern = "/home/my_files/*.txt"
path = random.choice(glob.glob(pattern))
print("copying contents of ", path)
The_text_of_the_file_that_will_be_copied = open(path, 'r').read()
pyperclip.copy(The_text_of_the_file_that_will_be_copied)
Thanks to #Asocia
Thanks to #Asocia for insisting that the script above works correctly. I don't know what I had been doing wrong, but I must have been doing something wrong when I indicated the script above did not work properly.
You're code raises a TypeError: 'list' object is not callable exception when you try to assign path, in this line:
path = random.choice((glob.glob(pattern))("/home/my_files"))
glob.glob() returns a list (possibly empty). (Also, you put the glob.glob() call inside redundant parentheses.) Then, you try to call glob.glob()("/home/my_files/") (in essence, [...](), raising the TypeError exception.
import glob
import random
import pyperclip
files = [os.path.abspath(f) for f in glob.glob("./home/my_files/*.txt")]
path = random.choice(files)
with open(path) as f:
pyperclip.copy(f.read())
Can anyone spot why this is failing?
import pathlib
from shlex import quote
path = 'testdir(abc)/subdir(123)'
filename = 'test'
content = \
"""hello
world
"""
pathlib.Path(path).mkdir(mode=0o770, parents=True, exist_ok=True)
md5_filename = quote(str(pathlib.Path(path) / (filename + '.txt')))
with open(md5_filename, 'w') as f:
f.write(content)
I'm getting this traceback
(tools) $ python test_filemake.py
Traceback (most recent call last):
File "test_filemake.py", line 13, in <module>
with open(md5_filename, 'w') as f:
FileNotFoundError: [Errno 2] No such file or directory: "'testdir(abc)/subdir(123)/test.txt'"
I think I don't understand posix paths well enough to understand what's going on. If I take the parentheses out of the directory names in the path, it works fine. shlex.quote() is adding the extra layer of double quotes, which seems to be breaking things.
I'm trying to create a text file with a tree of all files / dirs from a place that I choose using os.chdir(). My approach is to print the tree and to save all prints to the text file. The problem is that it doesn't copy the printed tree and the file is blank.
What am I doing wrong?
And is there a way to write this kind of data to the file without to actually print it?
My code:
import os
import sys
f = open("tree.txt", "w")
os.chdir("c:\\Users\Daniel\Desktop")
sys.stdout = f
os.system("tree /f")
f.close()
Edit
I was able to get the file tree from the clipboard after executing the command, however it gives me and eror when it tried to write to the txt file.
code:
import os
import tkinter
with open("tree.txt", "w") as f:
os.system("tree /f |clip")
root = tkinter.Tk()
tree = root.clipboard_get()
print(tree)
f.write(tree)
eror:
Traceback (most recent call last):
File "c:\Users\Daniel\Desktop\Tick\code_test\files.py", line 9, in <module>
f.write(tree)
File "C:\Users\Daniel\AppData\Local\Programs\Python\Python38-32\lib\encodings\cp1252.py", line 19, in encode
return codecs.charmap_encode(input,self.errors,encoding_table)[0]
UnicodeEncodeError: 'charmap' codec can't encode character '\u2502' in position 80: character maps to <undefined>
solution
So I found the problem, I needed to use codec to be able write unicode to the text file. Now it works very well
code:
import os
import tkinter
import codecs
with codecs.open("tree.txt", "w", "utf8") as f:
os.chdir("c:\\Users")
os.system("tree /f |clip")
root = tkinter.Tk()
tree = root.clipboard_get()
f.write(tree)
Method check_output from subprocess module can help you to catch program output:
import subprocess
f = open("tree.txt", "wb")
tree_output = subprocess.check_output('tree /f', shell=True, cwd=r'c:\Users\Daniel\Desktop')
f.write(tree_output)
f.close()
Or with context manager:
import subprocess
with open("tree.txt", "wb") as f:
f.write(subprocess.check_output('tree /f', shell=True, cwd=r'c:\Users\Daniel\Desktop'))
Option wb is required because check_output returns bytes not a str. If you want to process output like a string - call tree_output.decode() first.
I have images in the same directory with a python file, i am trying to loop over the images and convert them into base64 but am getting this error.
Am using Ubuntu 14.0.4
Traceback (most recent call last):
File "convert_to_base64.py", line 33, in <module>
print(main())
File "convert_to_base64.py", line 26, in main
convert_to_base64()
File "convert_to_base64.py", line 19, in convert_to_base64
with open("*.jpg", "rb") as f:
IOError: [Errno 2] No such file or directory: '*.jpg'
Here is my python code
# -*- coding: utf-8 -*-
import os
import sys
import xlrd
import base64
import urllib
from datetime import datetime
reload(sys) # to re-enable sys.setdefaultencoding()
sys.setdefaultencoding('utf-8')
def convert_to_base64():
"""
Read all jpg images in a folder,
and print them in base64
"""
with open("*.jpg", "rb") as f:
data = base64.b64decode(f.read())
print data
def main():
start_datetime = datetime.now()
convert_to_base64()
end_datetime = datetime.now()
print '------------------------------------------------------'
print 'Script started : {}'.format(start_datetime)
print 'Script finished: {}'.format(end_datetime)
if __name__ == '__main__':
print(main())
print('Done')
someone help me figure out what am doing wrong.
Thanks
This is how I looped for images in a directory:
import os
pictures = []
for file in os.listdir("pictures"):
if file[-3:].lower() in ["png"]:
pictures.append(file)
Please refer to Python documentation https://docs.python.org/2/tutorial/inputoutput.html for more info on open() function:
open() returns a file object, and is most commonly used with two arguments: open(filename, mode).
When I run my program, I get the following error and am not sure on how to correct it. Can someone help with explaining what this error is and how to correct it? Newb here so details are appreciated. Thanks for your time in advance!
Code:
#!/usr/bin/python
import zipfile
from PySide import QtGui
import re
#Select file to extract
app = QtGui.QApplication([])
dialog = QtGui.QFileDialog()
dialog.setFileMode(QtGui.QFileDialog.AnyFile)
if (dialog.exec()):
fileName = dialog.selectedFiles()
#Select Directory to extract to
dialog = QtGui.QFileDialog()
dialog.setFileMode(QtGui.QFileDialog.Directory)
dialog.setOption(QtGui.QFileDialog.ShowDirsOnly)
if (dialog.exec()):
dirName = dialog.selectedFiles()
print("Extracting.....")
zFile= zipfile.ZipFile(fileName)
zFile.extractall(dirName)
Error output:
Traceback (most recent call last):
File "C:\Users\Jennifer\Documents\BatchScripts\unzip.py", line 22, in <module>
zFile= zipfile.ZipFile(fileName)
File "C:\Python33\lib\zipfile.py", line 933, in __init__
self._RealGetContents()
File "C:\Python33\lib\zipfile.py", line 970, in _RealGetContents
endrec = _EndRecData(fp)
File "C:\Python33\lib\zipfile.py", line 237, in _EndRecData
fpin.seek(0, 2)
AttributeError: 'list' object has no attribute 'seek'
In your file and target directory code blocks, dialog.selectedFiles() returns a list. zipfile.ZipFile can only handle one file at a time, hence your error. To iterate over the list being provided by dialog.selectedFiles(), use the following:
for archive in fileName: # you should probably change it to fileNames to reflect its true nature
zfile = zipfile.ZipFile(archive)
print("Extracting " + str(zfile.filename) + "...")
zfile.extractall(dirName[0]) # also a list, extract to first item and ignore rest
and you should be all set.