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I am relatively new to coding in Python. I have mainly used MatLab in the past and am used to having vectors that can be referenced explicitly rather than appended lists. I have a script where I generate a list of x- and y- (z-, v-, etc) values. Later, I want to interpolate and then print a table of the values at specified points. Here is a MWE. The problem is at line 48:
yq = interp1d(x_list, y_list, xq(nn))#interp1(output1(:,1),output1(:,2),xq(nn))
I'm not sure I have the correct syntax for the last two lines either:
table[nn] = ('%.2f' %xq, '%.2f' %yq)
print(table)
Here is the full script for the MWE:
#This script was written to test how to interpolate after data was created in a loop and stored as a list. Can a list be accessed explicitly like a vector in matlab?
#
from scipy.interpolate import interp1d
from math import * #for ceil
from astropy.table import Table #for Table
import numpy as np
# define the initial conditions
x = 0 # initial x position
y = 0 # initial y position
Rmax = 10 # maxium range
""" initializing variables for plots"""
x_list = [x]
y_list = [y]
""" define functions"""
# not necessary for this MWE
"""create sample data for MWE"""
# x and y data are calculated using functions and appended to their respective lists
h = 1
t = 0
tf = 10
N=ceil(tf/h)
# Example of interpolation without a loop: https://docs.scipy.org/doc/scipy/tutorial/interpolate.html#d-interpolation-interp1d
#x = np.linspace(0, 10, num=11, endpoint=True)
#y = np.cos(-x**2/9.0)
#f = interp1d(x, y)
for i in range(N):
x = h*i
y = cos(-x**2/9.0)
""" appends selected data for ability to plot"""
x_list.append(x)
y_list.append(y)
## Interpolation after x- and y-lists are already created
intervals = 0.5
nfinal = ceil(Rmax/intervals)
NN = nfinal+1 # length of table
dtype = [('Range (units?)', 'f8'), ('Drop? (units)', 'f8')]
table = Table(data=np.zeros(N, dtype=dtype))
for nn in range(NN):#for nn = 1:NN
xq = 0.0 + (nn-1)*intervals #0.0 + (nn-1)*intervals
yq = interp1d(x_list, y_list, xq(nn))#interp1(output1(:,1),output1(:,2),xq(nn))
table[nn] = ('%.2f' %xq, '%.2f' %yq)
print(table)
Your help and patience will be greatly appreciated!
Best regards,
Alex
Your code has some glaring issues that made it really difficult to understand. Let's first take a look at some things I needed to fix:
for i in range(N):
x = h*1
y = cos(-x**2/9.0)
""" appends selected data for ability to plot"""
x_list.append(x)
y_list.append(y)
You are appending a single value without modifying it. What I presume you wanted is down below.
intervals = 0.5
nfinal = ceil(Rmax/intervals)
NN = nfinal+1 # length of table
dtype = [('Range (units?)', 'f8'), ('Drop? (units)', 'f8')]
table = Table(data=np.zeros(N, dtype=dtype))
for nn in range(NN):#for nn = 1:NN
xq = 0.0 + (nn-1)*intervals #0.0 + (nn-1)*intervals
yq = interp1d(x_list, y_list, xq(nn))#interp1(output1(:,1),output1(:,2),xq(nn))
table[nn] = ('%.2f' %xq, '%.2f' %yq)
This is where things get strange. First: use pandas tables, this is the more popular choice. Second: I have no idea what you are trying to loop over. What I presume you wanted was to vary the number of points for the interpolation, which I have done so below. Third: you are trying to interpolate a point, when you probably want to interpolate over a range of points (...interpolation). Lastly, you are using the interp1d function incorrectly. Please take a look at the code below or run it here; let me know what you exactly wanted (specifically: what should xq / xq(nn) be?), because the MRE you provided is quite confusing.
from scipy.interpolate import interp1d
from math import *
import numpy as np
Rmax = 10
h = 1
t = 0
tf = 10
N = ceil(tf/h)
x = np.arange(0,N+1)
y = np.cos(-x**2/9.0)
interval = 0.5
NN = ceil(Rmax/interval) + 1
ip_list = np.arange(1,interval*NN,interval)
xtable = []
ytable = []
for i,nn in enumerate(ip_list):
f = interp1d(x,y)
x_i = np.arange(0,nn+interval,interval)
xtable += [x_i]
ytable += [f(x_i)]
[print(i) for i in xtable]
[print(i) for i in ytable]
I have 2 columns in data frames.
Column 1 = Source
Column 2 = Target
My data source
Source Target
A B
W X
B C
C D
C Z
A Z
Z Y
Input = A, The output should be display as below.
Source Target
A B
B C
C D
C Z
A Z
Z Y
I try to code as below but not finished yet.
In [1]:
a = input()
b = []
for Source, Target in zip(data.Source,data.Target):
if Source == a:
b.append(True)
else:
b.append(False)
Input = A
In [2]: is_long = pd.Series(b)
is_long
Out [2]: 0 True
1 False
2 True
3 True
4 ...
In [3]: data[is_long]
Out [3]: Source Target
A B
B C
C D
C Z
A Z
Z Y
As I understood, the idea is:
try in turn each vertice from the source DataFrame,
the current vertice is "OK" when its Source node has been visited
before,
the visited list contains initially only the node given by the user and
should be extended by Target node of each checked vertice.
Start from defining the following class:
class Visitor:
def __init__(self):
self.clear()
def addNode(self, node):
if not self.isVisited(node):
self._nodes.append(node)
def isVisited(self, node):
return node in self._nodes
def clear(self):
self._nodes = []
This class keeps a register of visited nodes. It will be used soon.
Then define a function checking the "continuation criterion" for the current
row:
def isContinued(row, vs):
res = vs.isVisited(row.Source)
if res:
vs.addNode(row.Target)
return res
The first argument is the current row and the second is a Visitor object.
Then run:
vs = Visitor()
vs.addNode(a)
df[df.apply(isContinued, axis=1, vs=vs)]
The first line creates a Visitor object.
The second adds the "starting node" (just given by the user) to the
"visited list".
Then df.apply(isContinued, axis=1, vs=vs) creates a Boolean vector
- the continuation criteria for edges.
As isContinued function is applied to subsequent edges, the "visited list"
is extended with Target node.
The (just updated) visited list is then used to compute the continuation
criteria for subsequent edges.
The result is a list of edges meeting the continuation criterion.
I am trying to find conditional mutual information between three discrete random variable using pyitlib package for python with the help of the formula:
I(X;Y|Z)=H(X|Z)+H(Y|Z)-H(X,Y|Z)
The expected Conditional Mutual information value is= 0.011
My 1st code:
import numpy as np
from pyitlib import discrete_random_variable as drv
X=[0,1,1,0,1,0,1,0,0,1,0,0]
Y=[0,1,1,0,0,0,1,0,0,1,1,0]
Z=[1,0,0,1,1,0,0,1,1,0,0,1]
a=drv.entropy_conditional(X,Z)
##print(a)
b=drv.entropy_conditional(Y,Z)
##print(b)
c=drv.entropy_conditional(X,Y,Z)
##print(c)
p=a+b-c
print(p)
The answer i am getting here is=0.4632245116328402
My 2nd code:
import numpy as np
from pyitlib import discrete_random_variable as drv
X=[0,1,1,0,1,0,1,0,0,1,0,0]
Y=[0,1,1,0,0,0,1,0,0,1,1,0]
Z=[1,0,0,1,1,0,0,1,1,0,0,1]
a=drv.information_mutual_conditional(X,Y,Z)
print(a)
The answer i am getting here is=0.1583445441575102
While the expected result is=0.011
Can anybody help? I am in big trouble right now. Any kind of help will be appreciable.
Thanks in advance.
I think that the library function entropy_conditional(x,y,z) has some errors. I also test my samples, the same problem happens.
however, the function entropy_conditional with two variables is ok.
So I code my entropy_conditional(x,y,z) as entropy(x,y,z), the results is correct.
the code may be not beautiful.
def gen_dict(x):
dict_z = {}
for key in x:
dict_z[key] = dict_z.get(key, 0) + 1
return dict_z
def entropy(x,y,z):
x = np.array([x,y,z]).T
x = x[x[:,-1].argsort()] # sorted by the last column
w = x[:,-3]
y = x[:,-2]
z = x[:,-1]
# dict_w = gen_dict(w)
# dict_y = gen_dict(y)
dict_z = gen_dict(z)
list_z = [dict_z[i] for i in set(z)]
p_z = np.array(list_z)/sum(list_z)
pos = 0
ent = 0
for i in range(len(list_z)):
w = x[pos:pos+list_z[i],-3]
y = x[pos:pos+list_z[i],-2]
z = x[pos:pos+list_z[i],-1]
pos += list_z[i]
list_wy = np.zeros((len(set(w)),len(set(y))), dtype = float , order ="C")
list_w = list(set(w))
list_y = list(set(y))
for j in range(len(w)):
pos_w = list_w.index(w[j])
pos_y = list_y.index(y[j])
list_wy[pos_w,pos_y] += 1
#print(pos_w)
#print(pos_y)
list_p = list_wy.flatten()
list_p = np.array([k for k in list_p if k>0]/sum(list_p))
ent_t = 0
for j in list_p:
ent_t += -j * math.log2(j)
#print(ent_t)
ent += p_z[i]* ent_t
return ent
X=[0,1,1,0,1,0,1,0,0,1,0,0]
Y=[0,1,1,0,0,0,1,0,0,1,1,0]
Z=[1,0,0,1,1,0,0,1,1,0,0,1]
a=drv.entropy_conditional(X,Z)
##print(a)
b=drv.entropy_conditional(Y,Z)
c = entropy(X, Y, Z)
p=a+b-c
print(p)
0.15834454415751043
Based on the definitions of conditional entropy, calculating in bits (i.e. base 2) I obtain H(X|Z)=0.784159, H(Y|Z)=0.325011, H(X,Y|Z) = 0.950826. Based on the definition of conditional mutual information you provide above, I obtain I(X;Y|Z)=H(X|Z)+H(Y|Z)-H(X,Y|Z)= 0.158344. Noting that pyitlib uses base 2 by default, drv.information_mutual_conditional(X,Y,Z) appears to be computing the correct result.
Note that your use of drv.entropy_conditional(X,Y,Z) in your first example to compute conditional entropy is incorrect, you can however use drv.entropy_conditional(XY,Z), where XY is a 1D array representing the joint observations about X and Y, for example XY = [2*xy[0] + xy[1] for xy in zip(X,Y)].
I am trying to put numbers in a function that has partial derivatives but I can't find a correct way to do it,I have searched all the internet and I always get an error.Here is the code:
from sympy import symbols,diff
import sympy as sp
import numpy as np
from scipy.misc import derivative
a, b, c, d, e, g, h, x= symbols('a b c d e g h x', real=True)
da=0.1
db=0.2
dc=0.05
dd=0
de=0
dg=0
dh=0
f = 4*a*b+a*sp.sin(c)+a**3+c**8*b
x = sp.sqrt(pow(diff(f, a)*da, 2)+pow(diff(f, b)*db, 2)+pow(diff(f, c)*dc, 2))
def F(a, b, c):
return x
print(derivative(F(2 ,3 ,5)))
I get the following error: derivative() missing 1 required positional argument: 'x0'
I am new to python so maybe it's a stupid question but I would feel grateful if someone helped me.
You can find three partial derivatives of function foo by variables a, b and c at the point (2,3,5):
f = 4*a*b+a*sp.sin(c)+a**3+c**8*b
foo = sp.sqrt(pow(diff(f, a)*da, 2)+pow(diff(f, b)*db, 2)+pow(diff(f, c)*dc, 2))
foo_da = diff(foo, a)
foo_db = diff(foo, b)
foo_dc = diff(foo, c)
print(foo_da," = ", float(foo_da.subs({a:2, b:3, c:5})))
print(foo_db," = ", float(foo_db.subs({a:2, b:3, c:5})))
print(foo_dc," = ", float(foo_dc.subs({a:2, b:3, c:5})))
I have used a python package 'sympy' to perform the partial derivative. The point at which the partial derivative is to be evaluated is val. The argument 'val' can be passed as a list or tuple.
# Sympy implementation to return the derivative of a function in x,y
# Enter ginput as a string expression in x and y and val as 1x2 array
def partial_derivative_x_y(ginput,der_var,val):
import sympy as sp
x,y = sp.symbols('x y')
function = lambda x,y: ginput
derivative_x = sp.lambdify((x,y),sp.diff(function(x,y),x))
derivative_y = sp.lambdify((x,y),sp.diff(function(x,y),y))
if der_var == 'x' :
return derivative_x(val[0],val[1])
if der_var == 'y' :
return derivative_y(val[0],val[1])
input1 = 'x*y**2 + 5*log(x*y +x**7) + 99'
partial_derivative_x_y(input1,'y',(3,1))
I have a folder with 38 files. The names are like this:
AWA_s1_features.mat, AWA_s2_features.mat......AWA_s38_features.mat
Each file is an array with 28 columns but with different # of rows. For example: AWA_s1_features.mat = (139,28), AWA_s2_features.mat = (199, 28) and so on.
As I am doing machine learning I need to join all these files in 1 huge array and label each row. So for the 139 rows of AWA_s1_features.mat there must be 139 1s; for AWA_s2_features.mat there must be 199 2s, and so on until AWA_s38_features.mat which must have a # of 38s.
This is what I mean:
I wrote some code. But I have found that the files are not called in order and therefore the labeling is wrong. For example, AWA_s1_features.mat is not the first file to be called and it has been labeled as 11. AWA_s2_features.mat has been labeled as 21.
So how can I improve my code so that it calls each file in the correct sequence?
Here is the code:
import numpy as np
import scipy.io as sio
import glob
read_files = glob.glob('I:/2D/Features 2D/AWA_s*.mat')
x = np.array([])
y = np.array([])
q = 1
for f in read_files:
l=sio.loadmat(f)['features']
x = np.concatenate((x, l), axis=0) if x.size else l
y_temp = q*np.ones((l.shape[0],1))
y = np.concatenate((y, y_temp), axis=0) if y.size else y_temp
q = q + 1
sio.savemat('AWA_FeaturesAll.mat', {'x':x, 'y':y})
The problem is that the default sorting is alphabetical, meaning that "11" comes before "2". You want numerical sorting and one way would be to use the sorted function with a key parameter, like so:
import numpy as np
import scipy.io as sio
import glob
read_files = glob.glob('I:/2D/Features 2D/AWA_s*.mat')
x = np.array([])
y = np.array([])
q = 1
for f in sorted(read_files, key=lambda f: int(f.split('_')[1][1:])):
l=sio.loadmat(f)['features']
x = np.concatenate((x, l), axis=0) if x.size else l
y_temp = q*np.ones((l.shape[0],1))
y = np.concatenate((y, y_temp), axis=0) if y.size else y_temp
q = q + 1
sio.savemat('AWA_FeaturesAll.mat', {'x':x, 'y':y})