Problems to display Web Scraping values in Tkinter - python-3.x

Question

I am trying to display an image inside a Tkinter window through Web Scraping displaying a message from a certain point on the website that says in Portuguese "Capella Ganhou" or "Procyon Ganhou".
I tried to look in different forums for a solution but I couldn't find any that fixes the error in my situation. I also tested with print to make sure the string exists and is returning its value and also encapsulated it into a variable.
The source code and the error are below .
from tkinter import *
import urllib.request
from bs4 import BeautifulSoup
from IPython.display import Image, display
from PIL import Image, ImageTk
import io
def capella_tg():
resultado_tg = StringVar()
resultado_tg.set(soup.find_all("font")[5].string)
label_resultado_tg = Label(root, textvariable=resultado_tg).pack()
def procyon_tg():
resultado_tg = StringVar()
resultado_tg.set(soup.find_all("font")[4].string[3:])
label_resultado_tg = Label(root, textvariable=resultado_tg).pack()
def img_capella():
raw_data = urllib.request.urlopen("https://i.imgur.com/AHLqtt0.jpg").read()
im = Image.open(io.BytesIO(raw_data))
image = ImageTk.PhotoImage(im)
label1 = Label(root, image=image).pack()
def img_procyon():
raw_data = urllib.request.urlopen("https://i.imgur.com/TQyCnfD.jpg").read()
im = Image.open(io.BytesIO(raw_data))
image = ImageTk.PhotoImage(im)
label1 = Label(root, image=image).pack()
root = Tk()
with urllib.request.urlopen("http://www.cabaleasy.com") as url: page = url.read()
soup = BeautifulSoup(page, "html.parser")
#print(soup.find_all("font")[5].string)
try:
capella_tg()
except:
procyon_tg()
if capella_tg():
img_capella()
elif procyon_tg():
img_procyon()
root.mainloop()
-------ERROR---------
Traceback (most recent call last):
File "C:/Users/LucasDEV/PycharmProjects/LucasDEV/WEB_SCRAPPING/TESTES.py", line 49, in <module>
elif procyon_tg():
File "C:/Users/LucasDEV/PycharmProjects/LucasDEV/WEB_SCRAPPING/TESTES.py", line 17, in procyon_tg
resultado_tg.set(soup.find_all("font")[4].string[3:])
TypeError: 'NoneType' object is not subscriptable

Answer 1

#Dipen Shah That is why I used the try/except structure for. But it's not working and I'm getting the same error. I also tried this way:
def capella_tg():
resultado_tg = StringVar()
try:
resultado_tg.set(soup.find_all("font")[5].string)
label_resultado_tg = Label(root, textvariable=resultado_tg).pack()
except:
pass
i tested just using text and it works:
import urllib.request
from bs4 import BeautifulSoup
with urllib.request.urlopen("http://www.cabaleasy.com") as url: page = url.read()
soup = BeautifulSoup(page, "html.parser")
try:
print(soup.find_all("font")[5].string)
#At this moment, it will not be showing, cuz the status changes every hour
except:
print(soup.find_all("font")[4].string[3:])