I need a way to execute my python script every 15 mins starting from 9:30:42 till 15:00:42 every day from Mon-Fri.
I have explored APScheduler with cron syntax but can't figure out how to code the above condition. I tried below but doesn't work (execute is my function name)
sched.add_cron_job(execute, day_of_week='mon-fri', hour='9:30:42-15:00:42', minute='*/15')
Any pointer is deeply appreciated.
As far as I can tell you won't be able to do what you want with a single job.
This is the closest I could get with one:30-59/15 9-14 * * 1-5 which equates to Every 15 minutes, minutes 30 through 59 past the hour, between 09:00 AM and 02:59 PM, Monday through Friday.
Although it isn't exactly what you wanted I hope this helps as a base.
I wrote custom code to solve my problem. Posting here in case it helps someone. Any optimisations suggestions are welcome.
The first infinite loop starts the job when the start time is hit. The 2nd infinite loop wakes up every x minutes to check if next run time has approached. If yes, it executes else goes back to sleep. If the end time for execution has reached, then it breaks out
def execute_schedule_custom():
start_time_of_day = datetime.combine(date.today(), time(9, 30, 42))
next_run_time = start_time_of_day
end_time_of_day = datetime.combine(date.today(), time(15, 0, 42))
interval = 15
sleep_secs = 60 * 5 #sleep for 5 mins
while True:
if datetime.now() >= start_time_of_day:
execute()
next_run_time = start_time_of_day + timedelta(minutes=interval)
break
while True:
if datetime.now() >= end_time_of_day:
break
elif datetime.now() >= next_run_time:
execute()
next_run_time = next_run_time + timedelta(minutes=interval)
t.sleep(sleep_secs)
Related
scheduler = BlockingScheduler(timezone='US/Eastern')
scheduler.add_job(get_scores, 'cron', day_of_week='mon-fri', hour='8-18', minute='*/15')
scheduler.start()
I need this code to execute every 15 minutes from 9am - 5pm M-F EST. But for some reason it is doing:
Next wakeup is due at 2021-07-22 08:00:00-04:00 (in 47626.905794 seconds)
Thanks in advance!
timezone needs to be in the add_job, like:
scheduler.add_job(get_si_data, trigger='cron', day_of_week='mon-fri', hour='8-18', minute='*/15', timezone='US/Eastern')
I am trying to write cron job for every 5 minutes, starting from 4th minute, 9th, 14th, and so on...
const cron = require("node-cron");
cron.schedule(`4,9,14,19,24,29,34,39,44,49,54,59 * * * *`, async function() {
console.log('scheduleCron ',new Date());
// my function call
})
It is executing perfectly, but I want to know is this the only method to do like this or any other method?
Thanks in advance :)
“At every 5th minute from 4 through 59.”
4/5 * * * *
Crontab guru
Warning: Non standard! May not work with every cron.
Given two strings :
ex:
start_time="3:00 PM"
Duration="3:10"
Start time is in 12-hour clock format (ending in AM or PM), and duration time
that indicates the number of hours and minutes
Assume that the start times are valid times.The minutes in the duration time will
be a whole number less than 60, but the hour can be any whole number.
I need to add the duration time to the start time and return the result
(WITHOUT ANY USE OF LIBRARIES).
The result should be in 12-hour clock format (ending in AM or PM) indicates the
number of hours and minutes
ex:
start_time = "6:30 PM"
Duration = "205:12"
# Returns: 7:42 AM
I Tried and finally got the required answer but unable to produce correct AM or PM for
the result after addition.
what I Tried:
start_time = "6:30 PM"
Duration = "205:12"
#My answer =7:42
#expected :7:42 AM
Can someone help me with the logic to produce correct AM or PM after addition of start
time and Duration.
def add_time(a,b):
a=a.split()
b=b.split()
be=int(a[0][:a[0].find(':')])
af=int(a[0][a[0].find(':')+1:])
be1 = int(b[0][:b[0].find(':')])
af1 = int(b[0][b[0].find(':') + 1:])
return(((be+be1)//24)+1)
s=be+(be1)%12
p=af+af1
if ((s>12) and (p<60)) :
return(str(s-12)+":"+str(p))
elif ((s<12) and (p>60)) :
f = p-60
if len(str(f))<=1:
return(str(s+1)+":"+str('0'+str(f)))
else:
return (str(s + 1)+":"+(str(f)))
elif ((s<12) and (p<60)) :
return(str(s)+":"+str(p))
elif ((s>12) and (p>60)):
f=p-60
if len(str(f)) <= 1:
return (str((s -12)+1)+":"+('0' + str(f)))
else:
return (str((s -12)+1)+":"+(str(f)))
print(add_time("10:10 PM", "3:30"))
# Returns: 1:40 AM
print(add_time("11:43 PM", "24:20"))
# Returns: 12:03 AM
Your code does not seem to cover all edge cases, e.g. add_time("11:43 PM", "1:20") returns None because the case s==12 is not covered.
Therefore one should put <= instead of < in the respective if conditions. The case where the addition of the minutes leads to hours greater than 12 although the addition of the hours itself did not, is not covered either. So we should check the minutes first and the hours after that instead of simultaneously.
To make the code more readable, we use f-strings and can use str.split() with an argument, forgive me for changing the code quite a bit:
def add_time(a,b):
start = a.split()
start_h, start_m = [int(val) for val in start[0].split(':')]
start_app = start[1]
dur_h, dur_m = [int(val) for val in b.split(':')]
end_m = start_m+dur_m
end_h = end_m//60
end_m %= 60
end_h += start_h+dur_h
if (end_h//12)%2==0:
end_app = start_app
else:
end_app = 'AM' if start_app=='PM' else 'PM'
return f'{end_h:02}:{end_m:02} {end_app}'
I have the following scenario to be load tested for a service and it does not seem to work as expected. My scenario is as follows.
Test with rampUsers(100) over 15 minutes duration
Hold the users for about 10 minutes holdFor(10 minutes)
Then again rampUsers(200) over 15 minutes duration
Hold the users for about 10 minutes holdFor(10 minutes)
Then again rampUsers(200) over 15 minutes duration
I am trying to use throttle option for this but it does not seem to work as expected
here is my code snippets combinations that I have tried so far
//NUM_USERS = 300
//DURATION = 15 minutes
//CONSTANT_DURATION = 5 minutes
// Tried with different combinations of NUM_USERS and DURATION but not helpful
scn.inject(
rampUsers(NUM_USERS*1) during DURATION,
constantUsersPerSec(1) during CONSTANT_DURATION,
rampUsers(NUM_USERS*2) during DURATION,
constantUsersPerSec(2) during CONSTANT_DURATION,
rampUsers(NUM_USERS*3) during DURATION,
constantUsersPerSec(3) during CONSTANT_DURATION
)
scn.inject(
rampUsers(NUM_USERS) during DURATION
).throttle(
reachRps(NUM_USERS/4) in (CONSTANT_DURATION),
holdFor(CONSTANT_DURATION),
jumpToRps(NUM_USERS/3),
holdFor(CONSTANT_DURATION),
jumpToRps(NUM_USERS/2),
holdFor(CONSTANT_DURATION)
)
scn.inject(
rampUsers(NUM_USERS) during DURATION
).throttle(
holdFor(CONSTANT_DURATION),
reachRps(NUM_USERS+NUM_USERS) in (DURATION+DURATION),
holdFor(CONSTANT_DURATION)
)
Can any one help on this which one works in this case. I would like to have a graph like this
To target injection rate as you stated you want in the comments, you need something like this
scn.inject(
rampUsersPerSec(0) to (300) during DURATION,
constantUsersPerSec(300) during CONSTANT_DURATION,
rampUsersPerSec(300) to (600) during DURATION,
constantUsersPerSec(600) during CONSTANT_DURATION,
...
)
import pyttsx3
import time
time = time.strftime("%M minutes past %I")
engine = pyttsx3.init()
engine.setProperty('rate',200)
engine.say("Hi Tom");
engine.say("The time is" + time);
engine.runAndWait();
When running this it will say "Hi Tom, the time is 07 minutes past 10" for example and will say a 0 in front of the minutes if its between 0-9 but 10-59 its says it normally. Is there a way to remove the 0 from being said?
Could this be useful
t = time.localtime()
...
engine.say('The time is %d minutes past %s' % (t.tm_min,t.tm_hour))