I have intial date time in this format
'2017-01-01 09:00:00.000'
I want to increment it by preferably by millisecond. Even second will do. I can't find formula for to increment Date time in particular format.
What I found was Time(hours,minutes,seconds) but it does not work.
Assuming your date is in Cell A1. The formula to add 1 second would be =A1+1/86400. To add a millisecond would be =A1+1/86400000. To add 5 milliseconds would be A1+5/86400000
Related
Is there a way for me to format a column where the values I enter in the format HH:MM (elapsed time, not datetime) are converted to hours in decimal, preferably in the same column via some custom formula?
For example,
HH:MM
H (Decimal)
07:39
7.65
02:15
2.25
06:00
6
At the moment, I manually calculate the equivalent and enter them into the column but it would be nice to directly copy a timestamp and have the column automatically format it but I couldn't see an option for this in Date/Time formatting settings.
Simply multiply your hh:mm durations by 24, ensuring that the cells where you want the decimal hours returned are formatted as 'Number'. Or to force formatting as a number using a formula: =text(duration_cell*24,"#.##") where duration_cell is a cell with the duration in hh:mm format.
There is no way to do that I know of because Excel stores times/dates as floats. Each 24 hour period equals 1, therefore 7:33 equals .31458 Therefore, you won't be able to do this without a helper column.
You can do this with either #The God of Biscuits answer, or alternatively your helper column can have the formula:
=(A1*24)
and you set that column's cell format to Number.
All date and time is a format of a double value.
Time is the amount after the comma.
And all in front of comma is days since 00.01.1900.
Meaning 07:37:00 = 0,32 days.
Excel have a ways to pull the amount of hours with =HOUR('Your referance date time cell value')
You can aply this formula: =HORA(A2)+(MINUTO(A2)/60)
I'm struggling to make a formula work in excel.
My case : I have data in m/d/yyyy h:mm AM/PM format on E col.
I have data that goes to the next day post midnight. I'm looking to create another column lets say F where I want to check for data between time 5:30pm to next day 5:30am and return date in m/d/yyyy(col F)
Example :
Let's say a job request came in at 3/21/2021 4:30am, I want it to return 3/20/2021 on col F (previous date)
This is required due to different timezone and unfortunately the timezone cannot be altered on the data.
If it's really true that your data are in "m/d/yyyy hh:mm PM format" then this formula will deduct 8 hours from the value found in E4 and return a true date.
=DATE(RIGHT(LEFT(E4,FIND(" ",E4)-1),4),LEFT(E4,FIND("/",E4)-1),MID(E4,FIND("/",E4)+1,1+ISERROR(FIND("/",MID(E4,LEFT(E4,FIND("/",E4)-1),2)))))+TIMEVALUE(MID(E4,10,10))-(8/24)
A "True" date is a number which takes its display format from the cell format you set, meaning the "data" are different from the display. A "Fake" date (my expression) is a text string that looks like a date but is unsuitable for calculations because it's not a number. The "data" underlying a fake date are identical to the display. My above formula spends 95% of its effort on converting the fake date into a true one and is likely to earn your comment that it "doesn't work" because it returns a number. If so, don't comment. Set the cell format to the kind of display you want.
Of course, if E4 has a true date the effort can be reduced and the formula you seek would be simply
=E4-(8/24)
This is because in Excel dates one day has a value of 1. Therefore 1 hour = 1/24 and 8 hours = 1/24*8 or 8/24. Change the number of hours as desired, add or subtract them from the original as needed.
BTW, if your original data are really text (fake dates) do consider converting them to true dates using the 95% part of my first formula and then processing them as true dates. As you see, there is no advantage in keeping fakes around.
I have got a start date and end date in this custom format
dd.mm.yyyy hh:mm in excel cells.
What i need is to fill specific row with dates incremented by half hour from start date to end date using VBA code. And i havent got any idea how to do this.
On web there are some examples with similar problems but with only months or only hours and those are dates format not custom.
You can do this with a simple formula.
Write your start date into cell A1
In A2 write =A1+(1/48)
Copy formula from A2 down
done.
How does this work?
Excel dates are represented as count of days since 1900. That means 1900-01-01 is the first day and represented by 1. All other dates are just the count of days since then. 1 represents one day. So since 1 day has 24 hours 1/48 represents half an hour.
The number format dd.mm.yyyy hh:mm how Excel shows the date is not relevant, because Excel only saves the value (amount of days since 1900) in the cell value.
So if you type the date of today into a cell 2018-10-11 Excel actually saves 43384 in the cell value (today it is 43384ᵗʰ day since 1900-01-01).
One option is to find the interval between start and stop point. Remember that excel dates that are actually dates and not strings are actually integers. The second thing to remember is time is the decimal part which represent fraction of a day. Test if your date (assuming it's in A1) is an actual date or a string with
=ISNUMBER(A1)
If that comes back TRUE you do not need to worry about converting your date. If it comes back FALSE, its actually a string and will need to be converted for excel to work with it.
Divide this interval by 30 minutes, or 30/60/24 to and add 1. This will tell you how many iteration you will need which you can put into a For loop
Start_Number = Range("A1")
End_number = Range(("A2")
Stamp = Start_Number
Interval_number = End_Number - Start_Number
Counter = integer of (Interval_number / (30/60/24))
For x = 1 to counter
write Stamp to cell
Stamp = Stamp + 30/60/24
Next x
Allternatively you could set up a while loop.
Do While datetime < Stop_Point
Write datetime to cell
Datetime=datetime + 30/60/24
Loop
Please note, not actual code but giving idea where OP had no idea where to start.
I have a spreadsheet that lists the date and time of an event in the same cell (mm/dd/yy h:mm). I need to find a way to count how many events took place between a certain time range in a Hourly Basis.
I could sum if the cell contains dates only however the cell contains with date which i am unable to get the values.
Basically, all datas are in cell A, so i need to count how many events happened at 6am, 7am , and so on... as on hourly basis.
Your column A looks like properly formatted date & time value, so its manipulation is easy. If it's not (ie, not date but text) you should first convert it to date value.
=DATE(MID(A2,7,4), MID(A2,4,2), LEFT(A2,2)) + TIME(MID(A2,12,2), MID(A2,15,2), RIGHT(A2,2))
Say this was C2. Now that column C is date & time, set $D$2 to date to query(ex 2017-03-26), E2 to start time(ex 6:00), and F2 to end time(ex 7:00), then you can count events from 6:00 to 7:00 like this:
=COUNTIFS(C:C,">="&($D$2+E2), C:C,"<"&($D$2+F2))
Sample file is here and its screenshot is below.
If the times spanned different dates and you still wanted to see how many events happened in a particular hour of the day, you would need an array-type formula, e.g. if the start time in hours (entered as a normal number) is in C2
=SUMPRODUCT(--(HOUR($A$2:$A$10)=C2))
or if the start hour is entered as a time
=SUMPRODUCT(--(HOUR($A$2:$A$10)=HOUR(C2)))
I have a column "cycle time" with hh:mm:ss value format. I want to count the number of cells on the column which has the value of lesser than or equal to "04:00:00".
My below formula returns "0" value instead of "4". Here's the column values
and my formula is =COUNTIF('sheet1'!I:I,"<= 4:00:00")
Can anyone share me how to solve this?
Basic unit in date and time is one day is 1. So a fraction of a day represents time.
One day is 24 hours, so 4hs is 1/24 * 4=0.16666667
=COUNTIF('sheet1'!I:I,"<=0.16666667")
I recommend you save this value in a cell, i.e. P1=4/24
=COUNTIF('sheet1'!I:I,"<="&P1)
And also, as #Jeped commented, using TIME funciton:
=COUNTIF('sheet1'!I:I,"<="&TIME(4, 0, 0))