I have the following query and would like to extract the year from login_time. login_time is in timestamp format (i.e. 2019-03-12 08:51:35.000)
Select year(from_unixtime(cast(login_time as int))) from profile limit 100
There is an error - cannot cast timestamp to integer when I run this query. Does anyone know what's the reason for it? Would appreciate any advice!
There is an error - cannot cast timestamp to integer
This suggests the login_time is of timestamp data type, so you should just call year() on it:
year(login_time)
Related
Im trying to convert a varchar value into a date format.
The varchar value is 99/01/30and the result should be 1999-01-30.
Would somebody help me with this?
I'm trying to do this but :
select convert(date, convert(varchar, '99/01/30', 11),23) as date
but this gives me an error: Conversion failed when converting date and/or time from character string.
This
select convert(date, '99/01/30', 2) as date
will get you what you want. See also this page for more information about what the 2 means
I'm able to get the current timestamp using now() in NIFI. But I want to get the yesterday's timestamp in the below format and could not achieve it. what expression should be given for getting yesterday's timestamp at NIFI processor.
Egg: "superDate":"2021-03-07 23:59:00"
Thanks in advance!
${now():toNumber():minus(86400000):format('yyyy-MM-dd HH:mm:ss')}
Require your help as stuck in time conversion in presto.
I have a epoch column with name timestamp as a string datatype and i want to convert this into date timestamp.
I have used the below query after reading through various blogs:
SELECT date_parse(to_iso8601(from_unixtime(CAST(timestamp AS bigint)) AS date ,
'%Y-%m-%dT%H:%i:%s.%fZ'))
FROM wqmparquet;
Everytime i run this query i get an error:
INVALID_FUNCTION_ARGUMENT: Invalid format: "2020-04-27T19:49:50.000Z" is malformed at "T19:49:50.000Z"
Can somebody please help me on this.
I might be oversimplifying this, but if you want to convert an epoch string to a timestamp datatype, you can just do:
from_unixtime(cast(timestamp as bigint))
You can generate a timestamp with time zone by passing a second argument to from_unixtime(), as a time zone string.
Have done a lot of search before asking this question, like How to convert a string into date format, How to convert a string into date, but still can't figure it out.
So, here's the question, how to convert these string dates into date in Oracle:
"2016-08-15 10:45:30" (String type) -> 20160815 (Date type)
"20160815104530" (String type) -> 20160815 (Date type)
Any idea will be appreciated.
You are mixing two things here:
The first is the conversion of a String data type, in Oracle VARCHAR2 into a DATE data type.
The DATE data type has a precision of seconds, you can't change that. A DATE data type will always give you the date and time component, i.e year, month, day, hours, minutes and seconds: Oracle SQL Data Type Documentation
However, the second part of what you are asking is about how to format the date when retrieved. This is helpful when running reports, or other kinds of visual display of dates. For example, in the US you would most likely want your date columns appear in the format MM/DD/YYYY while everywhere else in the world you most likely want to stick with DD/MM/YYYY. Oracle lets you do that by telling it what NLS_DATE_FORMAT you want to use. You can set that parameter for each individual session as well as on database level, it is up to you (and your DBA) to decide where and when you want to set that. In your case you can apply this via the ALTER SESSION command:
SQL> ALTER SESSION SET nls_date_format='YYYY-MM-DD';
Session altered.
SQL> SELECT TO_DATE('2016-08-15 10:45:30', 'YYYY-MM-DD HH24:MI:SS') FROM DUAL;
TO_DATE(
----------
2016-08-15
SQL> SELECT TO_DATE('20160815104530', 'YYYYMMDDHH24MISS') FROM DUAL;
TO_DATE(
----------
2016-08-15
You use to_date():
select to_date(substr(str1, 1, 10), 'YYYY-MM-DD')
select to_date(substr(str2, 1, 8), 'YYYYMMDD')
I am very new to Cassandra. I have one table with the following columns CustomerId, Timestamp, Action,ProductId. I need to select the CustomerId and from date - to date using time stamp.I dont know how to do this in cassandra any help will be appreciated.
First of all could you should remember that you should plan what queries will be executed in future and make table keys according to it.
If you have keys as (customerId, date) then your query can be for example:
SELECT * FROM products WHERE customerId= '1' AND date < 1453726670241 AND date > 1453723370048;
Please, see http://docs.datastax.com/en/latest-cql/cql/cql_using/useAboutCQL.html