Using a generic trait as a trait parameter - rust

Question

How can I use related generic types? Here's what I've got (only the first line is giving me trouble):
impl<G, GS> TreeNode<GS> where G: Game, GS: GameState<G>{
pub fn expand(&mut self, game: &G){
if !self.expanded{
let child_states = self.data.generate_children(game);
for state in child_states{
self.add_child_with_value(state);
}
}
}
}
GameState is a trait that is generic to a Game, and self.data implements GameState<Game> of this type. The compiler tells me
error[E0207]: the type parameter `G` is not constrained by the impl trait, self type, or predicates
--> src/mcts.rs:42:6
|
42 | impl<G, GS> TreeNode<GS> where G: Game, GS: GameState<G>{
| ^ unconstrained type parameter
error: aborting due to previous error
but it seems to me like I'm constraining G both in the expand function, and in the fact that G needs to belong to GS.
Here are some more definitions as of now:
trait GameState<G: Game>: std::marker::Sized + Debug{
fn generate_children(&self, game: &G) -> Vec<Self>;
fn get_initial_state(game: &G) -> Self;
}
trait Game{}
struct TreeNode<S> where S: Sized{
parent: *mut TreeNode<S>,
expanded: bool,
pub children: Vec<TreeNode<S>>,
pub data: S,
pub n: u32
}
impl<S> TreeNode<S>{
pub fn new(data: S) -> Self{
TreeNode {
parent: null_mut(),
expanded: false,
children: vec![],
data,
n: 0
}
}
pub fn add_child(&mut self, mut node: TreeNode<S>){
node.parent = self;
self.children.push(node);
}
pub fn add_child_with_value(&mut self, val: S){
let new_node = TreeNode::new(val);
self.add_child(new_node);
}
pub fn parent(&self) -> &Self{
unsafe{
&*self.parent
}
}
}

Answer 1

impl<G, GS> TreeNode<GS> where G: Game, GS: GameState<G>{
// ...
}
The problem is that G is not constrained, so there may be multiple (possibly conflicting) implementations in this block, since GS maybe implement GameState<G> for multiple G. The parameter G is ambiguous.
If you want to keep GameState<G> able to be implemented for multiple G, you should move the constraints from the impl block to the method instead:
// note: G is now a type parameter of the method, not the impl block, which is fine
impl<GS> TreeNode<GS> {
pub fn expand<G>(&mut self, game: &G) where G: Game, GS: GameState<G> {
if !self.expanded{
let child_states = self.data.generate_children(game);
for state in child_states{
self.add_child_with_value(state);
}
}
}
}
If you only want GameState to be implemented for a single G, you should make G an associated type of GameState instead of a generic type parameter:
trait GameState: std::marker::Sized + Debug {
type G: Game;
fn generate_children(&self, game: &Self::G) -> Vec<Self>;
fn get_initial_state(game: &Self::G) -> Self;
}
// note: now G is given by the GameState implementation instead of
// being a free type parameter
impl<GS> TreeNode<GS> where GS: GameState {
pub fn expand(&mut self, game: &GS::G){
if !self.expanded{
let child_states = self.data.generate_children(game);
for state in child_states{
self.add_child_with_value(state);
}
}
}
}

Answer 2

The concrete type of G cannot be detemined based on the type of TreeNode<GS>; it is only known when expand is called. Note that expand could be called twice with different types for G.
You can express this by constraining the type parameters for the method instead of the entire implementation block:
impl<GS> TreeNode<GS> {
pub fn expand<G>(&mut self, game: &G)
where
G: Game,
GS: GameState<G>,
{
if !self.expanded {
let child_states = self.data.generate_children(game);
for state in child_states {
self.add_child_with_value(state);
}
}
}
}
If it should not be possible for expand to be called with different Gs then this is a problem of your modeling. Another way to fix this is to ensure that the type of G is known for all TreeNodes. e.g.:
struct TreeNode<G, S>
where
S: Sized,
{
parent: *mut TreeNode<G, S>,
expanded: bool,
pub children: Vec<TreeNode<G, S>>,
pub data: S,
pub n: u32,
}
And then your original implementation block should work as written, once you account for the extra type parameter.