After binding a function once and then unbinding it, I cannot bind it again later to the same function when later needed. I saw it works fine when I do not use '+' the binding function (I'm using bind_all incase it makes any difference). But when I use '+', it does bind it again...
IDLE:
>>> def Released(evnt):
print(evnt.keysym, ' Removed')
>>> funcid = _Win.bind_all("<KeyRelease>", Released, '+')
I hit some keys and on releasing I got the print statement in Released()
>>> _Win.unbind("<KeyRelease>", funcid)
>>> funcid = _Win.bind_all("<KeyRelease>", Released, '+')
I hit some keys but no output came. But there were no errors either.
So how do I fix this issue?
Thanks in Advance :)
Since no one answered, I thought a bit more and I came to a workaround to the problem of unbinding... Its not a solution but a workaround...
class FunctionManager:
def __init__(self, funcs = []):
self.funcs = list(funcs)
def __call__(self, evnt):
for func in self.funcs:
func(evnt)
def add(self, func):
self.funcs.append(func)
def remove(self, func):
self.funcs.remove(func)
So now instead of binding and unbinding function, which didn't work for me, I will just bind an instance of this class containing all required functions and remove functions from it later when required...
Related
I don't very understand the classes logic in python but cannot answer on web.
I have create a class to generate person info:
class person:
def fristnameGen(gender):
...
def emailGen(firstname,surname):
...
i create a bot to call it like this:
from person import *
class bots:
def __init__(self):
self.person = person()
def createDB(self):
print(self.person.name)
#do something...
finally i call it by a button with thread
from bots import *
import threading
class Panel:
def __init__(self):
self.top = tk.Tk()
self.bot = bots()
self.buildUI()
def foo(self):
self.bot.createDB(self.stringPhone.get())
def threadTheAction(func, *args):
t = threading.Thread(target=func, args=args)
t.setDaemon(True)
t.start()
def buildUI(self):
Button = tk.Button(self.top, text ="Start", command = lambda :self.threadTheAction(self.foo))
I get this error:
TypeError: 'Panel' object is not callable
However, i call it directly, its work
Button = tk.Button(self.top, text ="Start", command = lambda :self.foo())
How to fix the error?
...
2. Moreover, i tried create p1 = person() and p2= person() and print it. Found p1 and p2 is a same person, i prefer each new a class have a new one. How to generate "new person" using classes?
Thank you
You seem to have a lot of confusion about Object Oriented Programming in Python. Some of your methods have self parameters and some do not, seemingly at random. That's the source of your current error.
The threadTheAction method in your Panel class is getting the Panel instance passed in as its first argument, but that's named func in the method (since you omitted self). The real function you're passing as an argument gets caught in the variable argument *args. When the thread tries unsuccessfully to call it, you get an exception. Adding self before func would fix the immediate problem:
def threadTheAction(self, func, *args):
I suspect if your code got further along, you'd run into other errors with other methods without self in their parameter lists. For instance, none of the methods you've shown in person are likely to work correctly.
As for your second question, you haven't shown enough of person to know what's happening, but you're probably doing instance variables wrong somehow. With no self parameter in the methods, that's almost inevitable (since you assign to self.whatever to set a whatever attribute on the current instance). If you need help squaring that away, I suggest you ask a separate question (Stack Overflow is best when each question is self-contained) and provide the full code for your person class.
This is a skeleton of the function I want to enhance with a cache, because doing RPC (remote procedure call) involves a TCP connection to other host.
def rpc(rpc_server, rpc_func, arg):
return rpc_server.do_rpc(rpc_func, arg)
However, the most convenient way of simply decorating it with:
#functools.lru_cache()
does not work well, beacuse rpc_server objects come and go and this parameter should be ignored by the cache.
I can write a simple memoizing code myself. No problem with that. Actually, I see no other solution.
I am unable to rewrite this function in such way that #lru_cache() decorator can be applied and rpc_server will be passed as an argument (i.e. I don't want to make rpc_server a global variable). Is it possible?
I'm posting this just for completness. Comments are welcome, but please do not vote.
I have found a way how to satisfy the conditions from my question. I'm not going to use this code. But it shows how flexible Python is.
import functools
class BlackBox:
"""All BlackBoxes are the same."""
def __init__(self, contents):
# TODO: use a weak reference for contents
self._contents = contents
#property
def contents(self):
return self._contents
def __eq__(self, other):
return isinstance(other, type(self))
def __hash__(self):
return hash(type(self))
#functools.lru_cache()
def _cached_func(blackbox, real_arg):
print("called with args:", blackbox.contents, real_arg)
return real_arg + 1000
def cached_func(ignored_arg, real_arg):
# ignored means ignored by the cache
return _cached_func(BlackBox(ignored_arg), real_arg)
cached_func("foo", 1) # cache miss
cached_func("bar", 1) # cache hit
cached_func("bar", 2) # cache miss
cached_func("foo", 2) # cache hit
Sorry if the title is confusing. I'm writing a minimalist game engine, and trying to define a class called "Area" where if the player enters the area, a function defined by the user happens. For example, one could create an instance
Area(location,function) that would fire function on the player when the player enters location (for the sake of simplicity, let it be a point or something).
Note: in pseudo-python
# in init.py
...
def function(player):
kill player
deathZone = Area(location,function)
--------------------------------------
# in player.update()
...
for area on screen:
if player in area:
Area.function(player)
The point of this is that the developer (aka me) can use any function they choose for the area. Is there anyway to do this, or should I try a better approach?
Sure, this kind of thing is certainly possible. In python, everything is an object, even a function. So you can pass around a function reference as a variable. For example try the following code:
import math
def rectangle(a, b):
return a*b
def circle(radius):
return math.pi * radius**2
class FunctionRunner(object):
def __init__(self):
self.userFunction = None
self.userParams = None
def setUserFunction(self, func, *params):
self.userFunction = func
self.userParams = params
def runFunction(self):
return self.userFunction(*self.userParams)
if __name__ == '__main__':
functionRunner = FunctionRunner()
functionRunner.setUserFunction(rectangle, 6, 7)
print(functionRunner.runFunction())
functionRunner.setUserFunction(circle, 42)
print(functionRunner.runFunction())
Here you have two functions that are defined for an area, and a class called FunctionRunner which can run any function with any number of input arguments. In the main program, notice that you need only pass the reference to the function name, and any input arguments needed to the setUserFunction method. This kind of thing will allow you to execute arbitrary code on the fly.
Alternatively, you could also replace a method on your class with a reference to another function (which is what you are asking), though this seems less safe to me. But it is certainly possible. For example you could have a class like this:
class FunctionRunner2(object):
def __init__(self):
pass
def setUserFunction(self, func):
self.theFunction = func
def theFunction(self, *params):
pass
And then do this:
if __name__ == '__main__':
functionRunner2 = FunctionRunner2()
functionRunner2.setUserFunction(rectangle)
print(functionRunner2.theFunction(6,7))
functionRunner2.setUserFunction(circle)
print(functionRunner2.theFunction(42))
Hi I've been struggling to get this to work, each time i change something I receive another error. I've been trying to create an entry box with a function and then get the variable from the entry box into a label, created by a button press. When I tried to do this often this error came up.
TypeError: get() missing 1 required positional argument: 'self'
I then put self in in the method brackets.
command = lambda: x.myFunc(self.my_variable.get(self))
Then another error, which I'm not sure how to sort out.
AttributeError: 'My_Class' object has no attribute '_tk'
Here's the full code, I'm new to classes and self, so any corrections are welcome.
from tkinter import *
import time
class My_Class:
def start(self):
self.root=Tk()
self.my_variable=StringVar
self.entry_box=Entry(self.root, textvariable=self.my_variable)
self.entry_box.pack()
self.button=Button(self.root,text="Pass variable now",
command=lambda:x.myFunc(self.my_variable.get(self)))
self.button.pack()
def myFunc(self,my_variable):
self.lab=Label(self.root,text=self.my_variable)
self.lab.pack()
x=My_Class()
x.start()
This is the correct way to create a StringVar object:
text = StringVar() # note additional ()
Can you explain me what x is in the following statement:
lambda: x.myFunc(self.my_variable.get(self))
x is not visible inside the class, because it's declared outside the class.
myFunc is not indented correctly: you should indent it like the __init__ method.
I really recommend you to watch some tutorials on OOP before proceeding. You are basically trying to guess how OOP works.
If you make myFunc A method if the class (which you might be trying to do; it's hard to know because your indentation is wrong), you don't have to pass anything to myFunc. That function has access to everything in the class, so it can get what it needs, when it needs it. That lets you eliminate the use of lambda, which helps reduce complexity.
Also, you normally don't need a StringVar at all, it's just one more thing to keep track of. However, if you really need the label and entry to show exactly the same data, have them share the same textvariable and the text is updated automatically without you having to call a function, or get the value from the widget, or set the value n the label.
Here's an example without using StringVar:
class My_Class:
def start(self):
...
self.entry_box = Entry(self.root)
self.button = Button(..., command = self.myFunc)
...
def myFunc(self):
s = self.entry_box.get()
self.lab = Label(..., text = s)
...
In my PyQt4-based program, QSliders (with signals sliderMoved and sliderReleased connected to callables) sometimes "freeze", i.e. they don't move anymore when trying to drag them with the mouse, even though sliderMoved and sliderReleased are still emitted.
This behaviour happens seemingly randomly, sometimes after running the program for hours -- making it more or less impossible to reproduce and test.
Any help to solve this issue would be welcome.
EDIT: This is with PyQt 4.10.4 on Python 3.4 and Windows 7.
After some debugging I am pretty sure that this was due to calling a GUI slot from a separate thread, which (I knew) is forbidden. Fixing this to use a proper signal-slot approach seems to have fixed the issue.
After calling the patch function defined below, all slot calls are wrapped by a wrapper that checks that they are called only from the GUI thread -- a warning is printed otherwise. This is how I found the culprit.
import functools
import sys
import threading
import traceback
from PyQt4.QtCore import QMetaMethod
from PyQt4.QtGui import QWidget
SLOT_CACHE = {}
def patch():
"""Check for calls to widget slots outside of the main thread.
"""
qwidget_getattribute = QWidget.__getattribute__
def getattribute(obj, name):
attr = qwidget_getattribute(obj, name)
if type(obj) not in SLOT_CACHE:
meta = qwidget_getattribute(obj, "metaObject")()
SLOT_CACHE[type(obj)] = [
method.signature().split("(", 1)[0]
for method in map(meta.method, range(meta.methodCount()))
if method.methodType() == QMetaMethod.Slot]
if (isinstance(attr, type(print)) and # Wrap builtin functions only.
attr.__name__ in SLOT_CACHE[type(obj)]):
#functools.wraps(
attr, assigned=functools.WRAPPER_ASSIGNMENTS + ("__self__",))
def wrapper(*args, **kwargs):
if threading.current_thread() is not threading.main_thread():
print("{}.{} was called out of main thread:".format(
type(obj), name), file=sys.stderr)
traceback.print_stack()
return attr(*args, **kwargs)
return wrapper
else:
return attr
QWidget.__getattribute__ = getattribute