I am trying to write some intermediate results in a user defined VBA function to a worksheet. I have tested the function, and it works correctly. I am aware that I cannot modify / write to cells from a UDF, so I tried passing the relevant results to a subroutine which I hoped would then be able to write to the spreadsheet.
Unfortunately my scheme doesn't work, and I am trying to think through this problem.
Public Function f(param1, param2)
result = param1 * param2
call writeToSheet(result)
f = param1 + param2
end
public sub writeToSheet(x)
dim c as range
c = range("A1")
c.value = x
end
I would like to see the product of param1 and param2 in cell A1. Unfortunately, it does not happen - the subroutine just ends abruptly as soon as it attempts to execute the first statement (c = range("A1") ). What am I doing wrong, and how can I fix it?
If it is simply impossible to write to a spreadsheet in this way, is there some other way in which to store intermediate results for later review? My real life problem is a little more complicated that my stylized version above, as I generate a new set of intermediate results each time I go through a loop, and want to store them all for review.
This idea might work for you. The function ParamProduct calls SetProps which writes both parameters to custom document properties (View from File > Properties > Advanced Properties > Custom). Call the function with =ParamProduct(A1, A2) or =ParamProduct(123, 321)
Function ParamProduct(Param1 As Variant, _
Param2 As Variant) As Double
Dim Fun As Double
Dim Param As Variant
Dim i As Integer
Param = Param1
For i = 1 To 2
SetProp "Param" & i, Param
Param = Param2
Next i
ParamProduct = Param1 + Param2
End Function
Private Sub SetProp(Pname As String, _
PropVal As Variant)
' assign PropVal to document Property(Pname)
' create a custom property if it doesn't exist
Dim Pp As DocumentProperty
Dim Typ As MsoDocProperties
If IsNumeric(PropVal) Then
Typ = msoPropertyTypeNumber
Else
Select Case VarType(PropVal)
Case vbDate
Typ = msoPropertyTypeDate
Case vbBoolean
Typ = msoPropertyTypeBoolean
Case Else
Typ = msoPropertyTypeString
End Select
End If
On Error Resume Next
With ThisWorkbook
Set Pp = .CustomDocumentProperties(Pname)
If Err.Number Then
.CustomDocumentProperties.Add Name:=Pname, LinkToContent:=False, _
Type:=Typ, Value:=PropVal
Else
With Pp
If .Type <> Typ Then .Type = Typ
.Value = PropVal
End With
End If
End With
End Sub
Use this UDF to recall the properties to the worksheet.
Function GetParam(ByVal Param As String) As Variant
GetParam = Propty(Param)
End Function
Private Function Propty(Pname As String) As Variant
' SSY 050 ++
' return null string if property doesn't exist
Dim Fun As Variant
Dim Pp As DocumentProperty
On Error Resume Next
Set Pp = ThisWorkbook.CustomDocumentProperties(Pname)
If Err.Number = 0 Then
Select Case Pp.Type
Case msoPropertyTypeNumber
Fun = CLng(Fun)
Case msoPropertyTypeDate
Fun = CDate(Fun)
Case msoPropertyTypeBoolean
Fun = CBool(Fun)
Case Else
Fun = CStr(Fun)
End Select
Fun = Pp.Value
End If
The worksheet function below works (A6 has a value of "Param2")
=GetParam("Param1")*GetParam(A6)
The above code will create a property if it doesn't exist or change its value if it does. The sub below will delete an existing property and do nothing if it's called to delete a property that doesn't exist. You might call it from one of the above subs or functions.
Private Sub DelProp(ByVal Pname As String)
On Error Resume Next
ThisWorkbook.CustomDocumentProperties(Pname).Delete
Err.Clear
End Sub
Thanks a mill everyone. Printing to the immediate window is the easiest by far, but allowed me to print only a single item. I therefore concatenated all 5 items into a single string and printed it in the immediate window:
dummystr = CStr(slope1) & ", " & CStr(intercept1) & ", " & CStr(slope2) & ", " & CStr(intercept2) & ", " & CStr(sse(i))
Debug.Print dummystr
Related
The single most annoying feature in Excel's built-in VBA editor is—in my opinion—the aggressive autoformatting of the code, which insists on rewriting what I have typed as soon as the cursor leaves the line. It is particularly distressing that the editor collapses all whitespace, thus preventing any meaningful code alignment. For example, if I try to align a sequence of assignments by the equals sign with values aligned by the decimal separator:
price = 10.01
quantity = 3.2
vat = 0.11
the editor inevitably scrambles it by collapsing all spaces:
price = 10.01
quantity = 3.2
vat = 0.11
Is there any way to avoid this kind unwelcome autoformatting?
Assignment cosmetics :-)
There's neither a special VBE property to change the VBE (autoformatting) options directly nor a way to do it programatically. - So afaik VBE irrevocably forces autoformatting upon the user by partial workarounds.
a) Class method
For the sake of the art and just for fun an actually (very) basic class approach to give you a starting idea; assignment arguments are passed as strings allowing any optical formatting - if that's what you really want:
Example call in current module
Sub ExampleCall()
Dim x As New cVars
x.Add "price = 11.11" ' wrong assignment
'...
x.Add "price = 10.01" ' later correction
x.Add "quantity = 1241.01"
x.Add "vat = 0.11"
Debug.Print "The price is $ " & x.Value("price")
End Sub
Class module cVars
Option Explicit
Private dict As Object
Sub Add(ByVal NewValue As Variant)
'split string tokens via equal sign
Dim tmp
tmp = Split(Replace(Replace(NewValue, vbTab, ""), " ", "") & "=", "=")
'Identify key and value item
Dim myKey As String, myVal
myKey = tmp(0)
myVal = tmp(1): If IsNumeric(myVal) Then myVal = Val(myVal)
'Add to dictionary
If dict.exists(myKey) Then
dict(myKey) = myVal
Else
dict.Add myKey, myVal
End If
'Debug.Print "dict(" & myKey & ") =" & dict(myKey)
End Sub
Public Property Get Value(ByVal myVarName As String) As Variant
'get variable value
Value = dict(myVarName)
End Property
Private Sub Class_Initialize()
'set (late bound) dict to memory
If dict Is Nothing Then Set dict = CreateObject("Scripting.Dictionary")
End Sub
Private Sub Class_Terminate()
Set dict = Nothing
End Sub
Edit #1 as of 3/3 2021
b) Rem Evaluation method
Once again only for the sake of the art a way to read assignments entered into outcommented code lines via, yes via Rem (heaving a deep sigh for this archaic use originating from former Basic times) as it allows to format data with any wanted spaces or tabs and won't be mixed up hopefully with current outcommentings via apostrophe '.
This Test procedure only needs the usual declarations plus some assignment calls as well as the mentioned Rem part. Two simple help procedures get code lines, analyze them via a dictionary class cVars and eventually assign them.
Note that the following example
needs a library reference to Microsoft Visual Basic Extensibility 5.3 and
uses the unchanged class cVars of section a) simply to avoid rewriting it.
Option Explicit
Private Const THISMODULE As String = "Module1" ' << change to current code module name
Sub Test() ' procedure name of example call
'Declare vars
Dim price As Double: Assign "price", price
Dim quantity As Double: Assign "quantity", quantity
Dim vat As Double: Assign "vat", vat
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'Enter assignments via Rem(ark)
'(allowing any user defined formatting therein)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Rem price = 10.01
Rem quantity = 1241.01
Rem vat = 0.11
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Debug.Print quantity & " à $" & price & " = " & Format(quantity * price, "$#,##0.00")
End Sub
Help procedure Assign evaluating Rem codelines in procedure Test
Sub Assign(ByVal myVarName As String, ByRef myvar)
Const MyProc As String = "Test"
Dim codelines
getCodelines codelines, THISMODULE, ProcedureName:=MyProc
'Debug.Print Join(codelines, vbNewLine)
Dim x As New cVars ' set class instance to memory
Dim line As Variant, curAssignment
For Each line In codelines
curAssignment = Split(line, "Rem ")(1) ' remove Rem prefix from codelines
If curAssignment Like myVarName & "*" Then
x.Add curAssignment
myvar = x.Value(myVarName)
End If
Next
End Sub
Help procedure getCodelines
Called by above proc Assign. Returns the relevant Rem Codelines from the calling procedure Test. - Of course it would have been possible to filter only one codeline.
Sub getCodelines(ByRef arr, ByVal ModuleName As String, ByVal ProcedureName As String)
Const SEARCH As String = "Rem "
'a) set project
Dim VBProj As Object
Set VBProj = ThisWorkbook.VBProject
If VBProj.Protection = vbext_pp_locked Then Exit Sub ' escape locked projects
'b) set component
Dim VBComp As Object
Set VBComp = VBProj.VBComponents(ModuleName)
Dim pk As vbext_ProcKind
'd) get relevant code lines
With VBComp.CodeModule
'count procedure header lines
Dim HeaderCount As Long: HeaderCount = .ProcBodyLine(ProcedureName, pk) - .ProcStartLine(ProcedureName, pk)
'get procedure code
Dim codelines
codelines = Split(.lines(.ProcBodyLine(ProcedureName, pk), .ProcCountLines(ProcedureName, pk) - HeaderCount), vbNewLine)
'filter code lines containing "Rem" entries
codelines = Filter(codelines, SEARCH, True)
End With
'return elements
arr = codelines
End Sub
Don't forget to integrate the class module CVars from section a)!
I am having a very strange problem. I am not able to get the value returned from a simple function as below if the return value is more than one char. Now the second problem is that following code is not assigning "WTH" to sheetName variable. Refer to the screenshot 2. UPDATED AFTER CYRIL'S COMMENTS
Public Sub WTHFormatter()
Dim sheetName As String
sheetName = "WTH"
Dim rng1 As Range
'delete empty rows
lastRowWTH = getLastRow(sheetName, 2)
'Delete rows below the last Row
Worksheets(sheetName).Rows(lastRowWTH + 1 & ":" & Worksheets(sheetName).Rows.Count).Delete
' build first range
Set rng1 = Worksheets(sheetName).Range("B11:F" & lastRowWTH)
Call setCellBorders(rng1)
Set rng1 = Worksheets(sheetName).Range("H11:K" & lastRowWTH)
Call setCellBorders(rng1)
'determine the range for months
For i = 13 To 24
If Cells(7, i) = "" Then
lastCol = i - 1
Exit For
End If
lastCol = i
Next
ColLetter = returnLabel(lastCol)
ColLetter2 = returnLabel(lastCol + 2)
ColLetterX = returnLabel(lastCol + 14)
Set rng1 = Worksheets(sheetName).Range("K17:" & ColLetter & lastRowWTH)
Call setCellBorders(rng1)
Set rng1 = Worksheets(sheetName).Range(ColLetter2 & lastRowWTH & ":" & ColLetter3 & lastRowWTH)
Call setCellBorders(rng1)
End Sub
Function returnLabel(num1 As Long) As String
Dim ColumnLetter As String
ColumnLetter = Split(Cells(1, num1).Address, "$")(1)
returnLabel = ColumnLetter
End Function
The above function returns blank and varTest has nothing after the execution. If I do the line by line execution, I see that test1 in function is not 'Null'.
If I break the execution and probe the variables I see "test1 =" only as per the screen shot below. And this is breaking my code.
Strangely, If I call the function from 'Immediate Window', it returns the expected value.
Things I have already done:
I have tested in a fresh file using simple code as above.
Tested in different PC and the same code is working fine with same version of Windows 10 & Office 365.
Updated / Re-installed MS Office 365
Restarted the PC
If the return value is a single character like "A", the code is working fine.
Failed to understand the reason here. Any help is appreciated.
UPDATE1
I tried it on a fresh file while the code above worked, but the main code is having a new similar problem. This has started happening just now. It's not assigning a string value to the variable. See the attached screenshot.Screenshot of the VBA Code. I am assuming there is some problem with system or some virus.
If the idea is to have a function, that an array, this is possible with the following code:
Function Test1() As Variant
ReDim result(2)
result(0) = "AJ"
result(1) = "A"
Test1 = result
End Function
Sub Main()
Dim varTest As Variant
varTest = Test1(0)
Debug.Print varTest
varTest = Test1(1)
Debug.Print varTest
End Sub
It is questionable why would it be needed, but as a "test-exercise" it is ok.
Going to put my comments into an answer to consolidate and add more explanation.
Pointing out some errors in the code before correcting:
Function test1(num1) 'declare `as variant` to ensure you're returning an array
test1 = "AJ" 'this appears to be saving a single string to var test1
test1 = "A" 'you are now overwriting the above string
End function
Sub test()
varTest = test1(1) 'you have a single string from the function and arrays start at 0, not 1
End sub
You would want to specify the place in the array, after declaring an array, within your function such that:
Function test1() As Variant
Dim arr(2) As Variant 'added array because test1 = BLAH is the final output in a function
arr(0) = "AJ" 'added (1) to call location in array
arr(1) = "A" 'added (2) to call location in array
test1 = arr
End Function
Sub test()
Dim varTest As Variant
varTest = test1(0) 'outputs "AJ" in immediate window
Debug.Print varTest
End Sub
Now you can debug.print your array values, or set to varTest based on the location in the array.
Edit: Tested after my consolidating comments and recognized that there was not an actual output for test1 as an array at the end of the function, so had to go back and add a second array to set test = allowing an array output from a function.
Your code is running as it should.
The test1 function assigns the value AJ to the test1 variable, and then it assigns the value A to the test1 variable.
You could assign the value 50 in your test procedure and it will return A.
I think this is the code you're after:
Function test1(num1) As String
' Dim MyArray As Variant
' MyArray = Array("AJ", "A")
'OR
Dim MyArray(0 To 1)
MyArray(0) = "AJ"
MyArray(1) = "A"
If num1 >= LBound(MyArray) And num1 <= UBound(MyArray) Then
test1 = MyArray(num1)
Else
test1 = "Item not here"
End If
End Function
Sub test()
Dim varTest As String
'Return the second item in the array from the function.
varTest = test1(1)
MsgBox varTest
'Return the first item in the array from the function.
varTest = test1(0)
MsgBox varTest
'Returns "subscript out of range" error as array is only 2 elements in size (0 and 1).
'The error is dealt with in the function using the IF....ELSE...END IF block and returns
'"Item not here" instead.
varTest = test1(2)
MsgBox varTest
End Sub
I solved this by using declaring the variables even when option explicit is not used.
The old code runs without throwing errors even when the variable is not declared and option explicit is also not used. But, for some reasons, it doesn't read / write undeclared variables as expected.
Now as per #cyril suggestion, I declared the variables being used and run the code. This time code ran as expected.
This happened for multiple of variables and at different stages in the code.
I'm trying to figure this out and can't.
I keep getting an error: "Compile error - Argument not optional". I am supplying the arguments and they are set as Optional!
Trying to pass a string and an array to a function and count occurrences of the array strings within the string passed.
Code stops running at the line:
Public Function countTextInText(Optional text As String, Optional toCountARR As Variant) As Integer
with a "Compile error: Argument not optional" message highlighting the Val in the line:
For Each Val In toCountARR
Full code:
Private Sub Worksheet_Change(ByVal Target As Range)
Dim nameR As Range
Dim colR As Range
Dim TKRcnt As Integer
Dim TKRarr() As Variant
TKRarr = Array("TKR", "THR", "Bipolar")
Dim ORIFcnt As Integer
Dim ORIFarr() As Variant
TKRarr = Array("ORIF", "Ilizarov", "PFN")
Set nameR = Range("P2:P9")
Set colR = Range("B2:B50,G2:G50,L2:L50")
For Each namecell In nameR
For Each entrycell In colR
If entrycell.text = namecell.text Then
TKRcnt = countTextInText(entrycell.Offset(0, 2).text, TKRarr)
ORIFcnt = countTextInText(entrycell.Offset(0, 2).text, TKRarr)
End If
Next entrycell
MsgBox (namecell.text & " TKR count: " & TKRcnt & " ORIF count: " & ORIFcnt)
Next namecell
End Sub
Public Function countTextInText(Optional text As String, Optional toCountARR As Variant) As Integer
Dim cnt As Integer
Dim inStrLoc As Integer
For Each Val In toCountARR
inStrLoc = InStr(1, text, Val)
While inStrLoc <> 0
inStrLoc = InStr(inStrLoc, text, Val)
cnt = cnt + 1
Wend
Next Val
Set countTextInText = cnt
End Function
Val is a VBA function which requires a single, mandatory, argument - therefore the compiler generates the message saying "Argument not optional" if you don't provide that argument. (MSDN documentation of Val)
It is a bad idea to use VBA function names as variable names, so I would recommend you don't use Val as a variable name - use myVal or anything else that VBA hasn't already used.
If you really want to use Val (and you are sure that you won't be needing to access the Val function at all), you can use it as a variable name if you simply declare it as such, e.g.
Dim Val As Variant
You will also have problems with your line saying
Set countTextInText = cnt
as countTextInText has been declared to be an Integer, and Set should only be used when setting a variable to be a reference to an object. So that line should be
countTextInText = cnt
For those coming late to this question because of the question's title, as I did, having received this error while using the .Find method -
In my case, the problem was that the variable I was Seting was not Dimd at top of function.
My Example
Sub MyTest()
Dim tst, rngAll
rngAll = [a1].CurrentRegion
tst = fnFix1Plus1InValues(ByVal rngAll As Range)
End Sub
Public Function fnFix1Plus1InValues(ByVal rngAll As Range) As Boolean
Dim t1, t2, arr, Loc '<=== Needed Loc added here
Set Loc = rngAll.Find(What:="+", LookIn:=xlValues, LookAt:=xlPart, MatchCase:=False)
If Not Loc Is Nothing Then
Do Until Loc Is Nothing
t1 = Loc.Value
If fnContains(t1, "+") Then
'Do my stuff
End If
Set Loc = rngAll.FindNext(Loc)
Loop
End If
End Function 'fnFix1Plus1InValues
Task:
My goal is to check if a value has been set in the BuiltInDocumentProperties collection of an Excel workbook.
Amplifying remark:
I know that some doc properties items never show a value in Excel as they
belong to ms word or ppt applications (e.g. item 15 'Number of words', item 25 'Slides' ...).
On the other hand some properties have only occasional values in case of first use:
item 10: 'Last print time'
item 12: 'Last save time'
Of course one can do that by error trapping:
Example Code with Error trapping:
Sub test_showDocPropValue()
' Name of built in doc prog
Dim propName As String
' a) Choose builtin doc prop disposing about a set value, such as 'Author', 'Category', ...
' propName = "Category"
' b) Choose builtin doc prop of another ms application
' propName = "Number of pages"
' c) Choose doc prop with occasionally set values
propName = "Last print time"
' Show result
MsgBox propName & " = " & showDocPropValue(propName), vbInformation, "BuiltInDocumentProperties"
End Sub
Function showDocPropValue(ByVal propName As String) As Variant
Dim prop As Object
Dim ret
' Built in Doc Props collection
Set prop = ThisWorkbook.BuiltinDocumentProperties
' Error trapping
On Error Resume Next
ret = prop(propName).Value
If Err.Number <> 0 Then
ret = "(No value set)"
Debug.Print Err.Number & ": " & Err.Description
End If
' Return
showDocPropValue = ret
End Function
My Question:
For principal reasons I'd like to know if there is a straightforward method to get builtinDocumentProperties values avoiding error trapping
Additional hint
Just to complete the theme by showing methods without error trapping within CUSTOM doc props, you can easily check for the existence of such items with the following code:
Private Function bCDPExists(sCDPName As String) As Boolean
' Purp.: return True|False if custom document property name exists
' Meth.: loop thru CustomDocumentProperties and check for existing sCDPName parameter
' Site: <http://stackoverflow.com/questions/23917977/alternatives-to-public-variables-in-vba/23918236#23918236>
' cf: <https://answers.microsoft.com/en-us/msoffice/forum/msoffice_word-mso_other/using-customdocumentproperties-with-vba/91ef15eb-b089-4c9b-a8a7-1685d073fb9f>
Dim cdp As Variant ' element of CustomDocumentProperties Collection
Dim boo As Boolean ' boolean value showing element exists
For Each cdp In ThisWorkbook.CustomDocumentProperties
If LCase(cdp.Name) = LCase(sCDPName) Then
boo = True ' heureka
Exit For ' exit loop
End If
Next
bCDPExists= boo ' return value to function
End Function
I think there is not a straightforward way of doing it -- this is a Collection which doesn't have an easy way to test for existence of an item (versus a Dictionary.Exists method, or using a Match function against an array, etc.). Apart from error-trapping (which seems pretty straightforward IMO) you are left basically to use brute-force iteration over the collection's items, checking the .Name property for equivalence.
This is a approach similar to what you have with the CustomDocumentProperties to avoid the Error-handling if desired (although I see nothing explicitly wrong about that approach). Modified your showDocPropValue function and added an additional GetDocProp function to be used in tandem. This should work with your test case:
Function showDocPropValue(ByVal propName As String) As Variant
Dim prop As Object
Dim ret
' Get the BuiltInDocumentProperty(propName) if it exists
Set prop = GetDocProp(propName)
If prop Is Nothing Then
ret = "(No value set)"
Else
ret = prop(propName).Value
End If
' Return
showDocPropValue = ret
End Function
Function GetDocProp(ByVal propName$)
' returns the BuiltInDocumentProperties(propName) object if exists, else Nothing
Dim p As Object
Dim prop As Object
Set prop = ThisWorkbook.BuiltinDocumentProperties
For Each p In prop
If p.Name = propName Then
Set GetDocProp = p
GoTo EarlyExit
End If
Next
Set GetDocProp = Nothing
EarlyExit:
End Function
Personally, I would use this version instead (error handling in the GetDocProp function):
Function GetDocProp(ByVal propName$)
' returns the BuiltInDocumentProperties(propName) object if exists, else Nothing
Dim ret As Object
On Error Resume Next
Set ret = ThisWorkbook.BuiltinDocumentProperties(propName)
If Err.Number <> 0 Then Set ret = Nothing 'just to be safe...
Set GetDocProp = ret
End Function
I am Trying to run this code but it keeps giving me an error message while compiling
Argument not optional
I am using a function called csvRange
Sub CS()
csvRange()
End Sub
Function csvRange(FirstNum, SecondNum) As Double
i As Integer
For i = FirstNum.Value To SecondNum.Value
csvRange = csvRange & i & "+"
Next
End Function
can anyone help.
you want to call csvRange() but csvRange requires 2 arguments to pass.
And you forgot to save the return value.
for example
Sub CS()
var first = 1
var second = 50
var result
result = csvRange(first, second)
End Sub
Function csvRange(FirstNum, SecondNum) As Double
i As Integer
For i = FirstNum.Value To SecondNum.Value
csvRange = csvRange & i & "+"
Next
End Function
A couple of remarks:
- You call the function csvrange without parametervalues which you did not define as being optional.
- You do nothing with the value the function returns
- the i is an integer and the result a double. it is bad practice to mix them both in your for-next loop
Your code requires a few fixes:
1) Use appropriate arguments for csvRange.
2) Use the return value of csvRange for something (this is not mandatory, but typically required in well designed code).
3) Declare the type of arguments for csvRange.
4) You seem to be using csvRange to get a String. Change code accordingly.
You would use something like
Sub CS()
Dim rng1 As Range, rng2 As Range
Set rng1 = ...
Set rng2 = ...
Set retval As String
retval = csvRange(rng1, rng2)
End Sub
Function csvRange(FirstNum As Range, SecondNum As Range) As String
i As Integer
csvRange = ""
For i = FirstNum.Value To SecondNum.Value
csvRange = csvRange & Cstr(i) & "+"
Next i
End Function
PS1: Your output will end with a trailing "+". Perhaps this is not what you want.
PS2: I do not have a system to test this code.