I have data in Stata regarding the feeling of the current situation. There are seven types of feeling. The data is stored in the following format (note that the data type is a string, and one person can respond to more than 1 answer)
feeling
4,7
1,3,4
2,5,6,7
1,2,3,4,5,6,7
Since the data is a string, I tried to separate it by
split feeling, parse (,)
and I got the result
feeling1
feeling2
feeling3
feeling4
feeling5
feeling6
feeling7
4
7
1
3
4
2
5
6
7
1
2
3
4
5
6
7
However, this is not the result I want. which is that the representative number of feelings should go into the correct variable. For instance.
feeling1
feeling2
feeling3
feeling4
feeling5
feeling6
feeling7
4
7
1
3
4
2
5
6
7
1
2
3
4
5
6
7
I am not sure if there is any built-in command or function for this kind of problem. I am thinking about using forval in looping through every value in each variable and try to juggle it around into the correct variable.
A loop over the distinct values would be enough here. I give your example in a form explained in the Stata tag wiki as more helpful and then give code to get the variables you want as numeric variables.
* Example generated by -dataex-. For more info, type help dataex
clear
input str13 feeling
"4,7"
"1,3,4"
"2,5,6,7"
"1,2,3,4,5,6,7"
end
forval j = 1/7 {
gen wanted`j' = `j' if strpos(feeling, "`j'")
gen better`j' = strpos(feeling, "`j'") > 0
}
l feeling wanted1-better3
+---------------------------------------------------------------------------+
| feeling wanted1 better1 wanted2 better2 wanted3 better3 |
|---------------------------------------------------------------------------|
1. | 4,7 . 0 . 0 . 0 |
2. | 1,3,4 1 1 . 0 3 1 |
3. | 2,5,6,7 . 0 2 1 . 0 |
4. | 1,2,3,4,5,6,7 1 1 2 1 3 1 |
+---------------------------------------------------------------------------+
If you wanted a string result that would be yielded by
gen wanted`j' = "`j'" if strpos(feeling, "`j'")
Had the number of feelings been 10 or more you would have needed more careful code as for example a search for "1" would find it within "10".
Indicator (some say dummy) variables with distinct values 1 or 0 are immensely more valuable for most analysis of this kind of data.
Note Stata-related sources such as
this FAQ
this paper
and this paper.
I have let's say two files Input1.txt and Input2.txt. Each of them is a text file containing a single line of 5 numbers separated by a tab.
For instance Input1.txt is
1 2 3 4 5
and Input2.txt is
6 7 8 9 10
The output that I desire is Output.txt :
Input1 1 2 3 4 5
Input2 6 7 8 9 10
So I want to merge the files in a table with an extra first column containing the names of the original files. Obviously I have more than 2 files (actually 1000) and I would like to make it with a for loop. You can assume that all my files are named as Input*.txt with * between 1 and 1000 and that they are all in the same directory.
I know how to do it with R, but I would like to make it with a basic line of commands in the ubuntu shell. Is it feasible ? Thanks for any help.
Assuming the line in Input1.txt, Input2.txt, etc. is terminated with a newline character, you can use
for i in Input*.txt
do
printf "%s " "$i"
cat "$i"
done > Output.txt
The result is
Input1.txt 1 2 3 4 5
Input2.txt 6 7 8 9 10
If you want to get Input1 etc. without .txt you can use
printf "%s " "${i%.txt}"
Can't find a solution, although thousands of variants of this question have been asked before.
I have several text files in a directory. I want to add one column to the beginning of each file. The added column for the first file is a column of 0's, for the second file it is a column of 1's, for the third file it is a column of 2's etc.
So, how to turn this:
0 2 3 2
3 3 3 1
4 3 4 2
to this:
0 0 2 3 2
0 3 3 3 1
0 4 3 4 2
and this:
2 3 4 3
2 3 3 5
5 4 1 2
to this:
1 2 3 4 3
1 2 3 3 5
1 5 4 1 2
in a loop?
I tried the following without any success:
#!/bin/bash
path=/prosjekt/tvs/QSexpt1_16K
jj=0
for file in "$path"/*.lsf;
do
awk '{$1=$(($jj)); print}' $file >> qq.txt
$jj=$(($jj+1))
done
Try this:
#!/bin/bash
path=/prosjekt/tvs/QSexpt1_16K
jj=0;
for file in "$path"/*.lsf; do
awk "{printf \"$jj\"; print}" "$file" >> qq.txt
jj=$(($jj+1))
done;
Problems in your try were: $jj=$(($jj+1)) - you need to assign variable without $; bash variable won't expand into ''.
How do I findout missing number from two sequence using bash script
from example I have file which contain following data
1 1
1 2
1 3
1 5
2 1
2 3
2 5
output : missing numbers are
1 4
2 2
2 4
This awk one-liner gives the requested output for the specified input:
$ awk '$2!=l2+1&&$1==l1{for(i=l2+1;i<$2;i++)print l1,i}{l1=$1;l2=$2}' file
1 4
2 2
2 4
a solution using grep:
printf "%s\n" {1..2}" "{1..5} | grep -vf file
know question is not clear at a glance, i have this table:
ID Start End
1 1 4
2 2 5
3 4 9
4 8 10
I want to set these in an order (illustration below). I need an array that its indices will increment by one with respect to start and the end positions, and get the greatest index of all. For example:
1. ####
2. ####
3. ######
4. ###
so array will be;
array =(1,2,2,3,2,1,1,2,2,1)
i did not start to write anything because i could not figure whether that is possible with bash. please advice..
Just loop over all the elements of each interval:
#! /bin/bash
array=()
while read id start end ; do
for (( i=start ; i<=end ; i++ )) ; do
let array[i]++
done
done << EOF
1 1 4
2 2 5
3 4 9
4 8 10
EOF
echo "${array[#]}"